A Nice Simplification Challenge | Math Olympiad | Algebra

A Nice Simplification Challenge | Math Olympiad | Algebra
Welcome to another algebraic Olympiad challenge! 🎉 In this video, we tackle an interesting algebra simplification problem that will improve your skills and push your limits. Can you simplify this tricky algebraic expression?
Join us as we break down the steps, provide insightful tips, and reveal the solution to this special algebra problem. Whether you're preparing for a math competition or just love a good challenge, this video is perfect for you!
🔔 Don't forget to subscribe for more math hacks, tips, and challenging problems to sharpen your skills!
🔢 What You'll Learn:
Key techniques for simplifying algebraic expressions (substitution)
Common pitfalls and how to avoid them
Tips and tricks to approach Math Olympiad questions with confidence
📚 Additional Resources:
• Challenging Algebra Si...
• Crack This IMO Challen...
• A Fascinating Radical ...
• Math Olympiad | An Alg...
🎯 This video is perfect for students, math enthusiasts, or anyone seeking to sharpen their problem-solving skills and gain confidence in dealing with radical expressions.
#matholympiad #radical #simplification #problemsolving #mathematics #challenge #mathskills #radicals #math #algebra #learnmaths
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Thank You for Watching!!

Пікірлер: 8

  • @user-xk8fl7fc5t
    @user-xk8fl7fc5t10 күн бұрын

    👍

  • @abcekkdo3749
    @abcekkdo374911 күн бұрын

    E=41+29√2

  • @ramunasstulga8264
    @ramunasstulga826411 күн бұрын

    I just had my mind opened after you separated 99+70^½ into 7^²+(5×2^½)²+2×7×5×2^½ because I thought a+b×Z½ is sufficient method yet it can sometimes so long to get to the solution

  • @ZhilinChen-my7tp
    @ZhilinChen-my7tp11 күн бұрын

    29√2+41

  • @RajeshKumar-wu7ox
    @RajeshKumar-wu7ox11 күн бұрын

    41+29√2

  • @RyanLewis-Johnson-wq6xs
    @RyanLewis-Johnson-wq6xs11 күн бұрын

    (1/(99-70Sqrt[2])^5)^(1/6)=41+29Sqrt[2]

  • @RealQinnMalloryu4
    @RealQinnMalloryu411 күн бұрын

    (6/1.3 ➖ 11.35.2 )=(3^2/1^1.3^1 ➖ 11^1.3^15^1.2^1 ).=(1^1/1^1.3^11^12^1] 32 (x ➖ 3x+2

  • @RealQinnMalloryu4

    @RealQinnMalloryu4

    11 күн бұрын

    (1^1/3^33 ➖ 2^35 2^15^1)1^1/3^2 )=(3^3^11 2^5^7 2^1^5^1)3^2 (1^1^11^1 ➖ 1^1^1 1^1^1^1)3^2 (1^1)^3^2 3^2.(x ➖ 3x+2)

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