A Nice Exponential Equation | How to solve for X in this Problem ? | Two Methods
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@learncommunolizer
13 күн бұрын
You're so welcome! Thank you very much
I guess one day, a long time ago, I would have known how to do that. But if you don't use it, you lose it.
first - made blunders, so some work to get it right - but I think that is is easier. first converted exponents to just x, then it is a slug test to massage it. This is my work 2^(x-5) = 3^(x+1) 1/32* 2^x = 3*3^x 1/96 * 2^x = 3^x log(1/96) + x log(2) = x log(3) log(1/96) = x( log(3) - log(2) ) = x log(3/2 ) x = log(1/96)/log(3/2) = -11.257
I think you can change the first solution into log form and further calculate to correlate it to the second one
Excellent! Thank you!
@learncommunolizer
13 күн бұрын
You are welcome! Glad you enjoyed it!
Why did you use 'ln' in the first solution and 'log' in the second. It doesn't matter, does it?
@user-cg5xv4zz2b
13 күн бұрын
whn you take the log and do log match - ok - but when convert to real numbers - it matters a lot. ln is based on e, where log is based on 10. so log(5) and ln(5) are NOT the same number
At least the first 7 decimals are equal...