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  @TaraChand-uo2rq9 сағат бұрын

  81--26=65

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  @TaraChand-uo2rq10 сағат бұрын

  2^4=16.Pl.delete 26

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  @TaraChand-uo2rq10 сағат бұрын

  😮 Hence m=4

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  @TaraChand-uo2rq10 сағат бұрын

  3^4=81, 2^4=26

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  @TaraChand-uo2rq10 сағат бұрын

  81--26=66

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  @TaraChand-uo2rq10 сағат бұрын

  3^4 --2^4=65

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  @TaraChand-uo2rq10 сағат бұрын

  m=4

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  @sans133110 сағат бұрын

  an equation such as this is impossible without guess-and-check. this is a rearranged form of the equation a^x + b = c^x where a, b, and c are constants equations like this simply cannot be solved unless by calculator.

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  @ludmilak939615 сағат бұрын

  Это зеркальное изображение? Если нет, то кто же так делит, что за кретинизм!

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  @robertdownyjr.6008Күн бұрын

  Wonderful

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  @danielfranca1939Күн бұрын

  First to comment. Thanks for the nice work in mathematics.❤

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  @BetabdullahКүн бұрын

  To solve the equation (x+1)4+(x+2)4=17(x+1)^4 + (x+2)^4 = 17(x+1)4+(x+2)4=17, we need to find all possible solutions, including real and complex solutions. Step 1: Identify Integer Solutions by Trial and Error For x=0x = 0x=0: (0+1)4+(0+2)4=14+24=1+16=17(0+1)^4 + (0+2)^4 = 1^4 + 2^4 = 1 + 16 = 17(0+1)4+(0+2)4=14+24=1+16=17 Thus, x=0x = 0x=0 is a solution. For x=−3x = -3x=−3: (−3+1)4+(−3+2)4=(−2)4+(−1)4=16+1=17(-3+1)^4 + (-3+2)^4 = (-2)^4 + (-1)^4 = 16 + 1 = 17(−3+1)4+(−3+2)4=(−2)4+(−1)4=16+1=17 Thus, x=−3x = -3x=−3 is another solution. Step 2: Find Complex Solutions Next, let’s find the complex solutions by rewriting the equation. Rewriting the original equation using y=x+1y = x + 1y=x+1: y4+(y+1)4=17y^4 + (y+1)^4 = 17y4+(y+1)4=17 Trying y=0y = 0y=0: 04+14=0+1=1(Not a solution)0^4 + 1^4 = 0 + 1 = 1 \quad \text{(Not a solution)}04+14=0+1=1(Not a solution) Trying y=−1y = -1y=−1: (−1)4+04=1+0=1(Not a solution)(-1)^4 + 0^4 = 1 + 0 = 1 \quad \text{(Not a solution)}(−1)4+04=1+0=1(Not a solution) We need a different approach to find the remaining solutions. Let’s analyze the polynomial equation more deeply. Step 3: Solving the Polynomial We know from polynomial properties that it can produce complex roots. Considering: (x+1)4+(x+2)4=17(x+1)^4 + (x+2)^4 = 17(x+1)4+(x+2)4=17 Let’s solve for xxx in complex terms: We can solve for the polynomial by setting up: u=x+1u = x + 1u=x+1 v=x+2v = x + 2v=x+2 Then: u=v−12u = \frac{v-1}{2}u=2v−1 Substituting and solving for the complex roots using the quadratic formula properties, we get: u=−3±15i2u = \frac{-3 \pm \sqrt{15}i}{2}u=2−3±15i This results in: x=−3+15i2andx=−3−15i2x = \frac{-3 + \sqrt{15}i}{2} \quad \text{and} \quad x = \frac{-3 - \sqrt{15}i}{2}x=2−3+15iandx=2−3−15i Final Solution Set Thus, the complete solution set for the equation (x+1)4+(x+2)4=17(x+1)^4 + (x+2)^4 = 17(x+1)4+(x+2)4=17 includes: 1. Real solutions: x=0x = 0x=0 and x=−3x = -3x=−3 2. Complex solutions: x=−3+15i2x = \frac{-3 + \sqrt{15}i}{2}x=2−3+15i and x=−3−15i2x = \frac{-3 - \sqrt{15}i}{2}x=2−3−15i So, the complete set of solutions is: {0,−3,−3+15i2,−3−15i2}\{ 0, -3, \frac{-3 + \sqrt{15}i}{2}, \frac{-3 - \sqrt{15}i}{2} \}{0,−3,2−3+15i,2−3−15i}

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  @pradipkumarpatra5160Күн бұрын

  Great Exponential.

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  @hayat.oyundurКүн бұрын

  X2(1-X)=12 X=-2

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  @tomalabbasi3905Күн бұрын

  ❤

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  @danielfranca19392 күн бұрын

  Nice as always sir. I love your detailed explanation. More grace sir...❤❤❤

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  @danielfranca19392 күн бұрын

  Nice as always sir. I love your detailed explanation. More grace sir...❤❤❤

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  @MalikHamidov2 күн бұрын

  ❤Good question ❤👍👍👍

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  @brunodelenclos60352 күн бұрын

  Belle démonstration.Merci beaucoup..

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  @elongeelive5632 күн бұрын

  🙏 thank you so much sir,

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  @elongeelive5632 күн бұрын

  Please sir can you do another video of this same problem but this eliminate the x variable first we are facing it challenging to arrive at the same answer

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  @AhmedDebbahi3 күн бұрын

  🇩🇿🇩🇿 شكرا

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  @prakashbk97823 күн бұрын

  4

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  @user-qy8re3yx3d3 күн бұрын

  x=49, на вскидку!:)

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  @Damushorts3 күн бұрын

  Nice 👍👍👍

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  @boudboa3 күн бұрын

  Nice and thanks for the video! However, the sound goes out a few time during the video. Either you have a sound recording issue or maybe it's KZread automatic words filtering feature (?) I noticed that this happens twice, at around 4:10 and another time a little further in the video.

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  @nikolayguzman3314 күн бұрын

  The explanation is on high level. This is very good job.

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  @emmanuelahmadtambeayuk39704 күн бұрын

  I love both methods

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  @user-df8ph8hz9t4 күн бұрын

  Thanks

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  @justekiara19534 күн бұрын

  2nd method.

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  @dawituru64234 күн бұрын

  -2

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  @beverlyjin99485 күн бұрын

  If X=0 , Whole thing is meaning less, because 1/0.

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  @Parmodraybittu45455 күн бұрын

  Rjd. King 💚💚💚👑💚💚💚💚💚💚💚💚💚💚💚💚💚💚💚💪💪💪💪💪💪💪💪💪💪

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  @danielfranca19395 күн бұрын

  Second method asap.

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  @opulence32225 күн бұрын

  So lively dude, I like your enthusiasm. As for me, 2nd method is better.

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  @vitorchevitarese62346 күн бұрын

  Geneus

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  @ElvisSaturn6 күн бұрын

  Fun as always!

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  @opulence32226 күн бұрын

  Not clear to me

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  @opulence32226 күн бұрын

  Great video, man, but....

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  @thompinhas6 күн бұрын

  matemática é linda !!:3

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  @dardoburgos31797 күн бұрын

  X= ✓2.

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  @Calmminds7997 күн бұрын

  As the number is smaller we can apply trail and error method. Answer is 4.

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  @user-sy4yk3pb1x8 күн бұрын

  Just take m=1,2,3 4.Now 4 satisfies the eqn.

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  @pradipkumarpatra51608 күн бұрын

  The solution such as mind blowing. But there is a wrong line of solution is in the 2nd vertical line. x²-x-30=0 =>x²+5x-6x-30=0 =>(x²+5x)-(6x+30)=0 But Sir, instead this line you have written that x²-x-30=0 =>(x²+5x)-(6x-30)=0 Sir, please consider it. Thanks of a million Sir.🎉❤🎉

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  @BUY_YOUTUB_VIEWS.3048 күн бұрын

  you should do some colabs for sure