Wheatstone Bridge Problem
Physics Ninja shows you how to solve for an unknown resistance using a Wheatstone Bridge. We first use Kirchhoff's rules to get an expression for an unknown resistance and then look an at example problem
Physics Ninja shows you how to solve for an unknown resistance using a Wheatstone Bridge. We first use Kirchhoff's rules to get an expression for an unknown resistance and then look an at example problem
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Ahhhhh.....I'm just going to be more truthful right now. You are the only person who has been able to explain this to me😭😭😭😭😭😭, thank you so much sir. God Bless You. Please don't stop bringing out videos like these. Thank you so much sir.
Example 1- 750 ohms Example 2- 55.5 ohms Thanku so much for that explanation
Thanks for suggesting! It's really helpful 😁
thanks mate. got ready for my test
Thank you so much 750ohm 55.5 ohm
thank youu so much I finally see why those potential differences are equal ! my uni professor couldnt be more useless
@PhysicsNinja
2 ай бұрын
Thanks! You got this!
Thanks so much! My university professor did not explain this well at all, but with this video I now completely understand it.
Thank you sir !
Love you What an explanation...... 👍👍👍👍
Simple and concise explanation. Thanks.
Thanks a lot !
hi. RA is my (RX) whilst my RB is my variable resistor. RC and RD are known. How would I go about calculating this?
Thanks sooo much merrr
I have AB=1ohm, BC=4ohms, CD=5ohms, DA=3ohms and AD=2ohms. Find value of current in branch AB, AD, and BD
high precision Wheatstone bridge are capable to measure the resistance between ?
Thank you for your video explanations. im not goot at neither physics nor english, but you helped me both !!!! \^-^/
If R3 doesnt showed/tell any kilo ohms or ohms... How to solve it?
Seems to help, let's see if I retain it
Thanks bro
When the current flow through the resistor and the current is opposing the loop direction. Shouldn't the voltage drop be positive and not negative.
Kirchhoff’s loop rule states that if you travel against the current over a resistor, then +IR and if you travel with the current over a resistor then -IR. So im confused as to how you get the opposite at 4.20 in your video
@abenphilip4283
3 жыл бұрын
Yea.. I think he switched the signs...
@silverubica
3 жыл бұрын
Basicly its same thing,if u go your way E-I1R1+I3R3=0 or if u go his way E=I1R1-I3R3 he just should wrrite at end E not 0.I also use this way,if u have + of E following the direction of loop it will stay +,also if your current follow direction of loop on resistor it will be +,but u will write +E=+IR and not +E+IR
Actual king
thanx
Ex1 Rx = 750 ohms Ex2 Rx = 55.5 ohms. Is this corrects? Perhaps you could have showed us the answers on your video😬
@PhysicsNinja
5 жыл бұрын
Boom, you’ve mastered the Wheatstone bridge! Well done.
@kanchanthakurkt8437
4 жыл бұрын
Yeah me too
Is it ok to arrnge the r1 r2 r3 rx randomly
@PhysicsNinja
3 жыл бұрын
No! Be careful. If it’s balanced only some ratios will balance the bridge
@nsk6914
3 жыл бұрын
@@PhysicsNinja how to find the parallel equivalent resistance and capacitance
❤😊
From Bangladesh
ex 1 x=750 ex 2 x=55.5 is it right??
@PhysicsNinja
4 жыл бұрын
Nicely done!
Example 1: Rx= 75 ohms, example 2: Rx=55 ohms
@PhysicsNinja
5 жыл бұрын
Ex 1: 750 :) close enough
8:09 for lazy people. Jump there :)
@hercules1066
3 жыл бұрын
🖕🏿
15 goes into 900, 60 times. Missed a 0 in your example. Because 6 times 50 is only 300
@503jmn
3 жыл бұрын
But great video none the less.
Exteremly Confusing
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