Equivalent Resistance of a Cube
Physics Ninja considers a cube which has identical resistor along each edge. Symmetry arguments are used to find the equivalent resistance of the network. Visit www.physicsninja.org for more information about Physics Ninja.
Пікірлер: 50
6 years later this is still so helpful, thanks a lot!!
I made one of these in high school electronics in the 80's and stumped the teacher. Never could figure out how to solve it. I kept it for ages. Now finally I know how to solve it! Thanks!!!!
@PhysicsNinja
3 жыл бұрын
Awesome, I made one for my other video on the edge resistance. Check it out!
very intelligent way of looking at the circuit and visualizing the symmetry
Good to see AB de villiers teaching some high school physics
@varunmohan3760
2 жыл бұрын
they dont look THAT alike
very simple and brilliant at the same time
I'm trying to nab that bonus point for knowing how to get the Req. Thank you ninja!
@BMGRDNRJJ
Жыл бұрын
7:35 Req = 5/6R
You are amazing teach 🙌
What if we try to find the equivalent resistance between a and e points of a cube?
You're genius ❤️
I subscribed because initial sounds good of physics ninja😂
Is that KVL u r using or everything went through each other?
Can you do it using superposition method
Brother !!! How would I do if the resistance of the cube arm was unequal? I searched the whole net world and found no answer. If you have any known method. Let me know PLZ Don't skip this question.
Thank u sir
Thanks
Thank u
Great
Great!
nice
I have a question. What are the conditions for multiple resistors to be in parallel ? Please reply
@bharatgoel8809
2 жыл бұрын
wow what an idiot. The voltage across them should be same
Thank You.
can't we just use the symmetry lay and mark points with equal potentials? ex c,e,h have the same poential
@romayssaeabdessalami4004
2 жыл бұрын
Yeah I think we ca use this method
thank you sir best explanation
@PhysicsNinja
11 ай бұрын
So nice of you
@abhijeetgaming8848
11 ай бұрын
@@PhysicsNinja sir can you make video on series connection of bulb
so instead of considering the current through each resistor couldn't you just say that the resistors in each "section" of the diagram you made are connected in parallel, and then each section of the circuit is connected in series? Wouldn't you just be able to apply the equivalent resistance formulas for circuits in series and parallel?
Why do you chose only one path?
@PhysicsNinja
5 жыл бұрын
Great question - for this case i'm able to only choose one path because i've use symmetry to argue that the incoming current to the cube with be evenly split between the 3 branches - then split evenly between 2 branches. This allows me to get away with only doing one path and introducing the current I flowing into the cube. I can only do this because the resistors are all the same value.
@genecarlo3972
4 жыл бұрын
Also, the path is the same no matter which branch from junction A you choose :)
Can you please explain what is a current source,Thevenins Theorem and Nortons Theorem.
Put a high dollar ohm meter on it and read the answer.
This may be a stupid question but how did you calculate 5/6?
@PhysicsNinja
4 жыл бұрын
Not sure if this helps but 1/3+1/6+1/3 => 2/6+1/6+2/6 => 5/6
@KarlHerzog
2 жыл бұрын
one third and one third is 2 thirds, two thirds of 6 is 4, so that's 4 sixths + 1 sixth = 5 sixths
You are assuming the solution when you claim by "symmetry" that Iac = Iaf = Iah. You cannot KNOW that. This is the same as claiming that you KNOW that Vc = Vf = Vh. In reality you are just GUESSING that these currents are equal, and then deriving the resistance based on the guess. But you did not show that ALL the currents and voltages are consistent with the assumption/guess. Another way: You need to formulate your "symmetry guess" in the form of a set of equations that SHOWS there is symmetry. One way may be first to derive some equations that show that Vc=Vf and Ve=Vg and work from there.
madlad
I am from india
Hey can't you speak loud !!
Its just like u r murmuring and teaching to urself
Brother !!! How would I do if the resistance of the cube arm was unequal? I searched the whole net world and found no answer. If you have any known method. Let me know PLZ Don't skip this question.
@KarlHerzog
2 жыл бұрын
"I would use a voltage node method and basically set up a system of equations of 12 equations and 12 unknowns. You could also solve numerically using a simulation like ltspice." If you read the comments you'd have found your answer.
Brother !!! How would I do if the resistance of the cube arm was unequal? I searched the whole net world and found no answer. If you have any known method. Let me know PLZ Don't skip this question.
@mrgob26
Жыл бұрын
just like he made the 3 sections, take each resistor in their respective sections to be in parallel. now these 3 sections are in series. Using this you put any value of resistors and calculate parallel and series connections. A (1 | 2 | 3) --- (4 | 5 | 6 | 7 | 8 | 9) --- (10 | 11 | 12) B where 1,2,3.. denotes the resistors, " | " denotes parallel connection and "---" denotes series connection