Weighted Residual (5/5): Example #2

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Table of Contents:
2:07 - Boundary Conditions
3:00 - Exact Solution
5:36 - Assumed Solution & Residual Equation
8:12 - Collocation
9:49 - Subdomain
12:17 - Galerkin
15:22 - Comparison

Пікірлер: 15

  • @giorgitsintsadze9919
    @giorgitsintsadze9919 Жыл бұрын

    Terrific! I am glad I found it before I lost my mind

  • @andrepitt9226
    @andrepitt92264 жыл бұрын

    Thank you for all videos Mike!

  • @mmp434
    @mmp434 Жыл бұрын

    thank you so much

  • @zepallica123
    @zepallica1236 жыл бұрын

    Thank you for these videos!!!!!!

  • @DrMikeFoster

    @DrMikeFoster

    6 жыл бұрын

    You bet... thanks!

  • @Chaitanya123mech
    @Chaitanya123mech7 жыл бұрын

    very best explanation

  • @oukozamzu8627
    @oukozamzu86276 жыл бұрын

    Thank you

  • @rezagharibian986
    @rezagharibian9863 жыл бұрын

    Thank you very much

  • @cgswjs
    @cgswjs4 жыл бұрын

    May I ask how you got the assumed solution u=A(Y^4-H^3*Y)?

  • @psycho4570

    @psycho4570

    3 жыл бұрын

    ^^^ @mike foster

  • @TheRadChadDad

    @TheRadChadDad

    Жыл бұрын

    It was only an educated guess…one that can satisfy the boundary conditions.

  • @reddaxtor5662
    @reddaxtor5662 Жыл бұрын

    How to select an assumed solution?

  • @saipraneeth2959
    @saipraneeth29596 жыл бұрын

    All the videos are nicely explained . Thank you very much . i have a doubt in video 5 . In collocation method we forced the residual to zero at H/2 to be zero. But in the final solution when u solved for u at H/2 the collocation method solution is not equal to exact solution . Can you explain why ? when we made residual at H/2 as zero we have to get the exact solution at that point right ? why is this deviation ??

  • @midas32122

    @midas32122

    6 жыл бұрын

    This is because you are making another assumption to start with - the form of solution being a single sin function.

  • @gzitterspiller

    @gzitterspiller

    4 жыл бұрын

    He made that both functions on the differential equation give the same result at one point, that doesnt mean that both functions are equal at that point. In other words and to make it clear, the fact that the slope of the slope from 2 different functions at 1 specifict point is the same does not mean both functions are the same at that point.