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Very Very useful video 🎉🎉🎉🎉🎉

@NumericNest.

Ай бұрын

Thanks a lot

Fantastic 🎉🎉🎉🎉🎉

@NumericNest.

Ай бұрын

Thanks 🤗

Very very informative video 🎉🎉🎉🎉🎉

@NumericNest.

Ай бұрын

Glad you think so!

@NumericNest.

Ай бұрын

Glad you think so!

Couldn't figure out to use the degree indicator with 30, but did for 60. Oy.

Commas in description are wrong.Remove comma immediately okay 🎉🎉🎉🎉🎉

*=read as square root ^=read as to the power As per question 4^(sinx)^2+4^(cos x)^2=3.*2 Let us explain 4^(cosx)^2=4^(1-sinx^2) =(4^1)/(4^sinx^2)=4/(4^sinx^2) Suppose 4^sinx^2=Y So the given question can be written as below Y+(4/y)=3.*2 (Y^2+4)/y=3.*2 Y^2+4=3.*2.y Y^2- 3.*2y+4=0 Here a=1, b=-3.*2, c=4 Putting the formula (-b± *(b^2-4ac)/2a, we shall get Y=-(-3.*2)±*{(3.*2)^2-4.1.4)}/2.1 Y=3.*2±*{(18-16)}/2 Y={3.*2±*2}/2 Y=*2{(3±1)}/2 Y=(*2.4)/2 and( *2.2)/2 Y=2.*2 and *2 Y=(*2)^3 and (*2)^1 According to the 'suppose' Y=4^(sinx^2), {4=(*2)^4} Y=*2^(4sinx^2) Now put the value of Y *2(4sinx^2)=(*2)^3 4 sinx^2=3 Sinx^2=3/4 Sinx=±(*3/2) Sinx =sin60 X=60 degree Again (*2)^4sinx^2=(*2)^1 4sinx^2=1 Sinx^2=1/4 Sinx=±1/2 Sinx =sin30 X=30 degree (N:B: There may be another pair of answers for negative values )

@NumericNest.

21 күн бұрын

Nice

According to youtube policy hashtag should not be more than 15 🎉🎉🎉🎉🎉

@NumericNest.

Ай бұрын

👍🏻