8^(Log[2,1.25]+2)+2^(Log[2,1.25]+2)=130

*2^x[(2^x)^2+1]=130=26×5=5(5^2+1)* *2^x=5* *x=log2(5)*

Solution dans R: X=log(5)/log(2) Il y a bien d’autres solutions dans C

Analysis often eliminates paralysis!!

X is an exponent in this equation!!Much analysis can be done before trying natural numbers. The sum of the roots of this equation is zero. Since there is only one natural number root, the other two are probably irrational. Synthetic division is the way to eliminate long division.

a simple solution is x log 8 + x log 2 = log 130, x = log 130 / (log 8 + log 2)

@BigFatSandwitch

27 күн бұрын

I don't think log(a+b) = log(a) + log(b)

Nice Explanation Mam 🎉😊

@JJONLINEMATHSCLASSchannel

25 күн бұрын

Thanks a lot 😊

This is a cubic equation, 8^x=(2^x)^32, so y=2^x, and we're left with y^3+y-130=0. There is a formula for cubics, use that.

lg5/lg2.

Let's name 2^x = X We have then X^3 + X -130 = 0 F: X ---> X^3 + X -130 strictly increases on R, so if the equation f(X) = 0 has a solution then it is unique. As 5 is evident solution then it is the only one. So 2^x = 5 and x = ln(5)/ln(2) is the unique solution of the given equation.

@JJONLINEMATHSCLASSchannel

21 күн бұрын

👏👏👏

y-5 goes into y^3+y-130 y^2+5y+26 times

❤

@JJONLINEMATHSCLASSchannel

21 күн бұрын

❤️❤️

X= ln5 / ln2

x=Log[2,1.25]+2

The position of y² on top is wrong It was supposed to above the same degree (+0y²)

@JJONLINEMATHSCLASSchannel

29 күн бұрын

Thanks, I will be more careful next time

@Extratremendouszeus

29 күн бұрын

@@JJONLINEMATHSCLASSchannel thanks darling

× = 13

Good teacher👍 You need to work on your checking at the very end. Do avoid using approximations as equality.

Mam, plz Explain " Extraneous roots "

X =13

pack milk is very evpensive/ hpw a mldle class person afford. the packed milk is only for rich/ in pakistan . grib jaye bhar may.

Bullshit Use général solving or by computing