Thank you so much. It's rare when I get that, "FUCK, I GET IT NOW" feeling. The clear explanation is much appreciated.

Crisp and clear explanation of concepts, well done and thank you

this made so much more sense than my professor or textbook. thank you!!!!

you rock. thanks for the AMAZING explanation. i was clueless about the difference. now it all makes so much sense!

I just wanted to thank you for putting this together

Life makes sense again. Thank you!!!

my main man micheal evans coming to the rescue thank you!

very nice explanation.. Thanks

Thank you for simplifying it!

Great presentation. Thank you very much?

This helped a lot. Thank you so so much.

Thanks for the brief and clear explanation!

@mevansthechemist

Жыл бұрын

You’re welcome and thanks for watching!

Thanks a lot! Very helpful!

Good explanation, thanks!

how is kinetic control used to affect the outcome of a chemical reaction where several reaction paths are available

Thank you! great video.

amazing! thanks so much.

Good stuff

Great explanation. What I don't understand is how the factor reaction time works? Like why does the kinetic product eventually convert into the thermodynamic product? No new energy is added to overcome the larger activation energy barrier of the thermodynamic product. Thanks!

@mevansthechemist

4 жыл бұрын

Great question! You're absolutely right that no new energy is added, but keep in mind that the distribution of molecules in the reaction changes over time. It's all based on relative activation energies. Early in the reaction we have mostly the starting material (SM), which converts mostly into the kinetic product (KP) due to the lower activation energy leading to it. A little bit of thermodynamic product (TP) forms. Now, if we focus on the activation energies of the REVERSE reactions, we see that the KP reverts back to SM faster than TP. Thus, KP will eventually be funneled to TP due to its greater rate of reversion to the starting material.

If we change the temperature doesn't delta G of both reactions change? So how do we know that after changing the temperature p1 isn't more thermodynamicaly favorable than p2?

Grate job!!!

What organic chemistry software is that? Link please?

If you have a reaction that A+B->C, and it is only reversible then the only conclusion that you can make is that is kinetically controlled right?

@mevansthechemist

6 жыл бұрын

If the reaction as a whole is reversible, it's thermodynamically controlled, not kinetically controlled. "Reversible" in essence means that the forward and reverse reactions are proceeding at equal rates; i.e., that the reaction system is in equilibrium (caveat: this is the organic chemist's "back of the envelope" definition. The definition in physical chemistry is more rigorous.)

Thank you.

Is your activation energy correct? (0:20 - 0:25) I think activation energy is the whole value from the energy level of the starting material, all the way up to the peak of the transition state. Your second (right hand side) activation energy seems correct proceeding from left to right.

@mevansthechemist

6 жыл бұрын

Good question-for anyone still confused by this, note that the graph is showing two different reactions proceeding outward from the center. Thus, two separate activation energies are shown.

Great,,,

thank you

Thanks bro 😉

Thanks Bro !

Finally i understood.

thanks, helped

I still can't get it.. 😢

CN2116

whose here from AAMC C/P SB #20