The easy integration technique teachers DON'T want you to know about.
Good luck on your exams. Chapters: 0:00 1st problem 1:24 2nd problem
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Пікірлер: 9
@awildscrub2 ай бұрын
I mean this is just IBP arranged in a neatly order, bc you always have to choose the same u's and dv's, otherwise you'll end up right where you started.
@TheUnqualifiedTutor
Ай бұрын
Yeah, I appreciate you said that. Should've made it clearer in the video, it is essentially the same. I just like to use little shortcuts. Thanks!
@h3llh4x2 ай бұрын
The 1st problem is just extended by parts and second problem uses normal by parts, the DI technique does help the newcomers because it is easier to remember than the by parts formula. With all that said, you gave a great explanation on the technique and hope you keep it up.
@TheUnqualifiedTutor
Ай бұрын
Yeah, pick whichever suits you best! Much love bro.
@charlesokuom8747Ай бұрын
Well explained
@Hacker097Ай бұрын
Can you give an example for an exponential function? Say sinx e^x
@Hacker097
Ай бұрын
nvm I got it. Just have to do it twice.
@carultch
Ай бұрын
This one is an example of a looper, where you end up spotting the original integral across a row. In these examples with a simple exponential and either sine or cosine, it is arbitrary which function gets which treatment. Another method is to rewrite sin(x)*e^x, as e raised to a complex exponent, and avoid IBP entirely. Let e^x be integrated, and sin(x) be differentiated. S _ _ _ D _ _ _ _ I + _ _ sin(x) _ _ e^x - _ _ cos(x) _ _ e^x + _ _ -sin(x) _ _ e^x Spot the original integral across bottom row, call it I. Construct result: I = sin(x)*e^x - cos(x)*e^x - I Solve for I algebraically: I = 1/2*e^x * (sin(x) - cos(x)) Add +C, and we're done: 1/2*e^x * (sin(x) - cos(x)) + C
@The_Green_Man_OAP19 күн бұрын
Integrate this wrt r from r=a to r=a/10: 1/√(2μ/r -2μ/a), a is constant>x, μ is constant. Also, 6/10⁷
Пікірлер: 9
I mean this is just IBP arranged in a neatly order, bc you always have to choose the same u's and dv's, otherwise you'll end up right where you started.
@TheUnqualifiedTutor
Ай бұрын
Yeah, I appreciate you said that. Should've made it clearer in the video, it is essentially the same. I just like to use little shortcuts. Thanks!
The 1st problem is just extended by parts and second problem uses normal by parts, the DI technique does help the newcomers because it is easier to remember than the by parts formula. With all that said, you gave a great explanation on the technique and hope you keep it up.
@TheUnqualifiedTutor
Ай бұрын
Yeah, pick whichever suits you best! Much love bro.
Well explained
Can you give an example for an exponential function? Say sinx e^x
@Hacker097
Ай бұрын
nvm I got it. Just have to do it twice.
@carultch
Ай бұрын
This one is an example of a looper, where you end up spotting the original integral across a row. In these examples with a simple exponential and either sine or cosine, it is arbitrary which function gets which treatment. Another method is to rewrite sin(x)*e^x, as e raised to a complex exponent, and avoid IBP entirely. Let e^x be integrated, and sin(x) be differentiated. S _ _ _ D _ _ _ _ I + _ _ sin(x) _ _ e^x - _ _ cos(x) _ _ e^x + _ _ -sin(x) _ _ e^x Spot the original integral across bottom row, call it I. Construct result: I = sin(x)*e^x - cos(x)*e^x - I Solve for I algebraically: I = 1/2*e^x * (sin(x) - cos(x)) Add +C, and we're done: 1/2*e^x * (sin(x) - cos(x)) + C
Integrate this wrt r from r=a to r=a/10: 1/√(2μ/r -2μ/a), a is constant>x, μ is constant. Also, 6/10⁷