Speed of a Satellite in Circular Orbit, Orbital Velocity, Period, Centripetal Force, Physics Problem
This physics video tutorial explains how to calculate the speed of a satellite in circular orbit and how to calculate its period around the earth as well. It uses the formula for centripetal force and gravitation to derive the equation for the orbital velocity of a satellite.
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2 жыл бұрын
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2 жыл бұрын
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Жыл бұрын
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Жыл бұрын
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5 ай бұрын
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@joshuaprier2670
Жыл бұрын
Lol same I have my ap test this week and we took 1 semester to do kinematics and dynamics
@mensurmehmedagic24
8 ай бұрын
@@joshuaprier2670yo I’m in AP physics 1 rn we are doing this stuff right like centripetal acceleration and universal law of gravitation. What was the hardest unit in physics just curious?
@joshuaprier2670
8 ай бұрын
@mensurmehmedagic8751 Well, my physics 1 teacher kind of sucked (no one in my class got above a 2 on the test). I think the hardest thing for me was contact forces, torque, and gravitation. Right now, I'm in physics C and it's not as bad with a better teacher.
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@wojciechkaczorowsski
3 ай бұрын
meanwhile me in poland in 9th grade having these in physics
@feofino1
2 ай бұрын
@@wojciechkaczorowsskimost kids In America we take physics in 9th grade as well. This person is probably from the UK because they say grade 12.
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Ай бұрын
In NY the trend is 9 bio 10 chem 11 phys Or the easier track 9 bio 10 earth sci 11 chem And if your middle school had the option to take bio in 8 grade then you take those classes 1 year earlier
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8 ай бұрын
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8 ай бұрын
Bro I’m a sophomore and it still is the biggest mistake
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8 ай бұрын
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8 ай бұрын
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6 ай бұрын
As a senior taking physics, it's a mistake
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3 жыл бұрын
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8 ай бұрын
s its true
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The first part of this video helped me understand an extra credit question in my Geog605 class, remote sensing of the environment. We were asked how many times a certain satellite would orbit the earth in a day and we were only give the satellite altitude, earth's mass and radius, and the gravitational constant. The essential piece of missing info was the equation for the distance of a circular path. One question though, how did you translate your velocity value into m/s?
Extremely helpful 👍🏻
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is this related in calculating quantities related to planetary or satellite motion?
so helpful, thanks!!!
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Wow that's a really fast satellite.
@hannalot_
5 жыл бұрын
This is about the speed of an actual satellite
@studentvet3163
4 жыл бұрын
@Jebediah Jr,how?l mean what is the importance of calculating the speed of a satellite if it isn't real?
@studentvet3163
4 жыл бұрын
@@hannalot_ how?
@dominobuilder100
4 жыл бұрын
Sarah Abderrahman ISS moves in almost 8km/s, so that’s even faster. And what do you mean with not real? Being able to calculate these simple things are essential to understand the fundamentals of how an object would act when put into orbit. It’s important as hell
@studentvet3163
4 жыл бұрын
@@dominobuilder100 oh I just thought that a satellite with that high speed hasn't been made yet I mean it is still on paper
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Sir, how you can cancel both R, In centripetal Force R is the radius of circle(i think it should be the distance between Surface of Earth and Satellite) and in Gravitational Force R is the separation between two masses (from center of Earth to the Satellite). Could you Please Explain
Thankkks
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@MJFinn
2 жыл бұрын
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thanks bro
when do we use m/s and km/s when solving for velocity?
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while on a circular orbit if the velocity of the object is increased then it will go further away but a new balance can be achieved only if distance decrease. (Higher velocity means higher centrifugal force and it can be balanced only by a higher gravitational force which will happen only if distance decrease) in reality an elliptical orbit is created. how do you explain this by the above simple physics?
Isn't v the tangential velocity? So shouldn't T = 2pir/v/r since v/r = w which is the rotational velocity?
can u plz explain the variation of centripetal accl. and velocity of planets at different distances from sun?
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What will happen if new mass added to the satellite while moving? affect of the linear momentum? and how it maintain the speed constant?
@jo-oy4vj
3 жыл бұрын
if you add new mass the same way rockets dock to ISS, then it won't affect anything because the new mass already achieve equal speed to the satellite
@thidaswinathsara6164
3 жыл бұрын
@@jo-oy4vj ok, thanks
5:07 is the speed of the satellite angular velocity?
Where did you get the 6254.3 m/s from. What did you do to get it.
@TheJoey3590
5 жыл бұрын
He used the equation: v=square root (GM/r). This will give you the speed of the satellite which is in circular orbit. If it was in an elliptical orbit, you'd have to use a different equation.
@cristhianv.5649
3 жыл бұрын
It is probably too late now, but what he did was double parenthesis like this: ((6.67 X 10 ^ -11)(5.97 X 10^24) divided by 1.018 X 10^7))
To me nice lesson sir
could you maybe explain what the variables mean
@heavennoes
3 жыл бұрын
he did.
I'm not getting the calculation for r even though I put in all the values u have in for the cube root thingy
@nsifrahman9031
4 жыл бұрын
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@ianfjay6883
4 жыл бұрын
@@nsifrahman9031 lol how is thingy girly?
@homeofsports3295
3 жыл бұрын
I think he made a mistake in the calculations, I wasn't able to find the same answer as him for the radius between the center of the earth to the satellite.
so satelies move at 11059.2km/h? constantly around earth?
Isn't it v=√(2GM/R) ? First example speed of satellite
@DeletionRoad
4 жыл бұрын
pretty sure thats the escape velocity my guy
42,200,000 x 2pi / 86,400 = 3068 Seems a good deal easier for the last answer and we'll within reason given rounding. If we had more sigfigs for R it would be just as accurate.
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3 жыл бұрын
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3 жыл бұрын
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please clarify me it's angular speed is equal to that of earth about its own axis
@redbean9410
4 жыл бұрын
you have been clarified
could any one tells me what is the different between the velocity in circular orbit an in elliptical orbit? رد
@notjazzberry
5 жыл бұрын
I know I'm really late but in a circular orbit, the object is moving at a constant velocity. in elliptical orbits, the speed varies according to Kepler's second: faster when it is closer to the object the satellite is orbiting and slower when it is further away
@omardiab2887
4 жыл бұрын
rood 3alya rood
Can you do ESCAPE VELOCITY OF A SATELLITE
How was F =mv^2 ÷ r formed? Physics is hard for me.
but isn't this not going to work because orbits are elliptical and the distance with radius isn't 2pi*r (I'm just nitpicking)
Believe it or not, I'm having to perform many calculations for a singular mission that I'm planning in Kerbal Space Program
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Is the 6.38x10^6 constant?
@homeofsports3295
3 жыл бұрын
As far as I'm aware the radius of the earth doesn't change, so 6.38x10^6 meters or 6371 kilometers should be a constant. edit : "The scientists estimated the average change in Earth's radius to be 0.004 inches (0.1 millimeters) per year, or about the thickness of a human hair, a rate considered statistically insignificant." *Source : NASA* (www.nasa.gov/topics/earth/features/earth20110816.html#:~:text=The%20scientists%20estimated%20the%20average,a%20rate%20considered%20statistically%20insignificant.) edit 2 : at this rate of 0.1 milimeters per year, it would take 10 milions year just for the radius to go up by 1 kilometer, so I would say 6.38x10^6 meters or 6371 kilometers is good enough
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@toxiclock1905
8 ай бұрын
You are?
Im an average student and nim thankful for this but kinda lost in number 2(b) 😭
What is the work of the Earth on the satellite and why is it equal to zero?
@potatoeater2629
5 жыл бұрын
XxPlayMakerxX131 i dont fucking know but these are so fucking hard fr
@Fleischgewehr
5 жыл бұрын
Forces only do work if they have some vector component along the path of motion. This path of motion is the circular orbit, the force is the centripetal force directed towards the center of the Earth. These are perpendicular, so gravity does no work. It's a similar story for charged particles moving in a mass spectrometer, if you've seen that.
@rye-bread5236
5 жыл бұрын
if the earth is inside the system it cannot do work. hence 0. If it is outside the system like external forces. it does work. my prof has us set it up like so work= change in energy work= PE + KE ... on the left is external forces that create work (b0th pos. and neg. work has to be parallel though. Work that is perpendicular is 0. Torque is when there are perpendicular force and distance ) on the right is internal energies, Gravitational potential and kinetic. If 0 work that means the internal forces are equal and opposite (for this scenario) Hope this helps.
I keep getting 6.2543E10 for the speed on my calculator. I was wondering what am I doing wrong? I did convert the km into m by multiply it by 1000 and got the same radius in the video. I plugged the exact number in also.
@plenitudee8320
7 ай бұрын
i got the same problem
Gold