My strategery is: x^4 - 16 = 0; factor it and you are assured of all four roots.
@skill_issuesmo7367
4 ай бұрын
(x-2)(x+2)(x^2+4)
@kaique2716
3 ай бұрын
Ayoo same pfp
@tileguy918
Ай бұрын
@skill_issuesmo7367 x²+4 is just difference of squares in disguise! x²-4i² = x²+4
@f.r.y58574 ай бұрын
Factor it (x²-4)(x²+4) = 0 x² = 4 or x² = -4 x = ±√4 or x = ±√-4 x = ±2 or x = ±2i
@mohankayastha4 ай бұрын
Sir please solve: X³ - 4x=64
@yeet6356
3 ай бұрын
Let the coefficient of x (-4) be 3st Let the constant (64) be s^3 - t^3 Let x^3 be (s-t)^3 Solve s-t for x Visual proof: m.kzread.info/dash/bejne/ZIyWqLZqmLq6j84.html&pp=ygUcRGVwcmVzc2VkIGN1YmljIHZpc3VhbCBwcm9vZg%3D%3D
@atzuras4 ай бұрын
Yes take the 4th root. 2×e^i(0+2k•pi/4) for k in 0...3
@daddymuggle
4 ай бұрын
The simplest approach.
@bacchadumII
3 ай бұрын
Idk why ppl do such complex methods when we have THIS
@aradyashetty114 ай бұрын
Nice
@user_084104 ай бұрын
is that all the 4th root of number are all have 4 answer? 😮
@atzuras
4 ай бұрын
yes. it is called the Fundamental Algebraic Theorem ( in Complex Numbers).
@Ninja20704
4 ай бұрын
Yes, but with the exception of 0.
@user_08410
4 ай бұрын
@@atzuras thx
@syndrac62544 ай бұрын
Why find the square root of -4 though.?
@drobotk
4 ай бұрын
Sometimes science is about "Why not?"
@daddymuggle
4 ай бұрын
Because all complex numbers (other than 0) have precisely 4 4th roots. Gotta catch 'em all.
@Teltelteltelaja3 ай бұрын
Super easy and faster X⁴ = 16 X⁴ = 2⁴ X = 4√2⁴ (cancel the root and power) X=(+-2)
@the6278
2 ай бұрын
cheating
@znk753
Ай бұрын
you only found one root
@cyrusyeung80964 ай бұрын
Why are you redoing the same question? Bprp math basics has just solve the SAME question 6 days ago.
Пікірлер: 29
My strategery is: x^4 - 16 = 0; factor it and you are assured of all four roots.
@skill_issuesmo7367
4 ай бұрын
(x-2)(x+2)(x^2+4)
@kaique2716
3 ай бұрын
Ayoo same pfp
@tileguy918
Ай бұрын
@skill_issuesmo7367 x²+4 is just difference of squares in disguise! x²-4i² = x²+4
Factor it (x²-4)(x²+4) = 0 x² = 4 or x² = -4 x = ±√4 or x = ±√-4 x = ±2 or x = ±2i
Sir please solve: X³ - 4x=64
@yeet6356
3 ай бұрын
Let the coefficient of x (-4) be 3st Let the constant (64) be s^3 - t^3 Let x^3 be (s-t)^3 Solve s-t for x Visual proof: m.kzread.info/dash/bejne/ZIyWqLZqmLq6j84.html&pp=ygUcRGVwcmVzc2VkIGN1YmljIHZpc3VhbCBwcm9vZg%3D%3D
Yes take the 4th root. 2×e^i(0+2k•pi/4) for k in 0...3
@daddymuggle
4 ай бұрын
The simplest approach.
@bacchadumII
3 ай бұрын
Idk why ppl do such complex methods when we have THIS
Nice
is that all the 4th root of number are all have 4 answer? 😮
@atzuras
4 ай бұрын
yes. it is called the Fundamental Algebraic Theorem ( in Complex Numbers).
@Ninja20704
4 ай бұрын
Yes, but with the exception of 0.
@user_08410
4 ай бұрын
@@atzuras thx
Why find the square root of -4 though.?
@drobotk
4 ай бұрын
Sometimes science is about "Why not?"
@daddymuggle
4 ай бұрын
Because all complex numbers (other than 0) have precisely 4 4th roots. Gotta catch 'em all.
Super easy and faster X⁴ = 16 X⁴ = 2⁴ X = 4√2⁴ (cancel the root and power) X=(+-2)
@the6278
2 ай бұрын
cheating
@znk753
Ай бұрын
you only found one root
Why are you redoing the same question? Bprp math basics has just solve the SAME question 6 days ago.
@daddymuggle
4 ай бұрын
Probably because some people like this format.
Why not x= 16^(1/4)?
@SamLeroSberg
2 ай бұрын
Aint that just rooting it?
I hate that this worked out.
speed running meth