Solving Exponential Equation With Radicals | Japanese Olympiad Math Question | Mathematics.

In solving this Olympiad Math Exponential Equation with radicals, I will guide you on how to solve for the roots using a different approach different from the normal one you know.
In this Japanese Olympiad question, you will also learn how to handle the radicals with easy, formulate quadratic equation from the radical equation, substitute and factorize quadratic equation with easy.
I will lead you on how to use the natural logarithm to solve exponential equations.
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#matholympiad #exponential #radical #maths #mathchallenge #mathematics #math #mathtricks #olympiadpreparation #olympiads #solutions #mathskills #learningmaths #learningmathematics #simplification_with_tricks #simplification_tricks

Пікірлер: 88

  • @teacherheng1688
    @teacherheng16888 ай бұрын

  • @user-ly5bc4xd2s
    @user-ly5bc4xd2s Жыл бұрын

    تمرين جميل جيد . شرح واضح مرتب . شكرا جزيلا لكم والله يحفظكم ويرعاكم ويحميكم جميعا . تحياتنا لكم من غزة فلسطين

  • @onlineMathsTV

    @onlineMathsTV

    Жыл бұрын

    Many thanks to you for finding our videos very fascinating and thank you for your wonderful words of encouragement all the time to us on this channel sir. All of us @Onlinemathstv love you sir. Much love from everyone of us @onlinemathstv to you, your family and all the people of Gaza, Palestine ...💕💕💕❤️❤️💖💖

  • @user-wv3hl5yn8d
    @user-wv3hl5yn8d Жыл бұрын

    I firmly believe that either we should have restrictions for the solutions of the equation or, at least, if we ommit the restrictions we should check the solutions before we accept them.

  • @onlineMathsTV

    @onlineMathsTV

    Жыл бұрын

    Thanks for this wonderful comment sir. I have checked the two solutions and they are correct.

  • @venky3867
    @venky386710 ай бұрын

    I'm proud that I could do this in my mind

  • @HelenBlackG-xn9hf
    @HelenBlackG-xn9hf2 ай бұрын

    🎉🎉❤❤❤

  • @user-di1vf3fv7p
    @user-di1vf3fv7p8 ай бұрын

    hope see you again My teacher thanks for everthing

  • @moulikraina2186
    @moulikraina2186 Жыл бұрын

    Can u give more questions like this?As the question was amazing and also the way to explain .i enjoyed ur explanation

  • @onlineMathsTV

    @onlineMathsTV

    Жыл бұрын

    We are glad you enjoyed and gained something valuable from this video. Sure, we can make more of this sir. Thanks for the request. Much love 💖💖💖

  • @charlesmitchell5841
    @charlesmitchell5841 Жыл бұрын

    Good problem. Good explanation. Thanks for the video lesson!

  • @onlineMathsTV

    @onlineMathsTV

    Жыл бұрын

    Thanks for the encouragement sir. And thanks for watching our contents sir. Much love❤️❤️💕💕💕

  • @F.S.L.C.
    @F.S.L.C. Жыл бұрын

    WOW - THANK YOU.

  • @onlineMathsTV

    @onlineMathsTV

    Жыл бұрын

    You're very welcome sir. We are glad you gained some values from this tutorial sir.

  • @albinonhabanga8066
    @albinonhabanga806611 ай бұрын

    I think it's very important to check first the existence conditions of some functions, as this square root, to detect non valid solutions or include in your solving Anyhow you are a beast 😎

  • @hogec_enlightenmentarena6975
    @hogec_enlightenmentarena6975 Жыл бұрын

    Nice 👍

  • @onlineMathsTV

    @onlineMathsTV

    Жыл бұрын

    Thanks sir.

  • @sepehrarkani6689
    @sepehrarkani6689 Жыл бұрын

    Excellent videos. Greatly appreciated!

  • @onlineMathsTV

    @onlineMathsTV

    Жыл бұрын

    Glad it was helpful and thank you for appreciating our little effort sir. This is encouraging. Much love💕💕💕

  • @sepehrarkani6689

    @sepehrarkani6689

    Жыл бұрын

    @@onlineMathsTV you're very welcome 👍

  • @StephieJoseph-io3wt
    @StephieJoseph-io3wt Жыл бұрын

    Thanks for making this video sir.

  • @onlineMathsTV

    @onlineMathsTV

    Жыл бұрын

    You are welcome always ma. Love you...❤️❤️💕💕

  • @danielfranca1939
    @danielfranca1939 Жыл бұрын

    Great explanation. This is lovely sir.

  • @onlineMathsTV

    @onlineMathsTV

    Жыл бұрын

    Thanks @Daniel Franca Love you...💖💖💕💕

  • @youncheolshin6304
    @youncheolshin6304 Жыл бұрын

    if you put 3^x =a, 4^x=b you can rewrite the question as this : a-b= root( ab-b^2) and square each side that can be (a-b)^2 = ab-b^2 ; a^2 - 2ab + b^2 = ab-b^2 ; a^2 - 3ab + b^2 = 0 ; (a-b) (a-2b) =0 ; a-b=0 or a-2b=0 ; a=b or a=2b ; 3^x= 4^x or 3^x = 2* 4^x ; its more simple what do you think?

  • @onlineMathsTV

    @onlineMathsTV

    Жыл бұрын

    Very concise sir. It is a welcome approach too. Nice work and we have learnt something new from your comment. Thanks for watching and dropping this comment too. Much respect and love to you sir...🙏🙏💕💕💕

  • @douglasjunior5062
    @douglasjunior5062 Жыл бұрын

    Eu não fazia ideia de pra onde ir 😅😅 vídeo muito bom

  • @onlineMathsTV

    @onlineMathsTV

    Жыл бұрын

    😍😍😍 funny you sir. Coming here means you will definitely know where to go next time you come across any mathematical challenge/problem as u consistently visit OnlinemathsTV channel. Much love....💖💖💖

  • @honey-qqq
    @honey-qqq Жыл бұрын

    🙏

  • @onlineMathsTV

    @onlineMathsTV

    Жыл бұрын

    Thanks sir for you comment. It is a symbol but a big symbol of encouragement to us sir. We are glad that you gained some values from our little effort and we promise to do more effective work here in order not to disappoint you and others who believe even in our little beginning. We love you sir.❤️❤️💖💖💕💕💕

  • @abhijitgangopadhyay8962
    @abhijitgangopadhyay8962 Жыл бұрын

    Thank you Sir

  • @onlineMathsTV

    @onlineMathsTV

    Жыл бұрын

    You are most welcome sir, and thanks for watching our content sir. Much love 💖💖💕💕

  • @desirekouame3946
    @desirekouame3946 Жыл бұрын

    Congrats,bro !

  • @onlineMathsTV

    @onlineMathsTV

    Жыл бұрын

    Many thanks to you for encouraging us on what we are doing sir. Respect...👍👍

  • @M.Davit613
    @M.Davit613 Жыл бұрын

    I solved the exercise in 2 minutes․ x

  • @onlineMathsTV

    @onlineMathsTV

    Жыл бұрын

    Bravo👍👍👍 You the master👌👌👌

  • @M.Davit613

    @M.Davit613

    Жыл бұрын

    @@onlineMathsTV Thank U

  • @BN-hy1nd
    @BN-hy1nd8 ай бұрын

    Hmm, I should try a graphical solution method without drawing a proper graph Sketch a graph of graph of y = 3^x -4^x . y = (12^x -16^x)^0.5 when x = 0, y=0, certainly. y will always be +ve when x is -ve. When x is positive will generate complex numbers so, by inspection, both graphs meet at x=0 and y=0 Then try x = -1, -2 and -3 ; gradually the difference in y values get smaller and smaller In an exam, this sort of question requires an approximate answer for the second value

  • @marjaentrich7121
    @marjaentrich7121 Жыл бұрын

    Выражение под корнем должно быть не меньше нуля. Те, когда возаодили корень в квадрат, должны были получить модуль и нужно рассмотреть 2 случая

  • @sudhakaranpillai9623
    @sudhakaranpillai9623 Жыл бұрын

    In case 1,there is no need to go for' ln' because raised to the power 0 only gives 1

  • @onlineMathsTV

    @onlineMathsTV

    Жыл бұрын

    Noted sir.

  • @sans1331
    @sans1331 Жыл бұрын

    3^x-4^x=sqrt(12^x-16^x) y=3^x-4^x y=sqrty*(sqrt4^x) =sqrty*2^x divide both sides by 2^x 1.5^x-2^x=sqrty=y/2^x sqrty=y/2^x 2^x=y/sqrty=sqrty square both sides y=4^x=3^x-4^x +4^x both sides 2(4^x)=4^(x+0.5)=3^x z=ln4/ln3 [3^z=4] (3^z)^(x+.5)=3^x x=zx+0.5z *x both sides x^2=zx^2+.5zx -x^2 both sides (z-1)x^2+0.5zx=0 [1 rough quadratic formula later] x=(-0.5(ln4/ln3))/((ln4/ln3)-1) =-ln4/((2ln3)((ln4/ln3)-1) (2ln3)((ln4/ln3)-1)=((2ln3*ln4)/ln3)-2ln3 =2ln4-2ln3 =>x=-ln4/(2(ln4-ln3)) …and also x=0. edit: oh wow, different fractions yet the same constant

  • @onlineMathsTV

    @onlineMathsTV

    Жыл бұрын

    Wonderful and unique move. You are good at it sir, you the master here. Respect👌👌👌

  • @youncheolshin6304
    @youncheolshin6304 Жыл бұрын

    how about 0 or 1/{ log2 (3) - 2}

  • @onlineMathsTV

    @onlineMathsTV

    Жыл бұрын

    Thanks for the encouragement sir. We love you for watching and commenting sir. Much love 💕💕💖💖

  • @tunneloflight

    @tunneloflight

    6 ай бұрын

    This also has the advantage that many calculators natively perform lg2, so x = 1 / (lg2(3) -2) is trivial to calculate. In RPN: 3 ; lg2 ; 2 ; - ; 1/x. {five keystrokes}

  • @s.h.munasingha2590
    @s.h.munasingha2590 Жыл бұрын

    ,X= log( 3/4 ) 2

  • @ChristelleHilaire-lb6pu
    @ChristelleHilaire-lb6pu9 ай бұрын

    ×=-3

  • @petermak3980
    @petermak3980 Жыл бұрын

    You must set 3^x--4^x>=0 ...... x

  • @onlineMathsTV

    @onlineMathsTV

    Жыл бұрын

    noted sir. Thanks master.🙏🙏🙏

  • @loveharshvardhan4259

    @loveharshvardhan4259

    9 ай бұрын

    Only one to notice. Hats off

  • @user-vd3ky9cr1s
    @user-vd3ky9cr1s11 ай бұрын

    thank you very much, i suggest that the value of zero for u should be rejected, for otherwise the division by ( 3 px - 4 px) being equal to zero would not work

  • @onlineMathsTV

    @onlineMathsTV

    11 ай бұрын

    But 3 px - 4 px (i.e 1-1) will give us zero, which implies LHS = RHS. What do you think sir?

  • @SASS-yp8gu
    @SASS-yp8gu9 ай бұрын

    X не может быть равен "0", так как -1 не равно sqrt(-1)

  • @mahinofficial4671
    @mahinofficial4671 Жыл бұрын

    If we use log instead of using ln ,then what will happen

  • @onlineMathsTV

    @onlineMathsTV

    Жыл бұрын

    same result sir.

  • @faithlesshound5621

    @faithlesshound5621

    9 ай бұрын

    Using logs to the base of 10, we can fill in the numbers (the logarithms of 2, 3 and 4, which are 0.3010, 0.4771 and 0.6020) from memory and then calculate the quotient by hand. I don't have natural logs in memory.

  • @vansf3433
    @vansf34336 ай бұрын

    It seems that you like solving children' s math-probs 3^x - 4^x = sqrt(14^x -16^x). Notice that the expression inside the radical can not be negative, but 14^x 14^x - 16^x will always be negative. There is only 1 way to neutralise the negative result is to make the expression= O. since any value taken to pwer of 0 will become 1. If x = 0, 24^0 -16^0 = 1 - 1 = 0 Checking whether x = 0 the solution: 3^0 - 4^0 = sqrt(14^0 - 16^ 0) 1 -1 = sqrt(1 - 1) 0 = 0. Hence, x = 0 is the solution We're done

  • @onlineMathsTV

    @onlineMathsTV

    6 ай бұрын

    Ok sir, thanks for dropping this sir. We learn everyday from the best brains all around the globe and we sincerely believe you are one of these rare genius in mathematics. Nice to have you here sir, You are most welcome master.

  • @DilaverHamzayeva-fs6fg
    @DilaverHamzayeva-fs6fg3 ай бұрын

    🤎

  • @syedmdabid7191
    @syedmdabid719111 ай бұрын

    What's is the meaning of Wn( 2) ?????

  • @brightjovanny

    @brightjovanny

    9 ай бұрын

    Wn(z) is generally called the Lambert W function (or omega function or productlog) where the subscript n (an integer) represents the principal, positive or negative branch of the function with n = 0 being the principal branch. The Lambert W function is the inverse of the function: f(w) = we^w where w is any complex number and e^w is the exponential function. The function can also be written as: LambertW(n,z) ProductLog(n,z)

  • @MathsTuitionBangla
    @MathsTuitionBangla Жыл бұрын

    Hello students

  • @onlineMathsTV

    @onlineMathsTV

    Жыл бұрын

    Hi master!!! Anything for the student/s? We are at your service as your wish is our command sir.

  • @AloneStroller
    @AloneStroller Жыл бұрын

    I disagree with x2 solition - it is superfluous as we should use straight definition of logarithm: X2=log(3/4)2. log(a)b.

  • @onlineMathsTV

    @onlineMathsTV

    Жыл бұрын

    not too clear with your point here sir.

  • @FractAlkemist
    @FractAlkemist Жыл бұрын

    I tried my Genetic Algorithm with this; 'x' must be a negative number, and it needn't be an integer. There seems to be no real solution, the greater the (negative) number, the closer it gets. I scanned from 0-> -500 and the best I got was: X = -481.58408788993336 Left side evaluates to: 1.6826575283911937e-230 Right side evaluates to: zero (probably not real zero, the computer just doesn't display such a small number) Difference = 1.6826575283911937e-230 , effectively solving the equation (for engineers, not theoreticians!) (plus overflow errors and other Python squawking) Maybe I should watch the video ...... .

  • @onlineMathsTV

    @onlineMathsTV

    Жыл бұрын

    Smiles....nice work from you boss. But most times AI fails to give the actual result to a mathematical challenge. I believe you have watched the video sir. Did you agree with the approach I applied here? I made a video on a similar challenge with a different approach. Below is the link to that video, you can as well flip through it to check it out if you don't mind sir. kzread.info/dash/bejne/YpeLzM5uZpScoLQ.html And do not hesitate to make corrections where necessary because we are here to also learn from the best brains like you all around the world. Thanking in advance boss!!! Respect!!! 👍👍👍 Much love....❤️❤️

  • @vicferrmat4492

    @vicferrmat4492

    10 ай бұрын

    Do you mean "generic" algorithm?

  • @johnwren6138
    @johnwren6138 Жыл бұрын

    Easier to go m log7=log70

  • @onlineMathsTV

    @onlineMathsTV

    Жыл бұрын

    Bravo 👍👍👍 You the best sir.

  • @shoshosalah3447
    @shoshosalah3447 Жыл бұрын

    X1=0 X2~ -2.41

  • @onlineMathsTV

    @onlineMathsTV

    Жыл бұрын

    Bravo 👍👍👍 You the best sir.

  • @ilyashick3178
    @ilyashick3178 Жыл бұрын

    ln 1 is equal 0 so x1=0

  • @onlineMathsTV

    @onlineMathsTV

    Жыл бұрын

    Yap

  • @user-nd7th3hy4l
    @user-nd7th3hy4l6 ай бұрын

    X=0

  • @onlineMathsTV

    @onlineMathsTV

    6 ай бұрын

    Correct boss, but that is just one of the solutions. Thanks for stopping by sir. Much love.

  • @user-rf9mv7du5s
    @user-rf9mv7du5s9 ай бұрын

    빙빙 돌아가며 풀이해 지친다.. 무조건 자연로그로만 푸니 듣기가 힘듬

  • @loveharshvardhan4259
    @loveharshvardhan42599 ай бұрын

    In this video, the respected teacher is attempting to divide by zero, the value for which remains undefined and unknown. Thereby, his method is wrong.

  • @onlineMathsTV

    @onlineMathsTV

    9 ай бұрын

    Sir, are you of the opinion that zero as a root to this math challenge is wrong? Kindly do the simple substitution and check if an undefined expression will emerge in this math challenge sir. Thanking you for a positive response in advance.

  • @nasrullahhusnan2289

    @nasrullahhusnan2289

    9 ай бұрын

    I think there is no division by zero. In [(3^x)-(4^x)]²=(4^x)[(3^x)-(4^x)] the teacher didn't divide the equation by (3^x)-(4^x), rather he let (3^x)-(4^x)=u and then move all terms to one side. Directly moving all terms to one side follow by factorizing we get [(3^x)-(4^x)][{(3^x)-(4^x)}-(4^x)]=0 [(3^x)-(4^x)][(3^x)-2(4^x)]=0 Hence: • (3^x)-(4^x)=0 --> x=0 • (3^x)-2(4^x)=0 --> (¾)^x=2 NO DIVISION BY ZERO

  • @user-rq4ez5cb4q
    @user-rq4ez5cb4q9 ай бұрын

    I already see 0 as solution 😅

  • @himnishdhiman1370

    @himnishdhiman1370

    4 ай бұрын

    Yeah but thats only one solution!!

  • @vansf3433
    @vansf34336 ай бұрын

    You don't have to copy all such lengthy steps of human -invented motions of algebra to arrive at the correct answer Again, logical reasoning can help you solve all sorts of problems, but not copying such lengthy formulas and steps, like a photocopying machine

  • @onlineMathsTV

    @onlineMathsTV

    6 ай бұрын

    Noted and thanks sir.

  • @sobolzeev
    @sobolzeev10 ай бұрын

    I wonder who is meant as the audience of this piece. A general mediocre pupil will not get even this long and overworded explanation. A bit developed one (1) does not need 2/3 of this wording, (2) guesses x=0 is a solution in the first 30 seconds, by substitution, (3) since a square root from a negative number is not real, gets any other root is negative. Finaly, 3^x = 4^(x+1/2) can be trivially solved with much less wording.

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