Solving Exponential Equation With Radicals | Japanese Olympiad Math Question | Mathematics.
In solving this Olympiad Math Exponential Equation with radicals, I will guide you on how to solve for the roots using a different approach different from the normal one you know.
In this Japanese Olympiad question, you will also learn how to handle the radicals with easy, formulate quadratic equation from the radical equation, substitute and factorize quadratic equation with easy.
I will lead you on how to use the natural logarithm to solve exponential equations.
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#matholympiad #exponential #radical #maths #mathchallenge #mathematics #math #mathtricks #olympiadpreparation #olympiads #solutions #mathskills #learningmaths #learningmathematics #simplification_with_tricks #simplification_tricks
Пікірлер: 88
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تمرين جميل جيد . شرح واضح مرتب . شكرا جزيلا لكم والله يحفظكم ويرعاكم ويحميكم جميعا . تحياتنا لكم من غزة فلسطين
@onlineMathsTV
Жыл бұрын
Many thanks to you for finding our videos very fascinating and thank you for your wonderful words of encouragement all the time to us on this channel sir. All of us @Onlinemathstv love you sir. Much love from everyone of us @onlinemathstv to you, your family and all the people of Gaza, Palestine ...💕💕💕❤️❤️💖💖
I firmly believe that either we should have restrictions for the solutions of the equation or, at least, if we ommit the restrictions we should check the solutions before we accept them.
@onlineMathsTV
Жыл бұрын
Thanks for this wonderful comment sir. I have checked the two solutions and they are correct.
I'm proud that I could do this in my mind
🎉🎉❤❤❤
hope see you again My teacher thanks for everthing
Can u give more questions like this?As the question was amazing and also the way to explain .i enjoyed ur explanation
@onlineMathsTV
Жыл бұрын
We are glad you enjoyed and gained something valuable from this video. Sure, we can make more of this sir. Thanks for the request. Much love 💖💖💖
Good problem. Good explanation. Thanks for the video lesson!
@onlineMathsTV
Жыл бұрын
Thanks for the encouragement sir. And thanks for watching our contents sir. Much love❤️❤️💕💕💕
WOW - THANK YOU.
@onlineMathsTV
Жыл бұрын
You're very welcome sir. We are glad you gained some values from this tutorial sir.
I think it's very important to check first the existence conditions of some functions, as this square root, to detect non valid solutions or include in your solving Anyhow you are a beast 😎
Nice 👍
@onlineMathsTV
Жыл бұрын
Thanks sir.
Excellent videos. Greatly appreciated!
@onlineMathsTV
Жыл бұрын
Glad it was helpful and thank you for appreciating our little effort sir. This is encouraging. Much love💕💕💕
@sepehrarkani6689
Жыл бұрын
@@onlineMathsTV you're very welcome 👍
Thanks for making this video sir.
@onlineMathsTV
Жыл бұрын
You are welcome always ma. Love you...❤️❤️💕💕
Great explanation. This is lovely sir.
@onlineMathsTV
Жыл бұрын
Thanks @Daniel Franca Love you...💖💖💕💕
if you put 3^x =a, 4^x=b you can rewrite the question as this : a-b= root( ab-b^2) and square each side that can be (a-b)^2 = ab-b^2 ; a^2 - 2ab + b^2 = ab-b^2 ; a^2 - 3ab + b^2 = 0 ; (a-b) (a-2b) =0 ; a-b=0 or a-2b=0 ; a=b or a=2b ; 3^x= 4^x or 3^x = 2* 4^x ; its more simple what do you think?
@onlineMathsTV
Жыл бұрын
Very concise sir. It is a welcome approach too. Nice work and we have learnt something new from your comment. Thanks for watching and dropping this comment too. Much respect and love to you sir...🙏🙏💕💕💕
Eu não fazia ideia de pra onde ir 😅😅 vídeo muito bom
@onlineMathsTV
Жыл бұрын
😍😍😍 funny you sir. Coming here means you will definitely know where to go next time you come across any mathematical challenge/problem as u consistently visit OnlinemathsTV channel. Much love....💖💖💖
🙏
@onlineMathsTV
Жыл бұрын
Thanks sir for you comment. It is a symbol but a big symbol of encouragement to us sir. We are glad that you gained some values from our little effort and we promise to do more effective work here in order not to disappoint you and others who believe even in our little beginning. We love you sir.❤️❤️💖💖💕💕💕
Thank you Sir
@onlineMathsTV
Жыл бұрын
You are most welcome sir, and thanks for watching our content sir. Much love 💖💖💕💕
Congrats,bro !
@onlineMathsTV
Жыл бұрын
Many thanks to you for encouraging us on what we are doing sir. Respect...👍👍
I solved the exercise in 2 minutes․ x
@onlineMathsTV
Жыл бұрын
Bravo👍👍👍 You the master👌👌👌
@M.Davit613
Жыл бұрын
@@onlineMathsTV Thank U
Hmm, I should try a graphical solution method without drawing a proper graph Sketch a graph of graph of y = 3^x -4^x . y = (12^x -16^x)^0.5 when x = 0, y=0, certainly. y will always be +ve when x is -ve. When x is positive will generate complex numbers so, by inspection, both graphs meet at x=0 and y=0 Then try x = -1, -2 and -3 ; gradually the difference in y values get smaller and smaller In an exam, this sort of question requires an approximate answer for the second value
Выражение под корнем должно быть не меньше нуля. Те, когда возаодили корень в квадрат, должны были получить модуль и нужно рассмотреть 2 случая
In case 1,there is no need to go for' ln' because raised to the power 0 only gives 1
@onlineMathsTV
Жыл бұрын
Noted sir.
3^x-4^x=sqrt(12^x-16^x) y=3^x-4^x y=sqrty*(sqrt4^x) =sqrty*2^x divide both sides by 2^x 1.5^x-2^x=sqrty=y/2^x sqrty=y/2^x 2^x=y/sqrty=sqrty square both sides y=4^x=3^x-4^x +4^x both sides 2(4^x)=4^(x+0.5)=3^x z=ln4/ln3 [3^z=4] (3^z)^(x+.5)=3^x x=zx+0.5z *x both sides x^2=zx^2+.5zx -x^2 both sides (z-1)x^2+0.5zx=0 [1 rough quadratic formula later] x=(-0.5(ln4/ln3))/((ln4/ln3)-1) =-ln4/((2ln3)((ln4/ln3)-1) (2ln3)((ln4/ln3)-1)=((2ln3*ln4)/ln3)-2ln3 =2ln4-2ln3 =>x=-ln4/(2(ln4-ln3)) …and also x=0. edit: oh wow, different fractions yet the same constant
@onlineMathsTV
Жыл бұрын
Wonderful and unique move. You are good at it sir, you the master here. Respect👌👌👌
how about 0 or 1/{ log2 (3) - 2}
@onlineMathsTV
Жыл бұрын
Thanks for the encouragement sir. We love you for watching and commenting sir. Much love 💕💕💖💖
@tunneloflight
6 ай бұрын
This also has the advantage that many calculators natively perform lg2, so x = 1 / (lg2(3) -2) is trivial to calculate. In RPN: 3 ; lg2 ; 2 ; - ; 1/x. {five keystrokes}
,X= log( 3/4 ) 2
×=-3
You must set 3^x--4^x>=0 ...... x
@onlineMathsTV
Жыл бұрын
noted sir. Thanks master.🙏🙏🙏
@loveharshvardhan4259
9 ай бұрын
Only one to notice. Hats off
thank you very much, i suggest that the value of zero for u should be rejected, for otherwise the division by ( 3 px - 4 px) being equal to zero would not work
@onlineMathsTV
11 ай бұрын
But 3 px - 4 px (i.e 1-1) will give us zero, which implies LHS = RHS. What do you think sir?
X не может быть равен "0", так как -1 не равно sqrt(-1)
If we use log instead of using ln ,then what will happen
@onlineMathsTV
Жыл бұрын
same result sir.
@faithlesshound5621
9 ай бұрын
Using logs to the base of 10, we can fill in the numbers (the logarithms of 2, 3 and 4, which are 0.3010, 0.4771 and 0.6020) from memory and then calculate the quotient by hand. I don't have natural logs in memory.
It seems that you like solving children' s math-probs 3^x - 4^x = sqrt(14^x -16^x). Notice that the expression inside the radical can not be negative, but 14^x 14^x - 16^x will always be negative. There is only 1 way to neutralise the negative result is to make the expression= O. since any value taken to pwer of 0 will become 1. If x = 0, 24^0 -16^0 = 1 - 1 = 0 Checking whether x = 0 the solution: 3^0 - 4^0 = sqrt(14^0 - 16^ 0) 1 -1 = sqrt(1 - 1) 0 = 0. Hence, x = 0 is the solution We're done
@onlineMathsTV
6 ай бұрын
Ok sir, thanks for dropping this sir. We learn everyday from the best brains all around the globe and we sincerely believe you are one of these rare genius in mathematics. Nice to have you here sir, You are most welcome master.
🤎
What's is the meaning of Wn( 2) ?????
@brightjovanny
9 ай бұрын
Wn(z) is generally called the Lambert W function (or omega function or productlog) where the subscript n (an integer) represents the principal, positive or negative branch of the function with n = 0 being the principal branch. The Lambert W function is the inverse of the function: f(w) = we^w where w is any complex number and e^w is the exponential function. The function can also be written as: LambertW(n,z) ProductLog(n,z)
Hello students
@onlineMathsTV
Жыл бұрын
Hi master!!! Anything for the student/s? We are at your service as your wish is our command sir.
I disagree with x2 solition - it is superfluous as we should use straight definition of logarithm: X2=log(3/4)2. log(a)b.
@onlineMathsTV
Жыл бұрын
not too clear with your point here sir.
I tried my Genetic Algorithm with this; 'x' must be a negative number, and it needn't be an integer. There seems to be no real solution, the greater the (negative) number, the closer it gets. I scanned from 0-> -500 and the best I got was: X = -481.58408788993336 Left side evaluates to: 1.6826575283911937e-230 Right side evaluates to: zero (probably not real zero, the computer just doesn't display such a small number) Difference = 1.6826575283911937e-230 , effectively solving the equation (for engineers, not theoreticians!) (plus overflow errors and other Python squawking) Maybe I should watch the video ...... .
@onlineMathsTV
Жыл бұрын
Smiles....nice work from you boss. But most times AI fails to give the actual result to a mathematical challenge. I believe you have watched the video sir. Did you agree with the approach I applied here? I made a video on a similar challenge with a different approach. Below is the link to that video, you can as well flip through it to check it out if you don't mind sir. kzread.info/dash/bejne/YpeLzM5uZpScoLQ.html And do not hesitate to make corrections where necessary because we are here to also learn from the best brains like you all around the world. Thanking in advance boss!!! Respect!!! 👍👍👍 Much love....❤️❤️
@vicferrmat4492
10 ай бұрын
Do you mean "generic" algorithm?
Easier to go m log7=log70
@onlineMathsTV
Жыл бұрын
Bravo 👍👍👍 You the best sir.
X1=0 X2~ -2.41
@onlineMathsTV
Жыл бұрын
Bravo 👍👍👍 You the best sir.
ln 1 is equal 0 so x1=0
@onlineMathsTV
Жыл бұрын
Yap
X=0
@onlineMathsTV
6 ай бұрын
Correct boss, but that is just one of the solutions. Thanks for stopping by sir. Much love.
빙빙 돌아가며 풀이해 지친다.. 무조건 자연로그로만 푸니 듣기가 힘듬
In this video, the respected teacher is attempting to divide by zero, the value for which remains undefined and unknown. Thereby, his method is wrong.
@onlineMathsTV
9 ай бұрын
Sir, are you of the opinion that zero as a root to this math challenge is wrong? Kindly do the simple substitution and check if an undefined expression will emerge in this math challenge sir. Thanking you for a positive response in advance.
@nasrullahhusnan2289
9 ай бұрын
I think there is no division by zero. In [(3^x)-(4^x)]²=(4^x)[(3^x)-(4^x)] the teacher didn't divide the equation by (3^x)-(4^x), rather he let (3^x)-(4^x)=u and then move all terms to one side. Directly moving all terms to one side follow by factorizing we get [(3^x)-(4^x)][{(3^x)-(4^x)}-(4^x)]=0 [(3^x)-(4^x)][(3^x)-2(4^x)]=0 Hence: • (3^x)-(4^x)=0 --> x=0 • (3^x)-2(4^x)=0 --> (¾)^x=2 NO DIVISION BY ZERO
I already see 0 as solution 😅
@himnishdhiman1370
4 ай бұрын
Yeah but thats only one solution!!
You don't have to copy all such lengthy steps of human -invented motions of algebra to arrive at the correct answer Again, logical reasoning can help you solve all sorts of problems, but not copying such lengthy formulas and steps, like a photocopying machine
@onlineMathsTV
6 ай бұрын
Noted and thanks sir.
I wonder who is meant as the audience of this piece. A general mediocre pupil will not get even this long and overworded explanation. A bit developed one (1) does not need 2/3 of this wording, (2) guesses x=0 is a solution in the first 30 seconds, by substitution, (3) since a square root from a negative number is not real, gets any other root is negative. Finaly, 3^x = 4^(x+1/2) can be trivially solved with much less wording.