solving 1/2 + 1/sqrt(x) = 1/3 but you won't get a solution
Rational equation with square root.
Жүктеу.....
Пікірлер: 23
@ShubhayooBanerjee5 ай бұрын
Eminem been real quiet since this banger dropped🗣🗣🔥🔥
@manthankashyap9335 ай бұрын
The answer is 1/sqrt(x)=-1/6, But, there is no value of x, which satisfies this equation
@aneeshbro5 ай бұрын
Nah bro be rappin' math 🗿🗿🗿🗿
@syndrac62545 ай бұрын
When your math teacher is Eminem. Lyrics coming at you at super sonic speed.
@rythmicconvival5 ай бұрын
Nice
@spthepero22825 ай бұрын
BUT WHY TF? IF YOU PUT -6 IN PLACE OF SQRT(X), THEN YOU GET BOTH SIDES CORRECT.
@oZqdiac
5 ай бұрын
But sqrt(x) can’t equal -6
@spthepero2282
5 ай бұрын
@@oZqdiac so is it an extraneaous root? Oh I get it now, Ik about extraneaous root stuff
@bhaveshsinghbisht
4 ай бұрын
@@spthepero2282 actually 36 is not a solution . When you will put it in equation. , it will not satisfy .Let me tell you why 1/2+1/√36=1/2+1/6=4/6=2/3 | | \ / You took √36=-6 which is wrong . √36=6 only . That was the mistake and you got your answer correct . Hope this helps❤.
@spthepero2282
4 ай бұрын
@@bhaveshsinghbisht Yeah thanks for the clarifaction mate, I didn't realise that was an extraneous root.
@Happylittleradish4 ай бұрын
Why dident you rationalize the denominator?
@f.r.y58575 ай бұрын
√x² = |x|
@teoteo83515 ай бұрын
Apologies for a completely unrelated question. I am currently studying University, completed the chapters for basic differentiation and integration, what should I learn next or what can be my to-learn list? The professor won't upload any materials for me to prepare...
@user-gd1ej9eh1k
5 ай бұрын
Linear algebra and real analysis
@madsorcery
5 ай бұрын
Complex Numbers.
@johnathanpatrick61185 ай бұрын
Just looking at the equation itself you can tell 1/sqrt(x) had to somehow be negative since 1/2 > 1/3. Never gonna work.
@monttdher5 ай бұрын
Talk about conic sections
@robzan85 ай бұрын
Does sqrt(x) = -6 have a complex solution?
@user-cc6ci7jx5q
5 ай бұрын
No even the complex world can solve this as i (as the sqrt of -1) can’t be plugged anywhere
@allozovsky
3 ай бұрын
@@user-cc6ci7jx5q In fact, that's not that strict and mostly depends upon how we treat the square root notation. Steve himself in one of his videos (sqrt(i)) claimed that "√𝒊 has *two* answers", namely √𝒊 = ±(1 + 𝒊)/√2, so in the same manner one might claim that √(-1) = ±𝒊 and √36 = √(36 + 0·𝒊) = ±6, but that leads us to multivaluedness, which we mostly try to avoid in our notation (as much as we can).
@comdo7775 ай бұрын
asnwer=1 isit
@69Gigantosaur5 ай бұрын
No comments? 😮😮
@Grizzly01-vr4pn5 ай бұрын
End card obscuring pertinent parts of the video. Poor upload.
Пікірлер: 23
Eminem been real quiet since this banger dropped🗣🗣🔥🔥
The answer is 1/sqrt(x)=-1/6, But, there is no value of x, which satisfies this equation
Nah bro be rappin' math 🗿🗿🗿🗿
When your math teacher is Eminem. Lyrics coming at you at super sonic speed.
Nice
BUT WHY TF? IF YOU PUT -6 IN PLACE OF SQRT(X), THEN YOU GET BOTH SIDES CORRECT.
@oZqdiac
5 ай бұрын
But sqrt(x) can’t equal -6
@spthepero2282
5 ай бұрын
@@oZqdiac so is it an extraneaous root? Oh I get it now, Ik about extraneaous root stuff
@bhaveshsinghbisht
4 ай бұрын
@@spthepero2282 actually 36 is not a solution . When you will put it in equation. , it will not satisfy .Let me tell you why 1/2+1/√36=1/2+1/6=4/6=2/3 | | \ / You took √36=-6 which is wrong . √36=6 only . That was the mistake and you got your answer correct . Hope this helps❤.
@spthepero2282
4 ай бұрын
@@bhaveshsinghbisht Yeah thanks for the clarifaction mate, I didn't realise that was an extraneous root.
Why dident you rationalize the denominator?
√x² = |x|
Apologies for a completely unrelated question. I am currently studying University, completed the chapters for basic differentiation and integration, what should I learn next or what can be my to-learn list? The professor won't upload any materials for me to prepare...
@user-gd1ej9eh1k
5 ай бұрын
Linear algebra and real analysis
@madsorcery
5 ай бұрын
Complex Numbers.
Just looking at the equation itself you can tell 1/sqrt(x) had to somehow be negative since 1/2 > 1/3. Never gonna work.
Talk about conic sections
Does sqrt(x) = -6 have a complex solution?
@user-cc6ci7jx5q
5 ай бұрын
No even the complex world can solve this as i (as the sqrt of -1) can’t be plugged anywhere
@allozovsky
3 ай бұрын
@@user-cc6ci7jx5q In fact, that's not that strict and mostly depends upon how we treat the square root notation. Steve himself in one of his videos (sqrt(i)) claimed that "√𝒊 has *two* answers", namely √𝒊 = ±(1 + 𝒊)/√2, so in the same manner one might claim that √(-1) = ±𝒊 and √36 = √(36 + 0·𝒊) = ±6, but that leads us to multivaluedness, which we mostly try to avoid in our notation (as much as we can).
asnwer=1 isit
No comments? 😮😮
End card obscuring pertinent parts of the video. Poor upload.