Robot Inverse Kinematics With A Hexapod Leg

Ғылым және технология

This video has a detailed inverse kinematic solution for a 3 axis robot and videos of it in action applying the solution. There are also some mistakes that I cover that happened along the way and crucially unlike most other videos the arm segments are NOT the same length.
The code can be found here and is free to use and adapt:
github.com/JustAnotherMakerCh...
3D Print files: www.thingiverse.com/thing:646...
Music from #Uppbeat (free for Creators!):
uppbeat.io/t/danger-lion-x/gh...

Пікірлер: 135

  • @pieterpennings9371
    @pieterpennings93719 ай бұрын

    really cool. I am in the process of making my own hexapod and other projects that include inverse kinematics and I got this video suggested randomly and it's really well made.

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    9 ай бұрын

    Thank you :)

  • @JamesNewton
    @JamesNewton10 ай бұрын

    Excellent video! I expect I will use it with students in the future. I agree with others that less bubble popping would be good. I'm also not into cartoon violence. Love the "why didnt that work" bit in the middle because students often give up at those points and it great that you modeled working through it.

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    10 ай бұрын

    Thank you for the kind words and the honest feedback. I’m very glad to hear that you might use it to teach with, I had actually hoped someone would use for that very purpose! In the future (this year I hope) i’m going to explore the solutions for a 6 DOF robot and build one, maybe create my own programming language for it, and an interpreter, controller, teach pendant etc. I have experience with them in industry and I think there are a lot of barriers to people gaining an understanding of how it all fits together and how it works.

  • @rahadyanmuhammad271
    @rahadyanmuhammad2719 ай бұрын

    Really awesome. Thanks for sharing this video

  • @maurovianna4702
    @maurovianna470210 ай бұрын

    Thanks for the great explanation! I already saw a code for such a robot but now I finally understood it due to the math and interpolation.

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    10 ай бұрын

    You’re very welcome :) thanks for the support :)

  • @GuilhermeLimait
    @GuilhermeLimait3 ай бұрын

    The most simple way to learn it that I’ve seen so far, thanks for it❤

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    3 ай бұрын

    You're very welcome! Thank you so much, I really appreciate the comment :)

  • @jeremiahbullfrog9288
    @jeremiahbullfrog928810 ай бұрын

    Fascinating. Thank you for showing how to derive the formulas, this stuff seems like magic but it all comes down to maths.

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    10 ай бұрын

    Glad you enjoyed it!

  • @GCKteamKrispy
    @GCKteamKrispy5 ай бұрын

    Just some basic geometry, but my professor had to talk in some complicated engineering language. Thank you so much, very helpful

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    3 ай бұрын

    You're welcome and thanks for the comment!

  • @as2gmvenom835
    @as2gmvenom8352 ай бұрын

    Interesting video with a good explanation. I want to mention that you can use the same rules to make the leg move in a straight line rather than an arc instead of using interpolation. How: Use the variable names at 3:50 and 11:30 as a reference. Let J0 be the third angle of the triangle J3-J2-J0 at the cross point of J2 (Y) and J3L. Get the lines j3, j2, and j0. *You have to calculate the j3, j2, and j0 lines when the leg is in the stand position. Now you can calculate the angles J3, J2, and J0 from the given j3, j2, and j0 lines. The trick is to make the j3 line equal = j3/CosJ1. now the angles J3 and J2 will depends on J1 You just need to set J3 and J2 in the code. J3 = ArcCos((j2^2+j0^2-(j3/cosJ1)^2)/2*j2*j0) J2 = ArcCos(((j3/CosJ1)^2+j0^2-j2^2)/2*(j3/CosJ1)*j0) Boooom you got a straight line. Thank you!

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    2 ай бұрын

    Thank you, some interesting information that I’ll make the time to digest when I’m less tired. I don’t think it’s the IK solution that causes the arced motion rather the mechanical system, I have no direct control over the speed of the servos and thus when all changed at once from their respective starting angles to end angles they all move as fast as possible which is not necessarily linear. Since I have no influence over the servos speed, interpolation gives a very simple way to get an approximated linear move that can be refined by taking more smaller steps. I can’t immediately see how a change in end point calculation could achieve anything else?

  • @as2gmvenom835

    @as2gmvenom835

    2 ай бұрын

    @@JustAnotherMakerChannel 11:40 You used Pythagoras to get H so that's why the leg caused a rotary motion (arc) instead of a straight line. Because you calculated the radius of a circle with J1 its centre Description: Let's be in the same view by agreeing this. ****************************************************************************************************** - the joint J1 causes the arc motion because it has to rotate the leg causing circular motion (an arc). - [To convert an arc to a straight line] >> you must increase the radius (for each increase in angle) ~ exponentially. Ex. if J1 = 0 degree, radius = 10 cm when J1 = 15 degree, radius must be = 10.3528 cm when J1 = 60 degree, radius must be = 20 cm How to increase the radius (you called it H) >> [the radius length increase(+)] >> by decreasing(-) the angle of J2 and increasing(+) the angle of J3 assume the lower and the upper bones = 20 cm and J3=60 degree and J2 = 60 degree the radius = [upper_bone_cm / cos(180-J3-J2)] + [lower_bone_cm /cos (J2)] * (radius is result of looking at the leg from top view) * >> 20/cos(180-60-60) + 20/cos(60) >> 10 + 10 >> the radius = 20 cm [The equation] >> to convert the arc into a straight line radius = 20 / cos(J1) ** but you need to know the angles of J2 & J3 to adjust the radius changing its length in the code ** [you have to create an algorithm]>> that changes the angle values of J2 and J3 (this causes a change in the length of the radius) depending on the angle value of J1 using a loop for( J1 = 0 degree ; J1 { total_length_or_radius_cm = (upper_bone_cm / cos(180-J3-J2)) + (lower_bone_cm /cos (J2)) J3= Arccos (((lower_bone_cm^2 + upper_bone_cm^2 - (total_length_or_radius_cm / cos(J1))) / 2 * upper_bone_cm * lower_bone_cm) J2= Arccos (((total_length_or_radius_cm/cos(J1))^2 + upper_bone_cm^2 - lower_bone_cm^2 ) / 2 * upper_bone_cm * (total_length_or_radius_cm / cos(J1))) or J3 = ArcCos((j2^2+j0^2-(j3/cosJ1)^2)/2*j2*j0) J2 = ArcCos(((j3/CosJ1)^2+j0^2-j2^2)/2*(j3/CosJ1)*j0) delay = 100 ms \\increase the value of delay to decrease the motion speed and the vibration that caused by the momentum. } app.gemoo.com/share/image-annotation/615760982094012416?codeId=vzxdG9ZpE6o7n if you didn't get me or the images links dose not work type a guest account so i can send you images or a video

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    2 ай бұрын

    [QUOTED]"11:40 You used Pythagoras to get H so that's why the leg caused a rotary motion (arc) instead of a straight line. Because you calculated the radius of a circle with J1 its centre "[QUOTED] The solution I presented is correct, the value of H will change depending on the X & Y co-ordinate of the position required and therefore does not to be manually increased or manipulated. To achieve a positional deviation in X, all 3 joints require motion. This is accounted for in the video by substituting Y @11:57 for H to allow the J2 & J3 kinematics to be calculated on the plane projected by J1's changing angle, which ultimately accounts for the arced path of J1. The TOP-VIEW diagram you have presented in the link is exactly what we are doing @ 11:40, H is calculated using X & Y with Pythagoras, I can see that the underlying semi-transparent image does not make that too clear as I've arbitrarily drawn a vertical line from the Y axis, the value H shown @11:40 is exactly what you are referring to as 'H+L' in the link, which we cannot calculate from cos(J1) namely because we are trying to calculate J1, it is unknown. The example of arced motion shown @12:19 has no J1 involvement, no X or Z movement, only Y movement from 1 singular point to another singular point, the motion is arced because both J2 & J3 need to move by different amounts and travel at an uncontrolled speed and the inability to maintain position during the deceleration of the other axes. It's not very easy to see but @12:24 J2 completes it's movement in a fraction of the time that J3 takes, this causes the leg to plunge downwards from J2 moving and then upwards to the correct position as J3 catches up (then some overshoot and oscillation) I really appreciate all of the time and effort you have spent with your responses and the link and pictures too, I had to look through it a good few times and for a moment I was questioning whether my solution was correct! Let me know if you have and other questions :)

  • @as2gmvenom835

    @as2gmvenom835

    2 ай бұрын

    @@JustAnotherMakerChannel I used trigonometry to calculate the H, and you used pythagoras to calculate the H. Sorry, I just misunderstood you, You are right! I was confident because I made a hexapod and used this equation with mg996r and it was working. now i realize that if I am right, that does not mean you are wrong I was too hasty. Thank you, I have learned a lot because of you.

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    2 ай бұрын

    Thank you, I really appreciate all your comments :)

  • @Algardraug
    @Algardraug7 ай бұрын

    Really cool video and great explanation! Although I wish you had spent some extra time on the interpolation part as I don't understand how that helps when the distance that the servos have to travel doesn't change?

  • @sub2seany
    @sub2seany11 ай бұрын

    My brain has exploded

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    11 ай бұрын

    Exploded with your newfound knowledge of inverse kinematics!

  • @onurkarakas2814
    @onurkarakas281410 ай бұрын

    This video is very epic, thanks for sparing time to make such a video.

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    10 ай бұрын

    No problem!

  • @gabrielpiazza8463
    @gabrielpiazza846310 ай бұрын

    This is awesome, you explained everything so well, thank you for the good and clear content sir. Keep it up.

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    10 ай бұрын

    Thanks, will do!

  • @BrickRoom7
    @BrickRoom75 ай бұрын

    This is the best IK tutorial video on KZread, at least I think so. Thank you for this. Can you do a video on transformation and rotations?

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    3 ай бұрын

    Thank you so much, I'm planning to do a video on a 6 axis robot using Denavit-Hartenberg and it has a lot of matrix mathematics with transformations and rotations.

  • @anton4ik55
    @anton4ik5510 ай бұрын

    nice video, but those bubble sounds are waaaay too loud, gets very annoying to watch

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    10 ай бұрын

    Thanks you and thanks for the feedback, I’ll definitely use them less and at lower volume in future :)

  • @bernard2735

    @bernard2735

    10 ай бұрын

    I agree. Your content is great - clear images, a calm voice, and nice stepwise explanations - so you don’t need anything else. I subscribed ☺️

  • @timothysands5537

    @timothysands5537

    6 ай бұрын

    All the sound effects are too loud I think. But I like them if they were 1/3 their volume

  • @Maleko48

    @Maleko48

    6 ай бұрын

    I didn't even notice any bubble sounds

  • @The-KP

    @The-KP

    2 ай бұрын

    ​@@JustAnotherMakerChannel No need to use sound effects at all, the value of your information outweighs any added interest you might believe a sound effect provides. It's just a distraction. Watch the videos of Mathologer and Veritasium. No sound effects, just narration and some animation. Thanks for making an otherwise EXCELLENT video on hexapod kinematics.

  • @durgeshbg
    @durgeshbgАй бұрын

    03:11 that's where i lost track, cool work btw might get into robotics sometime in the future, thanks

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    Ай бұрын

    You should, it’s a fascinating subject, glad you liked the video :)

  • @tijnvanraak7711
    @tijnvanraak771110 ай бұрын

    Thanks, best IK explanation I am able to find!

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    10 ай бұрын

    Glad it was helpful!

  • @mohanadebada2298
    @mohanadebada22986 ай бұрын

    thank you for the math part btw its really fresh to see some math in things like this

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    3 ай бұрын

    I totally agree!

  • @user-tb9xv3fy8n
    @user-tb9xv3fy8n10 ай бұрын

    Man just came into my recommendation and saved me Tnx G! Subbed

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    10 ай бұрын

    I’m glad it helped :)

  • @shark5651
    @shark56518 ай бұрын

    hi do you have a link to the 3d printed parts?

  • @grahamnichols1416
    @grahamnichols14164 ай бұрын

    That is really well explained = an instant subscription. Tada!

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    3 ай бұрын

    Thank you very much, I really appreciate it :)

  • @ahmedbenyoucef3238
    @ahmedbenyoucef32389 ай бұрын

    Thank you for your great explanation. In fact, it was very cool.

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    9 ай бұрын

    Glad you liked it!

  • @oluwaferanmi100
    @oluwaferanmi1009 ай бұрын

    This guy is low key funny, nice video by the way. Keep it up.

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    9 ай бұрын

    Appreciate it :)

  • @fnsociety2827
    @fnsociety282710 ай бұрын

    Thanks a lot bro, i found the best IK explaination, waiting for trajectory from your video ❤

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    10 ай бұрын

    Thank you, you can see it's first steps here: kzread.info/dash/bejne/aZiD1KSOk9Cyhrw.html I'll be working on the walking some more and making it remote control soon :)

  • @fnsociety2827

    @fnsociety2827

    10 ай бұрын

    @@JustAnotherMakerChannel Cool. I'll wait for it. I'd suggest you use a dynamixel servo for smoother things. But the important thing your explaination in math robotic is very nice, keep'it up!

  • @sulesmith897
    @sulesmith8979 ай бұрын

    Amaxing work!😊

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    9 ай бұрын

    Thank you! 😄

  • @arevindmohan3523
    @arevindmohan352310 ай бұрын

    Thank you very much bruv! This helped me out a ton..❤

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    10 ай бұрын

    You’re very welcome :)

  • @andres154525452
    @andres1545254526 ай бұрын

    Good video!

  • @MrEnkelmagnus
    @MrEnkelmagnus10 ай бұрын

    Cool, that was really helpful.

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    10 ай бұрын

    Glad to hear!

  • @a330turbinex7
    @a330turbinex718 күн бұрын

    Superb!!!

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    17 күн бұрын

    Thank you so much :)

  • @Hyun_.18
    @Hyun_.1810 ай бұрын

    how can i code at 10:33 to servo move on 40mm like that?i understand what you said about algorithm but how to write command line to make servo move like this, thanks you

  • @SALSN
    @SALSN10 ай бұрын

    Very nice. I'll put this video in my build playlist, and get to it in a decade or two :-p

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    10 ай бұрын

    I know the feeling! I have so many things on my list too :)

  • @SALSN

    @SALSN

    10 ай бұрын

    @@JustAnotherMakerChannel I have at least 5 projects that are on hold somewhere in the making process :-p Quad copter, drone plane, new split keyboard, mini solar boat, and a remote controlled pick up truck, just of the top of my head :-p Oh well, summer vacation soon :-)

  • @Sjeedughait
    @Sjeedughait2 ай бұрын

    Maybe reverse engineer in algorytme and iterations something touchable. Like start and stop animations. Moving a robot engine by hand can be recored by software as steps. With or without a rhyme or repeatative steps in it. It is basically acting and can be started with dancing lessons. Like walse and rumba. Some rhyme can be distellid from that for your robot. Overlapping formulas can be used for more complex movements. Just coordinates with two equals signs.

  • @dadi3125
    @dadi31256 ай бұрын

    Nice video. I learned a lot from it.

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    3 ай бұрын

    Thank You!

  • @tshebeletsotjabane4979
    @tshebeletsotjabane49795 ай бұрын

    What about the horizontal YX kinematics?

  • @mohanadebada2298
    @mohanadebada22986 ай бұрын

    can you create a pnuematic wall climbing hexapod ?

  • @stefanguiton
    @stefanguiton10 ай бұрын

    Great video!

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    10 ай бұрын

    Thanks!

  • @daleyarrow5358
    @daleyarrow535811 ай бұрын

    Well that made for some interesting bed time entertainment…my brain is now scrambled and I have a new found respect for your infinite knowledge. I hereby dub thee, a wizard.

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    11 ай бұрын

    Thank you, thank you, I’m definitely going to be applying this to a robot arm with more axes and hopefully more accuracy, so watch this space!

  • @daltongabriel-9258

    @daltongabriel-9258

    10 ай бұрын

    I find this rather sarcastic 😂

  • @swannschilling474
    @swannschilling4746 ай бұрын

    Great Video!!! 🎉🎉🎉

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    3 ай бұрын

    Thank you, glad you liked it!

  • @katierobinson5399
    @katierobinson539910 ай бұрын

    You are incredible

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    10 ай бұрын

    Thank you :)

  • @evil_lime4378
    @evil_lime43782 ай бұрын

    How did you calculate the C angle at 10:15? Only part of the (excellent) vid that stumped me

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    2 ай бұрын

    My apologies for not being clearer, that angle is measured from the design, the reason being that the servo arm is not aligned with the leg. Really though it could have been designed in line and the angle C would not be needed at all!

  • @messerschmidtfpv4419
    @messerschmidtfpv44194 ай бұрын

    Hello, thanks for the tutorial. where can I find the STL file to print myself?

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    3 ай бұрын

    I will have a look back for the files and try to get them online in the next week - though it is not the best design.

  • @TubeClemens
    @TubeClemens2 ай бұрын

    Excellent video clear explanation. I build a hexapood myself. One question if I have a J1L=60 how does this affect the code?

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    2 ай бұрын

    Hi @TubeClemens, Do you mean you wish to have J2 not directly above and inline with J1 and call this offset J1L? If so then as a quick shot at this you would need to think about the following: @3:30 the Y value would need to have 60 taken off as this would be a fixed offset by J1L=60, similar to @9:41 where we apply an offset to Y to account for the leg resting position, but I think the real answer is below. @11:53 when we go back and substitute H in, we would substitute (H - J1L). For a quick look I think that would be the solution you are asking for. Hope this helps :)

  • @TubeClemens

    @TubeClemens

    2 ай бұрын

    @@JustAnotherMakerChannel Thank you very much this is exactly what I meant. I wil give it a try.

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    2 ай бұрын

    Great @TubeClemens, I’m glad I could help, please let me know how it goes :)

  • @hashiragamingyt2162
    @hashiragamingyt216211 ай бұрын

    You deserve more likes and subs

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    11 ай бұрын

    Thank you, you’re too kind :)

  • @user-mf6ij8ps2z
    @user-mf6ij8ps2z4 ай бұрын

    you have to implement PID regulation algorithm

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    3 ай бұрын

    An excellent point and definitely part of the problem!

  • @brandonheat5262
    @brandonheat526226 күн бұрын

    does it matter if J1 has offset away from J2? I see there are many designs of 3 dof leg in this way.

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    26 күн бұрын

    Yes it would have an effect on the XY solution, I think you would need to calculate the angle for J1 first, then using that angle and the offset to J2 calculate the X and Y value for where J2 is now located and subtract those from the X and Y used to calculate J2 and J3

  • @brandonheat5262
    @brandonheat526210 ай бұрын

    Best explaination in the world! Could you do one video of inverse kinematics for robot dog?

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    10 ай бұрын

    Thank you ! I have a lot of videos on the horizon, in the future I definitely want to make and explain a robot dog!

  • @katierobinson5399

    @katierobinson5399

    10 ай бұрын

    Sausage dog?

  • @senaalfarabi4077
    @senaalfarabi4077Ай бұрын

    I want ask something, in minute 3:25 . Are L variable is range between servo 2 and the lowest point of foot point can be?

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    Ай бұрын

    L is from servo 2 to the position of the foot, where we want to position it, there will be a range of motion that can be achieved depending on the lengths J2L and J3L. I hope this answers your question :)

  • @senaalfarabi4077

    @senaalfarabi4077

    Ай бұрын

    Another question at 9:37 , where you can get y,90 and z,-60?

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    Ай бұрын

    No problem, those are physical measurements, I obtained them from the CAD model of the design with the leg in the 'resting' position that I wanted.

  • @guilhermeconstantinov
    @guilhermeconstantinov21 күн бұрын

    should the angle really be negative? depending on the value, the J3 is negative

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    20 күн бұрын

    I’m not sure exactly where you are referring to in the video

  • @rezageraldy-gn1jw
    @rezageraldy-gn1jw15 күн бұрын

    could i ask you sir. we kinda have problem when it comes to writing j3 and j2 arduino. we use your formula but the output show nan. we are not missing any single information for video even though it only one mistake. so pls help us this for high school project.

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    15 күн бұрын

    Can you share your code?

  • @bruteforce8744
    @bruteforce874410 ай бұрын

    Make a video on inverse kinematics of 3 wheel omni drive

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    10 ай бұрын

    I’ll add this to my list, thanks for the suggestion

  • @guilhermeconstantinov
    @guilhermeconstantinov21 күн бұрын

    why were these values added? const double Y_Rest = 70.0; const double Z_Rest = -80.0;

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    20 күн бұрын

    These values were added so that the movements can be made relative to a ‘resting’ position, without them it’s not as practical to plan movements from the centre of J1.

  • @guilhermeconstantinov

    @guilhermeconstantinov

    19 күн бұрын

    @@JustAnotherMakerChannel got it, thanks for the explanation

  • @angelgomez9944
    @angelgomez99445 ай бұрын

    where can I get the design ?

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    3 ай бұрын

    Sorry for the delay, the files can be found here: www.thingiverse.com/thing:6463619

  • @tsheringphuntsho2325
    @tsheringphuntsho232510 ай бұрын

    i would be thankful if you could share me the components parts links so that it will easier for me to print

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    10 ай бұрын

    I can try, I’m away on business at the minute so I don’t have access to the files right now, when I return home I’ll put them onto thingiverse :)

  • @tsheringphuntsho2325

    @tsheringphuntsho2325

    10 ай бұрын

    Thanks for that😊😊

  • @tsheringphuntsho2325

    @tsheringphuntsho2325

    10 ай бұрын

    What about the connection for 3 Axis leg

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    10 ай бұрын

    Yes I’ll share all the files :)

  • @jamesgilmour7984
    @jamesgilmour798410 ай бұрын

    could this math be used for a biped reversed knee style robot?

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    10 ай бұрын

    I think you could use it for any similar configuration, might need to re-orientate the co-ordinate system, I’ll look into it and maybe do a video

  • @jamesgilmour7984

    @jamesgilmour7984

    10 ай бұрын

    @@JustAnotherMakerChannel also how much harder would the math/ coding be with 2 more servos/axis added?

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    10 ай бұрын

    Well it depends on how the axes are oriented, it could become quite a bit more complex, with some 5 and 6 DOF (degree of freedom) robot arms there can be infinite solutions for a single point in space, I am planning to to a 6 DOF robot arm in the future but I’m having to brush up on my matrices math and manipulation first!

  • @blankblank6889
    @blankblank68899 ай бұрын

    As a high school student it is nice seeing geometry being applied 😅😅

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    9 ай бұрын

    I think it would be more constructive if geometry was applied/taught using examples like this, half the battle is knowing what to apply and when rather than how to do it IMO

  • @tawsifulislam5208

    @tawsifulislam5208

    7 ай бұрын

    ​@@JustAnotherMakerChannelAbsolutely agree with you

  • @moon-gc2go
    @moon-gc2go3 ай бұрын

    Theres a way to not make it jittery just add i2c bus or library in arduino

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    3 ай бұрын

    Thanks for the feedback, I do use the servo and ramp libraries but I didn't make any special effort to think about the servo slew rates or PID. There is definitely an element of variability between the servos that is more noticeable when trying to coordinate motion with them.

  • @panmaneecnc
    @panmaneecnc4 күн бұрын

    Thank you very much for your information and I have taken your information to study and adapted it into python for learning. If anyone is interested, you can follow and test and try it at this link. colab.research.google.com/drive/1tpKsER2IazlSDh9AVQmRVnxvxA4uU8Hm?usp=sharing

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    4 күн бұрын

    Thank you for the positive feedback and thank you for this contribution!

  • @panmaneecnc

    @panmaneecnc

    4 күн бұрын

    @@JustAnotherMakerChannel You are amazing. I will continue to share the knowledge you have given me with my friends.

  • @rezaravanbakhsh8772
    @rezaravanbakhsh87728 ай бұрын

    This popup sound is really annoying

  • @saveusfromidiocracy35
    @saveusfromidiocracy35Ай бұрын

    Hexapod with Parkinsons 😂. Good effort. Try using better servos

  • @JustAnotherMakerChannel

    @JustAnotherMakerChannel

    Ай бұрын

    I agree better servos are a must for version 2!

Келесі