Reduction of Order, Basic Example
Thanks to all of you who support me on Patreon. You da real mvps! $1 per month helps!! :) / patrickjmt !! Reduction of Order, Basic Example. Here i use Reduction of Order to find a second solution and the general solution of a differential equation given one known solution.
Пікірлер: 217
Real heroes don't wear capes, real heroes tech you Differential equations.
@4chance610
6 жыл бұрын
Grammar is optional?
@Twothron3
6 жыл бұрын
i think im dizzy after watching this :P
@cmprice11
6 жыл бұрын
i lov teching studens maths
@joelu3691
5 жыл бұрын
this dude literally teaches everything in mechanical engineering
Reads book: *thonking* Attends lecture: *visible confusion* Watches patrick: R E V E L A T I O N
@patrickjmt
4 жыл бұрын
you are too kind :)
@mexicanwootwoot
4 жыл бұрын
Invest in Stonks.
@holopleasures4011
3 жыл бұрын
Sometimes it is just seeing the same thing multiple times from multiple perspectives.
From High School Algebra 2 to College Diff EQ, you're always there. Thanks for all your help! I wonder if you have any videos related to Real Analysis.
@patrickjmt
8 жыл бұрын
+Chandler “Thunder99879” Inman not many
@hemantslift
11 ай бұрын
Heyyy
And here, ladies and gentlemen, we have a man saving the day from almost four years in the past.
You know math is difficult when you understand every method and then you get to the test and draw a blank. And for that reason, I know for sure that Patrick is gifted.
I am literally crying tears of joy. Thank you for all you do. You are the reason I will pass this class. Not having in-person lectures during the quarantine means my professor is sending us bad videos which I can't understand as well as your videos.
@patrickjmt
4 жыл бұрын
tell her/him to send mine as well :) glad i could help!
You make this sound so much simpler than my Engineering Analysis professor does, and you don't just copy from a textbook! Thanks for what you do.
i like all of it :) i like the beauty of pure math and i also like being able to actually use it for something as well!
woww those 'v's look like square root signs, great video regardless
@missempoi1976
8 жыл бұрын
+Richard Butler yeah, at first im a little bit confused. O.o
@jazzm5557
7 жыл бұрын
Richard Butler ahhh damn, once seen can never be unseen D: 😂
@tomoguitaro
4 жыл бұрын
I hear v but see sqrt
Great video. It should be in the Differential Equations Playlist.
its amazing how much easier it is to understand you , than my text book on this subject. Great Job!
life saver, you deserve a Nobel prize
You taugh me in 12 min what my lecturer has been trying to teach up in 4 days thank you!!!!!
Having seen this, no need to disrupt my sleep for a lecture in the morning anymore :)
Thank you so much sir. I was feeling nervous about my maths exam now I am feeling much more confident after learning the concept through your video.
it did not seem as though people were that interested - more people keep asking for differential equations so i figured i would start making these. i often jump from topic to topic ;)
Hello Patrick, What if there is no given solution on that differential equation? how do you formulate y=vy1?
i dont really understand your question. w(x) = v ' (x). so, w ' (x) would equal v ''(x). i am not sure why you would need to product rule, or chain rule, or anything else.
Engineering Math 2, still here. Love you.
you definitely helped me understand this concept and how to start on this. Thank you
why even go to class when these exist?
@sbk1398
7 жыл бұрын
You don't :)
@ev4662
6 жыл бұрын
pop quizzes 😥
@6subswith0vids80
5 жыл бұрын
Fugging attendance ):
i'm astounded as to how you make this sound so simple. i'm really grateful. thanks.
The fact that you published this video today is astonishing. I have a math midterm that includes RoO in a few hours.
I have an exam on Wednesday. Thank you for the crystal clear explanation.
Patrick JMT is the God of Math. I seriously can't do anything without him.
v is a function of x. v' is also a function of x. if i let w = v' , you still have a function of x, you are just renaming. for example: let v(x) = sinx. so v' = cos(x). if i let w = v' , then w = cos(x) which is still just a function of x. v is a not a variable.
When should you use this method? like for a 1st 2nd order or a linear non linear equation? thanks for the video, great help.
Eternal Value. Thank you PatrickJMT.
great method of teaching...you eliminated all my confusion...thanks
Insightful. Thorough and detailed. Good shit!
Thanks for the video! Some advice (take it or leave it)... Elaborate more on when to use reduction of order and why we would even want to use it in the first place. I felt like we rushed into an example. I feel like after watching this video I learned a technique but have only a slight idea of when to apply it.
"Basic". Nice work, your explanation really helped me get a grasp of the method. Thanks.
Since in the previous video, we were given a general formula for any diff eq in the form, y''+py'+qy=0, and we found that if we let w=v', then we get the formula, given y_1(x), to be (y_1)w'+(2y_1'+py_1)w=0, could we just skip all those steps in all circumstances? Because, as soon as you showed the problem, I paused, plugged everything into the formula i mentioned and got the same final answer as you did.
Thanks man, you're a life saver. Exam in 10 minutes
Can you please show an example of using an Annihilator to solve a high order equation such as Y^6-Y"=t^2
this is differential equations. people typically take it after they are done with calculus or in conjunction with their last semester of calculus!
Thank you soo much sir , For such an informatic example
@07:15 how were you able to just omit the absolute value symbol from w when you canceled e^ln(|w|)?
Can I use the cauchy-euler method for this example too??
How do you find the Fundament set of equation if it's not given for these specific equations?
Thanks for all the helps in math !!
Great teaching! How should I do if f(x) on the right of equation instead of 0?
Can this also be used on nonhomogeneous equations?
How to find 3rd order linearly independent solution of the equation when two linearly independent solutions are given?
You are, as ever, a life saver
can we solve it using euler-cauchy equation? because it has the same equation form ax^2y" + bxy' +cy = 0
shouldn't the arbitrary constant C1 be added to e^(lnx^-7) instead of multiplying?
This is also an Euler Cauchy form, in case you were wondering.
@jackrecher6986
2 жыл бұрын
it takes like 30 seconds with an E-C haha
Helped a lot, thanks.
I thought that y2=vy1, so I did it wrong. But I understand now that vy1 is the general solution. Thank you very much!
Fantastically helpful video
Yeah i understand. Its good to watch for revision anyway. Thank you for your videos.
How do you know when to use reduction of order on a D.E. ?
Cant we just hire this guy to do all the maths we need for engineering?
Hey Patrick, U R AWESOME! Thank U so much I do really appreciate it.
Excellent teacher🙏🤝
you are a blessing
I am not entirely clear how we identify the Second Solution as x^-5. Please explain.
@XxKo0loxX
9 жыл бұрын
Lars Magnus Earlier on he explained that the question gave one of the two solutions. In this case the given/known solution is x. That is why he multiplied v to x. The standardized procedure is multiplying v into a known solution.
thanks a lot Patrick!
VERY CLEAR! THANK YOU!
thanks dude, u save my final test in this semester
YOU MAKE BETTER WORK THAN MY STUPID PROFFESOR IN COLLEGE.
y''-3y^2=0 is it the same way ?i got down to v''x+5v'-3v'x
Excellent example. Very similar to what you will see
Havent done this yet but it seems so fun :)
can someone explain why the second solution Y_2 was only the first term of that general solution
Thank you. Can i make a question please? How is Game Theory series going. Should we wait more videos in the near future or you need time?
One point of fact- it's actually "homogeneous", not "homogenous". Super helpful video!
!!Does anyone know how to get the first solution (Y1=x)? It is given here, but not with the questions in my book.
U helped a lot....thanks
THANKS BRO .... u are a superhero
Isn't the general solution y=C_1(y_1)+C_2(y_2) where you plug the y that you just solved for into y_2?
Thank you for saving my life
Your videos are so good
I wish I found your videos in high school! (Really I mean to say I wish I cared enough to look) you got me through my college physics degree and I have to say thank you! (And give a broke college student donation)
How can you say w = dv/dx and then dw/dx = d2v/dx2 ? doesnt dw/dx = d2v/dx2 + v? by product or chain rule; since it depends on x?
the Vs looking like sqrts and your notation around 2:10 is killing me
Nice explanation 👌👌
love your videos! thank you thank you!
@patrickjmt
10 жыл бұрын
happy to help!
Shouldn't the second solution be the first solution multiplied by x? Why is it different here?
veeery helpful, thanks a lot! :)
like r u a professor or something in Austin ? I"m in DE right now and these videos are really helpful. thanks alot
Thanks a lot Sir
Should be x^-3 though for the last step as we do: 1/(x^4) * x = 1/(x^3) = x^(-3)
@sand-barry
8 жыл бұрын
+whyisthisnicknamebad That is 1/(x^6), I think you're mistaking the exponent -6 for a -4 x^(-6) * x = x^(-5)
But the way greatest videos I have watched it thank you again
Since C_1 is exp(C_0), doesn't that mean that C_1 cannot equal zero? Does that matter for the general solution? You can put C_2 as zero, and get the second solution, but not C_1 to get the exact first solution. Although, C_1 can be arbitrarily close to zero. I'm not sure if this breaks anything...
How do we solve using the formula if there is no P(x). I have a homework problem asking to solve y''+36y=0 by using the formula. I've read in other places that you cant use the formula in this case. I'm pulling my hair out trying to figure this out.
@taylorjaime8108
5 жыл бұрын
For equations completely missing y variables you can simply let y' = P and y" =P'. For equations completely missing x variables let y' = P and y"= P*P'. Sub these in and then it will be a First Order Diff Eq. Solve with whatever method works and then don't forget to sub in for P and then solve again.
Thanks a lot 🤝
How can you sure about that general solution will be "v" time of any particular solution when we know that two particular solution can't be linearly dependent???
@soumahakase7124
5 жыл бұрын
because "v" is a function of a "x" and not a constant.
Of course, It all make sense now! (atleast most of it..) - Thank you so much
what does second solution literally mean?
very clear explanation, I got B in my Calc class just because of you God bless
thank you sir I am very greatful,
Can you give a book with exercise like this with solutions step by steps please
why it's too long for this DE : xy''-y'+4.x^3.y=0 , x>0 y1 = sin(x^2) ???? please answer me !! and there are many DEs ,, I can't Remove/delete V with another V !
You're extremely helpful.
thanks dude really much appreciated .. i am in south africa but you turned into my lecture by just a click ..
hello there, Im having trouble in solving y'' - 4y' + 4y = 0 , y = e^ (2x) I have tried a number of times by following the example above but Im unable to solve this question. Please help.
@BasketOFmuffins
7 жыл бұрын
Yeah, i tried to solve it too. I get 2ve^(2x) = 0 and since there is no V' or V'' left in this equation i cannot do a w substitution so i don't know either.
@taylorjaime8108
5 жыл бұрын
For equations completely missing y variables you can simply let y' = P and y" =P'. For equations completely missing x variables let y' = P and y"= P*P'. Sub these in and then it will be a First Order Diff Eq. Solve with whatever method works and then don't forget to sub in for P and then solve again.
you set w = dv/dx ... doesnt that make w a function of v which itself is a funcion of x? thus using the chain rule when culculating the derivetives... when you say w' = v'' you just derive v as normal, not as if it was a function of x... What peice of the puzzle am i missing?
yeaaaaaaaa! austin / round rock are gonna merge into one megalopolis one day anyways.