Push-Pull Pair - Class B, Class AB and Class A operation

Ғылым және технология

In this video, Gregory explains the working principle behind push-pull pairs or complementary emitter follower stages. The differences between Class B, Class AB and Class A of operation are discussed, and a practical circuit is explained and develop for demonstration on the bench.
00:22 - Working principles
08:03 - Biasing for Class B operation
10:54 - Improvements by Class AB
14:26 - Current waveforms
15:55 - Condition for Class A operation
16:41 - Output impedance discontinuity in Class AB
20:38 - Bench circuit description
27:42 - Waveforms on the scope
33:09 - Ending
Push-pull stages are fundamental building blocks of electronics design and are present in all kinds of circuits, from high power, high fidelity and digital high speed.
Many operational amplifier use push-pull stages on the output to provide low impedance to drive real world loads. Many analog or digital signals need to be transmitted with matched impedance lines, and this kind of output stage provides the power gain necessary for signal transmission even between different signal domains.
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Пікірлер: 155

  • @AllElectronicsChannel
    @AllElectronicsChannel3 жыл бұрын

    Hey guys! Don't forget to subscribe to channel to help me grow it 😁 Support the channel being a Patron www.patreon.com/allelectronics

  • @muzate

    @muzate

    Жыл бұрын

    00

  • @donandmaudevandis5349
    @donandmaudevandis53493 жыл бұрын

    Probably the clearest explanation I've ever seen. Excellent presentation

  • @AllElectronicsChannel

    @AllElectronicsChannel

    3 жыл бұрын

    Thank you, man! 😄😄

  • @johnnyshinnichi1785
    @johnnyshinnichi1785Ай бұрын

    I have been watching youtube videos on electronics for years, but I have never seen anyone explain the operation of amplifiers as clearly as you. For the first time I actually understand how an audio amp works. Well done and thank you.

  • @AllElectronicsChannel

    @AllElectronicsChannel

    9 күн бұрын

    Glad you liked it!

  • @prydin
    @prydin5 ай бұрын

    I’ve seen this explained about a million times, but this video highlighted some subtleties that I never considered before. Well done!

  • @cpunter
    @cpunter3 жыл бұрын

    Excellent teaching! Where many videos explain too little and others over complicate things, your explanations are perfectly clear. Thanks very much!

  • @MrRadbadger
    @MrRadbadger2 жыл бұрын

    You're a natural teacher Gregory. Keep up the great work!

  • @creativetoday3826
    @creativetoday3826 Жыл бұрын

    I am sure that you are a treasure for me in the science of electronics, because no one can explain like you. The only obstacle is that I do not understand English, but thank God this video is translated into Arabic. I hope that all your videos will be like this. Thank you very much, creator of electronics. Thank you very much.

  • @isuckatthisgame
    @isuckatthisgame5 ай бұрын

    First time on your channel. I'm amazed by the amount of devices you've got here. Outstanding!

  • @AllElectronicsChannel

    @AllElectronicsChannel

    5 ай бұрын

    Thanks and welcome!

  • @souflikar6702
    @souflikar67023 жыл бұрын

    Very nice explanation and example. Well done!

  • @12345spidy
    @12345spidy3 жыл бұрын

    Beautifully explained! Thank you so much!

  • @rubenhidalgocarrillo
    @rubenhidalgocarrillo3 жыл бұрын

    Excelent. The most clear explanation I've ever seen about amplifiers

  • @egomezmx65
    @egomezmx652 жыл бұрын

    2 years latter, thanks for this very clear explanation, the best yet of a push-pull configuration

  • @AllElectronicsChannel

    @AllElectronicsChannel

    2 жыл бұрын

    Thank you Edgar! Welcome to the channel

  • @tabakoff700430
    @tabakoff7004303 жыл бұрын

    One of the best explanations ever - excellent for beginners!!!

  • @AllElectronicsChannel

    @AllElectronicsChannel

    3 жыл бұрын

    Thank you!!

  • @robertthompson5908
    @robertthompson59088 ай бұрын

    That was an excellent explanation and excellent demonstration.

  • @AllElectronicsChannel

    @AllElectronicsChannel

    8 ай бұрын

    Glad you enjoyed it!

  • @akashsardar495
    @akashsardar4953 жыл бұрын

    Thanks A Lot.This Is A Clear Explanation .

  • @manusudha4269
    @manusudha4269 Жыл бұрын

    Thank you for this precise lecture /presentation. You have a subscriber.

  • @kunalblack
    @kunalblack2 ай бұрын

    Excellent!!

  • @stevesfascinations1516
    @stevesfascinations15164 жыл бұрын

    Thank you Gregory, I think your English is quite good. Thank you for explaining the topic so well.

  • @AllElectronicsChannel

    @AllElectronicsChannel

    4 жыл бұрын

    Thank you !! I will be posting every week something new. Thanks for your support

  • @louisdesipio3343
    @louisdesipio3343 Жыл бұрын

    you can not disagree with your perfection! keep teaching !

  • @AllElectronicsChannel

    @AllElectronicsChannel

    Жыл бұрын

    Thanks! Welcome

  • @hubercats
    @hubercats2 жыл бұрын

    Excellent explanation of push-pull amplifiers. You would make an excellent electrical engineering professor. Thanks for sharing your expertise!

  • @AllElectronicsChannel

    @AllElectronicsChannel

    2 жыл бұрын

    Thank you!

  • @ReyciclismoMTB
    @ReyciclismoMTB Жыл бұрын

    No doubt the best explanation on the net. Most are too superficial, you do a great class, white board and then actual build and test. Keep at it, making videos is tough, subject matter tricky. Awesome work. Thanks

  • @AllElectronicsChannel

    @AllElectronicsChannel

    Жыл бұрын

    Thanks man!!

  • @garygranato9164
    @garygranato91649 ай бұрын

    this is the best push pull video , thank you

  • @AllElectronicsChannel

    @AllElectronicsChannel

    9 ай бұрын

    Glad you liked it!

  • @rafamuratt_
    @rafamuratt_Ай бұрын

    Perfect didactic, Greg! Thank you!!!

  • @AllElectronicsChannel

    @AllElectronicsChannel

    9 күн бұрын

    Thanks man!

  • @ruhnet
    @ruhnet2 жыл бұрын

    Superb explanation. Every word was valuable. Thank you so much for this!

  • @AllElectronicsChannel

    @AllElectronicsChannel

    2 жыл бұрын

    Thank you!!

  • @ruchitpatel8299
    @ruchitpatel82992 жыл бұрын

    Absolutely incredible video thank you so much!!

  • @AllElectronicsChannel

    @AllElectronicsChannel

    2 жыл бұрын

    Thank you! Welcome to the channel

  • @GianfrancoTronu
    @GianfrancoTronu2 жыл бұрын

    Beautiful video ! In addition to the technical content, I would add that your clear way of expressing yourself and your slow pronunciation is of vital importance to me, since I am Italian. Well done !

  • @AllElectronicsChannel

    @AllElectronicsChannel

    2 жыл бұрын

    Thank you!! Greetings from Brazil

  • @seanolsen0
    @seanolsen010 ай бұрын

    Great explanation!

  • @AllElectronicsChannel

    @AllElectronicsChannel

    10 ай бұрын

    Glad you think so!

  • @availablenowonwards
    @availablenowonwards2 жыл бұрын

    Excellent..!!

  • @enivaldopaiva6676
    @enivaldopaiva66762 жыл бұрын

    A melhor explicação! The best explanation!

  • @AllElectronicsChannel

    @AllElectronicsChannel

    2 жыл бұрын

    Thanks !!

  • @sergeypoltavtsev7148
    @sergeypoltavtsev71482 жыл бұрын

    Thank you man. Great explanation! 👍

  • @AllElectronicsChannel

    @AllElectronicsChannel

    2 жыл бұрын

    Thank you!

  • @cityoflights3808
    @cityoflights3808 Жыл бұрын

    This is so clear. Great explanation that I finally get what class AB bias vs class A nice 😊

  • @cityoflights3808

    @cityoflights3808

    Жыл бұрын

    Seriously, I am not an engineer or anything just like audio stuff and can do only do minor repair to vintage stuff with a 50/50 success rate. But this really allowed me to understand very basic concepts in a much more concrete way. Just the right amount of detail. I feel much more confident adjusting and checking bias on old equipment and understanding how to use a ‘scope for it. Now if I can only figure out why two resistors just went up in smoke on my old turntable…

  • @amitanaudiophile
    @amitanaudiophile2 жыл бұрын

    Most valuable information related to understanding operating of hi fi amplifier. Great upload,,thanks a lot sir...

  • @AllElectronicsChannel

    @AllElectronicsChannel

    2 жыл бұрын

    Thank you.

  • @rw80
    @rw80Ай бұрын

    I wish my teacher at university had explain it like this

  • @tiagomello
    @tiagomello Жыл бұрын

    Very good explanation. Congrats. Keep up the good work!

  • @AllElectronicsChannel

    @AllElectronicsChannel

    Жыл бұрын

    Thanks Tiago!

  • @tiagomello

    @tiagomello

    Жыл бұрын

    I like the way you built the prototypes. Could you go over some techniques for building circuits using one side copper boards (as a suggestion for a new video, if you haven’t done it already)? Thank you!

  • @p.v.jayaprakash4494
    @p.v.jayaprakash44944 ай бұрын

    Superb, good learning. Thanks

  • @AllElectronicsChannel

    @AllElectronicsChannel

    3 ай бұрын

    You are welcome!

  • @sabih1677
    @sabih16773 жыл бұрын

    Please keep doing such great videos, your explanation was way simple and clearer than that of my professor

  • @AllElectronicsChannel

    @AllElectronicsChannel

    3 жыл бұрын

    Thank you! What other topics would be interesting?

  • @sabih1677

    @sabih1677

    2 жыл бұрын

    @@AllElectronicsChannel How about AC analysis of a BJT and Mosfet?

  • @AllElectronicsChannel

    @AllElectronicsChannel

    2 жыл бұрын

    @@sabih1677 Really nice!! We will do it! Thanksss

  • @SenthilKumar-ht2op
    @SenthilKumar-ht2op2 жыл бұрын

    👋Hello Gregory I am from India you explained very great using oscilloscope this video will help the people who are interesting in designing of complimentary symmetry amplifier. Please upload one video of push pull amplifier using high voltage mosfet like IRF 150, IRF 250 And so on

  • @AlexanderPatrakov
    @AlexanderPatrakov Жыл бұрын

    It would be interesting to see (both theoretically and in practice) how such a push-pull pair operates given a load that includes reactive components. The reason is that it's the current which matters when deciding which transistor is open, but its phase is not the same as of the voltage.

  • @billmcdonald2436
    @billmcdonald24362 жыл бұрын

    Excellent explanation thank you

  • @AllElectronicsChannel

    @AllElectronicsChannel

    2 жыл бұрын

    Thanks!

  • @elihaviv7715
    @elihaviv77152 жыл бұрын

    great explanation, thanks

  • @AllElectronicsChannel

    @AllElectronicsChannel

    2 жыл бұрын

    Thanks!

  • @johnm4962
    @johnm496224 күн бұрын

    A video I understand clearly thank you.

  • @AllElectronicsChannel

    @AllElectronicsChannel

    9 күн бұрын

    You are welcome!

  • @sandunisulochana2304
    @sandunisulochana23043 жыл бұрын

    Thank u sir

  • @jesus_ur_my_love
    @jesus_ur_my_love8 ай бұрын

    Superb explanation bro❤😊

  • @AllElectronicsChannel

    @AllElectronicsChannel

    8 ай бұрын

    Thank you so much 🙂

  • @ronchinoy
    @ronchinoy7 ай бұрын

    More info on how to setup the scope for differential mode and why you used the mode and where you use it would help.

  • @LousyPainter
    @LousyPainter2 жыл бұрын

    Great job. Subbed and rang the bell. Thanks!

  • @AllElectronicsChannel

    @AllElectronicsChannel

    2 жыл бұрын

    Welcome to the channel!!

  • @velixzeen
    @velixzeen Жыл бұрын

    At 6'30''' the 0.3V output voltage will be split between the emitter R and the load if current is flowing, which it will be as the Q is on.

  • @anthonycalia1317
    @anthonycalia13175 ай бұрын

    well done!

  • @AllElectronicsChannel

    @AllElectronicsChannel

    5 ай бұрын

    Thanks!

  • @sam7901
    @sam7901 Жыл бұрын

    Beautiful explanation, couldn't we also use an opamp with feedback going from output to the inverting terminal and the signal coming into the non inverting terminal of the opamp

  • @scottbrady419
    @scottbrady4193 жыл бұрын

    Great video Gregory! How does one go about calculating the value to be used for the Emitter resistors when building out a push pull amplifier? You mentioned you used a 3.9 ohm for each transistor, but I'd like to know how you determined that please.

  • @AllElectronicsChannel

    @AllElectronicsChannel

    3 жыл бұрын

    Hello man! In the example I used 3.9 because it was what I had around. The resistance needs to be calculated based on the bias voltage and the bias current needed, and it needs to compensate the Vbe temperature coeficient.

  • @music3121
    @music31213 жыл бұрын

    Hello sir u r perfect teacher

  • @AllElectronicsChannel

    @AllElectronicsChannel

    3 жыл бұрын

    Thank you man!! Please show the channel to your friends to help me grow it!! 😀

  • @therfnoob7697
    @therfnoob76972 жыл бұрын

    This video is just fantastic! Had to watch it a few times to absorb all of it (and probably still missing some insights). I have one question. At @30:16, what are those little current spikes (red trace) when the signal enters in cross-over? They seem to remain there also when we move to AB class.

  • @AllElectronicsChannel

    @AllElectronicsChannel

    2 жыл бұрын

    Thank you!! Good question! It seems more like current spikes from the junctions capacitance, responding for the transients between the positive and negative cycle. Would be nice to investigate it more!

  • @skanderbenmrad946
    @skanderbenmrad946 Жыл бұрын

    good work !

  • @AllElectronicsChannel

    @AllElectronicsChannel

    Жыл бұрын

    Thanks!!

  • @danieltsalazar
    @danieltsalazar Жыл бұрын

    Thanks!

  • @AllElectronicsChannel

    @AllElectronicsChannel

    Жыл бұрын

    Welcome!

  • @user-ub5su9vj6d
    @user-ub5su9vj6d4 ай бұрын

    You are the BEST!!!! 😀😀😀👍👍👍🙏🙏🙏.Can you have some class talk about feedback circuits?

  • @elkercarvalho3795
    @elkercarvalho37952 жыл бұрын

    May I ask a question? At 24:11 you say that it'd have 0,7v across each resistor but the total voltage would be 1,2V. Why? Wouldn't it be 1,4v? And after when you consider the trimoot with 2k ohms, it is 0,7v , 1,4v and the results would be 2,3v? Why? Why not 2.1v?

  • @AllElectronicsChannel

    @AllElectronicsChannel

    2 жыл бұрын

    I think I got confused.. some times I use 0,7 and some times 0,6 as the base voltage

  • @jamesminor1202
    @jamesminor12023 жыл бұрын

    Each class of amplifier depend on bias voltage upon base on the same of amplifier circuit.

  • @hafizanikhsan2527
    @hafizanikhsan25272 жыл бұрын

    so interesting video. can u please teach me how to design amplifier push pull with 80W minima outgoing

  • @MakmotAcellam
    @MakmotAcellam2 ай бұрын

    Xselent teacher

  • @christiaanbezuidenhout1180
    @christiaanbezuidenhout11802 жыл бұрын

    Awesome explination thank you! I am just a little confused on how the biasing network works when you use a diode to achieve your biasing. Why does the transistor also recieve a 0.7V when the boasing diode has the same. Will you please be able to explain this in a beginner way showing the cutrent flow of this system. Thank you!!

  • @AllElectronicsChannel

    @AllElectronicsChannel

    2 жыл бұрын

    The diode is in parallel with the base !!

  • @omsingharjit
    @omsingharjit Жыл бұрын

    does rf Amplifier Use Class D Amp if yes than its circuit should be much faster than processing Frequency right ?

  • @Ma_X64
    @Ma_X648 ай бұрын

    What is the "chewing" of active device? Can't get it.

  • @kbruin79
    @kbruin793 жыл бұрын

    Excellent explanation Gregory! Thank you for sharing. Can you demonstrate the diode solution as a method of compensation instead of using a transistor?

  • @AllElectronicsChannel

    @AllElectronicsChannel

    3 жыл бұрын

    Hello, thank you! I don't have any video about it now. Basically using a diode to generate the DC offset will automatically compensate for the junction voltage to temperature relationship. You need to put the diode VERY close to the transistor (in the same heatsink and side by side) so any increase in temperature of the transistor will be coupled to the diode.

  • @ahmedalshalchi
    @ahmedalshalchi4 жыл бұрын

    Hi Gregory ... Thank you very much for going by English language in this channel and your explanation on Class A , B , AB was very clear to understand the topology of these classes... But I would to ask if you can rename your channel to have " ( ENGLISH ) " word so it will be much easier for viewers to know than your original Portuguese one , you may add a link to your original channel in the DESCRIPTION for Portuguese speakers if they may be here !.... Also, Can you please correct your LOCATION country in the ABOUT page to be BRAZIL than USA ?

  • @AllElectronicsChannel

    @AllElectronicsChannel

    4 жыл бұрын

    Hello! I`m retiring from the brazillian KZread as I had some legal problems and will focus only on English markets. This is now my main channel. Over time my english will improve. Thank you!

  • @ahmedalshalchi

    @ahmedalshalchi

    4 жыл бұрын

    Hi again ... Even with your planning to retire your Portuguese channel , you still have to rename your new channel with good name like to mark it as " ( ENGLISH ) " and specify the location as from BRAZIL as I could not find any other electronic material channel from Brazil at all except yours and WR Kits since 3-4 years of surfing all over the world of KZread ... Also , I forgot to say , please put all your communication contact links in the ABOUT page with the most priority of Website URL and Email address... Great thanks for improving your channel content....

  • @stefano.a
    @stefano.a2 жыл бұрын

    This is the best explanation I found. Thanks. I have two questions: 1) has the capacitors to be polarity dependent(electrolytic)? In such case, how we can connect the capacitor in series to the load?(is the positive pole on the load or between the two Re?) 2) are the two identical resistors in series with Vbe multiplier used to maintain reverse polarity of collector base of BJTs so that they are in active region? If so, how can we choose their values?

  • @AllElectronicsChannel

    @AllElectronicsChannel

    2 жыл бұрын

    1) for lower frequencies, probably you will use high value electrolytic capacitors. In this situation, you connect the positive side to the transistor bridge. 2) You can calculate as a voltage divider. The bottom resistor will always have constant 0,65V, so you calculate the upper one to get the desired output voltage.

  • @stefano.a

    @stefano.a

    2 жыл бұрын

    @@AllElectronicsChannel I tried the circuit. Re must be greater (10 Ohms) and transistors heats up too much after some time. With Re=3,9Ohms the transistors was damaged. I will try with bigger transistors

  • @jimmychua6529
    @jimmychua6529 Жыл бұрын

    How do I know the amplifier is class A, B, AB

  • @alv9619
    @alv96192 жыл бұрын

    One u have to consider about emitter resistors is u dont want to have voltage drop more than the reverse bias emitter base voltage

  • @AllElectronicsChannel

    @AllElectronicsChannel

    2 жыл бұрын

    True!

  • @Yorumcu63
    @Yorumcu632 жыл бұрын

    Nice Video.Could you make a video about noname toroid core's calculations values. I mean .Calculation of Al value to permability to other values and measuring effective working frequency and loses .Could you make this kind video?

  • @AllElectronicsChannel

    @AllElectronicsChannel

    2 жыл бұрын

    Thanks! I can try, core calculations always seems difficult for me also hahaha

  • @rickclink9196
    @rickclink91963 ай бұрын

    Excellent method of explanation.

  • @AllElectronicsChannel

    @AllElectronicsChannel

    3 ай бұрын

    Many thanks!

  • @gordthor5351
    @gordthor5351 Жыл бұрын

    So, theoretically it would be best (most thermally stable) to mount the biasing transistors on the same heatsink as the output transistors.

  • @AllElectronicsChannel

    @AllElectronicsChannel

    Жыл бұрын

    Yep!!

  • @SheikhN-bible-syndrome
    @SheikhN-bible-syndromeКүн бұрын

    But on the NPN why does the positive swing go through the emitter leg? Isn't that the negative leg of the npn and the collector is the positive leg?

  • @AllElectronicsChannel

    @AllElectronicsChannel

    11 сағат бұрын

    Read about emitter follower !

  • @hharannnathan7689
    @hharannnathan7689 Жыл бұрын

    does the push pull pair invert the input signal?

  • @AllElectronicsChannel

    @AllElectronicsChannel

    Жыл бұрын

    No!

  • @rukshanfdoable
    @rukshanfdoable3 жыл бұрын

    Do you know how to explain op ampe 741 in internal circuit transistors working by using wave forms like you explain this..more students are waiting..please if u can

  • @AllElectronicsChannel

    @AllElectronicsChannel

    3 жыл бұрын

    Nice one!! I will try to make a video about it

  • @omsingharjit
    @omsingharjit Жыл бұрын

    Now I understand this Amp from its root

  • @El650Jefe
    @El650Jefe2 жыл бұрын

    Can someone explain what a high and low impedance signal is?

  • @AllElectronicsChannel

    @AllElectronicsChannel

    2 жыл бұрын

    It is not a physical correct way o saying, but it helps to understand circuits. I call a high impedance signal, the one the comes from a high impedance source. These are signals "weak", represented by high voltages with low current capacity. Low impedance signals are signals "strong", the comes from low impedance sources.

  • @Enigma758
    @Enigma7582 жыл бұрын

    15:53, I am a little confused because I always thought that class A was a single NPN transistor (one active device) configured as an emitter follower, yet you are showing a two transistor configuration.

  • @AllElectronicsChannel

    @AllElectronicsChannel

    2 жыл бұрын

    Class A is any configuration wheres the transistor conduction isn't cut!! It is commonly shown with a single transistor, but it's not related to the topology!

  • @Enigma758

    @Enigma758

    2 жыл бұрын

    @@AllElectronicsChannel I didn't know that, I'll bet it's a common misconception. Thank you!

  • @toadroller

    @toadroller

    2 жыл бұрын

    @@Enigma758 It *is* a common misconception; that exact misconception led me to find this video! I read something about Class A push-pull and I thought "Wait. How can class A be push pull?" and here it is, explained. I believe what you and I previously understood is single-ended class A.

  • @Enigma758

    @Enigma758

    2 жыл бұрын

    @@toadroller Nice to know I'm not the only one who thought that. Thanks for your comment! :)

  • @Enigma758

    @Enigma758

    2 жыл бұрын

    @@AllElectronicsChannel Well then, "electronics-tutorials" must be incorrect then... "Class A Amplifiers are the most common type of amplifier topology as they use just one output switching transistor (Bipolar, FET, IGBT, etc) within their amplifier design. This single output transistor is biased around the Q-point within the middle of its load line and so is never driven into its cut-off or saturation regions thus allowing it to conduct current over the full 360 degrees of the input cycle. Then the output transistor of a class-A topology never turns “OFF” which is one of its main disadvantages."

  • @victimovtalent6036
    @victimovtalent6036 Жыл бұрын

    Look like store of instruments😯

  • @AllElectronicsChannel

    @AllElectronicsChannel

    Жыл бұрын

    Hahahahha

  • @lui5sous474
    @lui5sous474 Жыл бұрын

    are you Brazillian?

  • @AllElectronicsChannel

    @AllElectronicsChannel

    Жыл бұрын

    What?

  • @lui5sous474

    @lui5sous474

    Жыл бұрын

    @@AllElectronicsChannel you sounds like a brazillian

  • @makroradio6836
    @makroradio68362 жыл бұрын

    Transmitter am sw 2km +

  • @makroradio6836

    @makroradio6836

    2 жыл бұрын

    kzread.info/dash/bejne/dGl6krRqkcq6qJM.html

  • @pulenthirank.pulenthiran4485
    @pulenthirank.pulenthiran4485 Жыл бұрын

    Ic4580

  • @thanhnguyen-xi8fq
    @thanhnguyen-xi8fq2 жыл бұрын

    Why do you use 1Mhz signal? not 1Khz? Cheer

  • @AllElectronicsChannel

    @AllElectronicsChannel

    2 жыл бұрын

    We like to play with higher frequencies !

  • @islamicworld2277
    @islamicworld22772 жыл бұрын

    Your accent is so cute.

  • @AllElectronicsChannel

    @AllElectronicsChannel

    2 жыл бұрын

    😄😄😄

  • @soup4495
    @soup44957 ай бұрын

    damn bro save some silly scopes for the rest of us

  • @liberalesmatanceros
    @liberalesmatanceros8 ай бұрын

    crackk

  • @realchristopher4334
    @realchristopher43343 жыл бұрын

    I got mind-fucked! Only now I know what the heck 'distortion' and 'crossover' are in this context. I read and heard a lot about them but I do not think there is anyone else explaining them. Few of them even mention use small resistor as the bigger resistor is the more noise will be amplified. To a noob like me, it sounds magical not knowing how come resistor has noise. I am sure those 'tutorials' are meant for noobs, otherwise they will not be bothered with the babyish explanation.

  • @AllElectronicsChannel

    @AllElectronicsChannel

    3 жыл бұрын

    Thank you man!

  • @realchristopher4334

    @realchristopher4334

    3 жыл бұрын

    @@AllElectronicsChannel The pleasure is mine! By the way, Gregory, have you any video on how to choose the 'right' values of resistor? I was understood to always choose the smallest resistor to prevent internal noise (I guess it is inherent stray capacitance and inductance. Same story with capacitor, choose the smallest capacitance possible). But again, only one person (The AudioPhool. KZreadr) I found explaining how to calculate the values, sadly he goes too fast and only transistor that he uses as the example. I mean, I would like to know how to choose resistors for an operational amplifier as well because nowadays one small chip can do a lot more, saves much more space, and prevents so much more trouble than messing with discrete devices. About noise, integrated circuits these days have extremely low noise due to everything is in close proximity and internal resistors are microscopic.

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