Would you please solve hard and extremely hard questions, this question can be solve by a 4th grade student.

@Archeronus

2 жыл бұрын

Or solve them yourself you cannot do advanced stuff in 60 s

@RMF49

2 жыл бұрын

Here you go: N people wearing hats are in a room blindfolded. They all toss their hats into a pile. They form a line. Still blindfolded, the first person takes a random hat from the pile. Then the second. Then the third etc until everyone has a hat. On average what is the expected number of people who got their own hat?

@lerg_0

2 жыл бұрын

@@RMF49 1?

@RMF49

2 жыл бұрын

@@lerg_0 Correct. That was a trick question given to us in college when we were studying combinatorics. There is a temptation to try to apply combinatorics here buts it’s not applicable and just leads to more complexity. A much simpler observation solves the problem trivially.

@RMF49

2 жыл бұрын

@@lerg_0 Ok here’s another: A ball is released in a vacuum chamber on earth from a height of 16 feet. After its first bounce it rises to exactly 8 feet. It’s second bounce rises to 4 feet. It’s third bounce to 2 feet etc. Always EXACTLY half way up. For how long will the ball be bouncing?

The probability that the result is 5 is 1/6. An odd number is 3/6

@theonejosh

Жыл бұрын

5 is an odd number

@Stashkost

Жыл бұрын

@@theonejosh so if you role a dice you have a 50% possibility to be number 5? I don’t think so

@Kirstenzz

Жыл бұрын

EXACTLY

@R1ester

Жыл бұрын

​@@StashkostIt didn't ask for a separate answer it asked for both 5 and odd(which also have 5)

@dizzybarf

10 ай бұрын

@@Stashkost it’s asking for the probability of the die rolling on any of the 3 odd numbers it specifically mentions the number 5 to confuse you. A normal die has 6 sides 3 odd 3 even so the probability would be a 50/50

This is not two mutually exclusive events, so yes.

@Greviousness-kb8ld

2 ай бұрын

Nice to see someone who understands probability terminology

@VivianOkobiah

7 күн бұрын

​@@Greviousness-kb8ld yeah whatever

This isn’t even tricky, this is just a standard question about 1d6. Piss easy.

"An odd number" can be deconstructed into "1 or 3 or 5" so really the question is about the probability of it being "5 or 1 or 3 or 5" since "5 or 5" is just redundant the entire problem simplifies down to "any odd number"

@benwilliams3539

Ай бұрын

I was thinking that too, mentioning the 5 was redundant. I can only imagine it's to make the question confusing on purpose, add another thing to think about.

Answer is we dont know. We have not had the die declared fair, nor have we had the number of faces declared.

@baronbrummbar8691

3 ай бұрын

when not specified we have to assume a fair 6 sided die ...........

Man I thought we were rolling for initiative. Forget it I cast Magic missile. Thank you for help ing with my math

Actually there is more logic, if you already studied probaility you would see that: P(event A or event B)=P(A)+P(B)-P(A intersecting B). In other words: 3/6 (rolling odd number) +1/6 (rolling 5)-1/6 (rolling odd number and a 5) So basically if this way any other question he probably would have done this wrong

@thetsunamiisking

Жыл бұрын

!!! like!! i paused the video solved it before i watched it and in the end i’m like wtf! cause i did 1/6 (which is the probability of getting 5) + 3/6( 1/2 which is the probability of getting an odd number) = 2/3!

@froyocrew

9 ай бұрын

A union B, not intersection

@Me_encanta_el_ligma

8 ай бұрын

@@thetsunamiisking5 is an odd number! It specifically says five to confuse you!

@Hevach

6 ай бұрын

He wouldn't have done it wrong because he wasn't using probability in the way you describe. He was using a full traverse case test, applying the conditions to all possible outcomes and counting the results. So if it was "6 or odd" he would have circled 1, 3, 5 as odd and then 6, getting 2/3. This kind of test is not feasible for large data sets, but for things like dice rolls it's easy and very low error rate to simply test all possible outcomes rather than perform the proper statistical calculations.

@furiousbro4685

5 ай бұрын

Class 12th Probability chapter enters the chat 🤫🤫

Question cannot be solved because the task doesn't specify how many sides the die has.

The question is weird, 5 or an odd number?

@user-he7sc3fg3r

2 жыл бұрын

Yes its to throw u off. Somerimes someone might add 3 plus 1 as odd number making it 4/6

@Good-For-nothing-son

2 жыл бұрын

It's so that they can confuse you into thinking wrong answer

@Jgm101music

Жыл бұрын

It’s just the wording, expecting it to be hard

@FelipeValdez-og2tg

10 ай бұрын

@@Good-For-nothing-sonAlways works when they try confusing me lol

@angry_zergling

2 ай бұрын

@@user-he7sc3fg3r That's what I did =(

P(A)= To get number 5, P(B)=To get odd number, P(A intersecrion B)= 1/6(Number 5). Now, P(AUB) = 1/6+3/6-1/6= 1/2

@PatoChu

Ай бұрын

You just explained one of the easiest exercises I've seen in my life in the most complicated way possible lmao

My brain is hurting 😭

WOAHHHH NO WAYY!!!!

It’s like you were asking two different questions. The odd it is five is one in six. The odd that it is an odd number is one in two.

@chessandmathguy

2 жыл бұрын

"5 or an odd number" can also be phrased as just "an odd number." So it's 1/2. It's like saying "17 or larger than 2." Well that can be phrased as just "larger than 2."

bb thanks sir 🙏💯 ever best

Thank you so much more please

People, imagine this: When you roll a fair dice, what is the probability that the number you rolled is positive or less than 7? From your logic, the first event that is the number being positive, has a probability of 6/6, then the second event has the probability of 6/6 as well. Will you conclude the answer would then be 6/6 + 6/6 = 2? But we all know that probability ranges from 0 to 1, 2 is impossible.

@limweiheng4571

2 жыл бұрын

you must multiply the first probability by the 2nd probability, not addition. 6/6 x 6/6 = 36/36= 1

@user-cr4fc3nj3i

2 жыл бұрын

@@limweiheng4571 nah, addition is for the key word "or", multiplication is when the events are independent of each other. According to your logic tho, say the probability of rolling a fair dice and getting a negative number OR getting a positive number. The probability of getting negative is 0, while the one for positive is 6/6=1 But does that mean this probability is 0×1=0? Of course not! As we certainly can roll a dice and get a positive number, in fact the probability is 1 in this case. In particular, the following formula always holds: P(A or B) = P(A) + P(B) - P(A and B)

@TrevA102

2 жыл бұрын

the answer is 1/2

@robyglowing5238

Жыл бұрын

the answer to your paradoxes is, you cannot operate those two set by adding them, because its the same sets. in details : positif outcome {1,2,3,4,5,6} , and for less than 7 is {1,2,3,4,5,6}. it has the exact same member. so you cannot use the Adding rule for the probability for those both because they are the same sets.. hope this is cleared.

@bvssmouq6gamingofficialyt

4 ай бұрын

P(Favor 1)+P(Favor 2)-P(Favor 1&2) So the probability that it's less or equal to is 1. Probability that it's positive is 1. The probability that it's positive AND less than or equal to 7 is 1. 1+1-1=1

B option because 1, 3,5 are odd numbers so, possible outcome upon total outcomes possible

the question is wrongly formulated, please re-formulate it and then re-publish your video, it is so misleading and harmful

@Taylors_version133

Жыл бұрын

Yes

@coolskeletondude5902

2 ай бұрын

its not tho

🤩✨✨

And this is why you need to read the question. The answer is 2/3. 5 OR an odd number 1/6 + 3/6 = 4/6 = 2/3

@user-cr4fc3nj3i

2 жыл бұрын

Think about this: Say, A is "picking a number randomly from the set {1,2,3,4} which is not a multiple of 3", and B is "picking a number randomly from the set {1,2,3,4} which is an odd number". So that means P(A)=3/4, P(B)=1/2 What is the probability of A or B? According to your logic, the answer would be 3/4 + 1/2 = 5/4 > 1 Probabilities only range from 0 to 1, so having it being 5/4 is non-sense. You were smart to notice the "or", but not enough for noticing the formula P(A or B) = P(A) + P(B) *- P(A and B)*

@garys6135

2 жыл бұрын

@@user-cr4fc3nj3i I noticed, and couldn't be bothered deleting it. Clearly, I'm not that smart, and didn't read the question.

@banabconcept4625

2 жыл бұрын

Same answer am going with

@TrevA102

2 жыл бұрын

incorrect. the equation is P (A or B) = P(A) + P(B) - P(A and B) 1/2 is correct

@garys6135

2 жыл бұрын

@@TrevA102 or in simple dimple English, 5 is and odd number, and shouldn't be counted twice.

But it was never stated how many sides the die has?

@kraken_8

2 ай бұрын

Always assume it has 6 sides

@rustedsabre4699

2 ай бұрын

@@kraken_8 Never assume that. If you don't state the number of sides, then the answer is infinity. Math is meant to be as precise as possible. Blame the test maker for making a faulty question. Hopefully they can learn and make a better question next time. Education.

@kraken_8

2 ай бұрын

@@rustedsabre4699 actually there is not an infinite amount of die. Only 5 polyhedrons can exist in 3 dimensions. Also, you know this is a stupid question because the standard for dice is to have 6 sides, if it had more or less it would specify, I said to always assume 6 for your sake so you don’t ask this stupid question on the act/psat or whatever you take and get it wrong

@rustedsabre4699

2 ай бұрын

@@kraken_8 No, there is an infinite amount of sides you can add to a die. I know it's hard for you to understand that not all infinities are equal, it's something most people struggle with. For example, there are infinite prime numbers, and infinite odd numbers, but there are less infinite prime numbers than odd numbers. It's not a stupid question, the test maker screwed up if there are multiple answers, when there is only supposed to be one.

@kraken_8

2 ай бұрын

@@rustedsabre4699 No, only 5 regular polyhedrons can exist in 3 dimensions, you can look that up, what you can do, however, is combine different shapes to make a die but that is not a true polyhedron, so I can see how you were confused. I wouldn’t expect someone like you to understand 😊

You made a snowman.

I got a neat problem from a video game. So 5 ghosts have you trapped in a room with three doors. The game they play with you is 3 of them go into a wrong door and the other two may or may not be going into the right door they show you which three will be going into the wrong door. And all doors have to be entered so 2 of them go Into a door another two go Into a door and one enters alone. They scramble around but you cannot mentally handle keeping your eyes on three of them so instead you keep your eyes on just one of the neutral ghosts. Now let’s assume the ghosts are NOT tricking you and GIVE you A way out. The one you focused on will either enter a door by himself or with another ghost. If he walks in by himself your goochi. But if he walks in with one of his buddies hes either tricking you with a wrong one or he went in with his fellow neutral ghosts. If he does that and you counted the ghosts going into the other doors you immediately know it’s not the other one with 2 because there’s only one other neutral ghost and they gave you a way out. The question is does this become the monte hall problem where you have a 67% chance it’s the one where only one ghost entered or is it fifty fifty.

@FLINTMICHIGANMEGABOWL

Жыл бұрын

Neat

Who ever said it was a 6 sided die?

@carultch

2 ай бұрын

It's assumed to be a standard 6-sided die, with a fair probability distribution, unless otherwise specified.

You are smart

From where did you make the dice come From??

Zabardast

Correction after discussion below: Sorry for all confusions. I must have been drunk 😛 1/2 is the right answer. P(A or B) = P(A) + P(B) - P(A and B) P(A and B) = P(A)*P(B|A) = P(B)*P(A|B) There are two events OR means addition minus AND 3/6 + 1/6 - (3/6*1/3)= 4/6 - 1/6 = 1/2 AND means multiplication (3/6*1/3) = 1/6

@Sultan_Kenzo

2 жыл бұрын

That's what I thought too, I noticed that this guy doesnt always look at the details

@user-cr4fc3nj3i

2 жыл бұрын

Have a thought on this: Say, A is "picking a number randomly from the set {1,2,3,4} which is not a multiple of 3", and B is "picking a number randomly from the set {1,2,3,4} which is an odd number". So that means P(A)=3/4, P(B)=1/2 What is the probability of A or B? According to your logic, the answer would be 3/4 + 1/2 = 5/4 > 1 Probabilities only range from 0 to 1, so having it being 5/4 is non-sense. You were smart to notice the "or", but not enough for noticing the formula P(A or B) = P(A) + P(B) *- P(A and B)*

@navtiger007

2 жыл бұрын

@@user-cr4fc3nj3i yes, you are right the events are not mutually independent. 2/3 - 1/6 = 1/2

@TrevA102

2 жыл бұрын

incorrect the answer is 1/2

@FLINTMICHIGANMEGABOWL

Жыл бұрын

What are the odds I forget to wipe my butt on Tuesday but only if I eat some juicy pork chops the night before with a Mountain Dew? And what is the probability that I accidentally stole Liam Neesons pork chops and he eventually hunts me down and kills my pet hamster right it front of me? 😞 This scenario keeps me up at night. Haven’t had a solid 8 hours of sleep since 2015

Its 2/3 becuase the probablitity to roll 5 is 1/6, and an odd number, (including 5) is 1/2, then doing 1/6 + 1/2, you get 4/6 which can be simplified to 2/3

@velanginikumarvelagada5419

23 күн бұрын

Perfect brother

thank u

2 card are drawn from a fact of card with replacement.what is the P that the first card is diamond and the second is a clough (kamunggay)

@nicoleybalez

Жыл бұрын

Can you help me?

literally learned this in like 3rd grade

Bartan ❤️❤️❤️❤️❤️😊😊😊😊😊

Probability of 5= 1/6 Probability of odd numbers=1/2 Total prob=1/6+1/2 =2/3

@basedphilosopher

6 ай бұрын

The sets overlap. It's 1/2

@rohanbaste-bania6227

3 ай бұрын

This is the dumbest comment on all of KZread

@SBGamezSB

3 ай бұрын

Actually to find total prop you would multiply as it’s the possibility of getting a 5 AND an odd number. If it was OR, then you add. Or wait is it the other way around? 😅 either way you would multiply so the answer should be 1/12 But in this case the dice isn’t rolled twice and sets overlap so it’s 1/2

Can't beleive i am still studying this in 10th grade😂

I would have gotten stuck at 3/6 because the answer in that form isn’t there 💀

@Sleepingenthusiast

10 ай бұрын

3/6=1/2

@carultch

2 ай бұрын

You're supposed to reduce your fractions whenever you can.

5 OR an odd number, not 5 AND an odd number.

This question flouts Grice's maxims.

my logic says 1/3 cause we're choosing one out of 3 odd chances reason why it's the 4th time i'm repeating the proba test 😭💔

@silverseacow

Жыл бұрын

If we were only counting odd numbers, then 1/3 would be correct, be we are also including even numbers

@cyber5705

Жыл бұрын

@@silverseacow yeah right

Um isn't it just easier just to actually work it out bc i could work that is wayyyy faster than that weird method can

And this, kids, is why math can't handle natural language.

The question doesn't have enough info. You have to say "when throwing a *six-sided* die."

@griffinbrooks6748

2 жыл бұрын

Thats actually not true because if you add 7 and 8 it still stays 1/2 because evens and odds are every other number

@Nord1497

2 жыл бұрын

@@griffinbrooks6748 also not true because odd numbered dice exist so if you only add 7 the probability is different lol

@griffinbrooks6748

2 жыл бұрын

@@Nord1497 true... i thought about that but i couldnt thinik of a odd numbered die... but you are in fact correct :DD

@prafulyadav661

Жыл бұрын

Common sense

@trevora5568

5 ай бұрын

What numbers are on the sides? Could they be letters? P E D A N T

Letter B❤

Is this even a question ? If I’d get that in a exam I would assume it’s a scam and there is something hidden in the question

这是初一课程吗？

When throwing a die 😂😂

@NasirKhan-ek1us

2 ай бұрын

lol

@carultch

2 ай бұрын

Yes, die is the singular of dice.

Bruh just read it die and acted like it was dice ☠️

Im still working on the last problem: how much is 1 + 1. Anyone?

@WitherBox_

4 ай бұрын

4

@carultch

2 ай бұрын

1+1 = 10 As in, there are 10 types of people in this world. Those who understand binary, and those who don't.

Where do u get 6 from ☠️

@carultch

2 ай бұрын

It's a 6-sided die, with a uniform probability of each outcome. That's what you assume when given a problem with dice, unless otherwise specified.

B

What program are you using?

@princehalder6219

10 ай бұрын

ipad

@princehalder6219

10 ай бұрын

iOS helps you in that draw and drag feature

this is literally math for 2nd graders

@silverseacow

Жыл бұрын

IKR

@baronbrummbar8691

3 ай бұрын

2? i would say 3th graders - 2th graders doen´t usualy do devisions do they ?

But 5 is an odd number

@idlesquadron7283

2 ай бұрын

Yes? He does account that.

Too easy😂

Losing faith in humanity as we speak by looking at these comments

No

I fail prp

Incorrect

Funny, 5 is already odd.

@carultch

2 ай бұрын

Yeah, it's a trick question, because you think you have to combine probabilities. But really, one event is inclusive of all possibilities of the other event, so that piece of information is a red herring.

This is a false solution this 1/6 + 3/6 => 4/6 => 1/3

@daunderrated3106

Жыл бұрын

U fail division

Ez

Incorrect because of the OR function, only 1 and 3 count because 5 AND is an odd number, it is “this” OR “that” if it is both it doesn’t count Example you can buy an orange OR an apple at the store, you can’t buy an apple AND an orange at the store

@user-cr4fc3nj3i

Жыл бұрын

5 or odd number, the odd numbers are 1 AND 3 AND 5 so 5 or odd numbers are just simply the odd numbers which are 1 AND 3 AND 5

These questions are so dumb. No wonder the young generation sucks at math

@carultch

2 ай бұрын

Ok, you do better.

🎲 Dice ❌ die ✔️

@user-pr6bj6wn5d

5 ай бұрын

Pahlai khud spelling yaad kro😂😂😂😂

@carultch

2 ай бұрын

The singular of dice is die.

You’re all wrong. When he rolls the die, it either does or doesn’t land on one of the specified numbers. Therefore, the answer is 50/50 or 1/2. Everything has a probability of 1/2 because it either happens, or it doesn’t.

@user-cr4fc3nj3i

2 жыл бұрын

hope you are just joking but would you say the probability of 1+1=2 being true is 1/2? but we all know it is always true and will never "not happen"?

@largestbrain

2 жыл бұрын

The probability of you graduating from school is 0

@prafulyadav661

Жыл бұрын

Lmao

@pikabuu6315

Жыл бұрын

You are wrong, big brain alert. This question is unsolvable. We dont know how many sides the dice has. If its an even number then the probabilty is 1/2, if the dice is odd sided, then the probability becomes n+1/2n

Hi

Insufficient data. Number of sides not stipulated.

@YooperMapping

2 ай бұрын

You're right, the question definitely meant a 268-sided die

One is neither odd or even according to my math teacher

@labscience8271

Жыл бұрын

1 is odd 100% (You can't divide it by two completely). I think your teacher meant 0 not 1. Even then 0 is proven to be even.

@prafulyadav661

Жыл бұрын

I think ur confusing zero with one

"When throwing a die" So one roll of the die. "5 OR an odd number" You can see why so many get the answer wrong, including the questioner, regardless of written answers. So chance is 1 in 6 of rolling a five. Chance is 3 in 6 (or 0.5) of rolling an odd number. So, as you are probably aware, the question is incorrect. The correct answer is "D) AND B) respectively"

.

His solution is wrong. Correct answer is 2/3. There are two events, 5 or odd number

@TrevA102

2 жыл бұрын

no 1,3,5 are only posssibilties out of 6

@namski2410

2 жыл бұрын

@@TrevA102 No, you are failing to recognise that the question is asking about the probability of two events, i.e. getting an odd number and getting 5. In fact, my first answer is even wrong as I had thought the events are mutually exclusive which they aren’t. They correct way of describing the events is as ‘inclusive events’ and the formula is P(X or Y) = P(X) + P(Y) - P(X and Y). P(X) = P(odd#) = 3/6 = 1/2 P(Y) = P(5) = 1/6 P(X and Y) = P(X) x P(Y) = 1/2 x 1/6 = 1/12 Subbing in the inclusive formula gives: 1/2 + 1/6 -1/12 = (6+2-1)/12 = 7/12 This is the correct answer to the question. As it is not in the answer choices, I am thinking the question may not be what the examiner wants to ask

@HonestGiant

2 жыл бұрын

@@namski2410 so if i tell you to throw the dice and if it lands on 5 or odd you get an iphone from me. The chances of you winning an iphone is 66.6%?

@namski2410

2 жыл бұрын

@@HonestGiant why not give your answer instead of asking more questions

@TrevA102

2 жыл бұрын

@@namski2410 the probably of an “or” event is determined by: P(A) + P(B) - P(A and B) 1/2(odd numbers) + 1/6(#5) - 1/6 you were correct up until the point of saying P(X and Y) is 1/12. what is the probability of getting an odd number AND a 5. there are 6 possibilities and 1 contains an asset so P(X and Y) = 1/6

Assalamualaikum respectful sir I invite you to accept Islam so that you can success in this world and hereafter.

Incorrect. There are two events, also the first event exist in the second event, so you need to subtract that part. 1/6+3/6-(1/6)(3/6)=7/12

@chessandmathguy

2 жыл бұрын

"5 or an odd number" can also be phrased as just "an odd number." So it's 1/2. It's like saying "17 or larger than 2." Well that can be phrased as just "larger than 2."

@largestbrain

2 жыл бұрын

Why would you count rolling a 5 and rolling a 5 as separate permutations…

@Sleepingenthusiast

10 ай бұрын

Bro pulled 7/12 out of his asshole

Adults over 40 like " WTF SLOW DOWN " 😂😩

Throwing a DIE

You are wrong 2 is sn odd number

@largestbrain

2 жыл бұрын

No, 2 is even. You’re thinking of prime numbers, because 2 is prime

@Mironabcde

2 жыл бұрын

@@largestbrain you are right sorry

Misleading ..... 2 questions and your answer is only correct for 1 of them 👎👎👎👎👎👎👎

@baronbrummbar8691

3 ай бұрын

it is 1 question dumbo the point of it is to recognize that 5 is odd and the result is 1/2

@idlesquadron7283

2 ай бұрын

Nope this is one question. 5 OR odd.

Why is tht in the SAT haha Thts 5th grade

@TrevA102

2 жыл бұрын

it’s not on the SAT?

@prafulyadav661

Жыл бұрын

@@TrevA102 yeah it's too hard for SATs

It’s 2/3 lol

@handel136

11 ай бұрын

Can't be The problem is the question But answer is 1/2 Becoz There are only three possible outcomes That is, {1,3,5} Notice that 5 is odd Now therefore 3/6=1/2

@itspanda112

11 ай бұрын

⁠​⁠​⁠​⁠@@handel136your right sorry I was a little dumber back then but I can see that it’s 1/2 because of the 5,1,3 which makes it 3/6 and you reduce to 1/2 you get the gist. If I’m being honest I don’t even know how I got that answer lol 😅

@itspanda112

11 ай бұрын

Wait a second I think I was joking 2 months ago now that I think about it 😭

2 is also odd

YOUR ANSWER IS WRONG! Explanation: it said an odd number OR 5, therefore it can’t be an odd number AND 5. The formula for this is P(A) + P(B) - P(A&B). P meaning probability, and A and B being the events. Therefore our answer is 2/3.

@carultch

2 ай бұрын

OR doesn't mean exclusive OR, unless otherwise specified. By default, the term OR is always inclusive of the possibility of both events occurring. Suppose I ask you whether the following statement is true: "Your computer is using electricity, or it is raining." If the first half of that statement is true, we don't care if it is raining. It is a true statement, regardless of the weather.