Pigeonhole Principle (2 of 2: Generalising the cases)

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Пікірлер: 22

  • @montreadormontrez9378
    @montreadormontrez937811 ай бұрын

    I wish you taught me mathematics at high school. All my teachers failed to show the beauty of mathematics and do so in a way that was engaging.

  • @quentin2578
    @quentin25786 ай бұрын

    11:35 is also a crucial realization, that often in these types of problems with a random number of people, 15 in this case, it is a redundant piece of information; a red herring fallacy. That information is distracting from the relevant piece of information. The next time I will tackle such a problem I can try and simplify the case as we did in this video for 3-4 people. A great insight.

  • @JoelDave-wg3gn
    @JoelDave-wg3gn11 ай бұрын

    oh God! what wonderful man we have been given

  • @dakshajasingh2529
    @dakshajasingh252911 ай бұрын

    wow really needed this

  • @rafalszota1240
    @rafalszota124011 ай бұрын

    very nice explained

  • @isws
    @isws11 ай бұрын

    that was such o godd video! keep on making logic-related lessons

  • @emileventer

    @emileventer

    4 ай бұрын

    Google thinks it has had an handle on i 0:16 nfinity, but it does'nt whatsoever. Google and their communist overlords want us 2 suffer a similar fate as they wished upon their own somewhere in Siberia

  • @emileventer

    @emileventer

    4 ай бұрын

    Russia could never offer you a milkshake of any kind. They had bomba nuclear weapons 4 u Instead. People of the Rus has nil value 2 offer anyone else.

  • @wanfuse
    @wanfuse8 ай бұрын

    Pigeon hole principle is right, but it has its limits, for instance it’s application as far as temporal considerations, and locality :-)

  • @dakshajasingh2529
    @dakshajasingh252911 ай бұрын

    thanks

  • @emileventer
    @emileventer4 ай бұрын

    Hey, infinity = nil, which is number without value. Dividing 1 by zero produces a not a number result

  • @mattshatt7386
    @mattshatt73866 ай бұрын

    Case 2 can have 0, 1 or 2 handshakes, so the number of possible handshakes is still n - 1, not sure why Eddie said n - 2. I think he might have meant the maximum.

  • @RogueLawyer666
    @RogueLawyer66611 ай бұрын

    Can you have a session to explain why a negative number with an exponent that is not a whole number, gives an error?

  • @Nino-eo8ey

    @Nino-eo8ey

    9 ай бұрын

    I could somewhat explain that thought. If we have a real number K, taking K^(1/2) is the same as taking the square root of K, I know that this is pretty wild, but there exist a lot of simple proofs if you search on KZread. Assume K = -1, if we take K^(1/2) this basically means the -1^(1/2) OR the square root of -1. Taking the square root of a negative number obviously doesn't give you a REAL number, therefore your calculator gives an error. (Note: if your calculator does include complex numbers, then the calculator won't error, but you won't get a REAL number, you'll get something like 4i)

  • @YXiao
    @YXiao7 ай бұрын

    The more I hear about the Pigeonhole Principle the more I think it's an unnecessarily unrelatable metaphor of something that's more straightforward than it sounds.... 😅

  • @emileventer

    @emileventer

    4 ай бұрын

    Google et al boxes you. Afterwards, they sell your info to bad actors.

  • @emileventer

    @emileventer

    4 ай бұрын

    Next they want to verify your banking detaiks

  • @emileventer

    @emileventer

    4 ай бұрын

    Nighilists like the russian people always look 4 loopholes 2 break euro society. Or African society. Russians will never break chinese wall people

  • @emileventer

    @emileventer

    4 ай бұрын

    Or Afrikaners. We know their suffering, since 1799.

  • @emileventer

    @emileventer

    4 ай бұрын

    China Wall can be broken by Afrikaner Mense.

  • @emileventer
    @emileventer4 ай бұрын

    How many times do i have 2 say communists are bad humans

  • @rodicabrudea923
    @rodicabrudea92311 ай бұрын

    wrong. they could all shake hands with one another, in which case there would be 3 handshakes for everyone. but maybe I am not understanding the question correctly. what I mean is the minimum must not necessarily be 1.