🔥P&C for GATE || GATE 2025 APTITUDE || 5 Hrs Marathon || PrepFusion || Himanshu Agarwal

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Пікірлер: 29

  • @kartikeyaphale7553
    @kartikeyaphale755325 күн бұрын

    good lect, appreciate your efforts. Being an VLSI engineer still making time and teaching students requires efforts.

  • @crystalclear8395

    @crystalclear8395

    24 күн бұрын

    yes himanshu bro has gigantic amount of energy

  • @unCox_WbyL
    @unCox_WbyL23 күн бұрын

    Great intuition, was able to solve most of them effortlessly after the basics.

  • @stalin792
    @stalin79223 күн бұрын

    @2:50:19 all should be identical why can't we use 4! For I's

  • @thumulaneeraj8504
    @thumulaneeraj850422 күн бұрын

    Thank you so much sir.. ❤ Perfect lecture sir..

  • @abhinavawasthi7818
    @abhinavawasthi781823 күн бұрын

    bhaiya pls keep it for somedays, my sem exams are going on i m willing to but unable to complete it

  • @sureshkini6360
    @sureshkini636027 күн бұрын

    👍

  • @ramadasugude2954
    @ramadasugude295422 күн бұрын

    Probability lectures needed

  • @varshanagarajan4529
    @varshanagarajan452920 күн бұрын

    @1:36:48, you mention that DR Ram will now choose to see 9 people out of the 12 people. But after 3 people leave, only 9 will be left. So will the approach not be same as the first part of the question ?

  • @stalin792
    @stalin79223 күн бұрын

    Sir pls don't put private give some time to digest the concept

  • @stalin792
    @stalin79210 күн бұрын

    Sir please don't put black background it's straining 😢

  • @stalin792
    @stalin79223 күн бұрын

    For 1st question @2:35:30 here AAII needs to be mentioned whether they are stick together or it may be possible to permutations (AIIA)

  • @HimanshuAgarwal_

    @HimanshuAgarwal_

    23 күн бұрын

    You just need to select, not to arrange.( read the question) You are selecting 2A and 2I, now you can select in any order. AAII = AIAI = AIIA and so on..

  • @sureshkini6360
    @sureshkini636026 күн бұрын

    39:36 Why it cant be 6 x 8 x 9 x 5 ?

  • @HimanshuAgarwal_

    @HimanshuAgarwal_

    26 күн бұрын

    You cannot start from the last

  • @HimanshuAgarwal_

    @HimanshuAgarwal_

    26 күн бұрын

    Because the begining number is having a condition (not to put zero)

  • @sureshkini6360

    @sureshkini6360

    26 күн бұрын

    ​@@HimanshuAgarwal_ OHK

  • @sureshkini6360
    @sureshkini636023 күн бұрын

    Extend pls

  • @__Gowtham
    @__Gowtham26 күн бұрын

    Bro can i expect any other topic in aptitude like this video.

  • @PrepFusion_GATE

    @PrepFusion_GATE

    26 күн бұрын

    Write down the topic names. I will try to provide

  • @__Gowtham

    @__Gowtham

    26 күн бұрын

    @@PrepFusion_GATE . Geometry is enough bro

  • @PrepFusion_GATE

    @PrepFusion_GATE

    26 күн бұрын

    @@__Gowtham mensuration, right?

  • @__Gowtham

    @__Gowtham

    26 күн бұрын

    @@PrepFusion_GATE yes bro, actually I was unaware which is more important. With ur experience which one would u suggest.

  • @PrepFusion_GATE

    @PrepFusion_GATE

    26 күн бұрын

    ​@@__Gowtham To be honest, Solving Gate PYQs from 2017-2024 + P&C + Number Systems + Basic School Level Mathematics + Basic concepts of mensuration + Basics of Clocks and Calendar is more than enough for GATE Aptitude.

  • @thumulaneeraj8504
    @thumulaneeraj850422 күн бұрын

    Sir, at 4:15:45 ... In gate 2024 question ... Can we write 4! ÷ 2! =12 ans Explanation: I was assuming two twins as 1 ( because no need of permuting of those two ) and assuming E1 and E2 are empty spaces .... So arranging 5 items in 5 circular positions will be 4!.. ( E1 and E2 as 4th and 5th item ) as E1 and E2 are same I will divide it by 2! Finally, 4!/2! = 12 Answer Sir, Is this right way of solving..

  • @PrepFusion_GATE

    @PrepFusion_GATE

    22 күн бұрын

    How 5 items? Didn't get your explanation. Btw, thanks for putting your approach.

  • @thumulaneeraj8504

    @thumulaneeraj8504

    22 күн бұрын

    @@PrepFusion_GATE 1st item - twins 1 ( both ) 2nd item - twins 2 ( both) 3rd item - twins 3 ( both ) I am considering 2 twins as 1 item as there is no need of permuting because they were indistinguishable twins 4th item - empty 1 5th item - empty 2 I am assuming 2 remaining spaces filled by empty 1 and empty 2.. So, the no of circular positions will also be reduced to 5 as I was considering 2 twins as 1 item... In that way, 5 item to be placed in 5 places... which is 4! Empty 1 and empty 2 are same ... Divide by 2! Result 4!/2! = 12