The timestamps for the different topics covered in the video. 0:20 What is CMRR and what is the importance of CMRR. 4:58 Example

@damnjuliet

Ай бұрын

good explanation. thanks

I have seen many tutors chanting CMMR like a parrot, but here I got the applicability of the term in a vivid voice. Thanks for your efforts.

@nayil100

2 жыл бұрын

Seriously!! Professors kept chanting even before even introducing CMRR.

Best explanation of CMMR on the internet! Thank you! Subscribed :)

Best Channel for OP-AMPS tutorials! thank you

This series is the best explanation of op amp on the internet!Thank you sir for making this.

Made it so easy for self learning, thanks buddy!

after nptel/mit ocw/behzad razavi i found your lectures most clear and to the point.i am watching this because some topics were not covered in those lecture series....really loved your teaching...wish you a very very good fortune

A very good explanation of CMRR.

It's great, better explained than in my school.

Totally understand CMRR after watching the video. Thank you.

Yall should be grateful, dont see what all the complaining is for....Thanks ALL ABOUT ELECTRONICS ....you remind me of another teacher we have on here by the name Neso

@rishavsinha3376

5 жыл бұрын

They are the same I guess

@thisissharief7651

5 жыл бұрын

another student of neso academy

@balapranav7096

3 жыл бұрын

From there :)

I came here to cram, and i understand it all the better, appreciate the work !

Excellent video. Very good delivery of speech.

Thanks a lot for explaining such a confusing topic in this short video 🙏

thank you very much! You helped me a lot.

Thank you for your lectures ....ur all the lectures are very good clearing all the concepts and doubts....PLZZ create a quiz of some doubtful questions at the end so it become easier for us to clear our doubts more easily.....

Amazing style of teaching sir.....

Hai sir I m from visakhapatnam Today itself i watched ur videos Very clear and understanding manner

All videos are very good Awsome explaination on youtube

Sir you are going great excellent videos

Nice explanation sir. From Africa Ethiopia

Thank you very much sir very good explanation love from kerala

I like your video very much. It's really great. I'll keep an eye on your channel. I am your fan and I will support you.

Very helpful, thank you!

Thanks a lot sir ,i was struggling to understand cmrr

Very well explained 👍🏻

Amazing thing is that these stuffs are totally free!!

@sanjujohnson5523

4 жыл бұрын

Remember.. If you are not paying for the product,then you are the product.

You are the best! Thanks!

The best explanation!

Awesome!!

Thank you very much

well explained

Thanks for the applied problem. But please correct formula at arround 7:50. Acm = (1/Ad) * 10^(90dB/20)

@h2tchannel549

3 жыл бұрын

not understand.. why?

Thank you!

Nice Sir Thanks A lot Sir

Sir make some detailed video on sensors and how it is used in IC engine for daily uses like in car etc

THANKS BROTHER...

Good one

i think this guys explains best but don't tell us 100% of any part and thinks we know it already but we don't

absolute god

which software is this you use to draw the circuits?

Best sir 👏👏

Thank you sir

Sir at 9:18 you said that as the frequency increases the ability to suppress the common mode signal will also decrease. But sir as the freq increases then the common mode gain also decreases so the common mode signal would be attenuated more at higher freq just as the differential input signal. So how the ability decreases?

How we can say CMRR Depend on frequency??

The setup box we use .Is a opamp?

Excellent!!

@3.06 Why the term Acm*Vcm is included when we apply differential voltage instead of common mode voltage?

@noweare1

5 жыл бұрын

Because Common mode signal is always present.

Thank you

that means since we try to reduse commen mode signal is it not a sinal that is not be provided by us

Sir, could you please reply, how to calculate (formula) the Common mode gain, if CMRR is not given in a Numerical where all other parameters are same as you explained in above example....

@khamandhoklaa

Жыл бұрын

I think it you can find out cmrr in data sheet of that particular IC

Nice

Sir make some video on VLSI,MICROPROCESSOR AND RESISTORS

awesome

CORRECTION :- If input frequency increases then CMRR decreases. You have mentioned incorrectly. Kindly update if I am wrong.

Great!

Nice explanation thank you!!

Please confirm , * so basically common mode gain depends on the open/closed loop gain through CMRR .. ie A_cm it's not a fixed value * CMRR is calculated at what frequency ? in specs sheet in the begining of the video no frequency is mentioned.

10 ^ 4.5 where did it come from??

@AnuragKumar-lv3ul

3 жыл бұрын

I have the same problem

@sonnyasu

3 жыл бұрын

90=20log->. Log(ad/acm)=90/20=4.5->10^4.5

sir why the common mode input appers at input terminalds

Great...

Sir,if we interchange the pins of op-amp ic pin-2 (inverting terminal) and pin-3 (non-inverting terminal),then what will be happen?

@ALLABOUTELECTRONICS

4 жыл бұрын

I didn't get it. You mean the external connections ??

is coomen mode signal is only for differntial amplifers

it will be even more helpful if by drawing given input and outputs.

What if noise signal frequency is same as that of information signal in that case how lpf differentiate noise and information signal

@ALLABOUTELECTRONICS

6 жыл бұрын

If information signal and noise signal frequency are same then, of course, LPF will not be able to differentiate between the two signal. But usually, the output signals from the sensors are not very high-frequency signals. And at those frequencies, differential amplifier adequately suppresses the common mode noise signals. (In the case when noise signal frequency is same as signal frequency). But still by chance in your application, if information signal and the noise signal are high-frequency signals, in that case, you need select op-amp which has high CMRR at that operating frequency. I hope it will clear your doubt.

The information is there, buts whats with "THE" ?

sir why we try to reduse cm output voltage

sir is common mode gain is somthing associated with op amp

is common mode input apper becouse of noise signals

In numerical calculation of gains ,Is sign of voltage considered?

@ALLABOUTELECTRONICS

6 жыл бұрын

No, no need to consider the sign of the voltage. Because the gain defines the ratio of output voltage to the input voltage in absolute terms and it is independent of the sign of the voltage. Gain = | Vout/Vin| But suppose if the output voltage is inverted with respect to the input voltage (in case of inverting Op-amp) then we can say that there is a 180-degree phase shift between the output and the input. E.g in case of inverting op-amp, if the input is 1V and output is -5V, then we can say that the gain of the op-amp is 5, and there is a 180-degree phase shift between the output and the input. I hope it will clear your doubt.

At 7:37 how he wrote 10^4.5, Anyone please explain

@ALLABOUTELECTRONICS

3 жыл бұрын

90 = 20 log (Ad/Acm). That means 4.5 = log (Ad/Acm) Here the base of the log is 10. Hence, 10^4.5 = Ad/Acm. I hope, it will clear your doubt.

Sir ,may i know,what is the reason behind the amplification of common mode signal,why op-amp can't suppress that even if their difference is zero?

@ALLABOUTELECTRONICS

2 жыл бұрын

For more info, please check my couple of videos on BJT - Differential amplifier. I have explained it using the small-signal analysis. Once you will go through it, it will get clear to you. The basic reason is, the first stage of the op-amp is differential pair. Since the pair is not ideal, we have amplification of common-mode signal.

Sir, in the decibal scale op amp gain is given by A -> 10log(A). Then the CMRR should also be given as 10log(Ad/Acm). Please clarify my doubt

@ALLABOUTELECTRONICS

4 жыл бұрын

The voltage gain of the op-amp is defined as 20 log (A). When we are representing the power gain in dB then it is defined as 10 log (Ap). For more info please go through this video: kzread.info/dash/bejne/ppVl1beNma20m7w.html

HELLO SIR can you make one video for PSRR (power supply rejection ratio) of OP-AMP

@prajaktaramteke2025

3 жыл бұрын

I too need the same

Sir, at 6:11,i personally think that there should be a '---' in the front of the R2/R1.

@ALLABOUTELECTRONICS

5 жыл бұрын

It would be there if it is written as R2/R1 (V1- V2) But its (V2 -V1). So, the negative sign is already considered. I hope it will clear your doubt.

@martingu2033

5 жыл бұрын

@@ALLABOUTELECTRONICS But actually i think the Vinput is defined by the difference between non-inverting terminal and inverting terminal, so it should just be (V2--V1), if together with '--', it turns out to (V1--V2).

@ALLABOUTELECTRONICS

5 жыл бұрын

If you closely observe the input at the non-inverting is V2.

What is common mode source in fact?please

The entire video is a rhetorical question

Sir what will be the next videos on this opamp??

@ALLABOUTELECTRONICS

6 жыл бұрын

I will let you know very soon.

@ALLABOUTELECTRONICS

6 жыл бұрын

Next couple of videos will be on DC offsets/ DC imperfections (input offset voltage, input bias current etc.) in op-amp.

@prabhakardas4261

6 жыл бұрын

ALL ABOUT ELECTRONICS thanks for this notification.... By the way sir, can you say about the completion of the opamp course, how many lectures still left? This would aid in my preparation.

Don't throw the wards in 100 100 velocity

In the numerical the output voltage should be -50mv as it is a inverting amplifier .... Please clarify my doubt sir Thank you

@ALLABOUTELECTRONICS

2 жыл бұрын

First of all, the op-amp is used as a differential amplifier. The output would be -50 mV, if the differetial input V1 - V2 is 5mV. Here, we have assumed that the V2 - V1 is the differential input. And hence, the output is positive. I hope, it will clear your doubt.

Bro suggest me book name to study electronics

@ALLABOUTELECTRONICS

4 жыл бұрын

You can start with Electronic Principles by Albert Malvino

I have a question can u solve it please....

Subtitles covering most of the equations written.

@ALLABOUTELECTRONICS

7 ай бұрын

You can turn it off manually in the video settings.

where is above the head button

Please describe it more details

why Ad/Acm = 10^4.5 ?

@eleanorrigby226

6 жыл бұрын

oh no it's okay..got it hahaa

@ALLABOUTELECTRONICS

6 жыл бұрын

90/20= 4.5 and if you take the antilog then it will be 10^4.5. I hope it will clear your doubt.

@jamesacosta6090

3 жыл бұрын

@@ALLABOUTELECTRONICS the anti log of what.. how? im very confused w this .... u have an unknown inside the log.. not sure how to do this

@jamesacosta6090

3 жыл бұрын

i just remember how its done. I was confused with the 10, and it obviously comes from the log base 10.. thanx for the videos!!

Why we use 20 log here

@-dazz-

5 жыл бұрын

I believe it's because the formula refers to voltage gain. If it was power gain it would be 10 log.

it is 0.063 microvolts, not 0.63microvolts in the end

@ALLABOUTELECTRONICS

2 ай бұрын

It will be 0.63 uV. Please check it again, you will get it .

Why we want to compress the common signal

@ALLABOUTELECTRONICS

4 жыл бұрын

The noise, for example, is a common-mode signal. Because it is present at both terminal. And to improve the signal to noise ratio, it is required to remove or compress this common-mode signal.

bro please make bjt tutorials using pspice

@ALLABOUTELECTRONICS

4 жыл бұрын

I will include the simulation in the upcoming videos.

Please upload video to technics of increasing cmrr

Sir at 6:10 vo negative or not I mean it's input applied In inverting input plz sir reply

@ALLABOUTELECTRONICS

4 жыл бұрын

As I mentioned the overall output voltage is R2 / R1 * (V2 - V1) If V2 > V1 then Vo will be positive else it will be negative.

@leophysics

4 жыл бұрын

@@ALLABOUTELECTRONICS thanks

Maja aagya

i think i have not learnt at undergrade but now get the clear idea ..thanks. can u provide the pdf file or slide of this videoes

@noweare1

5 жыл бұрын

I am hearing that more and more. You are lucky to have you tube and the internet. When I graduated there was no internet, and no youtube. It was more of a struggle to learn.

Can you replace my lecturer at uni?

how do we know the Vid from the Vn?

we know, CMRR=(change in input)/output here you have used CMRR is 90db,,, it is wrong... here it must be CMR is 90db...

thoda dhire samjhaya kijie ....and important chij repeat kiya kro...

2:58 Dec

what language is this? It says English but the person isn't speaking English

@Zireael1706

2 жыл бұрын

bruh, it is english lmao. what are you on?

@captdeadpool2279

9 ай бұрын

You should be thanking him for not speaking in his mother tongue you ingrate