Let's change the variable name from x to t to avoid naming collisions. f(2t-3)=4t-2 y=f(x) x=2t-3 y=4t-2 2x=4t-6 4t=2x+6 y=2x+6-2=2x+4 y=f(x) =2x+4

@DrWangUSA

6 ай бұрын

Nice work and thanks for sharing

Or let f (x)=ax+b then f(2x--3)=a(2x--3)+b=4x--2 2ax--3a+b=4x--2 then 2a=4 and 3a+b=2 a=2 & b=4 f ((x)=2x+4...

@DrWangUSA

Жыл бұрын

nice work

@mr.cracker9317

Ай бұрын

Great 👍, But My question is why we let f(x) = ax + b please explain sir, I really need understand....

f(2x-3)=4x-2 let 2x-3=t 2x=t+3 4x=2t+6 4x-2=2t+4 f(t)=2t+4 f(x)=2x+4

@DrWangUSA

Жыл бұрын

nice work

What an interesting problem!

@DrWangUSA

2 жыл бұрын

thanks

Thanks

@DrWangUSA

2 жыл бұрын

Welcome

Thanks sir but it easy,.... in my mind

@DrWangUSA

2 жыл бұрын

Always welcome. We have some middle school viewers for my channel.

I did Method 2, just like Dr. Wang.

@DrWangUSA

Жыл бұрын

nice work

What kind of olympiad question is this easy

@DrWangUSA

11 ай бұрын

middle school level

@KookyPiranha

11 ай бұрын

@@DrWangUSA yeah maybe. What grade tho. Still it seems too easy even for middle schoolers. This isnt about the level of difficulty, it's more so about whether youve learnt the mathematical concept.

Thnku

@SuperYoonHo

2 жыл бұрын

sorry wrong person hello again

@DrWangUSA

Жыл бұрын

welcome

Thanks a lot sir Wang

@DrWangUSA

Жыл бұрын

welcome

Thank you for your solution This is my solution: Let f(𝑥) = a𝑥 + b Hence, f(2𝑥 - 3) = a(2𝑥 - 3) + b Hence, a(2𝑥 - 3) + b = 4𝑥 - 2 2a𝑥 - 3a + b = 4𝑥 - 2 2a𝑥 - (3a - b) = 4𝑥 - 2 Comparing coefficients, 𝑥 term: 2a = 4 a = 4/2 = 2 Constant term: 3a - b = 2 3(2) - b = 2 6 - b = 2 b = 4 Hence, f(𝑥) = 2𝑥 + 4 (Ans)

@DrWangUSA

6 ай бұрын

Nice work