Nice Exponent Math Simplification | Find the Value of X
It can easily be solved without taking log.
simple take out 3 common 3× 27^x =3³ 3 × (3³)^x = 3³ 3× 3³x = 3³ since the basses are same so we equate power 3x+1 =3 3x =2 x=2/3❤❤
I used the second method to solve, much easier and also faster. Why would you use the log when it's not needed to solve ?
Another Method: Rewrite 27 as 9 + 9 + 9, Then equate 27^x = 9, Then rewrite the entire expression with a factor base of 3 and equate exponents, thus: 27^x = 3^3x 9 = 3^2 3x = 2 x = 2/3 Checking: 27^2/3 = 3^3●2/3 = 3^6/3 = 3^2 = 9. 3^2 + 3^2 + 3^2 = 9 + 9 + 9 = 27 (Checked).
27^X ＝ 9 → 3^3x ＝ 3^2 ∴ ｘ＝2/3
No need to make it this big Just take 27^x as some variable for exams i then 3i=27 i=9 27^x=9 3^3x=3^2 3x=2 x=2/3
Зачем нужны логарифмы? А слабо решать через дифференцирование?)))
Пікірлер: 7
It can easily be solved without taking log.
simple take out 3 common 3× 27^x =3³ 3 × (3³)^x = 3³ 3× 3³x = 3³ since the basses are same so we equate power 3x+1 =3 3x =2 x=2/3❤❤
I used the second method to solve, much easier and also faster. Why would you use the log when it's not needed to solve ?
Another Method: Rewrite 27 as 9 + 9 + 9, Then equate 27^x = 9, Then rewrite the entire expression with a factor base of 3 and equate exponents, thus: 27^x = 3^3x 9 = 3^2 3x = 2 x = 2/3 Checking: 27^2/3 = 3^3●2/3 = 3^6/3 = 3^2 = 9. 3^2 + 3^2 + 3^2 = 9 + 9 + 9 = 27 (Checked).
27^X ＝ 9 → 3^3x ＝ 3^2 ∴ ｘ＝2/3
No need to make it this big Just take 27^x as some variable for exams i then 3i=27 i=9 27^x=9 3^3x=3^2 3x=2 x=2/3
Зачем нужны логарифмы? А слабо решать через дифференцирование?)))