@46:21 I missed that I need only injective not bijective. f(z)=z can be the function. Option 3 is correct also.

Thank you so much sir...

A lot of thanx sir...❤❤❤

tq so mach sir❤

The questions are so nicely selected, that the discussion revises the main concepts. Thank you so much.

49:05, we can have injective holomorphic function e.g, f(z)=z, then option 3 is correct. How can option 1 b true , holomorphic function maps bounded set to bounded set

@SBTechMath

13 күн бұрын

@@kulsoomarashid4266 yes. I 📌 in the comment box.

@kulsoomarashid4266

13 күн бұрын

Ok sir thank u

Entire function mapped on bounded/unbounded set(leaving more than 1 point) then f is bounded sir ye kaise hua?

@SBTechMath

2 ай бұрын

Picard se

@komalkapoor3488

2 ай бұрын

Sir only for bounded sets we can't said by liouville's thm also?

@SBTechMath

2 ай бұрын

@@komalkapoor3488 no. It works only for entire functions

@komalkapoor3488

2 ай бұрын

@@SBTechMath ok sir...i got it.. Thanks a lot🙏💟

If every limit point of zeros in domain then f is identically zero na

@SBTechMath

2 ай бұрын

Nhi. All limit points not required. Single limit point existence will solve the purpose.

@pravinkamble2757

2 ай бұрын

@@SBTechMath Set of zeros is (-1,1) Then f= 0 on open disc is true then

@pravinkamble2757

2 ай бұрын

Open unit disc

@SBTechMath

2 ай бұрын

@@pravinkamble2757 yes

Sir 36:51 agr ham F(z)=1 le le and z=1 pr hmari equality satisfy ho jati hai jo given hai to sir fr first option A to true nhi ho rha?

@SBTechMath

25 күн бұрын

Condition should be satisfied for all z

Fn bounded h ya unbounded h ye kaise pta chlega

@SBTechMath

2 ай бұрын

Range dekh kar

Plz.. sir upload the recorded videos of complex analysis live session (tjk5.0)

@SBTechMath

2 ай бұрын

Kon si pending hai?

@pawartutorials01

2 ай бұрын

@@SBTechMath most expected question wali class jo 9 baje live hoti hai uski recorded videos bhi upload kar dijiye sir (lecture,1,2,3 hai only)

@SBTechMath

2 ай бұрын

@@pawartutorials01 usse aage hui hi nahi hai

@pawartutorials01

2 ай бұрын

@@SBTechMath baki kab hogi sir..?

Sir apki class ka time kya hai

@SBTechMath

2 ай бұрын

9pm

Sir, I wanna buy your test series for CSIR NET June exam but can you please let me know how many Full Length Tests does it contain? and uptill when your 50% discount is going on? and last thing does it have solutions included to after every test??

@SBTechMath

29 күн бұрын

3 FLT, Solution with each test.

Sir in Q83 If we take f(z)=sin(1/1-z) and U = unit disk Then X ={1-1/nπ. : n€N} Here X is not closed. F satisfies all given hypothesis

@SBTechMath

Ай бұрын

Does 1 belong to the domain??

@14-nasirhusain83

Ай бұрын

@@SBTechMath no

@SBTechMath

Ай бұрын

@14-nasirhusain83 so it would not impact the result.

@14-nasirhusain83

Ай бұрын

@@SBTechMath Question is about set of zeros of f.....ie X Which doesn't becomes closed here

@14-nasirhusain83

Ай бұрын

Bze here 1 becomes limit point of zeros....but doesn't belong to set