One Stop Solution for CSIR-NET/GATE/IIT-JAM
Welcome to SB-TechMath. In this channel, I provide a complete solution of Mathematics for national level exams viz. CSIR-NET/GATE/IIT-JAM/NBHM and Ph.D. entrances.
The motive of this channel is to make Mathematics easy and accessible for all and that's why all the concepts are delivered in such a fluent and easy way so that everyone can understand it very easily. The videos on channel are useful for all students of mathematics. Engineering level students preparing for competitive and university exam would also be benefited with the content.
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Excellent sir
Thanks a lot once again sir... These series is helping me out for revision in short time.... Thanks a lot 🥰.. Please upload such videos on linear and remaining topics also😅so that these are helpful for other exams also.
Always grateful to you sir❤❤
1:27:00 Global solution to closed interval me h na!! But yahan to open interval mil raha h means ye maximal interval hoga . To isse global solution bolenge ??
f ki domain pe depend karta hai
Solution of the homework problem is (π/2,3π/2). Will it be maximal and global solution as well?
yes
@@eshitachakraborty7955 Okay mam. Thank you.
Adbhoot ❤❤
How much percentage in msc is required as eligibility along with gate??
55%. But if you have 70%+ then it will be good.
@@SBTechMath ok
Superb explanation mja aa gaya ❤
Nobody uploads these type of long explanation for free. No short trick only concepts ✅
Mam in last lecture .... There was result ...of q(x)> 0 on [a b] Then solution has atleast k number of zeros Now here ... 8:10 atmost finite number of zeros on [a b] So in last lecture.....there was a question at 49:27 ( last lecture)where one of option was " it has atmost 3n zeros on interval' Then that option was also correct????
no , atmost finite number of zeros and atmost '3n' zeros both are not same , how could u confirm that number of zeros are exactly lessthan equal to 3n.
@@SBTechMath yes mam ...point
1:15:13 C option correct
Very nice explanation sir
Keep watching
great ma'am you are absolutely right. please tell us ma'am how we will connect our learning to a practical way. so that we can understand what we are learning and why we are studying the particular topics this is my humble request please answer ma'am
Thanks sir... Sir app bhi iit jam ke batch mai kuch subject padhaiyega plz
@@rajeshsharma-ry4ck ji. Linear Mai hi karaunga
Happy Guru purnima sir🙏
Happy Guru purnima
Thnks sir ❤
Sadar pranam sir❤
Thank you sir 😊
Thanks alot sir...
Sir csir valo ke liye bhi kuchh bachho ke liye free kar dijiye 🙏🙏🙏
Is Guru Purnima par sir mera aapko pranam🙏
Yes sir
Jai gurudev 🙏 bus aap humko yahi aasir was dijiye ki mera net me pass ho jaye aache no. Se meri
1/(x+pi)² is inc in (-pi,o) and dec in (0,pi)...so overall kaise dec ho gya sir
Question bhi mention kr dijiye
@@SBTechMath Sir series of functions,53.59 pe
Very helpful session…
Prime numbers are uncountable so uncountable sets can be formed
@@rajeshsalvi8249 acha ji. Prime number integers hote hai ya nhi? And Integer ka set countable hai ya uncountable, please Iss par prakash daliye Rajesh ji
I have doubt in last option. Q[x] /(x^3) is isomorphic to Q×Q×Q, so first and second option will be wrong
No u cannot use the fact of Chinese remainder thm here...x,x,x are not coprime ...your assumption held if we can use that thm
At 50:30 the function u defined is not continuous at 1
Sir phir be csir net😢 nta karwa raha apne supreme court me shikayat kue nhi ki
Thank you sir 😊
Incredible lecture 😊. Nice explanation ma'am. And Thanku soo much sb tech maths academy 🙏🙏
Adbhoot ❤️❤️
Adbhoot ❤❤❤
Infinite solution
3:23:52 ..... Sir |sint |≤ 1 hai ..... Integral sint/t^p ≤1/t^p ......and this will be cgt for p<1
@@14-nasirhusain83 this don’t confirm divergence. Only convergence ka area pata chalta hai.
@@SBTechMath aur agr |sint/t| ≤ 1 we wala chale .....to divergence ka area bhi pata chalta hai. Is it so sir???
@14-nasirhusain83 yes. Since you can take limit and it will be non-zero so by comparison test converge and diverge.
Hats off to dear teacher .....Your r one of the Briliant applied mathematician.🙏
How I join applied math course for CSIR net December 2024 Please provide link
Join Dec-2024 Live Batch- bit.ly/livedec24 Contact- 8126545455