This is so freaking underrated

I watch many calculus videos and I just stumbled upon JK Math. These videos are so useful and abundantly clear, above all others. I'm very grateful!

@JKMath

Жыл бұрын

Thank you! I appreciate the support. Glad you find the videos to be useful! I do my best to make them as approachable and clear as possible. Please feel free to share them with others! :)

Thank you sooo muchhhhh 🙏🥹

@JKMath

15 күн бұрын

You're welcome! :)

I wish I found this channel sooner! Thank you!

@JKMath

Жыл бұрын

You’re welcome! Glad my videos have been helpful for you :)

life saver

Thank you for this video, so helpful!

@JKMath

Жыл бұрын

You're welcome! Glad it was helpful :)

your channel is the best calc 2 channel ever, + best explanations, don't stop uploading!

@JKMath

Жыл бұрын

Thank you! I appreciate the kind feedback. Glad to hear my videos have been helpful for you! :)

Excellent

thank you

Man this was extremely helpful thank you so much. It's just unfortunate i can't find more videos similar to the subjects in my book 😢

@JKMath

4 ай бұрын

You’re welcome! Glad I could help. What kinds of other topics/subjects are you looking for?

@Mo_Jafar

4 ай бұрын

@JKMath Actually our book is called "Thomas Calculus the 11th edition" and I noticed there is a few similarities between chapters but for example the next chapter in my book(chapter 7) is called "TRANSCENDENTAL FUNCTIONS" which I couldn't find in your playlist unfortunately.

@JKMath

4 ай бұрын

@Mo_Jafar I cover calculus of transcendental functions such as ln(x), e^x, etc. in my calculus 1 series if you are looking for videos on those topics!

@Mo_Jafar

4 ай бұрын

@@JKMath I will make sure to check them out thanks!

What should i do to find the center of mass of the region bounded by 4 different function? i.e a region bounded by y=(x^2)/2, y=4-x, y=1-x, and y=3x. im kinda confused on how to find the Mx or My since i cant describe the region by 1 integral

@JKMath

Жыл бұрын

So that's a tricky one... The only way that I can think to do this using only Calculus 1 and 2 skills is by using more than just one integral as you may have suspected. I think you would need to formulate some new equations for the moments about x and y axis to replace the formulas I find beginning at 25:12. I took a look at the region bounded by the equations you gave me, and it seems that you could split this region into 3 different sections. The reason being that (in the x direction) the "top" and "bottom" functions for the region change 3 times. For section 1 (x=1/4 to x=√3-1), y=3x is the top function and y=1-x is the bottom function. For section 2 (x=√3-1 to x=1), the top function is still y=3x but the bottom function changes to be y=(x^2)/2. Then for section 3 (from x=1 to x=2) the top function changes to y=4-x and the bottom function remains y=(x^2)/2. For each of those sections you could try to form the moment equations Mx and My, although that seems to be a lot to ask...as I am not sure whether it makes sense to add the moments for each section together or average them. I can see how this confused you, as it is confusing me as well haha. Like I said at the beginning, this is a pretty tricky problem. After thinking about it for a bit, I believe this problem would probably best be solved using a double integral, which is a Calculus 3 concept. Double integrals make calculating area of complex shapes like that a lot easier (and you only need "1" integral, no adding integrals together). Are you in a more advanced class than calc 2? Because this problem is certainly above the level of a typical calculus 2 course in my opinion. Let me know! Hope I was able to help in some way :)

@adhimasfathi6116

Жыл бұрын

@@JKMath thanks for the answer! Im in calc 2 class. Actually, the question i ask is not actually the main question, but the problem that my lecturer gave me requires that region center of mass in order to be solved. But there is a posibillity that my lecturer gave me a wrong problem or its my own mistake in understanding the problem itself. Again, thanks for the answer! :)

@JKMath

Жыл бұрын

You're welcome, I wish I could give you a better answer though. That's one nasty problem if you did interpret it right. I hope you are able to figure it out regardless!