Molarity, Solution Stoichiometry and Dilution Problem

This example shows three different types of ways a solution stoichiometry question can be asked, using molarity, stoichiometry and dilutions. I walk you through how to solve each part while showing you all the steps of course!
Chemistry Question:
According to the label on a bottle of concentrated hydrochloric acid, the contents are 36.0% HCl by mass and have a density of 1.18g/mL. What is the molarity of concentrated HCl? What volume of it would you need to prepare 283mL of 2.20M HCl? What mass of sodium bicarbonate would be needed to neutralize the spill if a bottle containing 1.75L of concentrated HCl dropped on a lab floor and broke open?
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Пікірлер: 56

  • @xxsheannaexx
    @xxsheannaexx5 жыл бұрын

    I took chemistry in highschool and totally failed all my exams. Im saying I got 3 right out of 50 questions haha Im taking chemistry in college now and I've been learning from all her videos! So far I've gotten B's on my exams! Thank you!!

  • @melissamaribel

    @melissamaribel

    5 жыл бұрын

    Wow, that is an incredible improvement!! You should be so proud, I know I'm proud of you 😊

  • @shanehebel
    @shanehebel Жыл бұрын

    I cant believe I have been trying to figure this out for 3 days now and you just taught it in a way that I understand and can apply in less than 15 min.. Just amazing!!!

  • @mattbraga4033
    @mattbraga40335 жыл бұрын

    My head hurts

  • @melissamaribel

    @melissamaribel

    5 жыл бұрын

    Hey Matt, let's fix that headache, what part isn't making sense?

  • @corymelaniepearson8025

    @corymelaniepearson8025

    4 жыл бұрын

    @@melissamaribel all of it :)

  • @Jennnvang
    @Jennnvang Жыл бұрын

    I don't know what I would do without your videos! Thank you for all your help! I have shared all your videos with classmates as well.

  • @kaithlyn-in5es
    @kaithlyn-in5es3 жыл бұрын

    Thank u so much! I have an exam tomorrow and am freaking out... but thanks to the videos it gives a clearer understanding! I never knew these were so easy:)

  • @fuzzers6233
    @fuzzers62333 жыл бұрын

    I’m figuring out how to do this while taking my test 👀

  • @WeAreObject
    @WeAreObject6 жыл бұрын

    Ayyyy I got an exam tomorrow, and this is on it. Thanks!!

  • @charistanbibimbia330
    @charistanbibimbia3304 жыл бұрын

    Thank you for this exercise . You're a great teacher in chemistry .

  • @shravansrinivasan4982
    @shravansrinivasan49824 жыл бұрын

    Thank you for your clear explanation towards these concepts It is extremely helpful for my Ap Chemistry work and I got A- so far in semester 1 and now aims for A+ in semester 2. Which means I will get an A thanks to you. I hope this will help for me to get A 4 and 5 in the exam.

  • @anthonylebario4460
    @anthonylebario44605 жыл бұрын

    Very helpful video! Please make more of these types of videos! It truly helps, especially for research lab.

  • @trinasalas3117
    @trinasalas31173 жыл бұрын

    This was so stressful learning this today in class -.- but thank you so much for your help

  • @nellyandende7722
    @nellyandende77223 жыл бұрын

    Thankyou my baby is enjoying your lessons

  • @kaylaaquilante9445
    @kaylaaquilante94454 жыл бұрын

    Wow this is a good video

  • @hiwakarem7640
    @hiwakarem76404 жыл бұрын

    very good tech

  • @dianareyes807
    @dianareyes8074 жыл бұрын

    For part b. Doesn't V2 have to be in Liters?

  • @bellering.930
    @bellering.9305 жыл бұрын

    u da best fr!

  • @melissamaribel

    @melissamaribel

    5 жыл бұрын

    Thank you so much Gabriel! 😊

  • @padmavathiganti8152
    @padmavathiganti81524 жыл бұрын

    We can also calculate Molarity for question.a)with this formula and gives an answer 11.6 M M=10×density×% by weight of solute/molecular mass of solute M=10×1.18×36/36.45 That gives 11.6M molarity.

  • @orhanavunduk4934

    @orhanavunduk4934

    2 жыл бұрын

    Why 3 sig figs in the answer ?

  • @ktq2236
    @ktq22366 жыл бұрын

    can you do particles to mole and mole to particles

  • @greatg5775
    @greatg57755 жыл бұрын

    YOU SHOULD DO a video on organic chemistry

  • @melissamaribel

    @melissamaribel

    5 жыл бұрын

    Good News, I have a whole second channel on Organic Chemistry! Here's the link: kzread.info/dron/SzvQG5seY5dA59RIkZlicg.html

  • @cally-fk5nt
    @cally-fk5ntАй бұрын

    not me watching this video on the same day as my anachem exam 💀 (THANK U SM)

  • @AvaDevaud
    @AvaDevaud Жыл бұрын

    how did we get 11.7 M HCl, what did I have to add/sub./divide/multiply to get that?

  • @melleesamson1210
    @melleesamson12104 жыл бұрын

    Hey Melissa at 0:53, where did you get the 100 g HCL solution from? How come you didn't put it over 1.18 g/mol

  • @meganhuang9062

    @meganhuang9062

    4 жыл бұрын

    Hopefully, I can answer that question for you although I'm not Melissa. In Chemistry, we typically assume that we have 100g of a certain solution unless otherwise specified. Now the 1.18g/mol has a different role in this problem. Because it's g/mol, you use that to convert the g of HCL to g of HCL divided by 1 ml of HCL solution. I hope that helped you, even a little bit.

  • @mohamudomar5828

    @mohamudomar5828

    2 жыл бұрын

    Hey mellee. The mass of Hcl is given in percentage form and it must be out of 100%.

  • @labibafarheen9563
    @labibafarheen95633 жыл бұрын

    Melissa, I’m so confused bcz my teacher never used conversion factor 😭😭😭😭 my finals coming soon n I’m so stressed

  • @orhanavunduk4934
    @orhanavunduk49342 жыл бұрын

    In the first question Why our answer has 3 sig figs while the least is 2 ?

  • @bittypie
    @bittypie2 жыл бұрын

    Melissa: We're asked 3 different questions here. Me not seeing any questions: 🥺😫

  • @bittypie

    @bittypie

    2 жыл бұрын

    Oh wait. I just realized the questions came after. I thought she got all those questions from the word problem alone 😂 That's how stressed I am.

  • @rorybaker5799
    @rorybaker5799 Жыл бұрын

    How do you get from 1.18 g HCL to 0.4258 g HCL, you say to divide by the g of HCL by Ml of HCL solution, but the initial thing doesn’t give the ml of HCL solution. Could somebody please help?

  • @rorybaker5799

    @rorybaker5799

    Жыл бұрын

    Because, 36g HCL / 1 ml HCL solution doesn’t equal to 0.4248 g HCL / 1 ml HCL solution

  • @alyanakaufman1514
    @alyanakaufman1514 Жыл бұрын

    why did it became 0.4248 g HCl in ? hopefully you see this

  • @marilynward8697
    @marilynward86973 жыл бұрын

    Do you have a version of this video without the music? It's hard to follow with the music going.

  • @dinoclasher4129

    @dinoclasher4129

    3 жыл бұрын

    Nope

  • @nurhasanahibrahim7622
    @nurhasanahibrahim76223 жыл бұрын

    Can I ask you a question?

  • @3456uify
    @3456uify5 жыл бұрын

    where is the number 0.4248 g HCL coming from?

  • @melissamaribel

    @melissamaribel

    5 жыл бұрын

    It's in part a at 1:17 , it's just changing grams of HCL solution to grams of HCl.

  • @isabellarodriguez3431
    @isabellarodriguez34315 жыл бұрын

    in the beginning,, why 100g HCL solution?

  • @alexism7294

    @alexism7294

    5 жыл бұрын

    I think it's because HCl is 36% by mass of the HCl solution and this is the the same as saying 36/100 or "36 g HCl OVER 100 g HCl solution" I had the same question and this is where I think the 100 came from. Hopefully someone can confirm this

  • @ewwxaca
    @ewwxaca5 жыл бұрын

    I dont get why you do 36g HCL/100g HCL * 1.18/

  • @melissamaribel

    @melissamaribel

    5 жыл бұрын

    We are given 36% by mass, the formula for percent by mass is (grams of solute/ grams of solution) x 100, this is where the 36 g HCl/ 100 g HCl solution comes from. Next we are looking for the molarity of HCl, the units for molarity are the mol of HCl solute/ L HCl solution. We need to get rid of the grams of HCl solution since that is not part of the molarity formula. This is why I needed to cancel out the grams of HCl solution units by multiplying by the density as shown at 1:29 This allows me to get to g HCl solute/ mL HCl solution. Now we must get to the units for molarity are the mol of HCl solute/ L HCl solution. This is why I converted the g HCl solute to moles and the mL HCl solution to L. Which will give us our final answer of molarity of HCl .

  • @paulvanlieshout369
    @paulvanlieshout3696 жыл бұрын

    can you show how to do grams of a product to prepare a solution

  • @melissamaribel

    @melissamaribel

    6 жыл бұрын

    Hey Jacquelyn, did you have a specific question in mind?

  • @paulvanlieshout369

    @paulvanlieshout369

    6 жыл бұрын

    The question is how many grams of Mg(OH) are needed to prepare 125ml pf 0.30M solution?

  • @melissamaribel

    @melissamaribel

    6 жыл бұрын

    Ok so we will use the molarity as our conversion factor since M= mol/L this is really telling us 0.30 mol Mg(OH)2/ 1 L Here's the plan: mL to L to mol to g We'll start with the mL and convert to L , then use the molarity to cancel out the L to get to moles, lastly convert the moles to grams using the molar mass. Looks like this: 125 mL x (1 L/ 1000 mL) x ( 0.30 mol Mg(OH)2/ 1 L )x (58.32 g Mg(OH)2 / 1 mol Mg(OH)2) Make sense?

  • @paulvanlieshout369

    @paulvanlieshout369

    6 жыл бұрын

    yes. Thank you

  • @tejpalsahani9295

    @tejpalsahani9295

    5 жыл бұрын

    Fantastic

  • @Sabrina-ln9ky
    @Sabrina-ln9ky3 жыл бұрын

    I’ve been watching all of your videos, but this one is the most confusing for me ☹️

  • @darmadeit
    @darmadeit2 жыл бұрын

    🐐🐐🐐

  • @thelivingzombie8403

    @thelivingzombie8403

    Ай бұрын

    Messi