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Пікірлер: 46
i secan't do this anymore
@julienewilkinson3798
3 ай бұрын
right?? you're hilarious!!😅
@unknownuser6757
2 ай бұрын
@@julienewilkinson3798That person is funny
@narcosu2088
2 ай бұрын
IM IN PAIN
@crybaby4111
17 күн бұрын
Usss
the whistles when you were drawing the 7s were the best part!
@theblueprint2001
Ай бұрын
really? i like the “wooop” “wooooop” with the 3rd 7
I was struggling memorizing this, but thanks to you sir it's far way easier to memorize and understand, you're one of the best! THANK YOU
you don't know how much you've helped with this. Thank you!!!!
You can remember the cofunction identities by looking horizontally across from left to right and right to left. The Even/Odd identities can be remembered by using the forward slash ("/") symbol to note that Cos & Sec are the only two positives. 😉
@masterraven8596
6 ай бұрын
Best comment and only 8 likes? We can fix that
@surrealistidealist
6 ай бұрын
@@masterraven8596 Thank you, my friend!
@masterraven8596
6 ай бұрын
@@surrealistidealist No thank you I passed my prep calc mid-term because of this comment.
For the cofunction IDs, just remember to go across and they all line up perfectly!
@thealtokid1012
Жыл бұрын
could you reiterate what you mean by this? not sure what exactly i should be doing
@ychickennugetsidk3880
Жыл бұрын
@@thealtokid1012 if you go from sin to the right you'll get cos. From tan ---> cos and then from sec --->Csc
@johnnybananas751
8 ай бұрын
@@ychickennugetsidk3880I think you meant to say Tan -->Cot. Basically you move across the hexagon in horizontal lines. Sin=cos(90-theta) And the opposite is true, moving from the right across the hexagon: Cos=sin(90-theta) Again: Tan=cot(90-theta) Cot=tan(90-theta) Sec=csc(90-theta) Csc=sec(90-theta)
@pigeonlove
8 ай бұрын
@@johnnybananas751another way to remember the co angles is to say the name in full, sine and cosine, tan and cotangent, secant and cosecant
By far the most helpful way I have seen Thank you!
I really appreciate your help. Thank you so much!
Holy SHIP!! I HAVE AM EXAM TODAY AND THIS WILL HELP ME OUT SO MUCH
FINALLY! The correlations are clear!!! Thank you :)
Thank you so much.
YOU CAN USE THIS WITH DERIVATIVES! Though its a bit difficult to see, there are some noticeable patterns. Once i noticed these, I haven’t had trouble with these derivatives at all! You’re not gonna understand without writing it out. Its a bit complicated at first glance, but simple when you understand it. I just drew the hexagon (without the edges, only the lines in between. It looks like a x with a horizontal line) 1. Search up the trig derivative online. Write them down across a page. 2.Then under each function, draw the hexagon thing 3. trace a line from the trig to derivative using a different color pen. Do you notice the patterns? Take a moment to study it for yourself. Anyway, hopefully you understand this: I found these patterns: Obtuse angles create fractional derivatives, Accute angles create singular or multiplication derivatives Following the inner lines left into the center and out, will give negative derivatives. Following the inner lines right into the center and out, will give positive derivatives. Csc and sec repeat themselves in their derivatives. The derivative angles on the left are opposite of those on the right. Ex: following the inner lines, draw a line from tan to it’s derivative 1/cosx. The line went right in a obtuse angle, so it’s solution is a positive fractional derivative. Ex2: following the inner lines, draw a line from cot to it’s derivative -1/sinx The line went left in a obtuse angle, so it’s solution is a negative fractional derivative. The angle is opposite to tangent. Ex3: following the inner lines, draw a line from sin to it’s derivative: cosx. The line went right in a acute angle so the solution is a positive singular or multiplication derivative. Ex4: following the inner lines, draw a line from cosx to its derivative -sinx The line went left in a acute angle, so the solution is a singular or multiplication derivative. The angle is opposite to sinx. Ex5: draw a line from secx to to tanx (not the derivative) The line goes right first, and is a acute angle, so the derivative is positive multiplication. Since it is sec, it’s repeated. So, the derivative is Secxtanx. Ex6: draw a line from csc to cot (not it’s derivative) The line goes left first so the derivative is negative multiplication. Since its csc, it is is repeated. So the derivative is cscxcotx. Haha, I did not explain that very well, so I encourage you to try figuring this out yourself! The pattern could probably be simplified a bit. For instance, it’s better to say the top accute angles are singular while the bottom accute angles multiply something by themselves. But whatevs! I wish you the best of luck!
@theblueprint2001
Ай бұрын
appreciate it brother/sister. i don’t need this for my current test gut its good to know 👍
Thank you, I love you.
Very useful indeed, thank you very much
This is the best video ❤❤❤
Thank you! ❤
It is very helpful for me 🤠😁😊😊😊.🇮🇳🇮🇳 From India 🇮🇳🔥🔥🚩
Excellent thanks 👍 very much sir
If yall can't remember this then the future of trig is grim 💀
@narcosu2088
2 ай бұрын
Yeah Im not looking forward to this future 👍
Wow..thank you for this
very usefull
great
THANK YOU SO MUCH
oh man love your way! from Pakistan.
Great work..🙏
This is a game changer
Why don't they teach this in America?
Long live 🇹🇼.
Taiwanese here 🙋
in india we learned this in 5th grade
@unknownuser6757
2 ай бұрын
No way
@autovozo5725
2 күн бұрын
No we didnt