This is so helpful and you're handwriting is fantastic!

+Online To The Brain Yes, that often becomes confusing. 1) The find the length of a strip where a is the left point and b is the right point is as follows: L = b - a 2) To find half the length (L/2) = (b - a) / 2 3) To find the midpoint between a and b : midpoint = (a + b) / 2 Try it with two numbers like 3 and 7 Quoting a comment below on why its (a+x)/2 instead of (a-x)/2

Great videos. Thanks for your service. Very clear and concise. I was thinking if we could calculate the Area while solving for y bar and use it for evaluating x bar. After all the area would not change. However it sure helps solving both ways.

Thank you from Brazil ... You helped a lot.

Such an amazing channel , thank you Doctor.

You are a great teacher.. please keep doing the good .. very good work you are doing SIR .. Thank you so much

that was an excellent video Michel!!!.. thanks.. as usual..... Sure glad I didn't need to solve that on a Final Exam... but then again.. my last final exam was back in 1994... lol... so.. I can enjoy this "STUFF" now..... and not feel pressured to know it for an exam... therefore I APPRECIATE it.. :D ..

Very much appreciated, thank you again. However, for me it turned out to be easier when using a horizontal area element when calculating y hat, and a vertical element when calculating x hat. Reason: From the formula (SUM y A(y)) / SUM A . If you use a vertical area for A(y), then there are many y values in each vertical area element. If a horizontal area element is used, it only has one value of y. This seems to make the math easier, for example, no need to remember to use y/2 for the y value.

Thanks for the video, but in the second part, when we need to find x bar you could simply follow the formula and do x bar=integ(xkx^2)/integ(kx^2). It's much more faster and easier!

@zuko8023

8 ай бұрын

could you explain this further please

sir how can you determine where's a and h if the parabolic spandrel is twisted?

Man you're much better than my teacher! (Thank you from Brazil)². The "h" looks like the "k" in your writing hahahahaha

sir how did you get the relation h=ka^2...(a square).

Thank you sir from India! This video was helpful for concept building.

@MichelvanBiezen

6 жыл бұрын

Welcome to the channel!

BEST VIDEO ABOUT CENTROIDS I'VE EVER WATCHED(IM TOO LAZY THAT CANT EVEN EVEN TURN OFF THE CAPS LOCK NOW)

for x I set da = kx^2 * dx and still got the same answer . How?

Professor i am confuse on Xbar you say in horizontal strip length of strip = (a-x) but in case of center of strip why it become =(a+x)/2 why not center is strip length/2 that mean =(a-x)/2 ??????

@MichelvanBiezen

8 жыл бұрын

+Online To The Brain Yes, that often becomes confusing. 1) The find the length of a strip where a is the left point and b is the right point is as follows: L = b - a 2) To find half the length (L/2) = (b - a) / 2 3) To find the midpoint between a and b : midpoint = (a + b) / 2 Try it with two numbers like 3 and 7

@OnlineToBrain

8 жыл бұрын

+Michel van Biezen thank you sir for your lecture and quick reply.

how to find centre of mass of a solid semi elliptical objects?

if we let k =1 and a= 1 and h=1 .. then 0

@ptyptypty3

6 жыл бұрын

by the way.. I figured the area under the entire curve is = the integral of y= x^2 from x=0 to x=1. That should be Area = (1/3) x^2 from x=0 to x=1.. so Area = (1/3) so the left AREA should be 1/6 and the right area should be 1/6 .. in order for the BALANCE to occur.... anyway... just babbling now MICHEL... thanks.. no need to respond...

A really good explanation, an even better bowtie

Today is your video loked so IAM very impress

Best teacher :D thanks

thanks sir u helped me alot really can u post about moment of inertia about bodies like this ?

@MichelvanBiezen

7 жыл бұрын

That is the next topic we are planning on covering after we complete friction.

you dont have to make a horizontal rectangle for y just a vertical rectangle is sufficient to solve x and y bar.

@gautamanand8866

4 жыл бұрын

How?

@shezanahmmed5582

4 жыл бұрын

Can you tell how it is possible?

@reed560

4 жыл бұрын

@@shezanahmmed5582 You can find both parts of the centroid of that same rectangle. Then set up your integration with the components for the respective part. While the setup is tricky, the integral is easier to solve.

@shezanahmmed5582

4 жыл бұрын

@@reed560 yes bro. I got it. Thank you so much.

@sabyasachiguha367

3 жыл бұрын

@@reed560 can you tell me how to do that?

Excellent sir ji

Hello Michael, These videos are amazing. This is astounding work. I have one question - shouldn't A be the same value for both calculations of xbar and ybar, since the area is the same??

@MichelvanBiezen

6 жыл бұрын

x bar and y bar represent the center of mass which also depends on the shape of the area, which is different with respect to the x-axis and the y-axis. (thank you for the comment).

@durga18991

4 жыл бұрын

@@MichelvanBiezen kzread.info/dron/_wDGFo02ck_egU6upx6AkQ.html

In the case of horizontal strip,shouldn’t the strip's length be considered as "X", just like in the case of vertical strip where u took the verticle length of the strip as " Y".In vertical strip u got ~y=y/2 where as in horizontal strip shouldn’t it be just ~x=x/2?

@MichelvanBiezen

4 жыл бұрын

No. The vertical strips all end at the x-axis where y = 0. That is not the case with the horizontal strips.

Thank x from India..

Helped me a lot sir. Thankyou

@beoptimistic5853

3 жыл бұрын

kzread.info/dash/bejne/ioV9xNBrZ8e1mqg.html 💐💐

Thank you so much sir

...wouldn't it be easier to find X by integrating K*X*X^2 from 0 to a ? am getting the same results 3a\4

@MichelvanBiezen

8 жыл бұрын

+iverson0523 I can't comment on your approach unless I can see how you calculated the center of mass starting from the definition of the center of mass. The video shows the general approach that works for all circumstances.

why we are not taking the average ( (Y+ h)/2 ) and not taking the area width ( h-y ) in the first equation ? as we did in the 2nd equation, ( ( X+a)/2 ) and ( a-x )

@MichelvanBiezen

6 жыл бұрын

Note that in the vertical direction the reference line is the x-axis. But in the horizontal direction the left side of the area is not the y-axis.

thank you do much for doing y bar there's already so many videos saying do y bar yourself

@MichelvanBiezen

4 жыл бұрын

Yes, I remember those frustrations when we were students. :)

Do we need horizantal strips to find the x coordinate? The center ~x of vertical strip is just x unlike y/2 and the formula gets a lot easier but it gave me wrong results on some questions.

@MichelvanBiezen

3 жыл бұрын

It is better to choose strips such that the center of mass of each strip is the same coordinate as the center of mass you are looking for.

Great video sir. Thank you!

@MichelvanBiezen

5 ай бұрын

Glad it was helpful!

Thank you sir

Love from India 🇮🇳

@MichelvanBiezen

5 жыл бұрын

Welcome to the channel!

Why did we square the function? Couldn't we just use it as it is, like what you did in the denominator? 2:04

@JeffersonWhovianFernandes

6 жыл бұрын

Because of the Y²

Thanks alot

U R the best

Hello sir, How do I find the moment of Inertia: Ix, Iy and Iz of this function? Having trouble with this.

@MichelvanBiezen

8 жыл бұрын

+Ibracadabra52 Take a look at the playlist: PHYSICS 13.5 which has applications on how to find the moment of inertia of a number of shapes.

why is the length of the vertical strip only denoted as y but for the horizontal strip, it is denoted as b - x? whats the difference?

@MichelvanBiezen

Жыл бұрын

In the vertical direction the botton is at the x-axis. For the horizontal strip, the left side is NOT at the y-axis.

Why can't we integrate x = y/k in the denominator for x bar? Why do we use (a -x)?

@MichelvanBiezen

7 жыл бұрын

The length of that strip is indeed (a - x) as in the video. What is the distance between 5 and 8 on the number line? You find it by subtracting the 5 from the 8 (8 - 5)

Would it be simpler if we use derivative of each dimensions and find min and max average out then find average then divided by 2 and intersect them? That way with any irregular shape be fastest on sound surrounding output can find min and max very fast

@MichelvanBiezen

11 ай бұрын

That will not work. Try and it see if you get the same answer.

@EricPham-ui6bt

11 ай бұрын

@@MichelvanBiezen not the same answer may mean many thing but not mean not working

Great vid. But why do you square y=kx^2 ? Cant you just substitute it directly?

@MichelvanBiezen

5 жыл бұрын

Try it and see if you get the same result. (There are often multiple ways to solve the same problem)

very nice

en el seg 8:50 , porque la integral de (a´2 - y/k)= (a´2 y - y´2/2k)?

@LinkinPark15Ash

5 жыл бұрын

a and k are constants

Thanks

Thank you

Buenísimo video

Dear sir, I am just wondering what if we have sinx , cosx, or lnx graph , how could we determine the centroid of the x and y coordinates? Are we gonna follow the same steps? thanks

@MichelvanBiezen

5 жыл бұрын

Yes, the method would be the same.

@mokarrommolla5820

5 жыл бұрын

@@MichelvanBiezen Thanks

Another question is when you're finding dA solving for y...you didn't make an average of y+h/2 instead you just made it a y then now when you got to solve for x, you then said a+x/2 instead of just x or should I say a..why is that sir...I don't understand

@MichelvanBiezen

Жыл бұрын

a-x represents the length of the dA (a+x)/2 represents the middle point of that dA

@iheyinwaemmanuel3496

Жыл бұрын

Ohh thank you sir

@iheyinwaemmanuel3496

Жыл бұрын

Taking notes

why is the denominator taken as integral of dA instead of A

@MichelvanBiezen

6 жыл бұрын

They are the same. If A is known, you don't have to integrate.

Great video

@MichelvanBiezen

3 жыл бұрын

Thanks!

excelent , but you can replace the complete value of k in terms of h and a and the second part would be easier , thnaks

@beoptimistic5853

3 жыл бұрын

kzread.info/dash/bejne/ioV9xNBrZ8e1mqg.html 💐💐

when dA =dydx then how it can be solved??

@jenna943

5 жыл бұрын

You use dL = root( (dx)^2 + (dy)^2 ). Then, choose which integration is needed and solve. dL should look something like dL = root( (dx/dy)^2 + 1 ) dy.

I'm sorry but I kinda lost at (a+x)/2. is it just a formula?

@MichelvanBiezen

5 жыл бұрын

To find the midpoint between two points you add them and divide by two.

@lanvu9323

5 жыл бұрын

@@MichelvanBiezen thank you

I dont know why but I like this person

@beoptimistic5853

3 жыл бұрын

kzread.info/dash/bejne/ioV9xNBrZ8e1mqg.html 💐💐

Man u saved me from failing

@MichelvanBiezen

2 жыл бұрын

Glad to hear it. Keep it going.

Just a question in 6.04, Why x_bar = 1/2*(a+x) ?, in this point i forget how to prove it.

@MichelvanBiezen

Жыл бұрын

The average (or the midpoint) of 2 number (for example 6 and 10). You add them and divide by 2. (6 + 10) / 2 = 8

@prawitsantisukpotha2748

Жыл бұрын

@@MichelvanBiezen Thank you so much.

@prawitsantisukpotha2748

Жыл бұрын

@@MichelvanBiezen Got it, Now I've solved/found a Yc.g. of sector of ellipse by your clip on 6.00+++ . Thank you so much.

@prawitsantisukpotha2748

Жыл бұрын

Mr Van Biezen, I've a result to show you in this link. thank you. kzread.info/dash/bejne/ZY6ilc1-gbvgaJc.html

Thank you teacher

@beoptimistic5853

3 жыл бұрын

kzread.info/dash/bejne/ioV9xNBrZ8e1mqg.html 💐💐

thank you

@MichelvanBiezen

Жыл бұрын

You're welcome

what if y = ax^2 + bx + c ? we just cant convert x into y, the x is still remain

@MichelvanBiezen

7 жыл бұрын

You can always convert your vertex position so that the constants b and c go to zero, and you will get the exact same result. That is why this general technique works for all such examples.

Thanks sir!

@beoptimistic5853

3 жыл бұрын

kzread.info/dash/bejne/ioV9xNBrZ8e1mqg.html 💐💐

sir i am confused how it becomes a+x/2 why nt a-x/2

@MichelvanBiezen

6 жыл бұрын

The half way point between 6 and 8 is found as follows: (6 + 8)/2 = 7

@rishabhshukla9189

6 жыл бұрын

but we need centre of that rectangle whose length is (a-x) then its centre should be (a-x)/2. am i right sir?

@ofentsemosima3363

4 жыл бұрын

YOU ARE RIGHT. VERY RIGHT I GEZ!

My kitty finds mass of gravity in mid flight without any calculus knowledge :)))))))))))

East or west u r d best

@beoptimistic5853

3 жыл бұрын

kzread.info/dash/bejne/ioV9xNBrZ8e1mqg.html 💐💐

the entire 2nd half was for nothing... thanks alot

Sir why are you integrating the denominator A?

@MichelvanBiezen

Жыл бұрын

To find the area under the curve. (That is part of the formula to find the center of mass).

@iheyinwaemmanuel3496

Жыл бұрын

Ohh but the parabola that had a curve in the former video you didn't integrate the area above it sir....why is that?

@MichelvanBiezen

Жыл бұрын

Better ask the question on the video itself, rather than placing the question here.

Wow, cant get this right no matter what I do, will try again though

@beoptimistic5853

3 жыл бұрын

kzread.info/dash/bejne/ioV9xNBrZ8e1mqg.html 💐💐

It's not visible

@MichelvanBiezen

Жыл бұрын

What is not visible?

center of gravity of mountain ????like a prism ??? like a pyramid ???

Thanks from pakistan .

@MichelvanBiezen

6 жыл бұрын

Welcome to the channel.

second part for finding the x bar could be done in much simple way .... you unnecessarily made it complicated

@MichelvanBiezen

3 жыл бұрын

Yes, but the purpose of the video is to show the various techniques, such that a greater understanding can be reached

يا لعيب

30 dislike by commerce students

when he say H but he keeps on writing R lol

@beoptimistic5853

3 жыл бұрын

kzread.info/dash/bejne/ioV9xNBrZ8e1mqg.html 💐💐

learning in 2021! (5/1/2021)

@beoptimistic5853

3 жыл бұрын

kzread.info/dash/bejne/ioV9xNBrZ8e1mqg.html 💐💐

Too complicated...

(Very useful for class 12th)⁴ (Thanks)ⁿ; n≥8