Measuring inductance with an oscilloscope and signal generator

Ғылым және технология

Here I show you an easy way to measure inductance using a signal generator and oscilloscope, if you don't have an LCR meter. In my case I wanted to check the inductance of a small inductor that my component tester couldn't read.
Here is an explanation of how this formual works:
www.dos4ever.com/inductor/ind...

Пікірлер: 98

  • @JohnSmith-iu8cj
    @JohnSmith-iu8cj Жыл бұрын

    This video and the link with the formulas helped me a lot to get back into the topic, I had forgotten almost all the formulas and the calculations and after this I feel like I am ready to continue!

  • @ajayjoseph4498
    @ajayjoseph44982 жыл бұрын

    What a fantastic video! Didn't realise measuring inductance can be so easy.

  • @jeff-73
    @jeff-73 Жыл бұрын

    Thank you soooo much for this. This was the first video I found on youtube where you SHOW the wiring setup. cheers

  • @noa97
    @noa973 жыл бұрын

    The great truth, I know other methods with AWG and oscilloscope, but this is the fastest to measure an inductance, thank you very much for your contribution.

  • @vinceotten129
    @vinceotten1293 жыл бұрын

    This is fascinating! The simplest method I’ve seen for using a function generator and a scope to determine inductance. Saved & noted.

  • @Regulatorrobb
    @Regulatorrobb2 жыл бұрын

    Awesome!!! thank you for the extra link in the description.

  • @lancetollenaar7905
    @lancetollenaar7905 Жыл бұрын

    Another way that I like to use is one that works well if your function generator is crappy and doesn't necessarily have a nice linear output impedance (e.g. the FG-100 DDS generator). You connect up the resistor (in your case the 178.2 ohm resistor) as a shunt resistor, and use a 2-channel scope to measure voltage across the inductor, and voltage across the (known) resistor - from which you can infer the inductor current. Note that you would want a low ESL resistor, or at least ESL orders of magnitude above what you're measuring. You also measure the delay between the "current" & voltage waveforms, from which you calculate phase shift (along with freq.). From there you can use Ohm's law to calculate the magnitude of the impedance, and with the phase shift you can calculate the complex impedance. Take a few different data points and plot them in Excel, and compare with the theoretical calculated impedance :) An interesting thing you can see with this method, is the ESR of an inductor shows up as a linear offset to the calculated theoretical impedance!

  • @ScottMarley

    @ScottMarley

    Жыл бұрын

    Great bit of theory there, thank you!

  • @yamakawa511
    @yamakawa5112 жыл бұрын

    This is a really practical method, well explained.Thanks for the link to Ronald's page, it's well worth reading. Y

  • @victorrodal5192
    @victorrodal51922 жыл бұрын

    Nice and concise explanation. Thanks for the effort :)

  • @Tony-mq5yo
    @Tony-mq5yo Жыл бұрын

    Measuring inductance with ordinary meters can be deceiving unless it is air core inductor. This video did great job on inductances measurement

  • @PbPilotnl
    @PbPilotnl Жыл бұрын

    Thank you for the video. It helped me confirming my LCR meter was crappy with higher inductance. I did had some problem with my Uni-t 962 Function Generator set to 50 ohm, i changed to HighZ (scope was on M as well) and everything was fine.

  • @tonyrebeiro
    @tonyrebeiro11 ай бұрын

    Very nice, neat explanation and video.👍

  • @acestudioscouk-Ace-G0ACE
    @acestudioscouk-Ace-G0ACE3 жыл бұрын

    I'm not the best with maths but you explained this so clearly, I followed easily. Thank-you. I like your calm and clear presentation style.

  • @calculatingcapibara2914

    @calculatingcapibara2914

    Жыл бұрын

    Yes, the style of presentation is great plus here.

  • @computerchemist

    @computerchemist

    6 ай бұрын

    @@calculatingcapibara2914 I'll third that. Or is it the square root of a third? :D

  • @nevmarr
    @nevmarr3 жыл бұрын

    Thanks Scott, that's brilliant. I tested two inductors I wound on two T50-6, they were wound per the toroid specs to give me 3.98uH on one and .13uH for the second. Using your method the first came out at 3.95uH. The second was too small for my scope & FG upper limits. I then modified the formula per your comments to 1/4 & sqrt(1/15) to try to estimate the smaller inductor value. The 1/4 volts was right on the limit of my gear and the math came out at .09uH. This has given me confidence that my winding calcs have created inductors pretty darn close to my target. Until I found your video I was progressing with fingers crossed, now I'm progressing with a lot more confidence. Cheers!

  • @ScottMarley

    @ScottMarley

    3 жыл бұрын

    Really glad it was useful, I've never wound my own inductors but maybe I should give it a go!

  • @farzadbakhtiar

    @farzadbakhtiar

    3 жыл бұрын

    Hi Neville. Can you point to any good resources online to wind my own coils? TIA.

  • @nevmarr

    @nevmarr

    3 жыл бұрын

    @@farzadbakhtiar Hi Farzad. My go to site for toroidial coils is kitsandparts.com/toroids.php Click on the part number eg T50-2 for a whole world of info. You'll notice there is a blue menu at the top of the linked page. It has some really useful info too. Sing out if you get stuck or have any other questions

  • @ftmmrbs1996

    @ftmmrbs1996

    3 жыл бұрын

    Hello @Neville would you please explain how you came up with 1/4 and sqrt(1/15)? for some inductors the voltage is never more than a certain value (600mVmax for 3 V input) no matter what the frequency. is it because of the core I'm using that is getting saturated? was this your problem too? is that why you used 1/4 and sqrt(1/15)?

  • @nevmarr

    @nevmarr

    3 жыл бұрын

    @@ftmmrbs1996 I'm sorry but I cheated with the 1/4 and sqrt(1/15) ... I got those numbers from Scott's reply to @Suresh Kumar's question in the comments. If you're good at maths the detail is in the link in the description. I'm useless at maths but maybe 1/6 and sqrt(1/35) may work for you??? [I went for 1/6 as your 600mV "limit" is 1/5]. I have no clue why you cannot exceed 600mV but I wonder if the inductor value is so small it cannot be assessed by this method?? I used 1/4 and sqrt(1/15) because my function generator could not generate a frequency high enough to get 1/2 3V.

  • @buffplums
    @buffplums2 жыл бұрын

    Excellent tutorial thanks chap

  • @PayneDK
    @PayneDK2 жыл бұрын

    If you adjust the frequency until the voltage is 0.71 x generator voltage (in this case 2.2V), then the coil impedance XL is the same as the generator output impedance. Hereby the inductance is calculated as: XL=2pi*f*L=50.5 Ohm and L=50.5/(2pi*f)

  • @andrewscottpersons

    @andrewscottpersons

    8 ай бұрын

    sqrt(2) / 2

  • @Stephens8x6Workshop
    @Stephens8x6Workshop3 жыл бұрын

    Thank you so much for this. As a newbie Radio Homebrewer this has helped me greatly. Much appreciated. Liked subbed and rang your bell too!

  • @ScottMarley

    @ScottMarley

    3 жыл бұрын

    Appreciate it chap!

  • @logcom482
    @logcom4823 жыл бұрын

    Now I andestent how you do))LC filter))Nice metod)

  • @pault6533
    @pault6533 Жыл бұрын

    Good tutorial, I was looking for a way to use my new oscilloscope and signal generator to measure inductors. You helped me do this plus also determine the output impedance of my signal generator. Does this work for capacitance too?

  • @pedrogodoycruz
    @pedrogodoycruz2 жыл бұрын

    Your method works perfectly. But, I usually test the resonant frequency. Place a known capacitor (measured value, not just from the specs) and connect it to any voltage source. Disconnect the voltage and look at the resonant frequency. You only need an oscilloscope (and a good tester to measure the actual capacitor value). Also, voltage measurements are usually not very accurate with regular oscilloscopes, but frequency/time measurement are spot on, even for cheap oscilloscopes.

  • @ScottMarley

    @ScottMarley

    2 жыл бұрын

    Very useful information, thank you!

  • @patrickmonnier2193

    @patrickmonnier2193

    4 ай бұрын

    Not sure to have understood your method. Do you mean, you connect L and C in parallel and connect them to a power supply (maybe 3V). Then with your scope setup for a single trig open the circuit and measure the ring frequency?

  • @pedrogodoycruz

    @pedrogodoycruz

    4 ай бұрын

    @@patrickmonnier2193 Correct. Set the oscilloscope trigger to capture the self oscillations when you disconnect from a low voltage power supply. It allows you to calculate the inductance within 5% in a few seconds if your oscilloscope has good resolution for the frequency.

  • @izsakitt3711
    @izsakitt3711 Жыл бұрын

    S11 Smith chart can be set to indicate the combination of resistance and inductance (capacitance) of a component as a direct reading. The impedance of a component may widely vary as a function of frequency and also with excitation level (volt seconds that is, flux density, gauss or tesla) The VNA is a great tool to plot the component impedance as a function of frequency. - for the case in this video, a 10 fold change in the capacitor value likely computes a different inductance value

  • @logcom482
    @logcom4823 жыл бұрын

    Very clever metod

  • @AlexA-ei4js
    @AlexA-ei4js3 ай бұрын

    Thanks Scott for the video. Could you please provide me the link where to purchase the M Tester the same as on your video? Have you done any modification on it?

  • @tedhayton2302
    @tedhayton23022 жыл бұрын

    Hi Scott A really fascinating video. I am trying to use your method to measure a large unmarked smoothing choke. The FG calc works out perfectly at just under 50 ohms but I get no p/p drop whatsoever with the choke in parallel and reducing the frequency as instructed. The DC resistance of the choke is 418 ohms. Is it possible this method only works for small inductors? I expect the choke to measure 10 -15 Henrys. Keep up the great work!

  • @calculatingcapibara2914

    @calculatingcapibara2914

    Жыл бұрын

    You will not get a drop more than roughly 12 percent and only at very low frequencies. In addition, the large Rind will cause severe inaccuracy, even when compensated for. This here is not a great method for large inductors. You might try the method by "DIY made" at its 50 Hz, provided that you take care of safety(!), proper compensation equation and significant readings from the multimeter (larger reference resistor and/or multimeter with accurate low AC range).

  • @TYGAMatt
    @TYGAMatt2 жыл бұрын

    Fantastic. How easy is that!!

  • @rZERO_game
    @rZERO_game2 жыл бұрын

    if u increse frequency without geving load then amplitude remains same when frequency 1khz sine wave?

  • @rZERO_game
    @rZERO_game2 жыл бұрын

    1 khz to 600khz output amplitude at no load position does amplitude remain same?

  • @fredgenius
    @fredgenius Жыл бұрын

    Superb, thanks.

  • @donmichaelsen5169
    @donmichaelsen51693 ай бұрын

    Neglecting the wire resistance of the inductor can introduce some error, I would prefer to adjust the scope time scale to look at the charge time of the inductor (or capacitor) and use that to calculate the value of the component.

  • @calculatingcapibara2914
    @calculatingcapibara2914 Жыл бұрын

    Thanks for the video. Btw, if you search for the frequency where the voltage is down to 1/3, the equation ends in L = 1/f within 1%. Having said so, a scope plus functiongenerator is a bit out of scope for me. I use an oscillator setup with a series LC circuit. In that, the Rinductor disappears. I measure the frequency with a soundcard on the PC. For an occasional measurement, it does the job.

  • @calculatingcapibara2914

    @calculatingcapibara2914

    6 ай бұрын

    Erratum: ...down to 1/3 ... is an error, it should be 1/8.

  • @ayhan6977
    @ayhan69772 жыл бұрын

    thank you very much. so, is it possible to measure the inductance with square waves instead of sine waves?

  • @calculatingcapibara2914

    @calculatingcapibara2914

    Жыл бұрын

    Not with this method.

  • @elizabethjohncollins9363
    @elizabethjohncollins93632 жыл бұрын

    If you have an oscilloscope and a known size of capacitor you can deternine the inductance in a perhaps more straightforward fashion. The idea is to constuct a series LC circuit and find the resonant frequency. Then use that frequency to calculate the inductance from the formula for series LC resonance. Put the inductor and capacitor in series, add a resistor (e.g 50 ohms) to stop the function generator from shorting out at low frequencies. Find the value of frequency which minimizes the p-p voltage,. Use this frequency you found, the known capacitance, to calcuate the inductance using the formula for resonant frequency of an LC circuit.

  • @srtamplification

    @srtamplification

    Жыл бұрын

    That's the way I do it.

  • @Felipe2077tv

    @Felipe2077tv

    4 ай бұрын

    Can you draw a basic schematic visualizing what you just said?

  • @MrEdwinHubble

    @MrEdwinHubble

    4 ай бұрын

    One addition. Series LC(R) circuit will have a resonant frequency when the measured voltage on R has a maximum when xL and xC are the same.

  • @choke173
    @choke1733 жыл бұрын

    Sir . 2.4Volt (connected with resistor) , how about 3.06 volt ? sorry sir , poor english i have ... Your method quite useful ...

  • @drashtipatel-il7te
    @drashtipatel-il7te2 күн бұрын

    How did you derived Final “L” formula?

  • @octogames6823
    @octogames68232 жыл бұрын

    Would you happen to know how many uH the chines MDS-60 metal detector kit might be?

  • @calculatingcapibara2914

    @calculatingcapibara2914

    Жыл бұрын

    You could give it a try, but it will be close to impossible with the components already soldered in place. You will need a high frequency on your fg too. Moreover, to get to know the design it is important to measure the mutual inductance, not only both self inductances.

  • @carl112466
    @carl1124662 жыл бұрын

    I think I am missing something! I take the unloaded voltage and it was 3v peak to peak. I connect the inductor but still get the same voltage value of unloaded generator

  • @aronhighgrove4100
    @aronhighgrove41002 ай бұрын

    At 4:17 you said it was 3.06Vpp but later in your calculations at 9:30 it became 3.08Vpp. Did you manually adjust it to get an output impedance closer to 50Ohm?

  • @rocifier
    @rocifier2 жыл бұрын

    Hi, I tried a large inductor that I have and it wouldn't drop the voltage at all. I have the same signal generator as you have and dialed all the way up to ~10Mhz to get to 3V. It only drops down to about 2.7V in the low frequencies. How can I measure it seeing as the voltage doesn't drop by half?

  • @calculatingcapibara2914

    @calculatingcapibara2914

    Жыл бұрын

    Try rearranging the Karen Orton equation for a ratio of 9/10 instead of 1/2. Measure the DC resistance in advance. Note that inductancies are complicated beasts. You can not avoid the need for theory. The method here is not fit for large inductancies. You are likely on the edge of usability here.

  • @CircuitCreator
    @CircuitCreator2 жыл бұрын

    NICE ONE

  • @djfisjtik
    @djfisjtik3 жыл бұрын

    I just wanted to double check. A 0.5 mH inductor at 9300 Hz (from the video) would have a resistance of 29.2 ohms (L * F * 6.28). I think I understand the voltage divider part of the measurement, but therefor it would make more sense to me if the found frequency would result in the same resistance of the output impedance (50 ohms). To get 50 ohms at 9300 Hz you would need 0.86 mH. I'm sure your formula is correct and I simply don't understand how it works. It would be nice if you can elaborate.

  • @ajgd

    @ajgd

    Жыл бұрын

    He puts the original formula in the description and works like you said, you measure the output voltage on the generator unloaded, and then you found a frequency that makes that voltage drops 1/2 and you say that you found the frequency for 50 ohm impedance. He is doing that, but the first thing that he does with the resistor is measuring that +/- 5% of the generator output, that's why he writes 50.49 ohms and not 50. but the other steps, with the inductors, are right, he is searching for a frequency that makes the voltage drops 1.5V (half the initial 3V without load)..... that formula only works if you are searching for 1/2 of Vgen unloaded. sorry if my english is not the best 😅

  • @calculatingcapibara2914

    @calculatingcapibara2914

    Жыл бұрын

    Not 29.2 ohm, but j times 29.2 ohms. J equals sqrt(-1), expressing the fase shift between current and voltage from an inductor.

  • @albertlagerman
    @albertlagerman3 жыл бұрын

    Could you just wire a resistor in series in front of inductor, put a probe before the resistor, and after the resistor, and adjust the frequency until the voltage on the probe after the resistor is half that of the first?

  • @calculatingcapibara2914

    @calculatingcapibara2914

    Жыл бұрын

    No, the faseshift of the L should be taken in account.

  • @kishorebadgujar7445
    @kishorebadgujar74452 жыл бұрын

    can we measure low wattage line 1/4 Watt inductance value using on DSO

  • @calculatingcapibara2914

    @calculatingcapibara2914

    Жыл бұрын

    Theoretically yes. Did you try?

  • @SureshKumar-nk2ok
    @SureshKumar-nk2ok3 жыл бұрын

    sir which frequency will be best to use

  • @ScottMarley

    @ScottMarley

    3 жыл бұрын

    It doesn't matter, just try some and see what works best. 20kHz is a good starting point but you will get the same answer regardless.

  • @Yorumcu63
    @Yorumcu63 Жыл бұрын

    I must watch again

  • @djfisjtik
    @djfisjtik3 жыл бұрын

    Great tips! I tried out this method on my Voltcraft DSO-1084F (rebranded Hantek DSO4084C) scope with builtin function generator and guess the measurement worked out. I measured the output impedance of the generator to be 390 Ohms. Alternative to your calculation of the output impedance of the generator, you could also measure it with a pot, aiming to achieve half of the peak voltage compared to the unloaded state.

  • @ScottMarley

    @ScottMarley

    3 жыл бұрын

    Nice work!

  • @rZERO_game
    @rZERO_game2 жыл бұрын

    my function generator metravi make is bad. its amplitude going smaller when increasing frequency other OHM tech indian make is good upto 1.4Mhz its amplitude remain constant as per set point. i have tested with multisim also, One problem shows that multisim inbuilt function generator or inbuilt agilent function generator shows 50 ohm impedence but when connecting any resistance like 132 ohm its voltage accross 132 ohm does not fall. so my test as per ur methode(finding impedence) is not functioning. then i add additional 50.49 ohm to output and measure as per ur video , it is perfectly working.thanks for ur video,

  • @SlowfingerJC
    @SlowfingerJC Жыл бұрын

    As I understand it, RO is output resistance not output impedance, as impedance is always frequency dependant, which is why it is used as a constant in the formular ie not as a frequency dependant value.

  • @mohamed_abdelrahman10
    @mohamed_abdelrahman103 ай бұрын

    I think to be more accurate in measuring , we should measure resistance of inductor first and do our calculations based on (resistance of function generator and resistance of inductor)

  • @mdasikkhan1610
    @mdasikkhan16102 жыл бұрын

    Im guessing this method is most accurate for higher inductor values. While for lower inductances, since you need to fairly large frequency, the parasitic in the circuit might be relatively big and give a erroneous result

  • @calculatingcapibara2914

    @calculatingcapibara2914

    Жыл бұрын

    It is not the parasitic here. 20Khz is too large a starting value for a large inductor. Try say 1 Khz or even less.

  • @ftmmrbs1996
    @ftmmrbs19963 жыл бұрын

    my function generator says its 50 ohm output impedance but I found it 400 ohms based on this video. is this not strange?

  • @calculatingcapibara2914

    @calculatingcapibara2914

    Жыл бұрын

    Could be that your fg is not 50 ohms output. So connect 400 ohm (or 180+220 or 4*100 in series) and observe the downfall of voltage, and at different frequencies. If 50 %, your Rout is 400, not 50.

  • @kishorebadgujar7445
    @kishorebadgujar74452 жыл бұрын

    how to measure low wattage value inductance(1/4 w,1/2 W) measurement using CRO and Function generator

  • @choke173
    @choke1733 жыл бұрын

    How to get the Vo & Vl value . Thx

  • @pedrova8058

    @pedrova8058

    2 жыл бұрын

    Vo is the voltage of the signal generator output UNLOADED Vl is the voltage with the inductor conected

  • @hanstap6502
    @hanstap65022 жыл бұрын

    Where is the 3.08 V PP coming from? I think it is 3.00 V PP everywhere?

  • @calculatingcapibara2914

    @calculatingcapibara2914

    Жыл бұрын

    I have the same question. Maybe Scott had a look on the oscilloscope, giving that value?

  • @alanpedder3912
    @alanpedder39122 жыл бұрын

    Really enjoyed using this method which was only hampered by my rusty maths. But works perfectly and simplified to 4.614/f for a sig gen impedance of 50.25 ohms

  • @SureshKumar-nk2ok
    @SureshKumar-nk2ok3 жыл бұрын

    sir in formula why 0.5 used for V out by V in

  • @ScottMarley

    @ScottMarley

    3 жыл бұрын

    Again, it doesn't matter. Look at the link in the description, and at the maths after the line "The question now is for what frequency (Vscope/Vgen) = 0.5:". Instead of 1/2, put 1/4 in instead, and follow it through to the end. You should end up with a formula of: L=sqrt(1/15)(R/2 pi f). So if you make the oscilloscope reading 1/4 of the original value instead of 1/2, you would use this formula to calculate the inuductance. 1/2 is just chosen for convenience.

  • @SureshKumar-nk2ok

    @SureshKumar-nk2ok

    Жыл бұрын

    @@ScottMarley yank u so much sir

  • @MichaelPechner
    @MichaelPechner4 ай бұрын

    triple checked. pk->pk 5.08V -> 4.32v 271.5 r so aim for 2.54v 17.490Mhz Getting 2.7 mH - INductor is a 5.6mH. Any clue what I am screwing up? signal generator is new rigol. Oscilloscope is a new 2ga sample siglent. dvm is old HP that passed certs recently. I should be measuring closer to 8Mhz. Just a software engineer trying tolearn to measure toroids he needs to wind.

  • @grahamnichols1416
    @grahamnichols14164 ай бұрын

    Shout out to the Chinese multitesters for having a decent crack at it.

  • @josepeixoto3715
    @josepeixoto37152 ай бұрын

    m or n?

  • @ernestb.2377
    @ernestb.23773 ай бұрын

    👍

  • @luouns
    @luouns2 жыл бұрын

    I have got a headache

  • @sibsbubbles
    @sibsbubbles3 жыл бұрын

    doesn't work

  • @ioscaleb
    @ioscaleb2 жыл бұрын

    Disappointed that you completely punted on explaining the math… I didn’t really need to watch 11 minutes of hooking stuff up to measurement devices; I can figure that out myself. The key thing to know is how to derive the inductance from the measurements, and you skipped that entirely.

  • @rowifi

    @rowifi

    2 жыл бұрын

    I was going to say exactly the same thing.

  • @johnwick7175

    @johnwick7175

    2 жыл бұрын

    He explained it perfectly well. He used the formula for inductive reactance to find a value for the inductance.

  • @spelunkerd

    @spelunkerd

    2 жыл бұрын

    The link in the video description goes through that in detail. I agree, most of the satisfaction comes from the understanding.

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