Max and Min and Second Derivative

At the top and bottom of a curve (Max and Min), the slope is zero. The "second derivative" shows whether the curve is bending down or up. Here is a real-world example of a minimum problem:
What route from home to work takes the shortest time?
View the complete course at: ocw.mit.edu/highlights-of-calc...
Chapters
00:00 Outline
00:24 The Second Derivative: The derivative of the derivative
01:43 Examples of Second Derivatives
08:00 Convex and Concave Curves
09:28 Locating the Maximum and Minimum and the Inflection Point
23:40 Application: Driving to Work, Finding the Minimum Time
License: Creative Commons BY-NC-SA
More information at ocw.mit.edu/terms
More courses at ocw.mit.edu
Subtitles are provided through the generous assistance of Jimmy Ren.

Пікірлер: 194

  • @tomscik1965
    @tomscik19657 жыл бұрын

    MIT courses are not about teaching simple things in a complicated way which ordinary ppl do not understand. It is about teaching complicated things in a simple way where ppl get an extra 'dimension' of understanding. THank you Sir for an excellent lecture and thanks to MIT initiative to provide these courses online for rest of the world.

  • @gurleenkaur9601

    @gurleenkaur9601

    6 жыл бұрын

    Tomsci K very true.

  • @111smily111
    @111smily1114 жыл бұрын

    I got really emotional seeing Professor Strang talk. Seeing a person devoting a lifetime to math and teaching itself is touching and inspiring.

  • @lewis6825

    @lewis6825

    Жыл бұрын

    I have had the same reaction, actually. Btw he just recently retired at age 88. End of an era.

  • @nishantshankarkhan4879
    @nishantshankarkhan48795 жыл бұрын

    This is called a genius because I don't know about others but this presentation is massive and therefore you are the teacher of MIT.Thanks a lot.

  • @Venturebits
    @Venturebits3 жыл бұрын

    Amazing how Professor Gilbert can explain the key ideas clearly. He is by far the best teacher I ever had. A lot of the concepts he explain I usually learned them by memory now I can see the big picture.

  • @ajayupy
    @ajayupy4 жыл бұрын

    It's like watching a superhero of calculus at it's best. Thank you, Sir!

  • @mayurkulkarni755
    @mayurkulkarni7557 жыл бұрын

    34:02 "Drive at a 30 degrees, hope there's a road going that way. Sorry about that point" LOL this guy is genius and funny at the same time :D

  • @Hiyrustrider
    @Hiyrustrider11 жыл бұрын

    This wasn't even part of what I was looking for but I watched the whole thing, I enjoyed this lecture because he's a great Prof.

  • @Tzvetkov
    @Tzvetkov6 жыл бұрын

    "And there's a sign of hope. It started bending up."

  • @saiprakashhadnoor3987
    @saiprakashhadnoor39874 жыл бұрын

    No words for this man's teaching.Really loved it.

  • @ninomatcharashvili9739
    @ninomatcharashvili97396 жыл бұрын

    I have been studying from you sir the main topics in calculus, thank you!

  • @georgesadler7830
    @georgesadler78303 жыл бұрын

    DR. Strang thank you for another excellent lecture on classical selection of max and min problems in calculus.

  • @ingeborgsvensson4896
    @ingeborgsvensson48966 жыл бұрын

    I wish I had had a teacher like Strang in high school. The example of the way to drive to MIT are great ways to explain why you would use these derivatives in real life. Great course! Thank you.

  • @aryaanpetiwalla2655
    @aryaanpetiwalla26553 жыл бұрын

    I saw concave and convex curves, and thought this lecture might be too difficult for me. Then, he explained it so easily and well, and I’m very satisfied having watched this. Thanks a lot!

  • @maelena14
    @maelena1413 жыл бұрын

    God bless you Mr. Strang!! Thank you very much for your efforts... I am taking a second look at calculus as I prepare for graduate school and your videos have been most helpful! Thank you!!!!!!!

  • @LuisMunozCompScience
    @LuisMunozCompScience12 жыл бұрын

    Thanks. One of the most simple, and brilliant explanations regarding this subject.

  • @sajidalishah2653
    @sajidalishah26534 жыл бұрын

    No Matter what Technology advances, need of such brilliant teachers will always be felt

  • @solvability2782
    @solvability27822 жыл бұрын

    Thank you, professor. This is amazingly clear.

  • @silkieshag9703
    @silkieshag97035 жыл бұрын

    excellent explanation, you could be in a regular university, but you could watch classes from the best teachers in the world. Thanks MIT

  • @saisaske1
    @saisaske14 жыл бұрын

    The maxima of "like" function for this video is infinte. This video kept on giving me "aww" moments. Thankyou sir. I always wondered why we need to take the derivative of x and assign to 0. I will always be indebted to you.

  • @zarsblackhorse123
    @zarsblackhorse1235 жыл бұрын

    I never thought i could finish this 38mins video lecture. but once i started to watch its really hard to close the video. Thank you for this excellent lecture Sir and also thanks to MIT for this initiative.

  • @NothingMaster
    @NothingMaster5 жыл бұрын

    Strange truly deserves a Medal of Honor of sorts for his monumental contributions to the advancement and dissemination of mathematical knowledge and intuitions in these MIT series. The Internet has created a whole new and accessible dimension of learning not available to the previous generations of students.

  • @Oneeightseven6
    @Oneeightseven66 жыл бұрын

    This man, has explained this very well!! Thank you for this video!!

  • @laldinpuiarenthlei7615
    @laldinpuiarenthlei76157 жыл бұрын

    hats off for gilbert strang

  • @vinodsah8330
    @vinodsah83304 жыл бұрын

    What a teaching style

  • @renaeneufeld
    @renaeneufeld7 жыл бұрын

    Thank you for this video!! Very well done. I understand soooo much better.

  • @zyxwvutsrqponmlk2000
    @zyxwvutsrqponmlk200013 жыл бұрын

    This is a Hats off to the Calculus Master. Durring my engineering this was just a night mare. I now love calculus after viewing the three parts of this vedio series. Thanks to you. To increase the reach to remotest areas of the world there are lots of breakages that happen during the sessions. It would be good if these vedios could be available for lower bandwidth connections too. A BIG THANK YOU!

  • @skoolwal3874
    @skoolwal38749 жыл бұрын

    Excellence and hard work personified!!

  • @nashabusmani3220
    @nashabusmani32204 жыл бұрын

    Most beautiful way to define double derivative test. Hats off to you sir.

  • @2fluffybunnies
    @2fluffybunnies11 жыл бұрын

    Holy cow, 38 minutes with you on KZread did more good then 2 hours with the book. THANK YOU SO MUCH

  • @Zwide97122
    @Zwide97122 Жыл бұрын

    Doing my masters in Econ Science and I still come to watch these intuition classes by Prof Gilbert. Legendary!

  • @TheFirstBK
    @TheFirstBK11 жыл бұрын

    Thank you very much Dr. Strang, wish I had you back when I took calculus.

  • @laurenmarzlock3419
    @laurenmarzlock34197 жыл бұрын

    I love calculus, It is great exercise for the brain. I love the logic and the patterns.

  • @micahbrill
    @micahbrill10 жыл бұрын

    I really enjoy your videos. You're helping me through my Business Calculus class at Brockport College this semester.

  • @FordBurden
    @FordBurden12 жыл бұрын

    Thank you! I am doing a condensed 8 week course that is kicking my ass and this is making it all "tangible"!

  • @abdalrahmanshaddow6121
    @abdalrahmanshaddow61214 жыл бұрын

    this man play beautiful mathematical music , the exact definition of deep learning

  • @zyxwvutsrqponmlk2000
    @zyxwvutsrqponmlk200013 жыл бұрын

    This is a Hats off to the Calculus Master. Durring my engineering this was just a night mare. I now love calculus. Thanks to you. To increase the reach to remotest areas of the world there are lots of breakages that happen during the sessions. It would be good if these vedios could be available for lower bandwidth connections too. A BIG THANK YOU!

  • @kglayyet
    @kglayyet11 жыл бұрын

    Thank you so much for uploading these courses..

  • @pettyjames7
    @pettyjames78 жыл бұрын

    Thank you, great job explaining.

  • @nemanihanumantharao7439
    @nemanihanumantharao74396 жыл бұрын

    the greatest calculus teacher in the whole wide world

  • @sanjeevmadan2610
    @sanjeevmadan26104 жыл бұрын

    Many thanks, you are excellent, so simple so clear

  • @MISERSTYLE
    @MISERSTYLE11 жыл бұрын

    This guy is an amazing teacher.

  • @mj6637
    @mj66377 жыл бұрын

    Great work, Professor!

  • @erikandresgarciavillarroel3005
    @erikandresgarciavillarroel30056 жыл бұрын

    Thanks a lot for sharing your knowledge!

  • @shibsankarbera9218
    @shibsankarbera92188 жыл бұрын

    nice lecture ...really I highly influenced ....because of its simplicity and graphical interpretation......

  • @jrmom4u
    @jrmom4u5 жыл бұрын

    Appreciated with impressive lecture!

  • @alias40anon
    @alias40anon6 жыл бұрын

    Very good point to point explanation

  • @arjunch2755
    @arjunch27554 жыл бұрын

    this videos are enough for gate exam without practice,i love this lectures

  • @Doug19752533
    @Doug197525338 жыл бұрын

    Prof Strang is COOL! love the videos

  • @choungyoungjae8271
    @choungyoungjae82717 жыл бұрын

    thanks for graphical explanation.

  • @Amine-gz7gq
    @Amine-gz7gq7 күн бұрын

    This video/topic is important to understand the Laplacian in multivariable calculus

  • @Khwartz
    @Khwartz7 жыл бұрын

    Really Very Nice Smooth Teaching :) Btw, been French, looks to me that the French name for calculus is way much meaningful as it is "analyse" (analysis), which is about "cutting in (little) peaces" etymologically, which goes very well imho with the concepts of "dx" and "dy" :)

  • @ankushpatil9039
    @ankushpatil90396 жыл бұрын

    I can't resist to myself to watch these explanations.

  • @andreranulfo-dev8607
    @andreranulfo-dev860722 күн бұрын

    Pure gold!

  • @lauras.9757
    @lauras.97576 жыл бұрын

    Great lecture Prof - thank you! Thanks MIT!! I love me some ♡Calculus♡

  • @lauras.9757

    @lauras.9757

    6 жыл бұрын

    I have now attended Walter Lewin's Physicd class, Susskind at Stanford and Yale Physics and now Mathematics at MIT! I am thrilled to learn from the greatest lecturers/ professors of the day - this is an opportunity I would not have otherwise and it means everything to me. I've learned so much! My sincerest gratitude to you all for these lessons.

  • @nandakumarcheiro
    @nandakumarcheiro2 ай бұрын

    The first and second derivative as combination of zero positive and negative bending as it oscillstes between convex and concave planes differentiated by that an be applied in digital communication developed by Nyquist further developed by shannon where the basic first and second derivative as otherwise may be a function of basic digital functions. Inspired by MIT course offered by this professor. Sankaravelayudhan Nandakumar

  • @mohfa1806
    @mohfa18068 жыл бұрын

    Thank you for this video......just a question , in the end problem why we assume that the answer is the minimum time and not the max time?.....any suggestions?

  • @zensorrow1
    @zensorrow111 жыл бұрын

    "Why move myself 20 miles to MIT when I can, with a click of the mouse, move not 20 inches and absorb the same knowledge." ~The wise musings of an unemployed student drowning in debt

  • @oskarrask9413

    @oskarrask9413

    4 жыл бұрын

    how did it go?

  • @tyrokell1
    @tyrokell111 жыл бұрын

    you are brilliant! thanks a lot mate

  • @nandakumarcheiro
    @nandakumarcheiro2 ай бұрын

    The triangulated surface in modili form is derived at in between maxima and minima around the point of inflection in between with increase in frequency of transition as applicable entropy equation in understanding the hydrogen attraction and repulsion in boson gas as a function of interactive magneticfield over electricfield as Hall's interpretation. A definition on electron gap in between atom and nucleus could be arrived at the interpretation of first derivative and sevond derivative based on the sign of the sevond derivative Sankarabrlayudhan Nandakumar.

  • @qzorn4440
    @qzorn44406 жыл бұрын

    what's up doc? a very relaxing informative lecture. thanks. B+)

  • @KarlSmithByrne
    @KarlSmithByrne12 жыл бұрын

    'If I knew where we were (22:58) mathematics would even more useful than it is...which would be hard to do!' This guy is fantastic.

  • @kaventhwe
    @kaventhwe11 жыл бұрын

    this stuff helps thanks

  • @SydiusVideo
    @SydiusVideo Жыл бұрын

    Thank You!

  • @user-ny1vt3ek4i
    @user-ny1vt3ek4i7 жыл бұрын

    Thank you!!

  • @ghanshyammishra5297
    @ghanshyammishra52977 жыл бұрын

    best explanation

  • @nandakumarcheiro
    @nandakumarcheiro2 жыл бұрын

    The oscillation becoming bending down convex and bending down a concave with inflexion point at which the sign of bending oscillate between concave and convex producing positive and negative energy.

  • @storaman12
    @storaman1213 жыл бұрын

    Thank you

  • @MsManoodle
    @MsManoodle10 жыл бұрын

    this guy is great!

  • @santoryu8940

    @santoryu8940

    7 жыл бұрын

    hi youre cute

  • @yuzheng3091
    @yuzheng309111 жыл бұрын

    thank you so much!

  • @AnkushSingh-kj1zl
    @AnkushSingh-kj1zl6 жыл бұрын

    Nice lecture 👍👍👍

  • @thebaniyabox8147
    @thebaniyabox814712 жыл бұрын

    if i could afford the mit's fees i definitely would have been a part of that institute which is the best in the world.

  • @gaithouri
    @gaithouri13 жыл бұрын

    thank you

  • @allenk7635
    @allenk76355 жыл бұрын

    Thanks!

  • @gdogvibes1
    @gdogvibes111 жыл бұрын

    Thanks.

  • @AndyThomasStaff
    @AndyThomasStaff7 жыл бұрын

    I'm having trouble understanding the word problem at 26:27. I don't understand *why* the fastest time is where the first derivative of the graph is zero. What is the actual graph, and why does the derivative of zero (where the first graph's slope is zero?) mean the fastest time when solving the equation?

  • @faliakuna8162

    @faliakuna8162

    7 жыл бұрын

    It is because the function "time it takes to arrive at work" reaches either a min or a max point when its first derivative is equal to zero. We don't know what its graph looks like, but we do know that its value must reach a min or max when its derivative is zero. So when the value of this function is minimum, the time it takes to arrive at work is minimum, because it is what the value of this function represent, the time it takes to arrive at work.

  • @surajyergude
    @surajyergude5 жыл бұрын

    Will you help me how did you get to the 30 degrees?

  • @chancewatkins5071
    @chancewatkins50717 жыл бұрын

    Love this, I've subscribed. Thanks for sharing; Jesus Christ Bless

  • @eleonoraformatoneeszczepan8807
    @eleonoraformatoneeszczepan88072 жыл бұрын

    MIT OpenCourseWare Max and Min and Second Derivative 'Professor Strang Chapters. The Second Derivative: The derivative of the derivative. Subtitles: Jimmy Ren.' 2:10 min ... acceleration 2:56 min ... Newton's Law, F = ma

  • @LenaIvanovak
    @LenaIvanovak12 жыл бұрын

    great! Thank you!)

  • @nandakumarcheiro
    @nandakumarcheiro2 жыл бұрын

    The combustion graph follow a sin and cos curve follow maximum and minimum.

  • @nandakumarcheiro
    @nandakumarcheiro2 ай бұрын

    The conflection points becomes the square comfogurstoon points pave the way for basic figitsl numbers while denfing the pulses in between zeros and ones in signal sending in computstionsl digitsal mathematics.

  • @nandakumarcheiro
    @nandakumarcheiro2 жыл бұрын

    Thus maxima and minima points with combustion inflexions follow a sine curve and cos curve.

  • @horizonbrave1533
    @horizonbrave15335 жыл бұрын

    @ 8:56 spoken like a true Mathematician!

  • @mahmoudeldesokey147
    @mahmoudeldesokey1476 жыл бұрын

    The best👌

  • @mohfa1806
    @mohfa18068 жыл бұрын

    Sorry i should have watched the last 40 seconds to know the answer to my silly question now :)..the answer is there....great video and wonderful lecturer

  • @JohnM...
    @JohnM...7 жыл бұрын

    what about the 3rd derivative test?....(used specifically when 2nd derivative is zero, giving no clue as to gradient and concavity - as you MAY or MAY NOT have an inflection pt. when f''=0 e.g. straight line). Cool thing about that test is that when the modulus of it >0, we have an inflection point (rising if > 0, falling if

  • @phillipmaina8801
    @phillipmaina88017 жыл бұрын

    When differentiating for the second time your found the two roots as 2/3 and 0. I understand how you got 2/3 but a bit shaky on how you got 0 without the graph. A bit of help would be nice...

  • @iloveselenafan

    @iloveselenafan

    7 жыл бұрын

    if your talking about the 3x^2-2x if you factor it you can pull out a 'x' and a '3x-2' and if you solve for x for both of them you get 0 for 'x' and you get 2/3 for '3x-2'

  • @phillipmaina8801

    @phillipmaina8801

    7 жыл бұрын

    Thank you so much 🙏

  • @RHOLAMOUALID
    @RHOLAMOUALID8 жыл бұрын

    while looking for the min time, you use the deriv=0, but that applies for both the min and the max, why assume that what you found was the min and not the max, without using the second deriv, or by studying the monotony of the function ???

  • @mohfa1806

    @mohfa1806

    8 жыл бұрын

    the lecturer in the last 40-50 seconds explain this point ......he explained that he should have calculated the second derivative at this point to show that the second derivative is positive , and hence its bending upward at this point , so its a minimum.....please watch the last minute of the lecture....regards

  • @LAnonHubbard
    @LAnonHubbard12 жыл бұрын

    Thanks Professor Strang.

  • @user-qj4zr1pj9y

    @user-qj4zr1pj9y

    2 жыл бұрын

    Do you stil remember what you have learned from these lectures ? 😄

  • @newbarker523

    @newbarker523

    2 жыл бұрын

    @@user-qj4zr1pj9y Hi. I was the original poster (though have a different account now). Yes, I still remember what the lectures taught me. Probably because I have found it useful in my job. Maths (I'm from UK) is awesome!

  • @user-qj4zr1pj9y

    @user-qj4zr1pj9y

    2 жыл бұрын

    @@newbarker523 Good for you !! Yaa Maths is awesome when you learn from Gilbert.!!

  • @changtillend5718
    @changtillend57183 жыл бұрын

    Grate...

  • @elamvaluthis7268
    @elamvaluthis72683 жыл бұрын

    Very nice explanation.superb.minutest of minutest study is knowledge.h ow?how?every thing is from mind.Mind is full of equation.while going to bed you must shake your head violently then only equations shall fall down you will get sleep.

  • @neilchakr
    @neilchakr3 жыл бұрын

    how. do. you. explain. so. well.

  • @taimoor722
    @taimoor72212 жыл бұрын

    thanks u sooooooooooooo much

  • @FallenSparrowNz
    @FallenSparrowNz11 жыл бұрын

    you can only do that if the formula for the equation is in the form ax^2 +bx = 0 in this form we can presume that one anwer has to be zero, and it is simple algebra to find out the second number. You would have not seen this very often because most equations we work with are in the form ax^2 + bx + c = 0 this c value muddles it up and means you can not do what he did.

  • @Joe11Blue
    @Joe11Blue7 жыл бұрын

    The good Dr. needs to switch to de-caf. Excellent presentation.

  • @jayadrathas169
    @jayadrathas1699 жыл бұрын

    Good one bruh..was a bit skeptic at first due to,too much fidgeting of yours...but the last problem was cool

  • @MATHSOLVESZONE
    @MATHSOLVESZONE5 жыл бұрын

    Awesome video!!!!! #mathsolveszone #maximaandminima

  • @chrisudell543
    @chrisudell5435 жыл бұрын

    Brilliant lecture! One question, I can't figure out why a/sqrt3 = 30 degrees. On the unit circle, cosx of 30 is sqrt3/2, and sine of 30 degrees is 1/2. Anybody?

  • @wbaumschlager

    @wbaumschlager

    5 жыл бұрын

    a = cos 30 x = sin 30 x = a / sqrt 3 ----------------- sin 30 = cos 30 / sqrt 3 Note that as he said this holds only for a speed ratio of 2/1 which is build in and hidden in sqrt 3. Actually it's x = a / sqrt( (60/30)^2 -1). He lost that somewhere during the process.

  • @lowersaxon
    @lowersaxon5 жыл бұрын

    First class teacher.

  • @PabstOut
    @PabstOut11 жыл бұрын

    divide x on both sides (3x^2)/x=(2x)/x, then simplify to get 3x=2, then divide each side by three to solve for x, x=2/3