Sir, good class

very cool!

I am by no means a mathematician, but here's a method I came up with: 1) **Expression Simplification** (x + 6)! / (x + 2)! = 1680 We know that all factors from 1 to x + 2 will cancel out. Let's introduce a variable u to denote x + 3. The expression can then be rewritten as: u * (u + 1) * (u + 2) * (u + 3) = 1680 2) **Prime Factorization** With our left side simplified to a product of consecutive numbers, let's factorize the right side as well: 1680 => 2^4 * 3 * 5 * 7 3) **Final Trick** Knowing that the factors on the left side are derived from these primes (2, 2, 2, 2, 3, 5, 7) and are consecutive, we can find the viable combination: (5) * (3 * 2) * (7) * (2^3) => 5 * 6 * 7 * 8 From here, we deduce that u equals 5, which means x is 2.

❤❤

did this guy just making math complicated or am I just thinking about that? cuz In my opinion just simplify the distributive property one

selection method: ❌ hard algebra: ✔

@Gekko-cs2ti

Ай бұрын

Selection is heresy

But who even gets 7 min to solve this. There should be a short and smart way.

@Gekko-cs2ti

Ай бұрын

The domain of factorial is positive integers and 0 , you waste time with the negative value