Math Olympiad | A Nice Exponential Problem | VIJAY Maths
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Пікірлер: 11
Another solution : a=18 , b=1 18^1 - 1^ 18 = 18-1 = 17
After thanking professor, we can return the powers of the original equation b= b2/2 and a= a2/2 and complete by your solution state, thanks.
@vijaymaths5483
14 күн бұрын
Thanks a lot 🎈
again:a=18,b=1 or a=1,b=-16
@mayankkatekhaye9220
13 күн бұрын
B can't be as negative as this question says that a,b belongs to +ve integer
You made mistake on (x-y)(x+y) = 17. You made assumption that x and y are whole numbers while they do not have to be as you created them as sqrt(a^b).
17/8=2.1➖ 17/8=2.1 {2.1+2..1}=4.2 2^2.2 1^1.2 1.2 (B ➖ 2+A)
a=1 b=-16 a=3 b=4 a=18 b=1
@petertai2893
13 күн бұрын
用 Python 寫個程式 for a in range(-20,20): for b in range(-20,20): if a==0 or b==0: continue elif a**b-b**a==17: print(f"a={a} b={b}")
@pendulumandraven9338
13 күн бұрын
First one isn't right as it says a,b belongs to Z+
@petertai2893
10 күн бұрын
己重新寫過，這個不會找到負數 for a in range(20): for b in range(20): if a**b-b**a==17: print(f"a={a} b={b}")