Linear Algebra: Projection onto a Subspace
Learn the basics of Linear Algebra with this series from the Worldwide Center of Mathematics. Find more math tutoring and lecture videos on our channel or at centerofmath.org/
Learn the basics of Linear Algebra with this series from the Worldwide Center of Mathematics. Find more math tutoring and lecture videos on our channel or at centerofmath.org/
Пікірлер: 19
The diagram at the beginning was very helpful! Thanks for the video
THANKS YOUR VIDEOS ARE REALLY HELPFUL
This video is not too clear. In order for this to be true, we must have our subspace W spanned by orthogonal or orthonormal vectors to proceed with using the projection formula. We can compute these dim(W) number vectors given dim(W) spanning vectors using the Gram-Schmidt procedure. In your case, your spanning vectors are orthogonal (specifically orthonormal), which is fine. Hope that clears things up in the comments. Computations on point
Thanks It was HELPFUL.
Thank you! Your video helped greatly with my hw
this was really helpful. thank you
Thank you so much sir
THANKYOU.
if I am not mistaking - in the formula in the beginning of the video, we are not dividing by the length - we are dividing by the length^2. since the length is sqrt(vdotv). Did I go wrong?
@AdiJ8
6 жыл бұрын
The length implies sqrt(vdotv)
holy shits, this was so good!
do the vectors in the subspace have to be orthogonal?
@cf9707
6 жыл бұрын
wondering the same thing...
@notme3154
4 жыл бұрын
Remember vector minus its projection being orthogonal to each vector of a subspace. In this case, vector X minus the projected v_ B in the video does workout to have a dot product of zero for each element ∈ V
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@UnifiedaxxS
4 жыл бұрын
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@iossif1000
3 жыл бұрын
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@anoniem012
3 жыл бұрын
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@anoniem012
2 жыл бұрын
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