I just want to Give this teacher a hug. Thank you so much for this lecture. This test is now cracked after years of not knowing it. No video has explained it better. ❤
@rP-ff8qq Жыл бұрын
This was the best video explanation of the JCC procedure. Thankyou for making it in a very easy and digestible way! Love your work!
@franklinduru13954 ай бұрын
This is the best video for JCC. Thanks for this wonderful lecture❤
@PiyaChoudhari
8 күн бұрын
Exactly 💯
@drbjn5362 жыл бұрын
Ma'am thanks for making it simpler to understand and practice. Please make video on binocular balancing/ confirmation of prescription.
@stephaniewilliams9094 ай бұрын
Thank you so much for taking time to make this video on jcc....explained so well❤
@dfrsdav23 Жыл бұрын
Better explanation than others. Thank you veey much
@liliharoon1800 Жыл бұрын
I would like to thank you for this consise yet very informative and helpful video... much appreciated
@drsalmaeissa Жыл бұрын
You are a perfect teacher god bless you
@Ranjuchaurasia7 ай бұрын
❤ everything covered in detail and explained so well… thank u
@daliashehata4839 Жыл бұрын
Thanks a lot ma"am ; Great and simple and to the point 👍👍👍👏👏
@PiyaChoudhari8 күн бұрын
This is the best video ! Accent and r sound is little irritating but it's so informative that I ignored it mine is also not perfect and sometimes my own accent irritates me and hence I improved upon my accent and pronunciations and still Improving but thanks it's very very informative such practical really useful things we were not taught by our consultants and were taunted,irritated for theoretical non sense and insignificant stuff, useless consultants absolutely useless and irritating ! Thanks for giving us the right accurate information thats actually practically very very significant amd useful ! Awesome video I am gonna share this video link 🔗 🖇️ on my revision part along with elkington audio book I am gonna make on my youtube channel !
@manchikantivijayakumari99062 жыл бұрын
Excellent madam, it is very clear for me now, 0.5 for power and 0.25 for axis. I will do this way. Thank you.
@ophthalmologypearls
2 жыл бұрын
Thank you You have interchanged the items. It is 0.5 for axis and 0.25 for power.
@7777simpleman77776 ай бұрын
what an awesome class
@shetyeechoy34283 ай бұрын
Thank you ❤
@user-et6xn2ih7u3 ай бұрын
well explained thank you sooo much
@ophthojooeileyecirclehisha4917 Жыл бұрын
thank you for your teaching thank you
@XxxxxsilvermistxxxxX2 жыл бұрын
Single best reference for JCC. Thank you ma'am! I do have a doubt, though, ma'am. At 6:48, If we are adding the SE to the sphere component, why is there a change in the cylindrical value since we have already accounted for that with the SE?
@ophthalmologypearls
2 жыл бұрын
I was trying to explain that if the cylinder change (by using JCC) is greater than or equal to 0.5, then you change the value of the sphere. In the example shown, the original prescription was -2.00 / -1.00 x 180. So the spherical equivalent becomes -2.50. If we add a -0.50 (because of JCC) to the cylinder, we get -2.00 / -1.50 x 180. Now the spherical equivalent is -2.75. so we add half the cylinder change of opposite sign to the sphere - so since we added a cylinder of -0.50, (to -1.00 to make it -1.50), we should add +0.25 to the sphere - so adding this to the sphere of -2.00, we get -1.75 / -1.50 x 180. The spherical equivalent of this is -2.50, which is the same as our original prescription (prior to JCC testing)
@beegumhazana45758 ай бұрын
Mam ..this is ok ..but when I do JCC .if the patient with - cyl after flipping JCC , pt reports red line is more clear, then theoretically we add minus power .right? But whether we done it practically it's not confirming the power ..y?
@aswanisidharthan34312 ай бұрын
Thank you so much
@SajidhaM-oh2oyАй бұрын
❤
@ahmedoptics99053 ай бұрын
Best ❤
@deepresearchersbynk Жыл бұрын
❤❤ nice
@user-tn2hl9mn4f Жыл бұрын
Mam jcc me phle axis finding karte h ya power
@Ahmed7oo Жыл бұрын
Thanks alots
@srisowmithamurugesan24902 жыл бұрын
Thankyou mam clear explanation mam
@ashikakhadka18228 ай бұрын
Thank you❤
@dr.zeeshanhameed18686 ай бұрын
Thank you so much❤
@issamidrissi5724 Жыл бұрын
THANKS FOR YOU 👍👍👍👍👍👍👍👍
@prasannashetty2526 Жыл бұрын
Hii mam while refining the axis of cyl if patient say minus side is better why should we trun around the minus axis .why we can't rotate towards the plus axis .
@ophthalmologypearls
11 ай бұрын
@prasannashetty2526 , In the example given in the video, the cylinder was rotated in the direction of the minus axis of the Jackson cross cylinder becoz the cylinder in the trial frame was a minus cylinder. If the cylinder in the trial frame was a plus cylinder, then it should be rotated towards the plus axis of the Jackson cross cylinder
@patriziopascotto69352 жыл бұрын
Ottima spiegazione, potrei sapere che tipo di programma usi per fare queste video lezioni? Thanks
@ophthalmologypearls
2 жыл бұрын
Thank you. I make the presentation in power point along with the animations, and screen record the slide show on my laptop while simultaneously doing the voice recording 🙂
@yousefawad1772 Жыл бұрын
Thank you, that was useful ❤
@indiamyland5298 Жыл бұрын
Mam,astigmatic fan test video plz mam
@ophthalmologypearls
Жыл бұрын
Are you an undergraduate or a postgraduate?
@indiamyland5298
Жыл бұрын
@@ophthalmologypearls UG mam
@ophthalmologypearls
Жыл бұрын
Out of curiosity, what is your special interest in this test? It is not required for an undergraduate to know this.
Пікірлер: 45
I just want to Give this teacher a hug. Thank you so much for this lecture. This test is now cracked after years of not knowing it. No video has explained it better. ❤
This was the best video explanation of the JCC procedure. Thankyou for making it in a very easy and digestible way! Love your work!
This is the best video for JCC. Thanks for this wonderful lecture❤
@PiyaChoudhari
8 күн бұрын
Exactly 💯
Ma'am thanks for making it simpler to understand and practice. Please make video on binocular balancing/ confirmation of prescription.
Thank you so much for taking time to make this video on jcc....explained so well❤
Better explanation than others. Thank you veey much
I would like to thank you for this consise yet very informative and helpful video... much appreciated
You are a perfect teacher god bless you
❤ everything covered in detail and explained so well… thank u
Thanks a lot ma"am ; Great and simple and to the point 👍👍👍👏👏
This is the best video ! Accent and r sound is little irritating but it's so informative that I ignored it mine is also not perfect and sometimes my own accent irritates me and hence I improved upon my accent and pronunciations and still Improving but thanks it's very very informative such practical really useful things we were not taught by our consultants and were taunted,irritated for theoretical non sense and insignificant stuff, useless consultants absolutely useless and irritating ! Thanks for giving us the right accurate information thats actually practically very very significant amd useful ! Awesome video I am gonna share this video link 🔗 🖇️ on my revision part along with elkington audio book I am gonna make on my youtube channel !
Excellent madam, it is very clear for me now, 0.5 for power and 0.25 for axis. I will do this way. Thank you.
@ophthalmologypearls
2 жыл бұрын
Thank you You have interchanged the items. It is 0.5 for axis and 0.25 for power.
what an awesome class
Thank you ❤
well explained thank you sooo much
thank you for your teaching thank you
Single best reference for JCC. Thank you ma'am! I do have a doubt, though, ma'am. At 6:48, If we are adding the SE to the sphere component, why is there a change in the cylindrical value since we have already accounted for that with the SE?
@ophthalmologypearls
2 жыл бұрын
I was trying to explain that if the cylinder change (by using JCC) is greater than or equal to 0.5, then you change the value of the sphere. In the example shown, the original prescription was -2.00 / -1.00 x 180. So the spherical equivalent becomes -2.50. If we add a -0.50 (because of JCC) to the cylinder, we get -2.00 / -1.50 x 180. Now the spherical equivalent is -2.75. so we add half the cylinder change of opposite sign to the sphere - so since we added a cylinder of -0.50, (to -1.00 to make it -1.50), we should add +0.25 to the sphere - so adding this to the sphere of -2.00, we get -1.75 / -1.50 x 180. The spherical equivalent of this is -2.50, which is the same as our original prescription (prior to JCC testing)
Mam ..this is ok ..but when I do JCC .if the patient with - cyl after flipping JCC , pt reports red line is more clear, then theoretically we add minus power .right? But whether we done it practically it's not confirming the power ..y?
Thank you so much
❤
Best ❤
❤❤ nice
Mam jcc me phle axis finding karte h ya power
Thanks alots
Thankyou mam clear explanation mam
Thank you❤
Thank you so much❤
THANKS FOR YOU 👍👍👍👍👍👍👍👍
Hii mam while refining the axis of cyl if patient say minus side is better why should we trun around the minus axis .why we can't rotate towards the plus axis .
@ophthalmologypearls
11 ай бұрын
@prasannashetty2526 , In the example given in the video, the cylinder was rotated in the direction of the minus axis of the Jackson cross cylinder becoz the cylinder in the trial frame was a minus cylinder. If the cylinder in the trial frame was a plus cylinder, then it should be rotated towards the plus axis of the Jackson cross cylinder
Ottima spiegazione, potrei sapere che tipo di programma usi per fare queste video lezioni? Thanks
@ophthalmologypearls
2 жыл бұрын
Thank you. I make the presentation in power point along with the animations, and screen record the slide show on my laptop while simultaneously doing the voice recording 🙂
Thank you, that was useful ❤
Mam,astigmatic fan test video plz mam
@ophthalmologypearls
Жыл бұрын
Are you an undergraduate or a postgraduate?
@indiamyland5298
Жыл бұрын
@@ophthalmologypearls UG mam
@ophthalmologypearls
Жыл бұрын
Out of curiosity, what is your special interest in this test? It is not required for an undergraduate to know this.
@indiamyland5298
Жыл бұрын
@@ophthalmologypearls den ok ma'am..thank u mam
very educative
❤
Thank you so much
❤