A level Chemistry Organic Chemistry Introduction - Isomers Structural: Chain Position Functional Group Organic Chemistry | Year 1
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@rah7317 Жыл бұрын
You don’t understand how helpful these videos are. I’ve been using your videos throughout this year and your consistently helping me get As in each test I’ve done. Now I have my chemistry mock exam in 2 days, hopefully that goes well too.
@chemistrytutor
Жыл бұрын
That's brilliant to know thank you! And well done on such consistent high scores! Best of luck for your mocks 😀
@ali_saleemzz7217
5 ай бұрын
how did it go
@rah7317
5 ай бұрын
A* in that mock exam mate, I have now got a levels in roughly 3 months so wish me luck!@@ali_saleemzz7217
@MA-ps5rx6 ай бұрын
I can only imagine the effort needed to produce this quality of videos and explanations, not just for this video but for the entire channel. Thank you very much for putting them on youtube for free.
@chemistrytutor
6 ай бұрын
You're kind to take the time to give this feedback! I really appreciate it 😀
@ordinarykaycee Жыл бұрын
🤍 Introduction - 00:44 Chain Isomers - 4:18 Position Isomers - 8:18 Functional group Isomers - 11:56 Questions on Structural Isomers - 15:56 Sterioisomers - 30:16 E/Z Isomers - 32:14 Questions on Sterioisomers - 39:51
@chemistrytutor
Жыл бұрын
Thanks for this!
@hammad37476 ай бұрын
Hi sir, I’m in year 12 and I’m really hoping by the time I’m in year 13 you have also made all the year 2 videos also as these videos are a huge help 😅
@chemistrytutor
6 ай бұрын
That's definitely my plan! Thanks for the feedback!
@stefanabreu3 жыл бұрын
these videos are a massive help, especially with the example question for us to try. thank you for your hard work in putting these up !
@natasha00743 жыл бұрын
ze zame zide
@chemistrytutor
Жыл бұрын
😀
@mariamadepoju7533 Жыл бұрын
To be very honest I had problems with isomerism but this video was very explanatory. Thank you very much for this lesson .
@chemistrytutor
Жыл бұрын
You're really welcome. It's great for me to know it's useful 🙂
@chikaohizu3357 Жыл бұрын
I'm really glad to have come across this video. Thank you so much sir
@chemistrytutor
Жыл бұрын
I'm really pleased it's useful! I've got other videos you might also like. Let me know if you can't find what you need!
@donmujtaba15 күн бұрын
Why is this being recommended to me on my vacation 😭😭
@chemistrytutor
15 күн бұрын
@@donmujtaba happy holiday!
@oneil12877 Жыл бұрын
Zee zame zide was crazy but it helps💯
@chemistrytutor
Жыл бұрын
Whatever helps you remember 👍👍
@SifaSayyed Жыл бұрын
Thank you very much! So glad to have found this video and channel
@chemistrytutor
Жыл бұрын
Lovely to know its useful!
@morindolph8438 Жыл бұрын
Thank you so much sir!! I have no idea about this chapter till i came across your videos. Thank you so much again!!!
@chemistrytutor
Жыл бұрын
That's really great to hear! So glad they're useful! This document of links may be helpful? drive.google.com/file/d/1s3I5prjbJRR1U1lcKpXO9TQpQMaVoP66/view?usp=drivesdk
@christmas9259 Жыл бұрын
Honestly thankyou so much, I was so stuck on the differences between cis/trans and E/Z for so long that I was lost, but your video was so concise and clear! Thankyou so much!
@chemistrytutor
Жыл бұрын
Thanks for your kind words 😊 I'm really glad the video is useful!
@stefiemartinez4290Ай бұрын
Amazing video, thank you for your effort and tome
@chemistrytutor
Ай бұрын
So nice of you! Glad it was useful 😀
@livetofullest78614 сағат бұрын
This vedio has helped me to calculate the number of isomers especially that include ring isomers like C6H12 Thank u sir from Pakistan 🇵🇰
@chemistrytutor
11 сағат бұрын
@@livetofullest786 that's great to hear! Thanks for your kind feedback 😀
@Wachu-G4 ай бұрын
This video helps a lot, thankk you alwayss. I cannot imagine your effort on the quality of explaination. thanks a lot again
@chemistrytutor
4 ай бұрын
Thank you very much for your kind feedback 😀
@ruhamaalemayehu Жыл бұрын
you explain it in a very detailed way that anyone could understand 🤯
@chemistrytutor
Жыл бұрын
Excellent! I'm really glad it's useful 😀
@nalahenry4531 Жыл бұрын
Find the video very help. Noticed at 24:56 we could have 6 isomers as 2-ethylbutane could be structured and have the same molecular formula
@chemistrytutor
Жыл бұрын
Good thought, but, actually 2-ethylbutane is the same as 3-methylpentane, one is just twisted more. 😃
@mayaresam4355
Жыл бұрын
@@chemistrytutor What about 2-propylpropane??
@chemistrytutor
Жыл бұрын
@@mayaresam4355 if you draw that out you've got a chain of 4 that is bent and you've actually got 2-methtyl butane Always look for the longest chain rather than the horizontal looking part
@joker.editz310 ай бұрын
😍 Thank You For Your Efforts To Make this video 🤩
@chemistrytutor
10 ай бұрын
You're very welcome 😀
@thesolfas2 ай бұрын
Thank up. God bless. 🙏🏼
@chemistrytutor
2 ай бұрын
Thank you! Glad it's useful 😊
@sahib3035 Жыл бұрын
Pleaseee can you do a a full transition metals video? Your videos are the ONLY chemistry resource that actually make me understand it so thank you for that, and currently we’re doing transition metals in class but my teacher is rushing through it as exams are soon. :/
@chemistrytutor
Жыл бұрын
That's really lovely to hear the videos are useful! I haven't got a TM full video scheduled for the near future. I'll add it to the list. I'll be releasing at least one exam question walkthrough soon. Invariably they end up being pretty detailed with their explanations. I've made these previously: kzread.info/dash/bejne/hZOExtmMmrebhdY.html And: kzread.info/dash/bejne/poholtKNqtXbicY.html
@sahib3035
Жыл бұрын
@@chemistrytutor thank you so much!
@chemistrytutor
Жыл бұрын
@@sahib3035 😀
@pariparii Жыл бұрын
you are th best
@chemistrytutor
Жыл бұрын
Thank you 😊
@fatimayasir4909 Жыл бұрын
tysm! you really helped
@chemistrytutor
Жыл бұрын
😀 you're welcome
@thee_pauline10 ай бұрын
Thank you so much sir this was really helpful❤
@chemistrytutor
10 ай бұрын
Thanks for the kind feedback 😀
@AmadoujuldehJallow-zc2sc10 ай бұрын
Thank you very much
@chemistrytutor
10 ай бұрын
I'm glad it's useful!! 😃
@tayyabanawaz34792 жыл бұрын
Hi sir, at 27:08 wouldnt it still be 2-methylbut-1-ene since your always starting from the lowest number, ie from ‘C’ on the right in that case? Thanks
@chemistrytutor
2 жыл бұрын
Hi, good question. It's 3-methylbut-1-ene because once you've started numbering from one end of the carbon you have to just keep counting up as you work along the chain. Since the "ene" is more important we number that as the 1 end and so counting upwards the methyl carbon has to considered to be on the 3rd carbon
@miyumithisewnithennakoon8141 Жыл бұрын
You are a god! That's all I have to say. A GOD!
@chemistrytutor
Жыл бұрын
Thanks so much! It's really great to know it's useful!
@dinoblock8516 Жыл бұрын
Thank you
@chemistrytutor
Жыл бұрын
No problem! Happy it's useful 😊
@pariparii Жыл бұрын
THANK YOU SO MUCH can you please make videos for A2 organic :)
@chemistrytutor
Жыл бұрын
Its on my list 😀 I have some question walkthrough videos already about aromatic and biochemistry
@swapnasreetamma Жыл бұрын
Thank you sir it is useful for my exam And it is easy topic now
@chemistrytutor
Жыл бұрын
That's great to hear, thank you! And well done 👏
@swapnasreetamma
Жыл бұрын
@@chemistrytutor thank you sir
@N1ght5ky Жыл бұрын
Hi sir, at 17:01 (the isomers written in yellow,) why would it not be a chain isomer as it has a different carbon skeleton; the chains are reorganised differently bearing in mind that a cycloalkane is not a functional group? Is this correct?
@chemistrytutor
Жыл бұрын
Good question! I think from the point of view of functional groups, the key thing to consider is that alkenes have the C=C bond and cyclic Alkanes don't. Therefore they're different functional groups. Different FG is always more significant in terms of classification rather than different chains
@MrThelegnd Жыл бұрын
Hi sir, the question at 21:57,, didnt you foreget 1-bromocyclobutane as functional group isomers ?
@chemistrytutor
Жыл бұрын
Great question, but no, when you switch from a regular alkane to a cyclic alkane you lose 2 H atoms. So they aren't Isomers anymore. Thanks for commenting!
@studentraphycraigie7 ай бұрын
Saved me 🙏🙏🙏
@chemistrytutor
7 ай бұрын
I'm glad they've helped ☺️
@breytonkruger7214 Жыл бұрын
You literally saved my exams thanks so much 🙏
@chemistrytutor
Жыл бұрын
Thank you 😊 Good luck!
@ezedavis7760 Жыл бұрын
Hi sir, at 21:57, you were talking about isomer of C4H9Br, you named the first isomer to be 1-bromo butane, I was just thinking, isn't alkane group having the molecular formula of CnH2n+2 ??? But from the compound given, the molecular formula of CH is an alkali, which is CnH2n+1 with br, please how do you explain this, I'm getting confused
@chemistrytutor
Жыл бұрын
Good question. The answer is that 1 bromo butane isn't an alkane, it is a halogenoalkane. Halogenoalkanes don't have the same general formula, it varies based on the type of halogen present, and the number of them present as well (it can be more than one). You can still refer to any branches present as 'alkyl' groups (methyl/ethyl etc), but fundamentally its still a Halogenoalkane
@ezedavis7760
Жыл бұрын
@@chemistrytutor thanks, i get it now... Please how can I get to reach you?? I'm having problems with chemistry way too much
@chemistrytutor
Жыл бұрын
@@ezedavis7760 I always try to respond to comments on videos to help people out. I've got loads of other a level videos you can check out as well. If there was a particular topic you'd be interested in then let me know and I'll see what I can do. I have an idea that I may do streamed tuition at some point, but not just yet
@moseschikusela91822 ай бұрын
exactly
@chemistrytutor
2 ай бұрын
👌
@georgia979 Жыл бұрын
really nice, clear video - thank you! (:
@chemistrytutor
Жыл бұрын
Thank you 😊
@kennyx8482 Жыл бұрын
Hey Sir, regarding ionic bonds. In NaCl, how exactly is the Cl atom stable after gaining an electron from Na (by doing this, its outermost 3rd shell goes from 7 to 8 electrons..BUT..dont you need 18 electrons in 3rd shell to be stable?
@chemistrytutor
Жыл бұрын
Great question! The 3d sub-shell has much more energy than 3p, so it's almost like it's part of the 4th shell not the 3rd. Which is why you fill the 4s before 3d. P block atoms in general don't need to have a full d sub-shell (from the outermost energy level) to be considered stable.
@kennyx8482
Жыл бұрын
@@chemistrytutor ; see this is where i need some brushing up..thanks for that!
@chemistrytutor
Жыл бұрын
@@kennyx8482 no worries 👍
@edgymomof8313 Жыл бұрын
Hello sir! at 24:38 can we have 1,2,3 trimethylpropane as one other isomer
@chemistrytutor
Жыл бұрын
Good question. The answer is no, because what you've drawn is actually 3-methylpentane, that you've curled up/down at the two ends. You can never have 1-methyl anything, in fact, for the same reason.
@edgymomof8313
Жыл бұрын
@@chemistrytutor Thanks a lot!
@oracle04222 жыл бұрын
hi sir... Have u covered hemolytic and hemolytic fission?
@chemistrytutor
2 жыл бұрын
Hi there, I discuss homolytic fission at length in this video... kzread.info/dash/bejne/X4Rhu7mPe5DcZNo.html
@noellecarter93297 ай бұрын
Hi I was taught that when looking at priority groups for CIP rules you look at atomic number NOT atomic mass?
@chemistrytutor
7 ай бұрын
You're 100% correct!! Well spotted. That's an important error to clarify, thank you!
@IgweDaniel-ft9bq3 ай бұрын
is there a way you can also include optical isomerism cause it is now there in my syllabus if you don't mind pls Lovely content too
@chemistrytutor
3 ай бұрын
Separate video 😃 kzread.info/dash/bejne/eJ1l3M6kZr3bf9Y.html
@mdaburaihansk3 ай бұрын
❤❤❤❤❤
@chemistrytutor
3 ай бұрын
😃 thanks
@ruben60002 ай бұрын
Hi, at around 27:00, why couldn't we have 1-methylbut-1-ene, where the methyl group is above, below or to the side of the first carbon? Thanks for the video too sir.
@chemistrytutor
2 ай бұрын
Good thinking... but when you have a hydrocarbon, you can't have 1-methyl anything actually. That would make it a longer chain by 1 that you've drawn curved. So 1-methylbut-1-ene as you named it, is actually pent-2-ene, just drawn twisted at the end
@monishamohan10466 ай бұрын
Thank you for the video! At 45:16 what are the names of E and Z isomers?
@chemistrytutor
6 ай бұрын
On the right? E- and Z- oct-2-ene
@makesan2827 Жыл бұрын
At 24:48 shouldnt there be 6 isomers? i dont know if im fully correct but i got 6 isomers and i did check again after you got 5 isomers.
@chemistrytutor
Жыл бұрын
In order to check your six, I suggest you name the ones you've drawn. The compare it to my list Hexane 2-methylpentane 3-methtlpentane 2,2-dimethylbutane 2,3-dimethylbutane Let me know what you get. I suspect you'll find that you've got 2 that are the same, maybe one is twisted, or you're numbering from different ends
@engineeringmadeasy Жыл бұрын
23:47 why did you CH3 on the second carbon atom instead of 1st carbon atom?
@chemistrytutor
Жыл бұрын
If you put a methyl group on the first carbon then it would not be a methyl group. It would be a longer carbon skeleton 😊
@syedatt68448 ай бұрын
At 29:09 what is the square cycloalkane called? Is there a methyl group there and if there is how would you know which carbon atom it’s coming out of to name it? Also (sorry I know I’m asking a lot) but for changing the functional group can certain molecules only be one other type of molecule. Like can carboxylic acids only be changed to esters so can butanoic acid only change it’s functional group to become an ester? Your video is saving my life in a level Chem thank you so much
@chemistrytutor
8 ай бұрын
A ring of 4 would be cyclobutane. With a methyl group sticking out, it would be methyl cyclobutane. When there is only one branch on a cyclic compound there is no need for a number. The carbon the single branch is on is assumed to be carbon number 1
@chemistrytutor
8 ай бұрын
Also, in terms of 1 FG turning into another FG, yes. Carboxylic acids and Esters are the only Single FG isomer. However, you could technically have a molecule with 2 separate FG being an isomer. So a botanic acid could be an isomer of 2-hydroxybutanal with a C=O group and an OH group on 2 different carbon atoms. Not normally that complicated for a levels though
@Maryam-me6xz5 ай бұрын
maaaaaaaaaaan u saved my life Iam so thankful Iam Egypation btw
@chemistrytutor
5 ай бұрын
That's lovely to know, thanks 😊
@soyadrink9831 Жыл бұрын
3:00 wouldn't it be: diethylcyclopropane? And, for the rules of higher or lower priority we use atomic numbers not the mass number.
@chemistrytutor
Жыл бұрын
At 30 minutes? There is only one ethyl group coming from the ring of 3. Each ethyl group is C2H5, so diethyl cyclopropane is C7H14 To have cylcopropane and only 5 Carbon, the largest size of two branchss you could have is dimethyl
@chanyingwen3589Ай бұрын
Hi for the 28:45 isn’t the C5H10 is alkene ? If it’s alkene can we use cycloalkane for the structural drawing? However, it’s really a useful video 🥹
@chemistrytutor
Ай бұрын
Thank you 😀 C5H10 could be an alkene or a cycloalkane. So when deciding how many structural Isomers there are we need to consider all the different alkenes there can be, as well as all the different cycloalkanes there can be
@daisy-do7wz11 ай бұрын
at 28:24, can 3-methylbut-2-ene also not be an isomer?
@chemistrytutor
11 ай бұрын
Since either of the double bond carbons could be numbered as "2" then the one with the methyl group attached is automatically numbered as 2. If you drew 3-methylbut-2-ene and 2-methylbut-2-ene you'd see that they're both the same. One is the other just rotated
@miawalker300 Жыл бұрын
Hi sir, hope you are well 😊 is there a trick to spotting these isomers?? I can always only spot like 2 for each molecule, I can never get the hydrogens to add up 😭😭
@chemistrytutor
Жыл бұрын
There are definitely strategies that can help. Was it a particular type of structural isomer you struggled with? Chain etc?
@miawalker300
Жыл бұрын
@@chemistrytutor mainly chain isomers
@chemistrytutor
Жыл бұрын
@@miawalker300 gotcha. Well my method is always to work downwards. Start with the longest unbranched chain. Then move one C to an internal position. See how many different places you can put the C. Name them roughly 1-methyl, 2-methyl... this trains you to think about other possible Isomers. 3-methyl?? This is often the same as one methyl (for chain of 5 or 6) so may not be an isomer. Then take a 2nd C off and repeat. Naming them is hugely useful because it stops you using the same one twice. I wouldn't necessarily worry about H if you've simply been asked how many isomers
@miawalker300
Жыл бұрын
@@chemistrytutor thankyou so much you are such a lifesaver honestly, you're literally the only reason I've understood organic chemistry so far 😂😂
@chemistrytutor
Жыл бұрын
@@miawalker300 that's very kind of you to say. I'm glad it's helping. Well done for sticking at it!
@Aakash-yy4jf2 ай бұрын
at 30:00 i think you have named cyclo alkanes wrongly. btw this vid was very useful..
@chemistrytutor
2 ай бұрын
Glad it was useful! In what way do you mean about the naming... which one of the 5 cyclo compounds do you mean?
@lizziellama8 ай бұрын
Do we also need to know cis/trans isomers? Is there a video on that? My teacher went through them even though I'm year 12.
@chemistrytutor
7 ай бұрын
For organic Chemistry you will need E/Z. Cis/trans has some use in the transition metals topic, but it's normally necessary to learn it. It does depend on what exam board you're doing. For AQA for instance the only mention of cis/trans on the specification is cis platin an anticancer drug. Whereas E/Z isomerism has its own section in the alkenes topic
@rooooooooooootib6 ай бұрын
In 27:07, shouldn't the naming be 2-mehtylbut-1-ene since we start counting from the side which has the least number of carbons?
@chemistrytutor
6 ай бұрын
For the one on the middle on the right? Good thinking but you can only number from one of the ends and then progress up as you move towards the other end. We give the alkene highest priority so that makes it -1-ene. Then since we have designated one carbon as carbon number 1 then the methyl carbon must be on carbon number 3
@rooooooooooootib
6 ай бұрын
@@chemistrytutor Got it! Thank you so much sir! These videos truly are a life saver.
@chemistrytutor
6 ай бұрын
@rooooooooooootib thanks for your kind feedback 😀
@chemmy8062 Жыл бұрын
Hello sir, how many past papers do you reckon I should do?
@chemistrytutor
Жыл бұрын
It depends when your exams are, and what type of exam you're working towards. Official external exams... do all of them and then go looking for more questions for challenge 👍
@bloomkitchen39802 жыл бұрын
why can't 2-ethyl butane be an structural isomer for c6h14
@chemistrytutor
2 жыл бұрын
Good question: 2-ethyl butane in fact doesnt exist, its actually 3-methyl pentane. If you've got a picture of it drawn out you should see that what you've done is bent the hydrocarbon chain and what you were thinking of as the ethyl group is actually the beginning of the pentane chain
@thee_pauline10 ай бұрын
Sir at 24:40 can you have 2,3-dimethylpropane , 1,3-dimethylpropane
@chemistrytutor
10 ай бұрын
You can never have a 'branch' on the end of a chain. So with a propane chain of three carbons, the 1 and 3 position are actually ends. Both of those positions turns propane into butane
@littlefry669110 ай бұрын
Your video was soo helpful but I was a little confused at about 22:00 in the video. Why couldn't you position the bromine at the 3rd or 4th carbon? Why can it only be positioned at the 1st and 2nd carbon?
@chemistrytutor
10 ай бұрын
Glad it's useful! You can put it in those positions. BUT, once it's placed in either of those positions, you number from whichever end of the chain makes the numbers the smallest. So if it was on what looks like position 4, for instance, you could turn the molecule over or simply start numbering from the opposite end
@littlefry6691
10 ай бұрын
thank youuu@@chemistrytutor
@chemistrytutor
10 ай бұрын
@@littlefry6691 😀
@ashaabdirahmanyusuf-bc5ti Жыл бұрын
20:11 how did you know that the structural formula in the question has a branch. Y not just a chain of 4 , which would give the second answer
@chemistrytutor
Жыл бұрын
It's because of how I framed the question. I asked which of the drawn formulae was an isomer of the straight chain I drew of butane. So the only Isomers possible *have* to be branched
@thee_pauline10 ай бұрын
Sir at 14:22 the oxygen only has 2 bonds around it does that mean that only carbon is suppose to have 4 bonds around it?
@chemistrytutor
10 ай бұрын
That's correct yes. Carbon has 4 outer electrons so needs another 4 to make the 8, hence 4 covalent bonds. Oxygen in group 6, only needs 2 more electrons, so 2 covalent bonds
@thee_pauline
10 ай бұрын
Thank you Sir ❤
@dancindwight6 ай бұрын
........Br | C / | \ H | H H3C- C - CH3 | H Hello sir I hope you're doing well. I wanted to ask if this (2-Bromomethylpropane?) could be a position isomer for C4H9Br other than the ones you've mentioned @22:35? Also, thank you so much for such a succinct and immaculate explanation!
@chemistrytutor
6 ай бұрын
Thanks for your kind words! And good creativity with drawing the isomer! You've actually drawn 1-bromomethylpropane though. If you swap the H at the bottom for one of the methyl groups on the same C it's more clear. The atoms/groups on a carbon are constantly moving so the fact you got the chain turning at a right angle doesn't prevent it from being a chain of 3, and the bromine is on an end carbon. Well done for thinking deeply about this 😃
@dancindwight
6 ай бұрын
@@chemistrytutor It took me a while to draw the isomer here 😭. Thank you so much for your corrections sir. I completely overlooked the IUPAC rule of starting the count w the carbon attached to the substituent. Thank you sir for clarifying my doubts!
@chemistrytutor
6 ай бұрын
@@dancindwight you're very welcome! Your determination does you credit! 👏
@adzfam81486 ай бұрын
I really enjoy watching your videos as these explain the topics far better than my teachers and in my recent mock i used your videos to get an outstanding grade. Keep it up!
@chemistrytutor
6 ай бұрын
That's really great to hear! Thanks for your kind words, and well done!
@breytonkruger7214 Жыл бұрын
Isn't there another isomer for C6H14 2-ethyl 2methyl propane ?
@chemistrytutor
Жыл бұрын
2 ethyl propane is actually methyl butane that's been twisted. 2 ethyl 2 methyl propane is in fact 2,2-dimethyl butane 😀
@breytonkruger7214
Жыл бұрын
@@chemistrytutor thanks so much have a chem exam tomorrow, your videos are helping me out alot
@chemistrytutor
Жыл бұрын
@@breytonkruger7214 thats great to know! Best of luck for the exam! 😀
@user-py1ch6ye4n6 ай бұрын
In 26:58I think you made a mistake in naming the alkene C5H10; there's a 2 methyl but-1-ene but there can't be a 3 methyl but-1- ene cus we are meant to number from the lowest side so rather it'll still be a 2 methylbut-1-ene
@chemistrytutor
6 ай бұрын
Good thinking but you can only number from one of the ends and then progress up as you move towards the other end. We give the alkene highest priority so that makes it -1-ene. Then since we have designated one carbon as carbon number 1 then the methyl carbon must be on carbon number 3
@chikodiibe8231 Жыл бұрын
Can we write it like this OH instead ft O-H
@chemistrytutor
Жыл бұрын
Sometimes, e.g. for structural and skeletal formulae. But if you've been asked for the displayed formula, you need to show every bond, including the one between the O and H
@MRASHI-ug5ks5 ай бұрын
Thank you very much, can you give me this summary?
@chemistrytutor
5 ай бұрын
I'm not sure what you mean?
@MRASHI-ug5ks
5 ай бұрын
@@chemistrytutor Im just want your file that you explain from it
@zainabbi49926 ай бұрын
For c5h10, is 3-methyl but-1-ene correct?
@chemistrytutor
6 ай бұрын
Yes, you can have 3- methylbut-1-ene. This keeps the double bond functional group ad the highest priority and therefore it gets the 1 👌
@zainabbi4992
6 ай бұрын
@@chemistrytutor so then there'll be a total of 11 isomers?
@chemistrytutor
6 ай бұрын
@@zainabbi4992 it's still 10 Isomers for C5H10. 3-methylbut-1-ene was one of the ones I included in my 5 possible alkenes
@zainabbi4992
6 ай бұрын
@@chemistrytutor oh yes i overlooked, what about 3 methyl but 2 ene?
@chemistrytutor
6 ай бұрын
@zainabbi4992 number it from the other end. I think I drew out this example and then crossed it out as a sneaky repetition
@SammyS9096 ай бұрын
27:50 can we also have 3-methyl-but-2-ene?
@chemistrytutor
6 ай бұрын
Good question. No we can't. If you draw that out as you think it would look, try naming it from the other end instead. You'll see its 2-methylbut-2-ene
@SammyS909
6 ай бұрын
ohhh thanks @@chemistrytutor
@chemistrytutor
6 ай бұрын
@@SammyS909 👌
@shaurya02 жыл бұрын
8:05 why is this not 1-methylpentane?
@chemistrytutor
2 жыл бұрын
That's because the group you want to call methyl isn't a branch, the chain is just twisted at the end. It's all part of the main chain of hexane. For something that is only made of C and H, you can't actually have 1-methyl
@chemistrytutor
2 жыл бұрын
Always think 'what's the longest continuous chain?' Including turns and twistS
@engineeringmadeasy Жыл бұрын
I'm doing OCR (A) A Level Chemistry, can I follow your videos? Can I get an A*?
@chemistrytutor
Жыл бұрын
Yes definitely you can use my videos! The vast majority of the content is the same for all exam boards. The main differences are how they structure the exams. The best way to get an A* is lots of exam paper practice. There are only so many ways they can ask questions about chemistry. Once you've seen all the ones so far, there won't be surprises
@engineeringmadeasy
Жыл бұрын
@@chemistrytutor Thanks you and I really appreciate the effort you put to make these videos.
@user-cv3ck8je1m5 ай бұрын
U forgot a hydrogen for the chain isomers
@chemistrytutor
5 ай бұрын
Great spot 👍
@user-vi2mj5uy7r2 ай бұрын
34:15 Great😂
@chemistrytutor
2 ай бұрын
If it helps, it's a good thing
@informationchannel22 Жыл бұрын
hallo man i have spotted a mistake in your video at 6:06 you fergot to Connect a Carbon atom with a h atom. but your video is assem but a Little too long.
@chemistrytutor
Жыл бұрын
Hey, yes good spot! Don't do that in the exam!! Thanks for the feedback, glad it's useful 😊 I agree, it's a bit long - I've got the pace up more for the more recent videos!
@JC-bu4mv Жыл бұрын
is this aqa?
@chemistrytutor
Жыл бұрын
Yes, definitely. I teach AQA and I always make my videos with aqa in mind. However 95% or more of exam board content is common across all exam boards. So they're good for everyone
@alizakhalid472 Жыл бұрын
where can I find A2 isomerism?
@chemistrytutor
Жыл бұрын
Optical Isomerism is the next video I will be making. Out this week 😃
@chemistrytutor
Жыл бұрын
It's out now 😃 kzread.info/dash/bejne/eJ1l3M6kZr3bf9Y.html
@alizakhalid472
Жыл бұрын
@@chemistrytutor thank you so much!!!
@chemistrytutor
Жыл бұрын
@@alizakhalid472 you're welcome 😊 Let me know what you think 😃
@MariamNuhu-fc9vz Жыл бұрын
Thank you for this video sir but i am a bit confused on 41:50 as i undertsand e/z isomerism but some other resources say that you use the atomic number(proton number) which is 6 for carbon and some say use the mass number which is 12 for carbon so i think thats where i am lost
@chemistrytutor
Жыл бұрын
You're correct, there's often confusion between them. I think it's because both normally go together (larger Ar also has a larger atomic number mostly). Strictly speaking, Atomic number is correct. Most a level questions don't require you to make that distinction. Normally you're drawing or Naming the different isomers
@MariamNuhu-fc9vz
Жыл бұрын
@@chemistrytutor ahh i understand now Thank you so much sir for taking the time to explain!
@zebamaryam Жыл бұрын
ze zame zide lol
@chemistrytutor
Жыл бұрын
😂 if it helps you remember it, perfect
@worsh1pperofAllah7 ай бұрын
Hi Sir, regarding 28:00, wouldn't another isomer be 3-methylbut-2-ene? Because there are no duplicates. Thanks in advance!
@chemistrytutor
7 ай бұрын
That's a great question, and I can see why you'd suggest it. In fact 3-methylbut-2-ene doesn't exist. It's identical to 2-methylbut-2-ene in terms of structure. So we name it in the way that keeps the numbers as small as possible 😊
Пікірлер: 201
You don’t understand how helpful these videos are. I’ve been using your videos throughout this year and your consistently helping me get As in each test I’ve done. Now I have my chemistry mock exam in 2 days, hopefully that goes well too.
@chemistrytutor
Жыл бұрын
That's brilliant to know thank you! And well done on such consistent high scores! Best of luck for your mocks 😀
@ali_saleemzz7217
5 ай бұрын
how did it go
@rah7317
5 ай бұрын
A* in that mock exam mate, I have now got a levels in roughly 3 months so wish me luck!@@ali_saleemzz7217
I can only imagine the effort needed to produce this quality of videos and explanations, not just for this video but for the entire channel. Thank you very much for putting them on youtube for free.
@chemistrytutor
6 ай бұрын
You're kind to take the time to give this feedback! I really appreciate it 😀
🤍 Introduction - 00:44 Chain Isomers - 4:18 Position Isomers - 8:18 Functional group Isomers - 11:56 Questions on Structural Isomers - 15:56 Sterioisomers - 30:16 E/Z Isomers - 32:14 Questions on Sterioisomers - 39:51
@chemistrytutor
Жыл бұрын
Thanks for this!
Hi sir, I’m in year 12 and I’m really hoping by the time I’m in year 13 you have also made all the year 2 videos also as these videos are a huge help 😅
@chemistrytutor
6 ай бұрын
That's definitely my plan! Thanks for the feedback!
these videos are a massive help, especially with the example question for us to try. thank you for your hard work in putting these up !
ze zame zide
@chemistrytutor
Жыл бұрын
😀
To be very honest I had problems with isomerism but this video was very explanatory. Thank you very much for this lesson .
@chemistrytutor
Жыл бұрын
You're really welcome. It's great for me to know it's useful 🙂
I'm really glad to have come across this video. Thank you so much sir
@chemistrytutor
Жыл бұрын
I'm really pleased it's useful! I've got other videos you might also like. Let me know if you can't find what you need!
Why is this being recommended to me on my vacation 😭😭
@chemistrytutor
15 күн бұрын
@@donmujtaba happy holiday!
Zee zame zide was crazy but it helps💯
@chemistrytutor
Жыл бұрын
Whatever helps you remember 👍👍
Thank you very much! So glad to have found this video and channel
@chemistrytutor
Жыл бұрын
Lovely to know its useful!
Thank you so much sir!! I have no idea about this chapter till i came across your videos. Thank you so much again!!!
@chemistrytutor
Жыл бұрын
That's really great to hear! So glad they're useful! This document of links may be helpful? drive.google.com/file/d/1s3I5prjbJRR1U1lcKpXO9TQpQMaVoP66/view?usp=drivesdk
Honestly thankyou so much, I was so stuck on the differences between cis/trans and E/Z for so long that I was lost, but your video was so concise and clear! Thankyou so much!
@chemistrytutor
Жыл бұрын
Thanks for your kind words 😊 I'm really glad the video is useful!
Amazing video, thank you for your effort and tome
@chemistrytutor
Ай бұрын
So nice of you! Glad it was useful 😀
This vedio has helped me to calculate the number of isomers especially that include ring isomers like C6H12 Thank u sir from Pakistan 🇵🇰
@chemistrytutor
11 сағат бұрын
@@livetofullest786 that's great to hear! Thanks for your kind feedback 😀
This video helps a lot, thankk you alwayss. I cannot imagine your effort on the quality of explaination. thanks a lot again
@chemistrytutor
4 ай бұрын
Thank you very much for your kind feedback 😀
you explain it in a very detailed way that anyone could understand 🤯
@chemistrytutor
Жыл бұрын
Excellent! I'm really glad it's useful 😀
Find the video very help. Noticed at 24:56 we could have 6 isomers as 2-ethylbutane could be structured and have the same molecular formula
@chemistrytutor
Жыл бұрын
Good thought, but, actually 2-ethylbutane is the same as 3-methylpentane, one is just twisted more. 😃
@mayaresam4355
Жыл бұрын
@@chemistrytutor What about 2-propylpropane??
@chemistrytutor
Жыл бұрын
@@mayaresam4355 if you draw that out you've got a chain of 4 that is bent and you've actually got 2-methtyl butane Always look for the longest chain rather than the horizontal looking part
😍 Thank You For Your Efforts To Make this video 🤩
@chemistrytutor
10 ай бұрын
You're very welcome 😀
Thank up. God bless. 🙏🏼
@chemistrytutor
2 ай бұрын
Thank you! Glad it's useful 😊
Pleaseee can you do a a full transition metals video? Your videos are the ONLY chemistry resource that actually make me understand it so thank you for that, and currently we’re doing transition metals in class but my teacher is rushing through it as exams are soon. :/
@chemistrytutor
Жыл бұрын
That's really lovely to hear the videos are useful! I haven't got a TM full video scheduled for the near future. I'll add it to the list. I'll be releasing at least one exam question walkthrough soon. Invariably they end up being pretty detailed with their explanations. I've made these previously: kzread.info/dash/bejne/hZOExtmMmrebhdY.html And: kzread.info/dash/bejne/poholtKNqtXbicY.html
@sahib3035
Жыл бұрын
@@chemistrytutor thank you so much!
@chemistrytutor
Жыл бұрын
@@sahib3035 😀
you are th best
@chemistrytutor
Жыл бұрын
Thank you 😊
tysm! you really helped
@chemistrytutor
Жыл бұрын
😀 you're welcome
Thank you so much sir this was really helpful❤
@chemistrytutor
10 ай бұрын
Thanks for the kind feedback 😀
Thank you very much
@chemistrytutor
10 ай бұрын
I'm glad it's useful!! 😃
Hi sir, at 27:08 wouldnt it still be 2-methylbut-1-ene since your always starting from the lowest number, ie from ‘C’ on the right in that case? Thanks
@chemistrytutor
2 жыл бұрын
Hi, good question. It's 3-methylbut-1-ene because once you've started numbering from one end of the carbon you have to just keep counting up as you work along the chain. Since the "ene" is more important we number that as the 1 end and so counting upwards the methyl carbon has to considered to be on the 3rd carbon
You are a god! That's all I have to say. A GOD!
@chemistrytutor
Жыл бұрын
Thanks so much! It's really great to know it's useful!
Thank you
@chemistrytutor
Жыл бұрын
No problem! Happy it's useful 😊
THANK YOU SO MUCH can you please make videos for A2 organic :)
@chemistrytutor
Жыл бұрын
Its on my list 😀 I have some question walkthrough videos already about aromatic and biochemistry
Thank you sir it is useful for my exam And it is easy topic now
@chemistrytutor
Жыл бұрын
That's great to hear, thank you! And well done 👏
@swapnasreetamma
Жыл бұрын
@@chemistrytutor thank you sir
Hi sir, at 17:01 (the isomers written in yellow,) why would it not be a chain isomer as it has a different carbon skeleton; the chains are reorganised differently bearing in mind that a cycloalkane is not a functional group? Is this correct?
@chemistrytutor
Жыл бұрын
Good question! I think from the point of view of functional groups, the key thing to consider is that alkenes have the C=C bond and cyclic Alkanes don't. Therefore they're different functional groups. Different FG is always more significant in terms of classification rather than different chains
Hi sir, the question at 21:57,, didnt you foreget 1-bromocyclobutane as functional group isomers ?
@chemistrytutor
Жыл бұрын
Great question, but no, when you switch from a regular alkane to a cyclic alkane you lose 2 H atoms. So they aren't Isomers anymore. Thanks for commenting!
Saved me 🙏🙏🙏
@chemistrytutor
7 ай бұрын
I'm glad they've helped ☺️
You literally saved my exams thanks so much 🙏
@chemistrytutor
Жыл бұрын
Thank you 😊 Good luck!
Hi sir, at 21:57, you were talking about isomer of C4H9Br, you named the first isomer to be 1-bromo butane, I was just thinking, isn't alkane group having the molecular formula of CnH2n+2 ??? But from the compound given, the molecular formula of CH is an alkali, which is CnH2n+1 with br, please how do you explain this, I'm getting confused
@chemistrytutor
Жыл бұрын
Good question. The answer is that 1 bromo butane isn't an alkane, it is a halogenoalkane. Halogenoalkanes don't have the same general formula, it varies based on the type of halogen present, and the number of them present as well (it can be more than one). You can still refer to any branches present as 'alkyl' groups (methyl/ethyl etc), but fundamentally its still a Halogenoalkane
@ezedavis7760
Жыл бұрын
@@chemistrytutor thanks, i get it now... Please how can I get to reach you?? I'm having problems with chemistry way too much
@chemistrytutor
Жыл бұрын
@@ezedavis7760 I always try to respond to comments on videos to help people out. I've got loads of other a level videos you can check out as well. If there was a particular topic you'd be interested in then let me know and I'll see what I can do. I have an idea that I may do streamed tuition at some point, but not just yet
exactly
@chemistrytutor
2 ай бұрын
👌
really nice, clear video - thank you! (:
@chemistrytutor
Жыл бұрын
Thank you 😊
Hey Sir, regarding ionic bonds. In NaCl, how exactly is the Cl atom stable after gaining an electron from Na (by doing this, its outermost 3rd shell goes from 7 to 8 electrons..BUT..dont you need 18 electrons in 3rd shell to be stable?
@chemistrytutor
Жыл бұрын
Great question! The 3d sub-shell has much more energy than 3p, so it's almost like it's part of the 4th shell not the 3rd. Which is why you fill the 4s before 3d. P block atoms in general don't need to have a full d sub-shell (from the outermost energy level) to be considered stable.
@kennyx8482
Жыл бұрын
@@chemistrytutor ; see this is where i need some brushing up..thanks for that!
@chemistrytutor
Жыл бұрын
@@kennyx8482 no worries 👍
Hello sir! at 24:38 can we have 1,2,3 trimethylpropane as one other isomer
@chemistrytutor
Жыл бұрын
Good question. The answer is no, because what you've drawn is actually 3-methylpentane, that you've curled up/down at the two ends. You can never have 1-methyl anything, in fact, for the same reason.
@edgymomof8313
Жыл бұрын
@@chemistrytutor Thanks a lot!
hi sir... Have u covered hemolytic and hemolytic fission?
@chemistrytutor
2 жыл бұрын
Hi there, I discuss homolytic fission at length in this video... kzread.info/dash/bejne/X4Rhu7mPe5DcZNo.html
Hi I was taught that when looking at priority groups for CIP rules you look at atomic number NOT atomic mass?
@chemistrytutor
7 ай бұрын
You're 100% correct!! Well spotted. That's an important error to clarify, thank you!
is there a way you can also include optical isomerism cause it is now there in my syllabus if you don't mind pls Lovely content too
@chemistrytutor
3 ай бұрын
Separate video 😃 kzread.info/dash/bejne/eJ1l3M6kZr3bf9Y.html
❤❤❤❤❤
@chemistrytutor
3 ай бұрын
😃 thanks
Hi, at around 27:00, why couldn't we have 1-methylbut-1-ene, where the methyl group is above, below or to the side of the first carbon? Thanks for the video too sir.
@chemistrytutor
2 ай бұрын
Good thinking... but when you have a hydrocarbon, you can't have 1-methyl anything actually. That would make it a longer chain by 1 that you've drawn curved. So 1-methylbut-1-ene as you named it, is actually pent-2-ene, just drawn twisted at the end
Thank you for the video! At 45:16 what are the names of E and Z isomers?
@chemistrytutor
6 ай бұрын
On the right? E- and Z- oct-2-ene
At 24:48 shouldnt there be 6 isomers? i dont know if im fully correct but i got 6 isomers and i did check again after you got 5 isomers.
@chemistrytutor
Жыл бұрын
In order to check your six, I suggest you name the ones you've drawn. The compare it to my list Hexane 2-methylpentane 3-methtlpentane 2,2-dimethylbutane 2,3-dimethylbutane Let me know what you get. I suspect you'll find that you've got 2 that are the same, maybe one is twisted, or you're numbering from different ends
23:47 why did you CH3 on the second carbon atom instead of 1st carbon atom?
@chemistrytutor
Жыл бұрын
If you put a methyl group on the first carbon then it would not be a methyl group. It would be a longer carbon skeleton 😊
At 29:09 what is the square cycloalkane called? Is there a methyl group there and if there is how would you know which carbon atom it’s coming out of to name it? Also (sorry I know I’m asking a lot) but for changing the functional group can certain molecules only be one other type of molecule. Like can carboxylic acids only be changed to esters so can butanoic acid only change it’s functional group to become an ester? Your video is saving my life in a level Chem thank you so much
@chemistrytutor
8 ай бұрын
A ring of 4 would be cyclobutane. With a methyl group sticking out, it would be methyl cyclobutane. When there is only one branch on a cyclic compound there is no need for a number. The carbon the single branch is on is assumed to be carbon number 1
@chemistrytutor
8 ай бұрын
Also, in terms of 1 FG turning into another FG, yes. Carboxylic acids and Esters are the only Single FG isomer. However, you could technically have a molecule with 2 separate FG being an isomer. So a botanic acid could be an isomer of 2-hydroxybutanal with a C=O group and an OH group on 2 different carbon atoms. Not normally that complicated for a levels though
maaaaaaaaaaan u saved my life Iam so thankful Iam Egypation btw
@chemistrytutor
5 ай бұрын
That's lovely to know, thanks 😊
3:00 wouldn't it be: diethylcyclopropane? And, for the rules of higher or lower priority we use atomic numbers not the mass number.
@chemistrytutor
Жыл бұрын
At 30 minutes? There is only one ethyl group coming from the ring of 3. Each ethyl group is C2H5, so diethyl cyclopropane is C7H14 To have cylcopropane and only 5 Carbon, the largest size of two branchss you could have is dimethyl
Hi for the 28:45 isn’t the C5H10 is alkene ? If it’s alkene can we use cycloalkane for the structural drawing? However, it’s really a useful video 🥹
@chemistrytutor
Ай бұрын
Thank you 😀 C5H10 could be an alkene or a cycloalkane. So when deciding how many structural Isomers there are we need to consider all the different alkenes there can be, as well as all the different cycloalkanes there can be
at 28:24, can 3-methylbut-2-ene also not be an isomer?
@chemistrytutor
11 ай бұрын
Since either of the double bond carbons could be numbered as "2" then the one with the methyl group attached is automatically numbered as 2. If you drew 3-methylbut-2-ene and 2-methylbut-2-ene you'd see that they're both the same. One is the other just rotated
Hi sir, hope you are well 😊 is there a trick to spotting these isomers?? I can always only spot like 2 for each molecule, I can never get the hydrogens to add up 😭😭
@chemistrytutor
Жыл бұрын
There are definitely strategies that can help. Was it a particular type of structural isomer you struggled with? Chain etc?
@miawalker300
Жыл бұрын
@@chemistrytutor mainly chain isomers
@chemistrytutor
Жыл бұрын
@@miawalker300 gotcha. Well my method is always to work downwards. Start with the longest unbranched chain. Then move one C to an internal position. See how many different places you can put the C. Name them roughly 1-methyl, 2-methyl... this trains you to think about other possible Isomers. 3-methyl?? This is often the same as one methyl (for chain of 5 or 6) so may not be an isomer. Then take a 2nd C off and repeat. Naming them is hugely useful because it stops you using the same one twice. I wouldn't necessarily worry about H if you've simply been asked how many isomers
@miawalker300
Жыл бұрын
@@chemistrytutor thankyou so much you are such a lifesaver honestly, you're literally the only reason I've understood organic chemistry so far 😂😂
@chemistrytutor
Жыл бұрын
@@miawalker300 that's very kind of you to say. I'm glad it's helping. Well done for sticking at it!
at 30:00 i think you have named cyclo alkanes wrongly. btw this vid was very useful..
@chemistrytutor
2 ай бұрын
Glad it was useful! In what way do you mean about the naming... which one of the 5 cyclo compounds do you mean?
Do we also need to know cis/trans isomers? Is there a video on that? My teacher went through them even though I'm year 12.
@chemistrytutor
7 ай бұрын
For organic Chemistry you will need E/Z. Cis/trans has some use in the transition metals topic, but it's normally necessary to learn it. It does depend on what exam board you're doing. For AQA for instance the only mention of cis/trans on the specification is cis platin an anticancer drug. Whereas E/Z isomerism has its own section in the alkenes topic
In 27:07, shouldn't the naming be 2-mehtylbut-1-ene since we start counting from the side which has the least number of carbons?
@chemistrytutor
6 ай бұрын
For the one on the middle on the right? Good thinking but you can only number from one of the ends and then progress up as you move towards the other end. We give the alkene highest priority so that makes it -1-ene. Then since we have designated one carbon as carbon number 1 then the methyl carbon must be on carbon number 3
@rooooooooooootib
6 ай бұрын
@@chemistrytutor Got it! Thank you so much sir! These videos truly are a life saver.
@chemistrytutor
6 ай бұрын
@rooooooooooootib thanks for your kind feedback 😀
Hello sir, how many past papers do you reckon I should do?
@chemistrytutor
Жыл бұрын
It depends when your exams are, and what type of exam you're working towards. Official external exams... do all of them and then go looking for more questions for challenge 👍
why can't 2-ethyl butane be an structural isomer for c6h14
@chemistrytutor
2 жыл бұрын
Good question: 2-ethyl butane in fact doesnt exist, its actually 3-methyl pentane. If you've got a picture of it drawn out you should see that what you've done is bent the hydrocarbon chain and what you were thinking of as the ethyl group is actually the beginning of the pentane chain
Sir at 24:40 can you have 2,3-dimethylpropane , 1,3-dimethylpropane
@chemistrytutor
10 ай бұрын
You can never have a 'branch' on the end of a chain. So with a propane chain of three carbons, the 1 and 3 position are actually ends. Both of those positions turns propane into butane
Your video was soo helpful but I was a little confused at about 22:00 in the video. Why couldn't you position the bromine at the 3rd or 4th carbon? Why can it only be positioned at the 1st and 2nd carbon?
@chemistrytutor
10 ай бұрын
Glad it's useful! You can put it in those positions. BUT, once it's placed in either of those positions, you number from whichever end of the chain makes the numbers the smallest. So if it was on what looks like position 4, for instance, you could turn the molecule over or simply start numbering from the opposite end
@littlefry6691
10 ай бұрын
thank youuu@@chemistrytutor
@chemistrytutor
10 ай бұрын
@@littlefry6691 😀
20:11 how did you know that the structural formula in the question has a branch. Y not just a chain of 4 , which would give the second answer
@chemistrytutor
Жыл бұрын
It's because of how I framed the question. I asked which of the drawn formulae was an isomer of the straight chain I drew of butane. So the only Isomers possible *have* to be branched
Sir at 14:22 the oxygen only has 2 bonds around it does that mean that only carbon is suppose to have 4 bonds around it?
@chemistrytutor
10 ай бұрын
That's correct yes. Carbon has 4 outer electrons so needs another 4 to make the 8, hence 4 covalent bonds. Oxygen in group 6, only needs 2 more electrons, so 2 covalent bonds
@thee_pauline
10 ай бұрын
Thank you Sir ❤
........Br | C / | \ H | H H3C- C - CH3 | H Hello sir I hope you're doing well. I wanted to ask if this (2-Bromomethylpropane?) could be a position isomer for C4H9Br other than the ones you've mentioned @22:35? Also, thank you so much for such a succinct and immaculate explanation!
@chemistrytutor
6 ай бұрын
Thanks for your kind words! And good creativity with drawing the isomer! You've actually drawn 1-bromomethylpropane though. If you swap the H at the bottom for one of the methyl groups on the same C it's more clear. The atoms/groups on a carbon are constantly moving so the fact you got the chain turning at a right angle doesn't prevent it from being a chain of 3, and the bromine is on an end carbon. Well done for thinking deeply about this 😃
@dancindwight
6 ай бұрын
@@chemistrytutor It took me a while to draw the isomer here 😭. Thank you so much for your corrections sir. I completely overlooked the IUPAC rule of starting the count w the carbon attached to the substituent. Thank you sir for clarifying my doubts!
@chemistrytutor
6 ай бұрын
@@dancindwight you're very welcome! Your determination does you credit! 👏
I really enjoy watching your videos as these explain the topics far better than my teachers and in my recent mock i used your videos to get an outstanding grade. Keep it up!
@chemistrytutor
6 ай бұрын
That's really great to hear! Thanks for your kind words, and well done!
Isn't there another isomer for C6H14 2-ethyl 2methyl propane ?
@chemistrytutor
Жыл бұрын
2 ethyl propane is actually methyl butane that's been twisted. 2 ethyl 2 methyl propane is in fact 2,2-dimethyl butane 😀
@breytonkruger7214
Жыл бұрын
@@chemistrytutor thanks so much have a chem exam tomorrow, your videos are helping me out alot
@chemistrytutor
Жыл бұрын
@@breytonkruger7214 thats great to know! Best of luck for the exam! 😀
In 26:58I think you made a mistake in naming the alkene C5H10; there's a 2 methyl but-1-ene but there can't be a 3 methyl but-1- ene cus we are meant to number from the lowest side so rather it'll still be a 2 methylbut-1-ene
@chemistrytutor
6 ай бұрын
Good thinking but you can only number from one of the ends and then progress up as you move towards the other end. We give the alkene highest priority so that makes it -1-ene. Then since we have designated one carbon as carbon number 1 then the methyl carbon must be on carbon number 3
Can we write it like this OH instead ft O-H
@chemistrytutor
Жыл бұрын
Sometimes, e.g. for structural and skeletal formulae. But if you've been asked for the displayed formula, you need to show every bond, including the one between the O and H
Thank you very much, can you give me this summary?
@chemistrytutor
5 ай бұрын
I'm not sure what you mean?
@MRASHI-ug5ks
5 ай бұрын
@@chemistrytutor Im just want your file that you explain from it
For c5h10, is 3-methyl but-1-ene correct?
@chemistrytutor
6 ай бұрын
Yes, you can have 3- methylbut-1-ene. This keeps the double bond functional group ad the highest priority and therefore it gets the 1 👌
@zainabbi4992
6 ай бұрын
@@chemistrytutor so then there'll be a total of 11 isomers?
@chemistrytutor
6 ай бұрын
@@zainabbi4992 it's still 10 Isomers for C5H10. 3-methylbut-1-ene was one of the ones I included in my 5 possible alkenes
@zainabbi4992
6 ай бұрын
@@chemistrytutor oh yes i overlooked, what about 3 methyl but 2 ene?
@chemistrytutor
6 ай бұрын
@zainabbi4992 number it from the other end. I think I drew out this example and then crossed it out as a sneaky repetition
27:50 can we also have 3-methyl-but-2-ene?
@chemistrytutor
6 ай бұрын
Good question. No we can't. If you draw that out as you think it would look, try naming it from the other end instead. You'll see its 2-methylbut-2-ene
@SammyS909
6 ай бұрын
ohhh thanks @@chemistrytutor
@chemistrytutor
6 ай бұрын
@@SammyS909 👌
8:05 why is this not 1-methylpentane?
@chemistrytutor
2 жыл бұрын
That's because the group you want to call methyl isn't a branch, the chain is just twisted at the end. It's all part of the main chain of hexane. For something that is only made of C and H, you can't actually have 1-methyl
@chemistrytutor
2 жыл бұрын
Always think 'what's the longest continuous chain?' Including turns and twistS
I'm doing OCR (A) A Level Chemistry, can I follow your videos? Can I get an A*?
@chemistrytutor
Жыл бұрын
Yes definitely you can use my videos! The vast majority of the content is the same for all exam boards. The main differences are how they structure the exams. The best way to get an A* is lots of exam paper practice. There are only so many ways they can ask questions about chemistry. Once you've seen all the ones so far, there won't be surprises
@engineeringmadeasy
Жыл бұрын
@@chemistrytutor Thanks you and I really appreciate the effort you put to make these videos.
U forgot a hydrogen for the chain isomers
@chemistrytutor
5 ай бұрын
Great spot 👍
34:15 Great😂
@chemistrytutor
2 ай бұрын
If it helps, it's a good thing
hallo man i have spotted a mistake in your video at 6:06 you fergot to Connect a Carbon atom with a h atom. but your video is assem but a Little too long.
@chemistrytutor
Жыл бұрын
Hey, yes good spot! Don't do that in the exam!! Thanks for the feedback, glad it's useful 😊 I agree, it's a bit long - I've got the pace up more for the more recent videos!
is this aqa?
@chemistrytutor
Жыл бұрын
Yes, definitely. I teach AQA and I always make my videos with aqa in mind. However 95% or more of exam board content is common across all exam boards. So they're good for everyone
where can I find A2 isomerism?
@chemistrytutor
Жыл бұрын
Optical Isomerism is the next video I will be making. Out this week 😃
@chemistrytutor
Жыл бұрын
It's out now 😃 kzread.info/dash/bejne/eJ1l3M6kZr3bf9Y.html
@alizakhalid472
Жыл бұрын
@@chemistrytutor thank you so much!!!
@chemistrytutor
Жыл бұрын
@@alizakhalid472 you're welcome 😊 Let me know what you think 😃
Thank you for this video sir but i am a bit confused on 41:50 as i undertsand e/z isomerism but some other resources say that you use the atomic number(proton number) which is 6 for carbon and some say use the mass number which is 12 for carbon so i think thats where i am lost
@chemistrytutor
Жыл бұрын
You're correct, there's often confusion between them. I think it's because both normally go together (larger Ar also has a larger atomic number mostly). Strictly speaking, Atomic number is correct. Most a level questions don't require you to make that distinction. Normally you're drawing or Naming the different isomers
@MariamNuhu-fc9vz
Жыл бұрын
@@chemistrytutor ahh i understand now Thank you so much sir for taking the time to explain!
ze zame zide lol
@chemistrytutor
Жыл бұрын
😂 if it helps you remember it, perfect
Hi Sir, regarding 28:00, wouldn't another isomer be 3-methylbut-2-ene? Because there are no duplicates. Thanks in advance!
@chemistrytutor
7 ай бұрын
That's a great question, and I can see why you'd suggest it. In fact 3-methylbut-2-ene doesn't exist. It's identical to 2-methylbut-2-ene in terms of structure. So we name it in the way that keeps the numbers as small as possible 😊