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it would help if you showed a failed capacitor...what will that show?

This test was NOT correct. In the last step, he tested the battery voltage since the 9v battery was still connected. What he should have done was disconnect the jumper cables before testing the charged voltage of the capacitor.

@larrymace2361

4 ай бұрын

You are right, however, he already addresses this mistake in the video.

@gabrieldegois8687

3 ай бұрын

True. Do disconnect the battery before or else you will measure the battery voltage.

@111boldoo

2 ай бұрын

How long should we wait before disconnecting the jumper ?

@larrymace2361

2 ай бұрын

@@111boldoo Depends on a few factors but you can calculate it if you know all the parameters. You will need to know the capacitance in farads so if you have a 1uf capacitor you would change it to its value in farads so 1uf would be 0.000001 farads. Next, you need to know the resistance of the circuit, with the setup they have, it is so small yet not 0. Use a small value if you are using wire like in this video but like I said not 0. Now the fun part! The formula for this is T = R * C * Tc T(charge time in seconds) = R(resistance in Ohms) * C(Capacitance in Farads) * Tc(Time Constant) For the Time Constant, we are only worried about the first 5 so if you want to know how long it will take to reach 63.2% charge then use 1 if you want to know how long it takes to reach 99.3% charge use 5. We are not worried about anything over 5 because a capacitor starts charging fast and then slows down and after it reaches 99.3% it charges super slow past that. So here is an example let's say we have these values Our resistance is 10 kOhms, Capacitance is 1uf, and we want to know how long it takes to reach 99.3% charge. Our formula would be T = 10,000 * 0.000001 * 5 T = 0.01 * 5 T = 0.05 So for our example, we know that after 0.05 seconds we will be at 99.3% charge close enough to know if our capacitor is good. Just so you know, if we use the same capacitor value but change the resistance from 10 kOhms to what this particular setup in the video would be less than 1 ohm, however, I'm going to use 1 just because at these values it really doesn't matter. T = 1 * 0.000001 * 5 T = 0.000001 * 5 T = 0.000005 So to finish this long post, unless you have a very high capacity capacitor and a very high resistance, you will charge the capacitor almost faster than you can clip it on and take it off. However, you may have a large value capacitor you want to test so I find it better to explain the math so you can do these calculations yourself. Hope this helps and was easy to understand, I wanted to explain it in a way that even someone not familiar with electronics could understand it.

@pontiacexchange4386

Ай бұрын

@@111boldoo The capacitor will be fully charged almost instantaneously. When it discharges it will release 50% of its power - then 50% of the remaining power - then 50% of the remaining power and so on and so on till discharged or charged back up.

Nice info, thank you for sharing it :)

The world's best thanks

Appreciate.thanks

Fantastic

@train4905

Жыл бұрын

😊😊

Helpful video, I love your tutorials

It was plain and simple instruction thanks for your help.

Thanx

thx

Has there ever been a point in history where it's worth it to remove every single part, and test every single component to fix something?

@AeroCraftON

9 ай бұрын

For science!

@OneyPlaysClips

9 ай бұрын

@@AeroCraftON i suppose if it helps. this made me realize i'm throwing away my old car eq though

@jj987987987

6 ай бұрын

You don’t, and that is why you learn to read schematics. You trace the board and find the comment that doesn’t work well and perform the test. I’d you are going to remove everything on the board just to test it that means you don’t know anything about it and have zero idea what you are doing.

@TheAWSOMEWORLD

6 ай бұрын

When hvac co’s want to charge you $19k for a new system. YES! 😊

@theprogrammerrolandmc3039

6 ай бұрын

ESR meter will test capacitors in circuit multimeter is the worst thing to test a capacitor with

can i test capacitor without removing it from the circuit board?

@pontiacexchange4386

Ай бұрын

No

@niteshmurti

Ай бұрын

@@pontiacexchange4386 ok

But how can I test a 2200uf capacitor if multimeters only go about 20uf?

Nice1..Electro & thank u

but with no markings how do I test to know what side is what? + -

@irgnedeinname

10 күн бұрын

There are non-polarized capacitors with no defined + and - contact. With those it doesn't matter which side is connected to positive and which to negative. If it has no markings it's probably non-polarized sometimes also referred to as a bipolar capacitor. Most ceramic capacitors for example are non-polarized

3:02 "....make sure your buttery (power source) is off" What is buttery? If it is a typo for battery, it shows connected.!!

@_LuxStein

3 ай бұрын

There are two types of people: 1) Those who can extrapolate from incomplete data

@AedanBlackheart

Күн бұрын

@@_LuxStein and those that are buttery

2:00 is 8.5 a good value for a 10uf capacitor? 15% lower?

@kevinerose

Жыл бұрын

I looked up capacitor tolerance online and it says up to +/- 20% is acceptable. More expensive capacitors can have +/- 1% tolerance values.

@kevinerose

Жыл бұрын

I just watched another video saying he replaces capacitors if they are out more than 10%. Maybe that is what technicians are told when to replace capacitors. A technician may want to swap them out at 10% just so they don't have to come back later for another service call? IDK. What do you think?

@Snurre86

Жыл бұрын

@@kevinerose yeah, maybe, they probably lose value over time.

@dakromis

11 ай бұрын

@@kevineroseThis is the case to my best knowledge, the capacitor already has demonstrated its starting to fail rather than having a callback that we have to prioritize we just replace the capacitor outright, they’re very cheap usually

@3333927

9 ай бұрын

@@kevinerose +- 20 % is ok, because on circuit boards manufacturers use higher rated capacitors than really at least needed. But when ever it's possible just replace every one below 10 % of its rating. You don't want to repair things more often, just because you didn't replace a cheap capacitor below 10% of its rating.

Third test didn't make any sense to me. If you'd removed the battery wires first I'd have understood it was something to do with the cap storing a voltage, but as it was you were effectively just connected to the battery were you not? I'm just here for some help with wiring a guitar. Don't pretend to understand this stuff at all.

@JustMe-gx4xt

6 ай бұрын

This test was NOT correct. In the last step, he basically tested the battery because the 9v battery was still connected. What he should have done was unplug the jumper cables first and then test the voltage of the capacitor.

In the voltmeter test , you got 9 volts and you said that the capacitor is good. If the capacitor was bad what value should I read in the voltmeter test ? Thank you

@paulos9304

7 ай бұрын

That will read whatever the battery is, he is measuring the battery. This has nothing to do with the capacitance.

@laserborn5787

7 ай бұрын

I thought the same thing

@nikoz4841

7 ай бұрын

Shorted capacitor will bring 9v to much lower reading.

@gabrieldegois8687

3 ай бұрын

If done correctly, should show the same voltage as the battery if given enough time to charge the capacitor.

why infinity ohm on a cap? and first so low?

@irgnedeinname

10 күн бұрын

When you charge a capacitor you have current going in right? The closer it gets to being full the less current flows until it stops completely. Remember the basics: high resistance means low current and vice versa. A multimeter measures resistance by applying a low testvoltage and measuring the resulting current. And with voltage and current it calculates the resistance. When measuring the resistance the capacitor gets charged with the multimeters testvoltage. While the capacitor is charging from empty to full the current decreases until it hits zero. The resistance behaves opposite to the current. So if the resistance doesn't continuously climb to infinity during the measurement it means there is a low resistance electrical connection inside the cap between the two sides that shouldn't be there and hence the test result would be: "failed"

ITS BEST FOR THE BEGINNERS

The voltage test is a false set up because you're just measuring the voltage of the 9V battery.

Do i have to remove every single capacitor? Can't i do it while on the circuit board.

@AedanBlackheart

Күн бұрын

no

🙏🙏🌹🌹

Bset

there's an "L" in soldering.

The voltage test at the end was the most brain dead shit I've ever seen

Nice1..Electro & thank u

@ElectroUniversity

5 ай бұрын

Thank you for your support!