How to Find Theoretical Yield (2023)

* Convert all amounts to Moles
* Divide all moles by the COEFFICIENT of balanced chemical reaction
* Whichever of those results is lowest corresponds to your LIMITING reactant
* Use that reactant's number of moles and a MOLE RATIO to figure out amount of product made
* Convert to grams if necessary

Пікірлер: 59

  • @daisydog4251
    @daisydog42519 ай бұрын

    Explained this better in 5 minutes than my professor did in an hour

  • @Kavin-S

    @Kavin-S

    3 ай бұрын

    So true

  • @VertexAnimations
    @VertexAnimations8 ай бұрын

    I watched 10+ tuts, and din't get any shit out of them, this explained the concept in less than 6 minutes, W professor.

  • @charrhylis
    @charrhylisАй бұрын

    for some reason theoretical yield is a concept i was NEVER able to wrap my head around no matter how many times it was explained to me. after literal and actual weeks, THIS is the video that's finally managed to drum it into my thick skull. Thanks man

  • @VelHazai
    @VelHazai Жыл бұрын

    It's the day before the last day of school. I've been stuck on the last problem on my portfolio assignment for hours. I couldn't figure out theoretical yield. I watch this video and in 5 minutes and 21 seconds I finally understand. Thank you very much for this video and teaching me a problem that closely resembles the one I have to do. Thanks again!

  • @abcdefg-hv2ks
    @abcdefg-hv2ks11 ай бұрын

    I don't know what to say, but thank you SOOO much!! You have NO idea how stressed I was because of chemistry. I couldn't study the entire year and i had only a month left till my exams and i binge watched all your videos and I absolutely aced my chem exam! THANK YOU!!!! You're so underrated, no one else explains topics and solves chem problems like you do. Your way of teaching helped keep focused. You also don't out all your knowledge behind a paywall like most people do.God bless you ♥️ Im an A-level AQA triple science student, so you can guess just how grievous my situation was ahaha.

  • @honeydew1411

    @honeydew1411

    6 ай бұрын

    How did it go?

  • @abcdefg-hv2ks

    @abcdefg-hv2ks

    6 ай бұрын

    @@honeydew1411 Passed 🥳🥳 top of my class.

  • @laithtouman1040

    @laithtouman1040

    2 ай бұрын

    @@abcdefg-hv2ksgood for u my guy. Glad ur finally stress free 👍

  • @annakohl2955
    @annakohl29554 ай бұрын

    What a great KZread find. 💯 Thank you for your services

  • @giselle3351
    @giselle33519 ай бұрын

    you explained this SO clearly, i finally understand THANK YOU !!

  • @naedagomez9101
    @naedagomez9101 Жыл бұрын

    I watched so many videos and could not understand how to do this until I found this one! Thank you so much!

  • @adrielisaacs1998
    @adrielisaacs19988 ай бұрын

    Thanks dude! I was confused by this for years and you made it so simple.

  • @adityapatel7577
    @adityapatel75774 ай бұрын

    Understanding the yield calculation was so easy. I never even thought about it before.

  • @GreenMantis27
    @GreenMantis273 ай бұрын

    You can't belive how much did your video help me... This subject has too many videos explaining too many different useless ways of solving something as simple as you just put it. Great job, you saved me! EDIT: I have a quiestion though... what do I do if I am not given the masses of not the reactants but only of the product?

  • @tamarkikvidze
    @tamarkikvidze4 ай бұрын

    Perfectly clear, thank you.

  • @zeroanime4076
    @zeroanime4076 Жыл бұрын

    Thanks sir for uploading such an amazing vid

  • @Zenoestequia
    @Zenoestequia8 ай бұрын

    Thank you!!best of luck!

  • @ynnna21
    @ynnna218 ай бұрын

    Thank you so much!!!!

  • @toporisnash1324
    @toporisnash13249 ай бұрын

    Really great explanation!! Thanks so much❤

  • @Egghead_12
    @Egghead_124 ай бұрын

    You may have just saved my grade, and for that I thank you ✨

  • @rim2675
    @rim26758 ай бұрын

    thank you!

  • @IsaacBorland-cv4zi
    @IsaacBorland-cv4zi4 ай бұрын

    Thank you thank you thank you👍👍👍👍👍

  • @abdulshah4419
    @abdulshah441910 ай бұрын

    very useful! Thanks a lot

  • @albertaawuku6989
    @albertaawuku698912 күн бұрын

    Thank you sooo much Uve really helped me tnx a lot

  • @TomasKalvach-mb9ti
    @TomasKalvach-mb9ti6 ай бұрын

    Thank you man😊

  • @qualisha5643
    @qualisha56439 ай бұрын

    Great explanation this is the only video that’s helpful for me

  • @nadia3824
    @nadia38243 ай бұрын

    very well explained!!

  • @idunno...2179
    @idunno...21797 ай бұрын

    Very helpful thank youuu

  • @yomeeyu7073
    @yomeeyu70738 ай бұрын

    Thank you!!!:)))

  • @oscarwressmark4945
    @oscarwressmark4945Ай бұрын

    ❤good video

  • @kingjoyryan1356
    @kingjoyryan13565 ай бұрын

    Good video, bit wanted to ask that what if we don't know the mass of one reactant

  • @madisonsargent6146
    @madisonsargent61468 ай бұрын

    Thank you

  • @MikeSpizzirri
    @MikeSpizzirri25 күн бұрын

    genious!

  • @vage_abod6764
    @vage_abod67645 ай бұрын

    love it

  • @user-hg4qo4hs4d
    @user-hg4qo4hs4d8 ай бұрын

    The explanation was great, I finally understand it. Thank You. BUUUT, where did you get the initial 3.0g for 2H2 and the 29.0g of O2. Can you please explain? Thank You,

  • @idrisrasak9445

    @idrisrasak9445

    4 ай бұрын

    It's part of the question

  • @marvellover1015
    @marvellover10154 ай бұрын

    How would I find the percent yield with this kind of equation, where neither PY or actual Yield is given. Would the AY be molar mass of a product - the amount of product lost?

  • @user-kk1yv2xz5s
    @user-kk1yv2xz5s4 ай бұрын

    Among the reaction which reactant are we suppose to use for us to find theoretical yield

  • @weridaxelot9217
    @weridaxelot92174 ай бұрын

    Damn that was faster than the other formula and much easier

  • @opufy
    @opufy9 ай бұрын

    I tried doing this with the net ionic eqn but it didn't give the same mass of product in the end. Strange It's for a quiz retake im doing with the reaction between 0.040 moles of Silver I Nitrate and 50.0 ml of 0.60 M Calcium Chloride.

  • @camillecalma9598
    @camillecalma95983 ай бұрын

    Angas gagi HAHAHAHA

  • @jademccormick5407
    @jademccormick54078 ай бұрын

    what if you not given the mases of the reactants only one?

  • @mohamedhuseein2626

    @mohamedhuseein2626

    Ай бұрын

    Then your screwed

  • @thobekasilika442
    @thobekasilika4424 ай бұрын

    @chemistNate what happens when you three products

  • @temwanimwika6726
    @temwanimwika672610 күн бұрын

    You might have just saved my chemistry exam😭

  • @JustinKohlberg
    @JustinKohlberg3 ай бұрын

    W mans

  • @honeydew1411
    @honeydew14116 ай бұрын

    Isn’t the molar mass 2H2 4?

  • @honeydew1411

    @honeydew1411

    6 ай бұрын

    Or are we ignoring the mole?

  • @OluwaseunFALANA-sw8yo
    @OluwaseunFALANA-sw8yo5 ай бұрын

    ❤❤

  • @RebeccaPhiri-ti2yh
    @RebeccaPhiri-ti2yh28 күн бұрын

    ❤🎉

  • @user-hk7md1dd4q
    @user-hk7md1dd4q9 ай бұрын

    But why dindnt you multiplythe 2 of H2O by the 1.5 of h2

  • @sheabutterandroses

    @sheabutterandroses

    7 ай бұрын

    Yes! Wonder why this wasn't the case?

  • @isaidmo
    @isaidmo10 ай бұрын

    Couldn't understand better

  • @ttkg6999
    @ttkg69995 ай бұрын

    where the hell did you get 18.0 grams from?

  • @nabioooooo

    @nabioooooo

    4 ай бұрын

    The molar mess of H2O

  • @MishelWhant-dj7rl
    @MishelWhant-dj7rl25 күн бұрын

    ❤❤❤🇵🇬🇵🇬🇵🇬🇵🇬🇵🇬

  • @haydenbishop549
    @haydenbishop5493 ай бұрын

    Wa Ter