Your explanation was extremely clear and easy to follow. Thank you for taking the time to make such a fine video. I will be looking for others that you have done.

@tcs20264

2 жыл бұрын

At 1:45 how b²i² is equal to -b²??

@neutronzz3543

Жыл бұрын

@@tcs20264 hopefully your question has been answered but I^2 = sqrt(-1) so if i square a square root it cancels so it's just negative 1 so b^2i^2 =b^2(-1) = -b^2

thank you this was very helpful!

this was an amazing explanation, thank u so much anil!!!

Thank you, very clear and concise video !!

Thank you, its beneficial for complex analysis

Very good explanation thanks for clearing doubts

how do you find the absolute value of a complex number that has both a numerator and a denominator

perfect, cheers

You have explained very well in comparison to other you tubers. . I liked this way a lot.. THANKING YOU 😎

Thank you!

Thank you so much you have helped me alot

Thank you Prof. Anil Kumar. I was a little bit confused about taking square root of a complex number , but now it is clear to me.

Although the result may be interesting, isn’t the reasoning up until you sub in values of (a) to get values of (b) only valid if (a) and (b) are real? In other words, a^2 +4 cannot be factorised over the real plane, and thus the other result although coincidentally correct, uses invalid logic to acquire it.

love your voice. Great teacher

where did the i go from abi when u separated the two equations at 2:13

Great explanation prof. Thanks

Superb! Thank you.

thanks that was very very helpful to me

you are really helping us. thanks sir!

@MathematicsTutor

Жыл бұрын

Thanks for appreciation

thanks much Sir. I'm confused about the second equation in question 1. I thought it is supposed to be. 2ab=-12? please I'm begging you to clarify me how the - sign disappeared in front of 12.

@juizybabyy

Жыл бұрын

Exactly why I'm reading the comments, I don't know what made the sign to disappear

thank you

this is so cool!!! thank you for making this video!

yo this was a perfect lesson! Thanks so much bro

This explaination was better than the ones they gave at school zzz

How do we solve the question - Find All Roots of (1 - i)1/4?

Thank you so much

Fantastic explanation. I am trying to help my niece with her maths tests. This is really going to help. Thank you so much for posting.

@MathematicsTutor

5 жыл бұрын

Thanks. Here is related Playlist: kzread.info/dash/bejne/oqZ8mpSChcaylqw.html

Thanks teacher iam very happy now😀, Acroding to before watching this vedio I get i get iget

How to find the square root of Andrew kolita ?

well explained

Helpful

explained this lesson in perfection. thank you very much and yes the result with the imaginary number being substituted is very interesting

@MathematicsTutor

6 жыл бұрын

Thanks a lot for appreciation

Nicely explained.... Thank you sir.

@MathematicsTutor

5 жыл бұрын

Thanks. Playlist on Complex Numbers: kzread.info/dash/bejne/oqZ8mpSChcaylqw.html

thank you sir

Sir at 4:45 , square of (a) cannot be equal to (-4), as square of any no. cannot be equal to any negative no.

At 1:45 how b²i² is equal to -b²??

Awesome

Thank you very much sir, your explanations are clear and concise. I comprehend the relation between imaginary and real numbers better now.

Nice!

nice and to the point explanation sir thank U

We got a^2+4=0 a^2=-4 (as i^2=-1) We can replace a^2=4i^2 And a=+-2i. So we got imaginary number +-2i

Nice explanation🥰🥰🥰🥰

Cant i use the (a^2 + 4 = 0)? give me some explaination

@neutronzz3543

Жыл бұрын

he did a^2+4 =0 can factor into (a+2i)(a-2i) which he did use

you can also convert it to phasor form and find the square root of that then convert it back to complex

This was great! Can you do this using Euler’s formula?

@Caller8194

3 жыл бұрын

NNNNOOOOOOOO

@subham3260

Жыл бұрын

Nahh it's a representation of a complex no.

Sir I want to know the square root of 1-i in form of x+iy.. please teach

@MathematicsTutor

4 жыл бұрын

Try some questions from this video: kzread.info/dash/bejne/oqZ8mpSChcaylqw.html Thanks

Very nice explanation. There's one doubt though. When you got the values for 'a' after solving the equation, how did you decide which value is complex and real? Because I get different answers when I did a = 3i and a = 2, instead of what you did.

@tcs20264

2 жыл бұрын

At 1:45 how b²i² is equal to -b²??

@bred3620

2 жыл бұрын

@@tcs20264 since I=√-1 so i^2 would be √-1×√-1 which is -1 so (bi)^2 =b^2×-1 =-b^2

Nice

No sir i want ask that how to choose the value between a=+-3 and a=+-2 for futher calculation after factorization of the equation

@MathematicsTutor

5 жыл бұрын

Thanks, will make a video for you in this regard. Thanks

I have a confusion sir Is it nessesary to take the first value of a as real number and if yes so the second value is always a imaginary number isit?

@MathematicsTutor

5 жыл бұрын

We started with a + bi, so b is the imaginary part and a is the real part. a = 3 or -3; Find b for these values. to get the result. Later half is showing that the result will not change even if you use a as 2i. Ignore it, if it creates confusion. Thanks

4:37 where is the square root symbol ? it should be a=+- squareroot 3

2ab=-12??

I don't get it how u find a and b

@Christmas-chan

3 жыл бұрын

Lol

Thank you

Your written letters look more standard font than my typed ones.

Solve the equation w^2=1+i............how do i solve this question.thank you

I saw on byjus, they told that +- in front of the bracket will not come.

Thank you so much sir, I was at a loss with why the square root of complex numbers have 2 values, when real numbers only have one. Thank you so much sir

@tcs20264

2 жыл бұрын

At 1:45 how b²i² is equal to -b²??

@ghotifish1838

2 жыл бұрын

@@tcs20264i is the square root of negative one so if you have i^2 that's equal to negative one

@tcs20264

2 жыл бұрын

@@ghotifish1838 oh. Thnkz

is there any short trick for this if it is then plz upload sir

@SakshamArmstrong123

6 жыл бұрын

yea there is just split the complex number in a perfect square as the square of a complex number can be represented as a^2 - b^2 +- 2abi the given complex number in the video 5 - 12i can be written as 9 - 4 +2(3)(2)i which is 3^2 - 2^2 - 2(3)(2)i which is (3-2i)^2 so you get the answer directly in like 15 seconds

@Ashutoshkumar-wm2cv

6 жыл бұрын

Thanxx sir,,, its so qualitative explanation,,,..🙏🙏🙏

@bluebloo5574

5 жыл бұрын

use Euler's formula

I have 5 minutes left in class of taking this test and this damn video is 9 minutes longggggg

amazing explanation and very calming voice! :)

@MathematicsTutor

3 жыл бұрын

Thanks

Which pen do you use???

@MathematicsTutor

5 жыл бұрын

Will share with you soon. Thanks

@MathematicsTutor

5 жыл бұрын

Here you can see the Pens: kzread.info/dash/bejne/ZHxpl7JvnbCofJM.html Thanks

@arnavarora9290

5 жыл бұрын

@@MathematicsTutor Thanks alot !!!!

Technically we do not need to considerthe imaginary solutions of a=2i and a = -2I as z = sqrt(5-12i) = a+bi, where a and b are real numbers.

Thank you so much Sir!😃😇

How did you directly found out that sir. 😅😅 I have to write factors and then find. Please reply.

@MathematicsTutor

5 жыл бұрын

a^2 - 9 = 0, you may factor and then get the answer or you can use -3 and +3 with experience. Soon yo will also write it directly. Thanks

@theindianpublicschoolbabug5532

5 жыл бұрын

Ok sir. Thanks.

Thank you sir.love your work

Well explained. I like it.

find the square root of (a to the power 2) +(1/a to the power 2) + 4 i (a+1/a)-2

Wow u saved me thanks

@MathematicsTutor

5 жыл бұрын

Check few more questions on this: kzread.info/dash/bejne/oqZ8mpSChcaylqw.html&list=PLJ-ma5dJyAqqImxqXhid9SQxjMyTOx4zj&index=4 Thanks

👌👌👌👌👌👌👌👌

Sir why did u took a=2i why not a=3i

@MathematicsTutor

5 жыл бұрын

a^2 + 4 = 0 gives that result. Thanks

@shreyas7749

5 жыл бұрын

Because it's square root of -4

How you got a=+_2i? Its real part

how he did it at 4:18

@AyushSingh-sg5st

5 жыл бұрын

Take a^4 as k^2 and a^2 as k which forms a quadratic equation. After you solve it input the original values..

I think it should be 2ab=-12.

@agbortambeferinhoo2807

Жыл бұрын

That's my worry too. thank God you also saw this....

@cedriclow28

11 ай бұрын

he corrected it later in the video

@khoado3539

11 ай бұрын

@@cedriclow28 oh okkkk

@khoado3539

11 ай бұрын

@@cedriclow28 thanksss

ans: {+ - (3+2i) , (-3-2i)} is that correct?

I’m in 6th grade and doing this lol

@beautifulaffliction1742

3 жыл бұрын

Keith Carden same, it's easy

2ab=-12 not 12

@MathematicsTutor

5 жыл бұрын

I have used 2ab = -12 only. Hope that is ok Thanks

@252-soumyabhattacharjee8

5 жыл бұрын

Find the sqroot of (1+i) without using quadratic formula?

find the square root of complex number \sqrt{8 + 6i}8+6i​

😭😭😭😭 this helped so much but my answer is still wrong. I officially quit. 😂😂😂😂

@anshshah8893

4 жыл бұрын

Sierra Fairbanks don’t give up keep trying you will get it eventually

False

Thank you sir

@MathematicsTutor

7 ай бұрын

Thanks for appreciation