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@rahul_IIT-Ghy

11 ай бұрын

Yes i got too much help from this Could you please share this Excel file

thanks

thanks this help for my final year project

@abaqusfem

10 ай бұрын

Welcome, you can give small contribution by joining the channel

Thankyou

@abaqusfem

Жыл бұрын

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From the cracking and inelastic strain how to a change it to displacement value? I want to use displacement instead

Thank you But this link of paper don't work

Hi sir, in the tensile part you are calculating the stress strain data with the second paper. There you have got 5 values. You have the maximum: so Y=0,7*sqrt(f_max) and y2=y*2/3 y3=y*3/8, y4=y/6. y5=0. In y5 you have epsilon_c*16. You did not calculate the last value. Was it on purpose? BG Thanks!

You mentioned that in case we have the experimental stress strain data that we dont need to use these model . Actually i only had the ascending branch from cylinder testing and due to absence of descending branch i used model Secondly can you please confirm that for CDP in Abaqus the concrete stress- strain relationship we need to use is for a confined concrete or unconfined concrete ?? Actually i have a simulation to run in which the grout is confined by steel sleeve so i modelled the sleeve and grout in Abaqus and i believe that Abaqus should consider the confining effect of this steel sleeve on grout and therefore in my CDP i used the unconfined stress - strain relationship ..is my approach ok or i need to used the confined stress -strain relationship for my CDP ?

@lyith6534

Жыл бұрын

Dear brother, the case he showed us was that of unconfined concrete. You'll see if you've read that paper.

If we use the Kent and Park model which say that it is applicable for the confined concrete and use its formula to establish the stress - strain relationship then my question is i had done cylinder testing and ultimate strength i got from that is 80MPa so now in Kent and Park model what value of ultimate strength sigma(cu) ?? i think it shouldn't be 80MPa and that from cylinder testing which is unconfined strength. Secondly this Kent and park model is developed considering transverse ties however my case the confinement is from a thin cold formed steel so this model would be applicable to my case ??

@abaqusfem

Жыл бұрын

For confined data use other models available in paper

@zainsaeed147

Жыл бұрын

@@abaqusfem The paper mentioned that Kent and Park Model for confined and unconfined concrete however the equation 16 mention in the paper you have shown in video is for unconfined concrete probably. il search for the confined equation . Thanks for the video and introducing the simplified way of making CDP sheet

FOR CONCRETE DAMAGED PLASTICITY

Sir please make a video on inputting material properties of steel under cyclic loading

@abaqusfem

Жыл бұрын

Ok

When I have done calculations for Grades 20, 40 etc I didn't get values as in the tables provided in the journal you are reffered.

@abaqusfem

Жыл бұрын

check properly, you may have done some mistake

@shivramojha1792

Жыл бұрын

@@abaqusfem I am also getting different

Sir can the same method be applied for M45 grade Or if u have the table available for M45 Please share that

@abaqusfem

Жыл бұрын

contact in whatsapp

please can you send me excel sheet ?

@abaqusfem

9 ай бұрын

Payment required

Sir please tell how to find CDP of confined concrete

@abaqusfem

Жыл бұрын

Ok will make a video on this

@lintapaul3108

Жыл бұрын

@@abaqusfem Thank you...

@harshdesai9977

10 ай бұрын

Hi, Have you made video on CDP model of confined concrete? Steel of FRP confined @@abaqusfem

@abaqusfem

10 ай бұрын

Yes

@abaqusfem

10 ай бұрын

Contact personally paid service