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Forced Harmonic Motion

MIT RES.18-009 Learn Differential Equations: Up Close with Gilbert Strang and Cleve Moler, Fall 2015
View the complete course: ocw.mit.edu/RES-18-009F15
Instructor: Gilbert Strang
When the forcing is a sinusoidal input, like a cosine, one particular solution has the same form. But if the forcing frequency equals the natural frequency there is resonance.
License: Creative Commons BY-NC-SA
More information at ocw.mit.edu/terms
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Пікірлер: 13

  • 7 жыл бұрын

    Thank you MIT for sharing the knowledge to the world!

  • @marktoffoli9186
    @marktoffoli91862 жыл бұрын

    Thank you professor Strang, you really have made learning engaging and insightful, I thoroughly enjoy watching your videos

  • @goytomt
    @goytomt6 жыл бұрын

    Love that "Hee'e" sound @6:51. Thank you sir!

  • @lexrogan2207
    @lexrogan22073 жыл бұрын

    Thank you Professor Strang!

  • @knowledgewith90shoomans97
    @knowledgewith90shoomans973 ай бұрын

    conside an at rest linear system described by : y"+25y=2 sint+5cos5t the response of the system will be : decaying oscillation in time, oscillatory in nature, growing oscialltion inb time, none

  • @irslanullahashraf5158
    @irslanullahashraf5158 Жыл бұрын

    thank you, professor ... you always add beauty into mathematics and make it super interesting

  • @T4l0nITA
    @T4l0nITA5 жыл бұрын

    So c1 and c2 of yn are the same of the oscillating function of the previous video, or do I need to solve for y(0) and y'(0) the whole yc solution instead of yn ?

  • @atomskyjahid1533
    @atomskyjahid15338 жыл бұрын

    Physical interpretations are what I'm here for. ^_^

  • @Hobbit183
    @Hobbit1836 жыл бұрын

    dam thats interesting

  • @bigdave6952
    @bigdave6952 Жыл бұрын

    i dont understand why did he end up calling a null solution a impulse response at the very end, it my must have been a slip up him. It cant possibly be true.

  • @maximus7043
    @maximus70435 жыл бұрын

    why impulse response is 1/mWn not just 1/m?

  • @leonardosoto5669

    @leonardosoto5669

    5 жыл бұрын

    watch the previus lecture,in the null solution the coefficient of sin(wnt) is (dy/dt)(0)/wn ,in this case (dy/dt)(0) is 1/m but you stil have to divide it by wn

  • @freeeagle6074

    @freeeagle6074

    2 жыл бұрын

    Since d(sin(wnt)) brings wn out, we need wn to exist at the denominator to cancel wn so the dy/dt is 1/m.