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Forced Harmonic Motion
MIT RES.18-009 Learn Differential Equations: Up Close with Gilbert Strang and Cleve Moler, Fall 2015
View the complete course: ocw.mit.edu/RES-18-009F15
Instructor: Gilbert Strang
When the forcing is a sinusoidal input, like a cosine, one particular solution has the same form. But if the forcing frequency equals the natural frequency there is resonance.
License: Creative Commons BY-NC-SA
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Пікірлер: 13
Thank you MIT for sharing the knowledge to the world!
Thank you professor Strang, you really have made learning engaging and insightful, I thoroughly enjoy watching your videos
Love that "Hee'e" sound @6:51. Thank you sir!
Thank you Professor Strang!
conside an at rest linear system described by : y"+25y=2 sint+5cos5t the response of the system will be : decaying oscillation in time, oscillatory in nature, growing oscialltion inb time, none
thank you, professor ... you always add beauty into mathematics and make it super interesting
So c1 and c2 of yn are the same of the oscillating function of the previous video, or do I need to solve for y(0) and y'(0) the whole yc solution instead of yn ?
Physical interpretations are what I'm here for. ^_^
dam thats interesting
i dont understand why did he end up calling a null solution a impulse response at the very end, it my must have been a slip up him. It cant possibly be true.
why impulse response is 1/mWn not just 1/m?
@leonardosoto5669
5 жыл бұрын
watch the previus lecture,in the null solution the coefficient of sin(wnt) is (dy/dt)(0)/wn ,in this case (dy/dt)(0) is 1/m but you stil have to divide it by wn
@freeeagle6074
2 жыл бұрын
Since d(sin(wnt)) brings wn out, we need wn to exist at the denominator to cancel wn so the dy/dt is 1/m.