great lecture, thanks, MIT

thank you ,mit

00:23

Thank you for your lecture. I was confused by this code. I think it is because I am confused about char1 and char2. char2 does not refer to the 2nd character in s2. Is char undefined? Python knows what char refers to? Thanks again for your lecture. It is very helpful.

@phillipgonzalez9776

6 жыл бұрын

"char1" and "char2" are just the names of temporary variables that will represent each character in the strings s1 and s2, respectively, because of the for loops.

@phillipgonzalez9776

6 жыл бұрын

Another thing that could be potentially confusing is that the print statement says "common letter" but the code actually is comparing every character, including the " " characters, hence "common letter" being printed 7 times for the matches "m", "i", "t", " ", "u", " ", "r"

do we count the 2 spaces?

@alcikelly2496

10 ай бұрын

Yes, you're absolutely right! It prints "common letter" for "m", "i", "t", " ", "u", " ", and "r", which is quite misleading, because it is checking every CHARACTER in the string, not just letters.

@dg2q

10 ай бұрын

@@alcikelly2496 gotcha thanks

Are the spaces include?

@funnyh0rr0r31

5 жыл бұрын

Where are included? In string every symbol considered an element and it's part of string. For example string "nice day" will have 8 symbols. " nice day " - 10 symbols.

@shokobata

4 жыл бұрын

@@funnyh0rr0r31 If you mean if the loop checks if the spaces are equal then yes

@thewryreport

3 жыл бұрын

@@shokobata Then why is the answer not 10? m = 1, i = 2, t = 1, space = 2, u = 1, space = 2, r = 1

@thewryreport

3 жыл бұрын

OK I think I get it now, it's because of the break, it only counts the 1st instance of each letter, so it's just m + i + t + space + u + space + r once each

@hieunguyenminh4677

8 ай бұрын

@@thewryreport thanks, i also think the answer is 10 before

The for loop really should have an else: statement in case the result is false.