I know you dropped this 8 years ago, but thanks anyways man. I got a Pre-Calc test tomorrow I've been studying for, and all I forgot to take notes on was slant asymptotes.

this video came out when i was in fifth grade ..... now i’m in my second semester of college and i use your videos almost every night for my math hw. THANK YOU!

some people still need that intimate teaching, but youtube has allowed a lot of students to skip tutoring for sure

@Atameow

6 жыл бұрын

but why dont we use remainder as slant asymptote. ithink thats what she was asking towards the end

didn't know randy orton could teach maths so well haha xD

@brianmclogan

6 жыл бұрын

now you know, haha

THANK YOU SO MUCH, you've literally saved my pre-calc grade. if i hadn't found your videos i probably would've failed my final but i feel so much more comfortable with the material, i can't thank you enough!!! :)

@raine_8990

5 жыл бұрын

esraa sammme

@deathreaper5226

7 ай бұрын

how was the pre calc final , im here for the same reason lol

@essy8626

7 ай бұрын

LOL hi i honestly don't remember but i go to usc marshall now so don't stress😭@@deathreaper5226

Sir, I am very thankful to have teachers online to help with my pre-calculus and I'll make sure to thumb you up. It is indeed a good asset to have people who use KZread in a positive manner.

This was 11 years ago!? Man how time flies, I remember watching these videos back in high school, didn't seem that long ago until now

well when we multiply (x-2) on both sides we have a couple things happen. On the left side of the equation we are multiply (x-2) by 0 so the left side will be zero. When we multiply (x-2) on the right side we have (x-2) in the numerator so that will divide to one leaving us with 0=2x^2-5x+5 per the video. Am i missing something with your question or did I clear it up. Let me know

You’re doing gods work on this channel. My teacher just gives us packets that she finds online with fill in the blanks and I don’t learn anything from them. I also don’t get engaged in the lesson. These videos are my savior before tests and thank you for helping me pass my classes :)

hey it's not simple, keep up the hard work, glad I was able to help you out. Stick with it

I got excited about synthetic division because you taught me how to do that. You are a GREAT teacher. You are a blessing 🙌

sweet so glad I could help you out!

what are you referring too?

Your videos are great. They’re an amazing supplement to my class and you’re great at teaching

@brianmclogan

5 жыл бұрын

Thanks Eric

This is awesome! Unfortunately, my math class is my first class of the day and I am usually still half asleep... Thanks so much!!!

Have a test tomorrow and this helped a lot. Thanks

How are you such a good teacher?!?!! Saved my ass for a test tomorrow! Thanks Mr. McLogan!!!

your videos are sooo helpful, thanks

Bro you are the goat

brother , you are one hell of a teacher

Man, I don't even know why people would even pay for tutors anymore. This video really helped, thanks!

i have a question why you multiple with 2. where"s you get this number?

such a great word

Very informative.. love so much

you did synthetic division in the video, but if you were to do long division would you come up with a different answer? because I keep getting 2x+1 (And a remainder of 7 over the divisor) instead of the -2x-1 that you got in the video.

You are really a semester saver 😭😭❤

You are magic, man! I finally understand!

Do you have a video where you teach more complicated problems where the vertical asymptote would require a bit more work? As in factoring, grouping, canceling?

@brianmclogan

6 жыл бұрын

of course here you go kzread.info/head/PL0G-Nd0V5ZMrCy9FP2EeZRJUlawuGJ0xr kzread.info/head/PL0G-Nd0V5ZMqmhh50eb84f5hePlrT7BrL

this was so helpful omg

Thank you This was very helpful!

@brianmclogan

6 жыл бұрын

you are very welcome!

great explanation

Amazing... thank you so much!

@brianmclogan

6 жыл бұрын

you are very welcome Alki!

god i fucking wish you were my professor your voice is soothing and you explain everything great and it seems like you enjoy teaching math

@brianmclogan

6 жыл бұрын

I do, and am very happy to help you out

This really helped reinforce my memory for my math final.

@brianmclogan

6 жыл бұрын

awesome! best of luck!

how can i pay attention to these videos but not my own professors lectures?? somethings not adding up LMAOO

Didnt you say in the previous video that if the top x has a higher power than the x in the denominator, then the horizontal asymptote is y=0? but in this video you said it does not exist. could you please clarify. thanks. really like your videos btw.

@Jrasa

6 жыл бұрын

Ibrahim Ansari Horizontal asymptote is different from slant asymptote

@samanthganti8451

5 жыл бұрын

If top power is more than denominator...then there is no horizantal asymptote...but there will be oblique asymptote if degree of numerator=(degree of denominator) +1

this man is my math teacher and he doesn’t even know my existence

You just saved my grade from tanking. Thank you my brother

thanks

do you have any videos about rational inequalities?

@brianmclogan

6 жыл бұрын

ummmmm no I do not believe I do, same process, just use test points at the end to determine where to shade

beauty!!!

dont we get 2x^2-6x+ 7 after we mutiply both side by (x - 2) ......x-2 = 2x^2 -5x + 5 ....minus x and plus 2 from both side .

thank you

@brianmclogan

6 жыл бұрын

you are very welcome!

wish a recommended graphing video was next so i could start graphing it.

Hi, I don't know if you still reply to a video from 8 years ago. First off, appreciate the lesson. It was very helpful in understanding asymptotes and finding them. Question: What if there is a function with no denominator, in that case, there won't be any horizontal asymptote because of the top> bottom rule. But, what about the vertical asymptote, I can't equate 1x^0 =0 to find the same? What happens here? thirdly, in graph transformations, are the asymptotes to be kept at x=0 and y=0, to begin with, and make changes to them based on the transformations? like for eg: f(x) = 3^(x-1) - 2 here, in the 1st step y =3^x , the horizontal asymptote was at y = 0 and in the next step f(x) = 3 ^(x-1), also the horizontal asymptote was at y=0 and finally, during the f(x) = 3^(x-1) -2 transformation, the horizontal asymptote moves down by 2 units and is at y =-2. Could you please explain this? I'd greatly appreciate your help. Thanks in advance.

@brianmclogan

6 жыл бұрын

Hi Minus, yes I still try to answer as many comments as I can. You have a lot of questions and I cannot always answer them but will do my best 1.) It depends on the function, if there is no denominator then yes you do not have to worry about the denominator equally zero for a vertical asymptote. However other functions have vertical asymptotes and no denominators, i.e. logarithms, tangent, cotangent, secant, cosecant. 2.) again depends on the asymptotes of the original function, if your function is 1/x then yes the vertical asymptotes are at x=0 and will move based on the transformations. The function you provide does not have a vertical asymptote but a horizontal asymptote at y=0 and since the graph is being shifted down 2 the new horizontal asymptote will be ay y=-2 Hopefully this helps

It wouldn't be 2x^2-6x+7?

How do you make this look so easy?!?! Every single time I attempt to do this I can't.

@brianmclogan

10 жыл бұрын

chymoney1 a lot of practice, it took me many times to learn this stuff. Struggled just like you over and over. Keep working hard and it will eventually come to you

really helpful!!! but try to look at the camera

what if the leading degree of both numerator and denominator is equal? does it have a Vertical asymptote or horizontal asymptote?

@brianmclogan

6 жыл бұрын

the horizontal asymptote will always by y=0 in the scenario, the VA remains the same, what values of x make the denominator equal to zero

@3d-ataydetimothymartin545

6 жыл бұрын

oh im sorry, what i meant was if it is a slant or horizontal

You just saved my algebra grade for the week,thank you soooo much in a matter of 1 minute and 42 seconds you cleared up what i'be been struggling with,Thank you!!

So what is h(x)=(x^2-25)/(x^2+2x-80)? Please tell me 😢

@wethetruenorth9374

5 жыл бұрын

the horz assymptote will be the numerator ld coeffecient / denominator ld coeffecient while vertical asymptote conditions remain the same

God my teacher explains everything so horribly, your videos are so clear and concise...thank you !

Mr. McLogan coming in clutch for my Pre-Calc test tomorrow, thanks!

Ohh so you basically ignore the remainder. Is it all the time tho

How's that not factorable?, If you can use (x-5) and (2x+5) as factors that will give you the middle term which is 5x?

@brianmclogan

5 жыл бұрын

multiply it out, it does not equal the equation i.e. 5 *-5 is -25

@holle_so_nyce8563

5 жыл бұрын

@@brianmclogan Oh, crap

How do you find the holes

@brianmclogan

6 жыл бұрын

holes are discontinuities that are divided out

just do long division (x-2)/ 2x^2-5x+5 then we have salt asymtote y= 2x-1

@brianmclogan

10 жыл бұрын

yes

love ur vids but u did not show how to solve to horizontal asymptote this time

They told me we can't multiply zero by x-2 in 1:00. Can you help me Mr.McLogan?

@chrisomara7416

5 жыл бұрын

you can but you also can think of it as this: if y/x = 0, then y must equal zero because if x were to equal zero, then it would be undefined. its basically the zero product property

How to find slant if its 4 cm greater than its projection

@eyyubovvv

4 жыл бұрын

The distance of slant from the plane is 8 cm

Ahhh I need help with finding the ha when it's like x^2+2x over -4x+8 😭😭

@matthewantin4728

5 жыл бұрын

Ajel Laqe there is no HA because the degree of the numerator is larger than the denominator therefore there is a SA instead

I can't put my finger on it, but I like this guy. Subbed.

@brianmclogan

6 жыл бұрын

appreciate it, and happy to have you

you should get the same answer, you are probably making an algebra mistake or setting up the problem wrong.

Why didn't he do quadratic equation to find the x intercept

@brianmclogan

6 жыл бұрын

because the x-intercepts are imaginary, so what is the point on knowing the imaginary intercepts?

Is finding the vertical asymptote the same as finding the domain ?

@brianmclogan

10 жыл бұрын

chymoney1 finding the vertical asymptotes helps us determine the domain because at each asymptote the function is undefined. So therefore usually you can say all real numbers except for the x-values where a vertical asymptotes is

@chymoney1

10 жыл бұрын

Thank you so much, your videos are very helpful.

Bro its been 10 years. you okay there?

Still this video waching.......after 10 years

What was the Horizontal?

@brianmclogan

6 жыл бұрын

there is none

Does he say astmptope?

how many times he gonna say therefore

@Mustanggt505

5 жыл бұрын

lol math teachers always talk alittle like robots XD

goat

aspmtopes lol

🎸

@brianmclogan

6 жыл бұрын

rock on

wait this dude doesn't age! I watched another video from 2017 and he looks the exact same 😳

istill dont get it

im so lost

The adds you placed are encouraging people not to watch your videos. Talk about irony.

@brianmclogan

6 жыл бұрын

I do not place any ads, KZread does that, I just allow them

@ChristianArreguin

5 жыл бұрын

who cares? Its way cheaper to watch an ad than to pay for an overfilled college course where its easy to miss steps. or just get an adblocker like most people do.