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ANSWER OF THE FIRST QUESTION EXPLANATION : 1. u {initial velocity} = 0 a {acceleration} = 2 m/s square t {time} = 5 s v {final velocity} = ? So here we have to find the final velocity. So we take the first equation. v = u + at = 0 + 2 x 5 = 10 m/s So the final velocity is 10 m/s So the speed or velocity of the car after 5 s is 10 m/s Please like if helpful...

@swetasharma8598

3 жыл бұрын

Can you send 2 and 3 question answer also

@nagulaharikrish6576

3 жыл бұрын

Did u got the ans

@ousmanjalloh4518

2 жыл бұрын

Can I get 2. I'm confused

Anyone 2024?

@kiranjain5831

22 күн бұрын

Yes me .. class 9th

@kiranjain5831

22 күн бұрын

Yes me , class 9th

@user-kj6tp4wd1u

22 күн бұрын

🔥

@yahyeabdi538

5 күн бұрын

Yes, me at college 😄

@shubhrasharma525

4 күн бұрын

Yessss

We need teachers like this in school

@hinaatique9968

3 жыл бұрын

Yes

@vijaykumarverma6684

3 жыл бұрын

@Ashwanth A S What do you mean ??

@SurinderKumar-uf9fj

3 жыл бұрын

Absolutely....right

@ibnbatuta-journeyoftravell8711

3 жыл бұрын

Kaisa laga Mera mazak 😂😂😂

@unknownomg5943

3 жыл бұрын

Yeah

Q1 - According to first equation of motion v = u + at Here , v = ? u = 0 m/s a = -2m/s square t = 5 s Put the value in equations v = 0 m/s + (2 m/s square * 5s) v = 0 m/s + 10 m/s Hence speed of the car is 10 m/s. Q2 - According to third equation of motion 2as = v square - u square Here , s = 10 m v = 0 m/s u = 72 km/h or 20 m/s Put the values in the equation 2*a*10 m = 0 square - 20 square 20 m * a = 0 - 400 m/s square a = -400 m/s square / 20 m a = -20 m/s square Q3 - According to the third equation of motion 2as = v square - u square Here , a = (-10 m/s square) because the acceleration due to gravity is in upward direction v = 0 m/s u = 10 m/s Put the values in the equation 2 * (-10 m/s square) * s = 0 square - 10 square -20 m/s square * s = -100 m/s s = -100 m/s / - 20 m/s square s = 5 m 2. According to the first equation of motion v = u + at Here , v = 0 m/s u = 10 m/s a = -10 m /s square t = ? Put the values in the equation 0 = 10 m/s + (-10 m/s square * t ) 10 m/s square * t = 10 m/s t = 10 m/s / 10 m/s square t = 1s As the time taken by the ball to cover 5m distance is 1 sec so it will take 1+1 sec = 2 sec to reach the thrower

@littleflowerslittleones8435

2 жыл бұрын

I too

@Kpop_fanboy2005

2 жыл бұрын

Got same answer too

@spkannon

2 жыл бұрын

You're asked to find the speed!

@serifatayotunde8385

Жыл бұрын

Why did you use 20m/s when it isn't in the question above Please explain

@janavi2311

10 ай бұрын

​@@serifatayotunde8385 when you convert 72 km/h to m/s , the answer is 20 m/s.. m/s is the SI unit so we can't use km/h

my understanding just went from not having a clue what any of this meant, to being able to get it right most of the time. Great video.

@ManochaAcademy

4 жыл бұрын

Happy to hear that video was helpful :) Do check out more videos at www.manochaacademy.com

Q1) u= 0 a=2 t=5 v=? (1)v=u+at= 0+(2 x 5)= 10m/s Q2) a=?, u=20 m/s(72 km/hr- m/s), v=0, s=10 (3) s= v^2- u^2/ 2a 10= 0^2 - 20^2/ 2x (a) a=-20^2/ 2x 10 a= -400/200 a= -4m/s Q3) Use equation v=u +at to find time= 1/20 then use equation s=ut+1/2at^2= 1/4 or 0.25 m

@pankajsood9089

3 жыл бұрын

2nd question 2nd part -2m/s is the answer....

@pankajsood9089

3 жыл бұрын

thanks ,your answers were quite helpful..

@jayarampp118

3 жыл бұрын

@@pankajsood9089 -400/20=-20m/s² is the ans

@pankajsood9089

3 жыл бұрын

but he has written -400/200,according to that the answer is -2.. \

@learniumlearnwithfun862

2 жыл бұрын

Second question's answer is -20m/s2

1. final velocity (v)= 10m/s 2. acceleration (a) = -20m/s^2 3. i) time (t)= 1s ii) displacement (s)= 5m

@kimsimby9615

2 жыл бұрын

Won't the time be 2 seconds? The time it uses to reach maximum height is the same time it will use to travel back from maximum height to the thrower, right?

@crystal1991

2 жыл бұрын

@@kimsimby9615 yes it will be 2s

Q.1) Given : initial velocity = 0 m/s, acceleration = 2 m/s^2, time = 5 s. To Find : speed of the car. To find the speed of the car we can apply the 1st equation of motion i.e v = u + at, v = 0 + 2*5, v = 0 + 10, v = 10 m/s. Therefore the speed of the car after 5 s is 10 m/s. Q.2) Given : Initial velocity = 72 km/hr. Now we have to convert 72 km/hr in m/s i.e 72 * 5/18 = 20 m/s. displacement = 10 m. final velocity = 0 m/s. To find : retardation of the brakes. Now to find the retardation of the brakes we can apply the 3rd equation of motion i.e v^2 - u^2 = 2as, (0)^2 - (20)^2 = 2a(10), 0 - 400 = 20a, - 400 = 20a, - 400/20 = a, - 20 m/s^2 = a. Therefore the retardation of the brakes is - 20 m/s^2. Q.3) Given : Initial velocity = 10 m/s, acceleration due to gravity = - 10 m/s^2, Final velocity = 0 m/s. To find : height & time taken. Now to find the height reached by the ball we can apply the third equation of motion i.e v^2 - u^2 = 2as, (0)^2 - (10)^2 = 2(-10)s, 0 -100 = -20s, -100/-20 = s, 5 m = s. Therefore the height reached by the ball is 5 m. Now to find the time taken to come back to the thrower we can apply 1st equation of motion i.e v = u + at, 0 = 10 + (-10)t, -10 = -10t, -10/-10 = t, 1 sec = t. Now the time taken for the ball to reach the height of 5 m was 1 sec. So, the time taken for the ball to reach to the person who throwed the ball will be 2 seconds. Sir I have solved the top three questions kindly tell me the answers are right or wrong.

@sk14_yt44

3 жыл бұрын

Thank you so much I got confused

@prathameshpatil9459

3 жыл бұрын

@@sk14_yt44 You are Welcome.

@jaronrallos3844

3 жыл бұрын

Hey! What made you use the 3rd equation? Especially since we were finding retardation. What does v2 mean? Final Velocity squared?

@prathameshpatil9459

3 жыл бұрын

@@jaronrallos3844 I used 3rd equation of motion because due to that formula we can find the answer in fraction of sec.

@bhavishyamishra2044

3 жыл бұрын

Op bhai 💗

Legends are watching this 1 day before exam

@sujalsharma5894

2 жыл бұрын

Mee too😂😂

@silentbtw1

Жыл бұрын

Haha I am

@tanishqdokewar2233

Жыл бұрын

Me not

@sharmiliagarwal2861

Жыл бұрын

@@tanishqdokewar2233 oh

@tanishqdokewar2233

Жыл бұрын

😁😁😁😁

Your explanation is more than enough! Your videos should be tagged by KZread for students 👏👏

Not just Better than byjus , vedantu , topper .. but also effective and hardworking ...

@ManochaAcademy

2 жыл бұрын

Glad to hear that.

15:35 Q1 ans = v = 10m/s Q2 ans = -a = 20m/s² Q3 ans = s= 5m

Thank oh sir for such a good explanation 1)10m/s 2)-2m/s^2 3)h=5m T=2s

@kkrnagula8234

3 жыл бұрын

Hlo sis how did you get these answers

Q1: Ans: Speed of the car after 5s is 10 m/s Q2: Ans: -20 m/s2 Q3: Ans: Maximum height reached by the ball is 5 m Time taken to come back to the thrower is 2 sec

@ManochaAcademy

4 жыл бұрын

Excellent!! All your answers are correct :)

@shreevigneswaran2112

3 жыл бұрын

Can u explain the answer for third question 🤔

@shreevigneswaran2112

3 жыл бұрын

How s =5m????

@neetnotesbyanisha8265

3 жыл бұрын

@@shreevigneswaran2112 U=10m/s S=? a= -10m/s^2 t=? Here we use V^2=U^2 +2as 0=(10)^2+2×-10 ×s 0=100 -20s 20s=100 S=100/20 S=5m I hope helpful 👍

The ball when at the top, it is in motion exactly as much as it is in motion, when it is at the bottom. That is because the ball is always in motion within space-time. All you can do is change its direction of travel of the ball within the 4D environment known as space-time.

Solution for Question 1: Given, Initial Velocity (u)= 0 Acceleration (a) = 2m/s² Time (t) = 5 seconds Final Velocity (v) = ? We know, v = u + at v = 0 + (2m/s²×5s) v = 10m/s Thus, the speed of the car after 5 seconds is 10m/s.

@j.os_h

2 жыл бұрын

Please explain why it is not 10m/s^2 ??

@srinijamaloth

2 жыл бұрын

@@j.os_h Here, we need to find Final Velocity. Note that Final Velocity has the same sign as speed (m/s). Thus, we write it as 10m/s. We write the magnitude of Accleration as m/s². Therefore, if you write any value as m/s², then the value you are referring is acceleration. Example, 10m/s².

a.) 10 m per second b.) 5 m per second per second c.) time to get to top = 1 sec Time taken to come back to the thrower= 2 seconds. Really appreciate your efforts Sir. Thanks.

@ManochaAcademy

5 жыл бұрын

Thanks a lot :) 1st and 3rd answers (a and c) are correct!! Try the 2nd question again, retardation should be 20 m/s2. 3rd Question asks to calculate maximum height also. Let me know if you have any doubts!

@laxmehassanarl4937

Жыл бұрын

I got the second one correct sir I was searching the ans of 2 thank you sir '

Sir you are doing the best you can. Where have you been in all my school life? Physics is now a piece of cake for me. Thank you sir! Thank you Manocha Academy.

Crystal clear explanation sir! An apt example of experiential learning. I am a chemistry teacher but physics has a special place in my life.

Thank u so much sir for this amazing session....things are crystal clear Answers to the H.W questions 15:35 are :- 1.)10m/s 2.)-20m/s^2 3.)s=5m and t=1s

@programmingwithkartik4319

2 жыл бұрын

Bhot hard

I have a physic test tomorrow about this topic😭😭😭

@ManochaAcademy

5 жыл бұрын

All the best for your Physics test!! You can also watch this related video on Motion Sums and Graphs if it is helpful for your test: kzread.info/dash/bejne/iHmaxcWaibisirw.html

@syraiwilliams5197

3 жыл бұрын

Me tooooo

@sajjagopika4534

3 жыл бұрын

I have physics and chemistry

@Oliver_Rayan

Жыл бұрын

Same 😞

@samarthpattan

Жыл бұрын

same😕

Aap jaise logo ki bahut jaruart hai sir hum students ko. Yha to sab bas ratta marne me mahir bnate hai jo mujhse nahi hota. Pahli baar lga ki mai sahi jagah par time investment kr rha hu. U r The great Teacher.......

My understanding just went from not having a clue what any of this meant, to being able to get it right most of the time. Great video. You are doing a great job providing all the lectures for free. I really appreciate that. Your content and video quality are really good. Thank you, you just gained a subscriber.

Sir You are literally very inspiring and your teaching is out of this universe. I have subscribed to you since 5 years and i have been a very big fan of you. I wish you would have millions of views and subscribers Thank you sir

Sir I easily solved the 1st and 3rd Question using the Equations . But I was unable to do the 2nd one , could you explain it ? Also I have a doubt in how to explain the equations of motion graphically ? Please explain sir , you are explaining very well , it is quite helpful for me . Regards , Abhilash Kar IX

@vibhormurti5877

2 жыл бұрын

i got -20 m/s^2

In question no. 2 and 3 time is not given so, we can Put Time= Distance/Speed instead of time. And both distance and speed is given in the questions.

ANSWER OF THE FIRST QUESTION EXPLANATION : 1. u {initial velocity} = 0 a {acceleration} = 2 m/s square t {time} = 5 s v {final velocity} = ? So here we have to find the final velocity. So we take the first equation. v = u + at = 0 + 2 x 5 = 10 m/s So the final velocity is 10 m/s

@paparazzo_megh

2 жыл бұрын

COPY PASTE!

The answers for the questions at the end of the video (15:36), Q1. v (final velocity) = 10 m/s Q2. a (retardation) = -20 m/s^2 Q3. s (height reached) = 5 meters, t (time taken for the ball to come back from the thrower) = 2 seconds Answers are correct, I confirmed it

@Spoon_dingding

6 ай бұрын

Q.3 2 sec is wrong it should be 1 sec

@tans6188

6 ай бұрын

@@Spoon_dingding it actually is 2 seconds because time taken to come back to the thrower means the total time taken for it to reach the thrower since it was thrown

Respected Sir Physics and math are the hardest subjects for me. This was the video I was looking for. THANK YOU SO MUCH SIR. I request you to make more videos on physics, not only for me but for all the viewers of your wonderful teaching!!!👍😀

Teacher my answer are; Qn 1=10m/s Qn2,retardation =20m/s^2 Qn3;max height=5m Total time=2s Please teacher confirm if my solutions are correct. Thanks for all the videos, really helpful.

@desmondouckama558

Жыл бұрын

this is what i got

@nwaforvictor9017

Жыл бұрын

Pls how did you solve the Q2?

Mind blowing Sir u teach In a very polite manner

@ManochaAcademy

2 жыл бұрын

Thanks and welcome

You gained a subscriber sir. Really, no physics channel teaches as practically as you do. I understood well😊

@ManochaAcademy

Жыл бұрын

Thanks! Great to hear that! Do share our channel with your friends!

@giwaabdulrahman4664

Жыл бұрын

True

1) V=10m/s 2)a=20m/s² 3)maximum height is 5metets Time taken back to thrower is 2 seconds

HOW TO FIND THE EXACT EXACT EXACT CIRCUMFERENCE OF CIRCLE. Procedure Step 1. Draw a square, 2 diagonals and inscribe a circle in the square. Thereby side and diameter will be the same Step 2 : Subtract 2 diagonals from the perimeter of square Step3. Divide step2 with 8 Step4. Add 3 times of the side. to Step 3 At the end we get the EXACT circumference of the inscribed circle

sir answers 1.10m/s 2.A=20metre/sec square 3.distance= 5m,time=1sec

@ChristabelOnyewuchi-ec6rh

Ай бұрын

please show me your workings

Ngl this is very helpful as I am starting my grade 11 this year,thank you very much

1. Ans=10m/s 2. Retardation of the bus= minus acceleration= -20m/s² 3. Maximum height= -5m Time taken to reach maximum height=1s and to come back to the thrower =1s. Total time for the motion =2s

Sir you are really the best teacher

Expert teacher Hats off to you sir 👌🏻🙏🏻

explanation of the 2nd question: Given: final velocity (v) = 0 (since the vehicle comes to rest) initial velocity (u) = 72 km/h => 72 x 5/18 = 20 m/s displacement = 10 m to find retardation (negative acceleration), v² = u² + 2as =>(0)² = (20)² + 2(a x 10) => 0 = 400 + 2 x 10a => 0 = 400 + 20a => 20a = -400 => a = -400/20 => a = -20 therefore the acceleration is -20 m/s

@drsatyabrata01

8 ай бұрын

a=-20m/s2

@ThilinaAd

8 ай бұрын

yh but they are asking retardation which is negative acceleration, which is again 20 m/s

@johnsimon5374

3 ай бұрын

Sorry to ask I'm just confuse I know u =72 so how did that 72*5/18 got in please

Q1) v=u+at u=0, a=2m/s ,t=5s v=o+2×5=10m/s

@ManochaAcademy

4 жыл бұрын

Correct!

Superb Sir... I am seeing this video in 2020 again... Salute to u

@ManochaAcademy

3 жыл бұрын

Thanks for watching again

@harshjethanandani21

3 жыл бұрын

@@ManochaAcademy Welcome sir

Sir please make one video to solve the equation of motion

Hello everyone. I am currently doing 9th term 2 examinations. even though this chapter isn't there in my term 2 examination, i had to study it as these formulas were to be used once again. so plz pay attention to this motion chapter.

Respected Sir u r a great teacher and I m ur fan. How I van attend ur Series/Chapter vise lectures on KZread. hope for swift response.

@ManochaAcademy

4 жыл бұрын

Thanks a lot :) Do check out more videos at www.manochaacademy.com

@avengerparty

4 жыл бұрын

Please give me the date of live class on equation of motion

@jayshreesharma2360

4 жыл бұрын

Super sir.......it is helping even for the students who are little slow.... Very well explained....🙏🙏🙏👍👍👍👍

This lecture helps so many students like me every day..thnku so much for making this..

@ManochaAcademy

2 жыл бұрын

It's my pleasure

Does it basically mean that whatever information is given to us after the = sign, we have to check that whether all the info. given in the question is the value of everything after the = sign in every equation?

Thanks very much Sir for your clear and understandable way of teaching, this has really contributed more in my knowledge in science

1(10) 2(-20) 3a(5) b(1)

Q1 answer is 10m/s Q2 answer is-20m/s² Q3 answers are 1sec and 5m

Sir i m extremly requesting you to make a video on thermal conductivity and if possible so plz cover the whole lesson of thermodynamics

the video is so good like everything but please try to make a short video cuz there are student like me who are trying to cover whole syllabus 2 days before my exams.😅

@prospersomto8547

2 жыл бұрын

Someone like me trying to cover up the whole syllabus 1 week before the exam 😂😂💔. Jamb no be my mate

Sir, Could you please upload the answers in *your comment description* cuz It would be extra useful, since its hard to look for the answers when ever in doubt ;)

@leaguegenix9304

2 жыл бұрын

yes

ALL CONCEPTS CLEAR 😀😀 YOU GOT MILLIONS OF VIEWS INSHAALLAH☺☺

This is the best video for explaining for people who have exams in 12 hours

Sir you are pro at teaching appreciate your teaching style

@ManochaAcademy

3 жыл бұрын

Thanks and welcome

This teacher like gold

@ccrgaming2187

3 жыл бұрын

Hai

@ccrgaming2187

3 жыл бұрын

Yes

@ccrgaming2187

3 жыл бұрын

Yes

@ccrgaming2187

3 жыл бұрын

Very good teacher if he is in my school I will get physics full marks

@iithater6624

3 жыл бұрын

Not gold diamonds

Sir from where are you I scored 70 out of 70 in my exams because of you only

Dear Sir, Can you please explain your audience the meaning of the equations of motion. Like, why we took out the half of acceleration times displacement and etc. This would be very helpful if you will make a separate video on this topic. Regards, Myth

Lack of quality of education in offline made a graduate to reach here and u proved my destination is perfect one to learn physics concepts thanks alot

A, 10m/s B,-20m/ss C ,5 m/s

The answer is 1=10m/s 2=20m/s 2 3=5m

@abdulmalikisa1075

Ай бұрын

Please explain cuz he didn't explain how to solve 2 and 3

@Naijaversal

Ай бұрын

answer 3 is not complete what is the time

Thankyou....I'm starting my studied for new career ...focusing on physics...this video was great simplifies things nicely a great introduction

Answers : 1 = 10m/s 2 = - 2 m/s^2 3 = Height : 5m Time : 1 sec Sir please check my answers. Thanks for your efforts of making videos , makes our studies simple and intresting !

@muhammadfaizantariq7537

3 жыл бұрын

I think second answer is 20

@muhammadfaizantariq7537

3 жыл бұрын

Soory -20

@ahaansings

3 жыл бұрын

@@muhammadfaizantariq7537 ur right he's wrong

@lijasarma33

3 жыл бұрын

Please explain the 3rd solution

@ashapabari2570

3 жыл бұрын

@@lijasarma33 u=10m/s V=0m/s S=? T=? a=-10m/s^2(because to find the time when the ball comes downward) To find T V =u + at 0=10+(-10× t) 0=10-10t 10t=10 t=1s To find s(distance) s=v^2-u^2÷2a S=0-100÷2×-10 s=-100÷-20 s=5m

You are doing a great job providing all the lectures for free. I really appreciate that. Your content and video quality are really good. Thank you, you just gained a subscriber.

@ManochaAcademy

4 жыл бұрын

Thanks for subscribing!! Do share it with your friends!

Yaaa great to see the motion from the ball, initial velocity, from the top and the bottom . I see carefully from the speed of the motion of the ball of the velocity of the ball around of it.

Thanks alot sir,you really help me in understanding motion,God bless you sir🙏🙏

Q1: 10 m/s Q2: a=-20 m/s squared Q3: s= 5m t= 1 sec . Are the answers correct ?

@sinachijune485

3 жыл бұрын

Q3 is -5m and -1 sec

@uzoechifranklin9817

3 жыл бұрын

@@sinachijune485 farida is correct

@faridaabdelhamid6475

3 жыл бұрын

@@sinachijune485 Time is always positive so whenever you find that your answer has time in negative, know that you've done sth wrong in the steps. Maybe u used gravity acceleration in positive not negative.

Best teacher clear concept 👌🙌 and in less time

@ManochaAcademy

3 жыл бұрын

Thanks

Thank you sir. Understood the concept. Also the video was simple and practical. Once again a hearty thanks sir.

Thanks for this you are changing the world by changing future of youths❤️

Thank you sir so much🤧🤧my physics teacher kept on complaining and shouting at me for falling behind but now I'm certain that it's because of the way she teaches thank you so much , I also tried answering Question 1 and it went well but question 3 ? When you say the height reached by the ball , are you also asking for the displacement, and I need to also find the time taken so how is it possible to find both at the same time ?

My test is tomorrow and you've explained this way better than my teacher. A big Thank you all the way from Zambia. I will let you know if I pass

@Jee_ne_aukat_dikha_di

3 жыл бұрын

You've failed as you didn't inform😂??

Answers: 1) 10 m/s 2) -2 m/s2 ( due to retardation) 3) maximum height: 5m Time taken to come back to the thrower: 1s

@suryajithnair2338

2 жыл бұрын

Can u please explain tje 2nd question didnt understand that

Sir I felt you are best in explaining topics about physics, I clearly understand your teaching sir, thank you sir🙏

The problem I'm facing is I can't understand where to put these equations for solving problems can u explain it sir pls?

@gameomania9551

3 жыл бұрын

😞😞 exams monday

@pantherop5829

3 жыл бұрын

@@gameomania9551 all the best friend all wishes

@gameomania9551

3 жыл бұрын

@@pantherop5829 tq bro love u

@pantherop5829

3 жыл бұрын

@@gameomania9551 OK bro you study better OK

@gameomania9551

3 жыл бұрын

@@pantherop5829 sure

Very good explanation sir

Really helpful.., teachers like you is a really great boon for every student

Sir may I ask how we've arrived at the formula v²=u²+2as ? I get that a is the change in v per time, but how did we get from a=v-u/∆t to v²=u²+2as?

Thank you very much Sir. Nicely explained. Is there a video for graphical representation of linear motion? Also it would be good if u could also add videos on numericals?

You are a born teacher. Your students must be happy and lucky to have you as their teacher just like us over here on KZread.

@ManochaAcademy

4 жыл бұрын

Glad you liked. Keep watching

thanks sir as i recieve a physics teacher who teach with principel and concept.

I'm watching this in 2021 and i hv my exam tom this vid was really helpfull much better than any other video i could find on this topic. Your explanation is really good sir i just went from clueless to being able to do most of the sums. Thqu so much sir pls keep uploading gr8 videos

(3)u=10 v=0 (because the ball comes to a momentary stop on reaching the max. height) g=10ms^-2 v^2=u^2-2aS 0=100-2×10×S 20S=100 S(max height reached)=5metre. v=u-at 0=10-10t 10t=10 t(time taken to reach max height)=1sec. the ball takes the same time to cover both upward and downward displacement, provided acc due to g is constant. Total time taken to reach thrower hand=1+1=2sec.

@farina10thb15

2 жыл бұрын

isn,t its the formula V^2=U^2+2aS?

@muhammadismail2925

2 жыл бұрын

Nice bro.i undertand the first equation well.i will correct the mistake i ave done.for the second part can u elaborate more pls cus it says THE TIME TAKEN TO COME BACK TO THE THE THROWER.tnx once more

Sir you are great tomorrow I have a science periodic test in which motion is coming I have not studied at all and when I see you video I shocked and now I am ready to give tomorrow test thanks a lot

@ManochaAcademy

4 жыл бұрын

Happy to hear that you liked the video :) All the best for your test!!

It's really good sir .. Who are study persons they watch this video. Really it's good guys watch this .

Ans 1: 10m/s And 2: -259.2km/h And 3: 5m, 1s

Thanku sir for clear my all doubts of this topic .

@ManochaAcademy

3 жыл бұрын

Most welcome

Answers... 1. 10 m/s 2. 20 m/s^2 3. h=5m and time taken to return = 2 s

@malayalamcomedy6354

4 жыл бұрын

Eveey thing os correct

@1234nadirkhan

4 жыл бұрын

Q2 answer is -2

14:59 Q1) u =0 (rest) a = 2 m/s t= 5 s (speed = v , adding this bcs i didnt know , so it give me a confusion) v =u+at =0+2*5 =10 m/s

5m/s is no 1 . professor am i correct

You teach with good technic.

Ans 1. v=10m/s Ans 2.a= -0.03m/s2 Ans 3. s=5m ,t=1sec

@anandvardhansharma4761

3 жыл бұрын

Is this the answers of top 3 q ??

@nathandias7509

3 жыл бұрын

@@anandvardhansharma4761 yes

@ayushisharma9697

3 жыл бұрын

yess!! You are absolutely right

@anandvardhansharma4761

3 жыл бұрын

Okk.....thnx

This is one of the best teachers In the world he takes time on his explanations, examples and he puts the examples into real life experience which makes it easier for the student watching to learn and retain for a very long time🙌

@versityict

2 жыл бұрын

I think this teacher should be awarded.

iI loved the lesson thank u for helping me understand the equations of motion esp. S part

Thanks a ton sir it really helped me a love from Pakistan.i wish we can have teachers like you in our schools🙂

Sir! I have answered a question that is (que 1) V=u+at^2 V=0+2m/s^2(into)5s V=0+10m/s So V=10m/s

@ManochaAcademy

4 жыл бұрын

Correct!

@guneetsingh9455

4 жыл бұрын

the equation has no power of 2

Thank you sir i understood this consept well and is the best educational you tube channel

you made my soul satisfied ...the way u give real life examples and clear the concepts of physics is really admirable .the best ever teacher in physics , will be waiting for many more videos in future. Thank you

@ManochaAcademy

3 жыл бұрын

It's my pleasure