Enzyme Inhibition (Part 1 of 3) - Competitive Inhibitors

Moof's Medical Biochemistry Video Course: moof-university.thinkific.com/...
Questions Answered in This Video:
- What are competitive inhibitors, and what is mechanism by which they act?
- How do competitive inhibitors affect the values of KM and VMAX?
- How do competitively inhibited reactions look on the hyperbolic graph and Lineweaver-Burk plot?
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Video Content Summary:
Competitive inhibitors "compete" with substrate for binding the enzyme's active site. Free enzyme will bind either the substrate OR the competitive inhibitor. It cannot bind both at the same time. If the enzyme binds the substrate, the enzyme-substrate complex forms, and the enzyme can convert the substrate into product. If, however, a competitive inhibitor binds the active site, the enzyme-competitive inhibitor complex forms, which cannot proceed towards products, for the simple reason that the competitive inhibitor impedes the ability of the substrate to bind to the enzyme.
Since a competitive inhibitor blocks the substrate from binding, the competitive inhibitor essentially lowers the affinity of enzyme for the substrate. Thus increasing the KM. Despite this, VMAX can still be reached with a high enough substrate concentration. If the substrate concentration is sufficiently high, the substrates will out-compete the competitive inhibitor for binding at the active site, thus effectively overcoming the effects of the inhibitor.
The effects of a competitive inhibitor on an enzyme-catalyzed reaction are depicted in a variety of ways in the video, and it is shown what happens to the hyperbolic graph and the Lineweaver-Burk plot, otherwise known as the double reciprocal plot.

Пікірлер: 23

  • @nathanstrugnell4819
    @nathanstrugnell48198 жыл бұрын

    Awesome explanation bro, exactly what I was looking for. Love that you don't waffle unlike a lot of other channels

  • @meranasummers5782
    @meranasummers57826 жыл бұрын

    Finally!!! I have read so many articles and watched so many videos and failed to understand. Yours was the first that explained this concept so elaborately. Thank youuuuuuuu

  • @MoofUniversity

    @MoofUniversity

    6 жыл бұрын

    Lol. So epic. I love it when that happens. You're very welcome! Thanks for watching!

  • @inacala8864
    @inacala88649 жыл бұрын

    You are simply AMAZING!!! Thank you from the bottom of my heart!

  • @sciencenerd7639
    @sciencenerd76392 жыл бұрын

    Great video

  • @karraralgburi8937
    @karraralgburi89378 жыл бұрын

    thank you my friend we ll support you

  • @yaronzaret632
    @yaronzaret6328 жыл бұрын

    Amazing explanation, thank you!

  • @carolinaescobar4763
    @carolinaescobar47636 жыл бұрын

    Amazing!

  • @MoofUniversity

    @MoofUniversity

    6 жыл бұрын

    Thanks!

  • @meamea6540
    @meamea65405 жыл бұрын

    tnxx aloott

  • @inaveenrajawat
    @inaveenrajawat8 жыл бұрын

    bdiya h bhai.....puro pdao nek

  • @rayanmutasim1115
    @rayanmutasim11155 жыл бұрын

    I love uuuuu😭😭😭😭❤️❤️

  • @Kobalamin88
    @Kobalamin885 жыл бұрын

    I dont understand how you would know where the line from the negative x-axis Ic´ starts, how do you know it starts from -2? and how should you draw it after you pass Vmax on the Y-axis. I understand how to calculate Km = -1/x-intercept= Km value. Is KM in this regard -2? I am very confused.

  • @ramchandrasuthar2848
    @ramchandrasuthar28489 жыл бұрын

    Very nice sir Great explanation

  • @MoofUniversity

    @MoofUniversity

    9 жыл бұрын

    Ramchandra Suthar Thanks! I'm glad you liked it!

  • @ramchandrasuthar2848

    @ramchandrasuthar2848

    9 жыл бұрын

    Sir please make a video on Ramchandran plot

  • @ramchandrasuthar2848

    @ramchandrasuthar2848

    9 жыл бұрын

    Your explaination is unique and enjoying way

  • @ramchandrasuthar2848

    @ramchandrasuthar2848

    9 жыл бұрын

    GOD bless you

  • @yuzu8284
    @yuzu82847 жыл бұрын

    We said that the km app is higher then why it's smaller in double reciprocal ?..and how does the inhibitor has a higher slope if it's 2 and the no inhibtor is 5???..i didn't get that..

  • @z0mbjes

    @z0mbjes

    5 жыл бұрын

    Yo Zora not sure what you’re talking about with the numbers but, since the Km is bigger, 1/Km is smaller. It’s on the left side of the graph, in the negative zone: -1/Km becomes bigger again (eg. -0.5> -1)

  • @aishahhearts8294
    @aishahhearts82946 жыл бұрын

    Thank you

  • @MoofUniversity

    @MoofUniversity

    6 жыл бұрын

    Sure thing!

  • @yvonnek4
    @yvonnek49 жыл бұрын

    cutie