Best basic explanation I've seen of this, after a lot of searching! Thanks very much. :)

VERY GREAT EXPLANATION SIR, i really love to watch your videos, be HAPPY sir.

sir , instead of using kirchoff's junction rule , can we use current division rule to relate the branching current variables ?

This is most helpful as I could understand further

Mr. Van Biezen has left out one important fact. The equations he came up with are correct as far as he has gone. Mr. Van Biezen has left out one very important fact. We need one more KVL equation that is a loop that includes the voltage source. Then you can solve for the currents in the resistors. If you express the currents I4 and I5 as functions of I1, I2 and I3 then you have three equations in three unknowns.

@MichelvanBiezen

2 жыл бұрын

You are correct. If the wrong combination of loops (equations) are picked, a solution cannot be found. To appreciate that, it is useful for the student to experiment with that so they can see how that works.

@trickytricks5119

Жыл бұрын

yeah - it's unsolvable otherwise

Dear Sir, Thank you very much for all your videos. I need your notes in ppt .

REALLY ENJOY YOUR HARD WORK

@MichelvanBiezen

2 жыл бұрын

Thank you. Glad you do. 🙂

Is the total resistance 16.10 ohms using d to y formula ?

thank you for saving my life

@MichelvanBiezen

2 жыл бұрын

That may be a bit dramatic, but we are glad that we were able to help.

HI, in case of R1 > R2 the I3 would have flown in opposite direction, isn't it? thanks!

@MichelvanBiezen

6 жыл бұрын

It also depends on the value of R4 and R5. Try a few combinations and see what happens. The best way to learn.

All equations have nothing to do with 10 V of source. How come?

Sir I am from India and I like you explaing us very good

@MichelvanBiezen

3 жыл бұрын

Thank you and welcome to the channel!

One of the biggest problems in understanding these problems is that many examples have the different I sections in different sides of the diamond and it gets very confusing. So when a book problem says that r1 is always I1? r2 to I2 and so forth and so forth?

@MichelvanBiezen

Жыл бұрын

That is a good point. (But different authors are going to use different combinations).

@lagunacorona

Жыл бұрын

@@MichelvanBiezen now in wheatstone bridge circuits does current always travel and split at the very first top node? why do books say there are loops of different kinds? again very confusing.

@MichelvanBiezen

Жыл бұрын

Current always splits in some ratio at every circuit junction. More current will flow through the branch with less resistance. Note that bridge circuits are complicated and it is better to start with some examples of simpler circuits before attemping to use Kirchhoff's rules to solve a bridge circuit.

thnak you for the lecture how can i simplify this circuit like you did in the previous vedio

@MichelvanBiezen

3 жыл бұрын

You're welcome!

what to do if the source is located inside the diamond.

@munirahmedkauswala1875

5 жыл бұрын

we can interchange souce and dimond resistance result will be same

The number of equations for Kirchoff's Current Law you can writer to solve a circuit equals the number of nodes minus 1. This circuit has 4 nodes, but you have written 4 KCL equations (the first 4). So aren't you still one equation short of being able to solve the circuit?

@MichelvanBiezen

2 жыл бұрын

You need an equation for each of the unknown currents. (you can use Kirchhoff's current equation to eliminate one of the unknowns).

How do you know which way the current in the center flows?

@MichelvanBiezen

5 жыл бұрын

It is usually possible to determine by looking at the size of the resistors. The smallest resistors carry the greatest current. If you can't tell then you can just guess and if you guess wrong, you'll get a negative answer for the chosen current.

@cyrilrelatado3874

4 жыл бұрын

@Michel Van Biezen, Sir what would be the answers?? I get I1 = 1.15 Amps I2 = 0.59 Amps I3 = 0.09 Amps I4 = 1.06 Amps I5 = 0.68 Amps Total current = 1.74 Amps Am I correct??

@cyrilrelatado3874

4 жыл бұрын

@@MichelvanBiezen @Michel Van Biezen, Sir what would be the answers?? I get I1 = 1.15 Amps I2 = 0.59 Amps I3 = 0.09 Amps I4 = 1.06 Amps I5 = 0.68 Amps Total current = 1.74 Amps Am I correct??

@Dissenter1688

4 жыл бұрын

@@cyrilrelatado3874 I obtained the same total current (1.74 Amps) when working the problem with two different methods (mesh analysis & delta-y conversion).

@trickytricks5119

Жыл бұрын

@@cyrilrelatado3874 yes

my formal understanding of math is somewhat "arrested" but conceptually I reckon that the purpose of the six equations is to calculate the unique current value of each branch (I1, I2, I3, etc ...) that would satisfy each and every one of them, hence arriving at the solution. Correct?

@MichelvanBiezen

7 жыл бұрын

Yes. (That would be a big task, but it can be done).

How do you know which side I3 will flow into

@MichelvanBiezen

2 жыл бұрын

We assume that some current (we don't know how much) flows through each of the branches. Then we label those currents for each branch. So the current flowing through R3 is now labeled as I3. Then we use one of the circuit evaluation techniques to determine what the value of that current is. (as illustrated in the video)

@paulian1888

23 күн бұрын

@@MichelvanBiezen What I am assuming is that due to Ohm's Law, more current will take the lower resistance path, which is 5 ohms as opposed to 10, so the higher current node won over the lower current node (the one connected to 10 ohms) and became our assumed current direction. Could be wrong.

if you use a matrix you cant use equation 4 because its the same as equation 1 and the determinant will be zero won't it? Plus as rickmcn1986 said, you do need an equation that includes the system's emf.

@juanjorbrr

4 жыл бұрын

I tried to get the final solution with this six ecuations with six unknowleges. Using an app in my mobile (Gauss-Jordan) there are infinite solutions. The determinant of coeficient matrix is zero. So, at least one ecuation is a linear combination of other.

For those who want the solution, we need to include another equation that factors in the voltage source: 10 - 5(I_1) - 4(I_4) = 0, a consequence of Kirchhoff's Voltage Law. If we solved the following equations simultaneously: -> (I_T) = (I_1) + (I_2) -> (I_1) = (I_3) + (I_4) -> (I_5) = (I_2) + (I_3) -> 5(I_1) - 10(I_2) + 2(I_3) = 0 -> 4(I_4) - 2(I_3) - 6(I_5) = 0 all are derived in the video (NOTE: I am not including: (I_T) = (I_4) + (I_5)) and -> 10 - 5(I_1) - 4(I_4) = 0 We obtain the following answers: I_T = 1.74216A I_1 = 1.14983A I_2 = 0.59233A I_3 = 0.08711A I_4 = 1.06272A I_5 = 0.67944A Note, these values also satisfy the equation we excluded: (I_T) = (I_4) + (I_5): 1.06272A + 0.67944A = 1.74216A = I_T

@MichelvanBiezen

Жыл бұрын

Thanks for the input.

@oliverdiaz4198

11 ай бұрын

In 10-5(i_1)-4(i_4)=0 Why did you only use 2 resistors if it includes the whole circuit? Im just confused

total current is 1.74 AMPS

These equations will not yield a result in amperes. The best you can do (as far as I can see) is end up with a series of relationships between currents.

🤗🤗

@MichelvanBiezen

Жыл бұрын

Glad you liked it. 🙂

I got I= 2.1 and Req=4.74 and I1=1.4 and I2=0.7, I3=0.93, I4=0.4667, I5=1.63 is is right?? Plz comment

@janitgjay3157

4 жыл бұрын

no

@trickytricks5119

Жыл бұрын

yeah, that isn't correct - did you include another equation, factoring in the voltage source? Otherwise, no solutions are possible