Thank you for yet another helpful video!

so helpful! thank you amreen. there truly is no better trainer thank you!

Thank you very much. You clear all my doubts in a very easiest way.thanks a lot❤❤

@PraxisAcademic

9 ай бұрын

I am so glad this helped make it easier! Thank You for watching!

Thank u for saving my time The best video ever ❤❤

@PraxisAcademic

2 ай бұрын

I am glad this helped!

Amazingly simplified! Couldn't explain it better, thank you!!

@PraxisAcademic

10 ай бұрын

Thank You!

you so so amazing! thank you so much for your help :)

@PraxisAcademic

11 ай бұрын

I am glad this helped! Thank You for watching!

omg.... you made my exact issues with aromatic molecules so much more clear... thanks

@PraxisAcademic

Жыл бұрын

I’m glad it cleared aromaticity up for you!

This is so helpful!

@PraxisAcademic

Жыл бұрын

I am glad this was helpful!

❤❤. Pls continue making it. Pls make a trick for gmp of hydrocarbons.

@PraxisAcademic

2 ай бұрын

I will work on a trick for that. Thank You for watching!

God bless that’s all I gotta say

@PraxisAcademic

7 ай бұрын

lol... thank you so much... glad this helped!

Thank you for helping me understand but I only have one question .why aren’t you counting the +charge at 9:15 to make it 8 pi electrons resulting to anti aromatic?

@PraxisAcademic

10 ай бұрын

Hi... thank you for watching! A +charge on a carbon indicates that it lost its 4th valence electron and therefore now only has 3 bonds (bond to H not shown) using its 3 remaining valence electrons, and no other electrons, so think of the +charged carbon as "void" of pi electrons (so, no electrons to count there), remembering that pi electrons are either lone pairs or the 2 electrons in a double bond. But we do consider the +charge when determining conjugation, because pi electrons can jump to the +charged carbon since there is a "void" of electrons, like there is a "vacancy" for pi electrons to jump into. It also helps to think about a carbon with a -charge; a negatively charged carbon has its 4th valence electron and gains a fifth electron that pairs up with the 4th to make a lone pair [plus the 3 bonds as mentioned above]; that's why we count the -charges as pi electrons (lone pairs). I hope this helps further understand aromaticity and why +charges are included but not counted as pi electrons.

@PraxisAcademic

10 ай бұрын

Good question... btw... it's a common question among my students, and hopefully this helps others better understand aromaticity!

@toptv1049

6 ай бұрын

Hello, does the "including in counting as double bonds, but not in counting as pi electrons" apply to both positive and negative charges?

You should increase the volume of the sound

@PraxisAcademic

8 ай бұрын

Thank You for the feedback! I will make sure to crank it up a bit on all future videos. I was always afraid I was making it too loud; I appreciate the constructive feedback!

Well cyclooctatetraen isn’t planar in the first place

@PraxisAcademic

5 ай бұрын

True... cyclooctatetraene predominantly exists as tub-shape due to its irregular bond lengths, however, I intended to show its planar transition state between its tub-shapes which is antiaromatic. I showed its antiaromatic state because that's how they usually show it on DAT or MCAT. If they were to show the 3D tub-shape, then indeed it would be nonaromatic. Thank You for watching!