EASY PEASY, BE SURE TO KNOW HOW TO DO IT....!

This video discusses another example of the theorem on definite integrals with lower limit is equal to zero. The theorem was originally introduced along with the proof in the previous video. The reason for posting this video is to show possible other forms of applications of the theorem, than being limited to the example discussed in that video with the introduction of the theorem.

Пікірлер: 9

  • @calbernandhowbe
    @calbernandhowbeАй бұрын

    Nice! In fact you can do the u-sub immediately even before multiplying above and below by cos^6(x), if you use the identity tan(π/2 - x) = cot(x). But of course this is essentially the same as your method :D

  • @gayansamarasekara

    @gayansamarasekara

    Ай бұрын

    Perfect….! You nailed it…!

  • @user-wj1qb3qu1y
    @user-wj1qb3qu1yАй бұрын

    Its become hard when the integral are undefine

  • @gayansamarasekara

    @gayansamarasekara

    Ай бұрын

    Thanks for your comment. I think you mean when the integral is indefinite. Yes, harder in that case, though it can still be evaluated.

  • @fernandoromeralopez8251
    @fernandoromeralopez8251Ай бұрын

    I do not understand the numerators are not de same.

  • @gayansamarasekara

    @gayansamarasekara

    Ай бұрын

    Thanks for your question. Yes, the numerators are not the same, but the denominators are. You have the first term in the form: a/(a+b), and the second term in the form: b/(a+b), meaning when the two are added you get: (a+b)/(a+b) = 1.

  • @fernandoromeralopez8251

    @fernandoromeralopez8251

    Ай бұрын

    @@gayansamarasekara thank you so much

  • @fernandoromeralopez8251

    @fernandoromeralopez8251

    Ай бұрын

    @@gayansamarasekara it’s so easy. Thanks

  • @gayansamarasekara

    @gayansamarasekara

    Ай бұрын

    @@fernandoromeralopez8251 Indeed, it's so easy. You are welcome....! Thanks for commenting....!