Nice , thank you

@CanBijles

Ай бұрын

You are welcome!

The same method can be used with the other switched converters such as the boost and buck-boost but deriving the plant transfer function is more complicated and requires state space averaging. This involves deriving a state space for all the switching states and averaging them. DCM will have a different transfer function to CMM due to the additional zero current state.

@CanBijles

Ай бұрын

Thanks for your message. Indeed, this method can be also used for other converter types. Not only the derivation will be somewhat difficult, but also also different for the modulator transfer function depending on the operating mode. For continuous conduction mode, the transfer function is much easier than for the discontinuous conduction mode.

@fablearchitect7645

Ай бұрын

@@CanBijles yes one could dedicate an entire video to deriving the transfer function per converter and operating mode

@CanBijles

Ай бұрын

Indeed, it is all about time and how far we need to go in the derivations.

Great!

@CanBijles

Ай бұрын

Thanks!

Hello,Thank you for a useful and informative lesson. It's just not clear why the divider R1 R3 is at the input and not at the output of the converter? Where in this scheme is the feedback from the output of the system to its input?

@CanBijles

Ай бұрын

Thanks for your message. The error amplifier compares the reference voltage Vref with the part of the output voltage. This should be done at the input of the error amplifier The part of the output voltage is set equal to the Vref using the voltage division created by the resistors R1 and R3. This is also explained in the video. Comparison is made best at the input of the error amplifier, because the circuit can act faster to changes in the output voltage.

@CanBijles

Ай бұрын

In addition: the circuit in the TINA-TI Spice simulator is for AC analysis. Here, we look at the loop transfer function, so we apply a AC signal at the point (output node) where we also measure the output voltage, thus we make a complete loop. The Vg is also Vo for normal operation. This is just for AC analysis.

@SMV1972

Ай бұрын

@@CanBijles Yes, everything is clear now, thank you!

@CanBijles

Ай бұрын

Great to know👍

@SMV1972

Ай бұрын

@@CanBijles And also, could you tell me, the step response can somehow be seen according to the scheme from TINA TI

Hello Sir, based on 25:43 the phase boost of the designed compensator will be 68.5 degree?

@CanBijles

Ай бұрын

How did you get the 68.5 degrees of phase contribution for the compensator?

@patrickliew2756

Ай бұрын

@@CanBijles Is is by 90 - 21.5 = 68.5 phase boost since the compensator starts from -90 degree to -21.5 degree.

@CanBijles

Ай бұрын

​@@patrickliew2756 You can see in 25:25 in MATLAB that the phase contribution of the compensator is -21.5 degrees. This is not taking into account the 180 degrees phase shift due to inverting amplifier action of the error amplifier. At 28:05 you can see that the phase of the compensator is 157 degrees in TINA-TISPICE, which is close to 180 - 21.5 = 158.5 degrees. TINA-TI Spice and MATLAB calculation the phase of the compensator different, because MATLAB does not include the phase inversion due to inverting amplifier action of the error amplifier.

Hello sir, I had emailed you some question regarding the design of type 2 compensator. Hope you can have a look when you are free. Thank you.

@CanBijles

Ай бұрын

Ok, I will get back to it as soon as possible. In the mean time, you can send the documents and files you have where necessary.