Your intro song was soo funny, it's like retro cartoon song

Your intro and outro reminds me of some old educational cartoon I use to watch when I didn't go to school as a child. I love that vibe

You are one of the best mathematics teachers l have seen ever. Your videos are too helpful for the students like us.We get immense help from your videos.These videos make our topics quite easier.Carry on.

There is a lot of intensity in your voice, your words directly go into my head.😄

Great tutorial. I completely understood continuous and discontinuous with just one explanation.

Thank you professor Dave!

Never seen a better teacher

Thabk you so much!!! This helps me a lot

Thank you professor dave! Liked and subbed

MR PROFESSOR DAVE THANK YOU SO MUCH I DONT KNOW WHAT I WOULDVE DONE IF IT WERENT FOR YOU THANK YOU AGAIN

Sir please make a lecture on how a discontinuous function is converted into a continuous function with the use of unit step function.

📚great video,keep it up!

thank you!! very clear and intuitive; you do know how to teach;

Thank you🌟

Your a great teacher amazing exmalantion

Thank you!!

super helpful!

Thanks for saving me again!

Do u have any video that teach about limit n continuous...

thank you professor

bro that's about as simple as it gets. you're a fucgggging G

very helpful ♥

Thank you Sirrrr

Very helpful

OMG THANK YOU SO MUCH GOD BLESS YOU

Sir can u give me any application of discontinuity in science

Very helpful for jee aspirants 🤘

Thanks

2:45 - so... (x^2-1)/x-1 = x-1 but x cannot equal 1 for the first case but CAN be 1 for the second case of function. Wouldn't that mean that we are "wrong" when we say (x^2-1)/x-1 = x-1??? i'm confused...

Superb sir... I understood in a easy way.. 😇

W you remind me of my younger days in elementary school but for harder math!

Any function with a vertical asymptote must me a "Continuous" function, according to my textbooks.. My teacher told me that they will never meet, but that doesn't mean there's a gap, they'll meet at infinity.

Dave, isn't the function 1 / x - 1 not graphed as it should be? For example, if you plug x = 2, y gives back 1, and the coordinate (2, 1) is not in the curve.

@ProfessorDaveExplains

4 жыл бұрын

hmm yeah it's not perfect, the asymptotes are correct but it's not a flawless representation. i don't really have a way to get the curves perfect as i just paste them together from a stock image of a parabola or something, please excuse the approximation!

@alburnto

4 жыл бұрын

@@ProfessorDaveExplains totally excusable :) Thanks for your work!

@ashutoshtiwari3785

4 жыл бұрын

@@ProfessorDaveExplains You should use Manim if you know Python for visualisations.

2:17 can this function be called piecewise function?

Done this lesson.

At 3:00 how would I know 1 is not a value if I was just seeing the simplified function of x +1??

@ummehabibahappy2161

4 жыл бұрын

if we put value 1 for x then it will undefined that's why here 1 cant be the value of x..

@heydrianluisanilao1757

2 жыл бұрын

Then x + 1 is the only thing you have to be concerned about

Life saver

Can someone please explain me the example of piecewise function..i didn't get how the coordinates (-2,5) and (-2,-3)were found .

@vodiact

Жыл бұрын

do you still need help

@Butterfly-bs7jp

Жыл бұрын

@@vodiact please explainnn 🥺

@vodiact

Жыл бұрын

@@Butterfly-bs7jp actually i have no idea now

The way he Explains.... Like puts effort in his voice..... I get it Totally.... Humble guy 😄

Hello Professor Dave. At 2:54, how would i know that x cannot be equal to 1 if it shows only the simplified function?

@BankBlitz818

3 жыл бұрын

Then you won't have to worry about it. :)

@anishpalabatla4543

3 жыл бұрын

The function is (x^2-1)/(x-1) by default hence, 1 is a point of discontinuity. But, if the function is x-1, there is no restricted domain, i.e x€R. Hope this helps you :)

@heydrianluisanilao1757

2 жыл бұрын

Then x + 1 is the only thing you have to be concerned about

@cometolearn8598

2 жыл бұрын

because if x is equal to 1 then we get x^2 - 1/1-1 which here 1-1 makes the denominator = to 0 meaning the function will become undefined and the function would be discontinuous Hope this helped :)

Good explanation. If a function is discontinuous then why we call it A FUNCTION ANYMORE? it is in the definition of a function that its all domain members MUST have unique image But one of the domain members does not have value then Why call it a function?? If the function is producing Irrational numbers then is it a continuous or discontinuous? if a function outputs Infinity it will be a continuous or discontinuous? if a function outputs a non-terminating value it will be a continuous or discontinuous? if a function outputs indeterminate forms type values is it a continuers or discontinuous?

3:05 that was totally you scratching your beard

Well detailed explanation. Wasted 3 hr trying to understand my professor 😒

Thank you Math Jesus

❤❤

Sorry professor, but I disagree with 2:55 . 0/0 is not undefined, it is indeterminate. Not the same. 0/0 can actually be anything we want, as any real number can be the solution to the equation "0x = 0". Therefore, since "(x-1)/(x-1)" CAN be 1 for all real values including 1, it can be safely simplified without having to exclude 1. If I'm wrong and you have the time to explain this to me, please do.

@manaarikicarpentier6038

2 жыл бұрын

Nope, you can't do 0/0 simply because you can't divide by 0 because this implies that 0 has an inverse which is false. Because if there's an x such that 0x = 1 that's absurde because for all x, 0x = 0. so for all x, x/0 is undefined in particular, 0/0 is undefined. We talk about indeterminate when we are dealing with limits (which we were not in this case)

@longlostwraith5106

2 жыл бұрын

@@manaarikicarpentier6038 No, sorry, you are utterly wrong about this.

@manaarikicarpentier6038

2 жыл бұрын

@@longlostwraith5106 why?

@longlostwraith5106

2 жыл бұрын

@@manaarikicarpentier6038 Because "0x = 1" and "0x = 0" are two completely different beasts. In the first one, "x" can't be any real number. In the second one, "x" can be any real number you want it to be.

@manaarikicarpentier6038

2 жыл бұрын

@@longlostwraith5106 exactly, you can't find any x such that 0x=1 so 0 isn't inversible thus you can't divide by 0

so most rational functions are discontinuous functions

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I am literally Speed running mathamatics🏃💨

@miguelcielos9442

27 күн бұрын

Bro's locking in

@sue4552

11 күн бұрын

do you understand how the thing became -3?

Professor Jesus Explains

first

Thank You Calculus Jesus

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@basketguitar9768

3 ай бұрын

Math is like crack

I'm literally gonna puke

If we are clever....

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